Week 1 Notes: Real Numbers, Sequences, and Fundamental Limits
Real Numbers: Field Axioms and Order Axioms
- Notation
N := {1, 2, 3, …}, the set of natural numbers- Z := {0, ±1, ±2, ±3, …}, the set of integers
- Q := {p/q : p, q ∈ Z, q ≠ 0}, the set of rational numbers
- R := the set of real numbers
- Geometric view: R is described by a bijection with points on a line extending infinitely in both directions
- Field Axioms: binary operations + and · on R satisfy the following for all a, b, c ∈ R
1) a + b ∈ R
2) a + (b + c) = (a + b) + c
3) ∃0 ∈ R such that a + 0 = a = 0 + a
4) ∃−a ∈ R such that a + (−a) = 0 = (−a) + a
5) a + b = b + a (commutativity of addition)
6) a · b ∈ R
7) a · (b · c) = (a · b) · c
8) ∃1 ∈ R such that a · 1 = a = 1 · a (multiplicative identity)
9) ∀a ≠ 0, ∃ a⁻¹ ∈ R with a · a⁻¹ = 1 = a⁻¹ · a (multiplicative inverses)
10) a · b = b · a (commutativity of multiplication)
11) distributive laws: a · (b + c) = a · b + a · c and (a + b) · c = a · c + b · c - Order Axioms (structure of positivity in R)
- There exists a nonempty subset R⁺ ⊆ R of positive real numbers such that for all a, b ∈ R⁺:
1) a + b ∈ R⁺
2) a · b ∈ R⁺
3) For any a ∈ R, exactly one of the following holds: a ∈ R⁺, a = 0, −a ∈ R⁺
- Definition 1 (ordering via subtraction)
- Let a, b ∈ R. If a − b ∈ R⁺, then a > b.
- If a − b ∈ R⁺ ∪ {0}, then a ≥ b.
- Law of Trichotomy
- For any a, b ∈ R, exactly one of: a > b, a = b, a < b.
- Definition 2 (Absolute value)
- For x ∈ R, |x| =
{x,amp;if xgt;0, 0,amp;if x=0, −x,amp;if xlt;0. - Examples: |7| = 7, |−3| = 3; |−x| = |x|
- Properties of |·|
- (1) |ab| = |a| · |b|
- (2) |a + b| ≤ |a| + |b|
- (3) ||a| − |b|| ≤ |a − b|
- Distance interpretation
- |a − b| denotes the distance between real numbers a and b
- |a| denotes the distance of a from the origin
- ε-translation notes
- |x − a| < ε translates to a − ε < x < a + ε
- |x − a| > ε translates to x > a + ε or x < a − ε
Bounds, upper/lower bounds, and supremum/infimum
- Definition 3 (Bounds)
- Bounded above: ∃M ∈ R such that x ≤ M for all x ∈ S; M is an upper bound of S
- Bounded below: ∃m ∈ R such that x ≥ m for all x ∈ S; m is a lower bound of S
- Bounded set: S is bounded if it is both bounded above and bounded below; otherwise S is unbounded
- If S ⊆ R is bounded, ∃K ∈ R such that |x| ≤ K for all x ∈ S
- Examples of sets (A–E)
- A = {5, 8, 10, 11, 12, 15, 19, 37, 99}
- B = {x ∈ R : x < 2}
- C = {x ∈ R : x ≥ 5}
- D = {x ∈ R : 1 < x < 3}
- E = {x ∈ R : 1 ≤ x ≤ √2}
- Observations
- A, D, E are bounded
- B is bounded above but not bounded below
- C is bounded below but not bounded above
- N is bounded below but not bounded above
- Z, Q, R are neither bounded above nor bounded below
- Maximum and minimum
- M is the maximum of S if M is an upper bound of S and M ∈ S
- m is the minimum of S if m is a lower bound of S and m ∈ S
Supremum, Infimum, and Completeness of R
- Definition 4 (Supremum and Infimum)
- Least Upper Bound (lub) or Supremum: If S is bounded above, ℓ is a supremum of S if ℓ is an upper bound of S and ℓ ≤ v for every upper bound v of S
- Greatest Lower Bound (glb) or Infimum: If S is bounded below, g is an infimum of S if g is a lower bound of S and g ≥ v for every lower bound v of S
