Isolating a in a Radical Equation Chapter 0 Problem setup Objective: isolate the variable a in an equation that involves a square root (radical). The radical shown is a square root, so we need to undo it by squaring both sides of the equation. Core principle: inverse operations. What you do to one side, you must do to the other side to preserve equality. The equation given (as interpreted from the transcript) is:5 a − 2 b c = 8 d − e \sqrt{\dfrac{5a - 2b}{c}} = 8d - e c 5 a − 2 b = 8 d − e After squaring both sides, the right-hand side becomes squared, i.e., ( 8 d − e ) 2 (8d - e)^2 ( 8 d − e ) 2 on the right, and the left becomes the radicand squared. Plan of steps: square both sides, clear denominators, isolate a , and then simplify the resulting expression. Step-by-step solution Step 1: Square both sides of the original equationLeft side after squaring: ( 5 a − 2 b c ) 2 = 5 a − 2 b c \left(\sqrt{\dfrac{5a - 2b}{c}}\right)^2 = \dfrac{5a - 2b}{c} ( c 5 a − 2 b ) 2 = c 5 a − 2 b Right side after squaring: ( 8 d − e ) 2 (8d - e)^2 ( 8 d − e ) 2 Resulting equation: 5 a − 2 b c = ( 8 d − e ) 2 \dfrac{5a - 2b}{c} = (8d - e)^2 c 5 a − 2 b = ( 8 d − e ) 2 Step 2: Clear the denominator by multiplying both sides by c 5 a − 2 b = c ( 8 d − e ) 2 5a - 2b = c\,(8d - e)^2 5 a − 2 b = c ( 8 d − e ) 2 Step 3: Add 2b to both sides to move the constant term on the left5 a = c ( 8 d − e ) 2 + 2 b 5a = c\,(8d - e)^2 + 2b 5 a = c ( 8 d − e ) 2 + 2 b Step 4: Divide both sides by 5 to isolate a a = c ( 8 d − e ) 2 + 2 b 5 a = \dfrac{c\,(8d - e)^2 + 2b}{5} a = 5 c ( 8 d − e ) 2 + 2 b Step 5: Optional but helpful – expand the square on the right using FOILExpand inside: ( 8 d − e ) 2 = 64 d 2 − 16 d e + e 2 (8d - e)^2 = 64d^2 - 16de + e^2 ( 8 d − e ) 2 = 64 d 2 − 16 d e + e 2 Substitution gives: a = c ( 64 d 2 − 16 d e + e 2 ) + 2 b 5 a = \dfrac{c\,(64d^2 - 16de + e^2) + 2b}{5} a = 5 c ( 64 d 2 − 16 d e + e 2 ) + 2 b Step 6: Distribute c inside the parenthesesc ( 64 d 2 − 16 d e + e 2 ) = 64 d 2 c − 16 d e c + e 2 c c\,(64d^2 - 16de + e^2) = 64d^2c - 16de c + e^2 c c ( 64 d 2 − 16 d e + e 2 ) = 64 d 2 c − 16 d ec + e 2 c Therefore: a = 64 d 2 c − 16 d e c + e 2 c + 2 b 5 a = \dfrac{64d^2c - 16de c + e^2 c + 2b}{5} a = 5 64 d 2 c − 16 d ec + e 2 c + 2 b Step 7: Provide an equivalent compact formCompact form (using the expanded square): a = ( 8 d − e ) 2 c + 2 b 5 a = \dfrac{(8d - e)^2\,c + 2b}{5} a = 5 ( 8 d − e ) 2 c + 2 b Expanded form (as shown in Step 6): a = 64 d 2 c − 16 d e c + e 2 c + 2 b 5 a = \dfrac{64d^2c - 16de c + e^2 c + 2b}{5} a = 5 64 d 2 c − 16 d ec + e 2 c + 2 b Step 8: Summary of final answer formsFinal answer in compact form: a = c ( 8 d − e ) 2 + 2 b 5 a = \dfrac{c\,(8d - e)^2 + 2b}{5} a = 5 c ( 8 d − e ) 2 + 2 b Final answer in expanded form: a = 64 d 2 c − 16 d e c + e 2 c + 2 b 5 a = \dfrac{64d^2c - 16de c + e^2 c + 2b}{5} a = 5 64 d 2 c − 16 d ec + e 2 c + 2 b Key concepts and techniques highlighted Inverse operationsRadical vs exponent: to undo a square root, square both sides. Addition/subtraction: add 2b to both sides to move terms. Multiplication/division: multiply by c to clear the denominator; divide by 5 to isolate a . Algebraic manipulation orderStart with removing the radical, then clear fractions, then isolate the variable. FOIL/Expanding squaresExpanding \((8d - e)^2\) using FOIL yields: \((8d - e)^2 = 64d^2 - 16de + e^2\). Distributing the resulting expression with c gives the expanded numerator: \(64d^2c - 16de c + e^2 c\). Alternative forms of the final answerKeeping the square inside: \(a = \dfrac{c(8d - e)^2 + 2b}{5}\). Expanding fully: \(a = \dfrac{64d^2c - 16de c + e^2 c + 2b}{5}\). Practical considerations and quick checks Consistency check: If you square both sides, you may introduce extraneous solutions; check any candidate a in the original equation if solving numerically. Real-world relevance: This method demonstrates how to undo radicals and isolate variables in equations with multiple terms and fractions, a common task in algebra and calculus problem solving. Connections to foundational principles Reversal of operations is foundational in solving equations: inverse operations (squaring corresponding to the square root, multiplying to clear denominators, adding to offset subtraction). The structure of the problem reinforces the idea that solving for a variable often involves isolating that variable step by step while keeping track of what happens to all other terms. The final expanded form illustrates how distributive law and FOIL connect compact and expanded representations of expressions.