- Supremum and Infimum are unique if they exist; denote sup(S), inf(S)
- Examples of sup/inf for given sets
- sup(A) = 99, inf(A) = 5
- sup(B) = 2, inf(B) = −∞ (B is unbounded below)
- sup(D) = 3, inf(D) = 1
- sup(E) = √2, inf(E) = 1
- Remark on maximum/minimum vs sup/inf
- A set may have a supremum without a maximum (e.g., non-attaining upper bound)
- D and B illustrate this phenomenon in various ways
- Completeness Property of R
- Every nonempty bounded above subset of R has a supremum in R
- Completeness vs Q
- Q is a field and satisfies the order axioms, but Q is not complete
- Example S = {x ∈ Q : x² ≤ 2} is bounded above in Q, but sup(S) = √2 ∉ Q
- Therefore, there exist nonempty bounded-above subsets of Q without a supremum in Q
- Exercise: Prove that √2 ∉ Q (√2 is irrational)
- Proof (sketch)
- Suppose √2 = p/q with integers p, q, gcd(p, q) = 1, q ≠ 0
- Then p² = 2 q², so p² is even → p is even → p = 2 p1
- Substitution gives q² = 2 p1² → q is even
- Contradicts gcd(p, q) = 1
- Hence √2 is irrational
Greatest Integer Function and Intervals
- Definition 5 (Greatest integer function)
- For any x ∈ R, there exists a unique m ∈ Z with x − 1 < m ≤ x
- Denote by [x] the greatest integer ≤ x
- Examples: [3.859] = 3, [−3.581] = −4, [2.9] = 2, [2.01] = 2, [4] = 4
- Definition 6 (Intervals)
- Closed interval (bounded): [p, q] = {x ∈ R : p ≤ x ≤ q}
- Unbounded closed interval: [p, ∞) = {x ∈ R : p ≤ x}, (−∞, q] = {x ∈ R : x ≤ q}
- Open interval (bounded): (p, q) = {x ∈ R : p < x < q}
- Unbounded open interval: (p, ∞) = {x ∈ R : p < x}, (−∞, q) = {x ∈ R : x > q}
- Semi-open/semi-closed: [p, q) = {x ∈ R : p ≤ x < q}, (p, q] = {x ∈ R : p < x ≤ q}
- Consequences of Completeness (selected)
- Infimum of a nonempty set bounded below exists (via the negative set trick)
- Archimedean Property: For any x ∈ R, ∃ n ∈ N with n > x
- Between any two real numbers there exists a rational and an irrational number
- Proof sketch: Given a < b, b − a > 0. 1/(b − a) ∈ R. By Archimedean property ∃ n ∈ N with n > 1/(b − a). Then ∃ m ∈ Z with na < m < nb, hence a < m/n < b (rational in (a, b)). For irrational, consider a + √2 and b + √2 and find rational c with a + √2 < c < b + √2, hence a < c − √2 < b (c rational, c − √2 irrational).
Real Sequences
- Definition 7 (Real Sequence)
- A sequence is a function f: N → R, f(n) = xn; denote as (xn)
- Representations of sequences
- (1) Listing: e.g., (1, 4, 8, 11, 52, …)
- (2) Rule: x_n = 3 n^2
- (3) Recurrence: x1 = 4, x{n+1} = 2 x_n − 5
- Some example sequences (illustrative)
- (a) a_n = 2 (constant sequence)
- (b) a_n = 1 − (−1)^n / (2n)
- (c) a_n = 1 + (−1)^n (oscillating)
- (d) an defined by a1 = 1, a{n+1} = an + a_{n−1} (Fibonacci-type)
- Definition 8 (Convergent sequence)
- (xn) converges to ℓ ∈ R if ∀ε > 0 ∃ m ∈ N such that |xn − ℓ| < ε for all n ≥ m
- Denote lim{n→∞} xn = ℓ
- Example: x_n = 1/n
- For any ε > 0, ∃ m ∈ N with |1/n − 0| < ε for all n ≥ m
- Archimedean property: ∃ m with m > 1/ε, so |1/m| < ε
- Therefore 1/n → 0
- Theorem 2.1 (Uniqueness of limit)
- If xn → ℓ1 and xn → ℓ2, then ℓ1 = ℓ2
- Sketch: For any ε > 0, choose m1, m2 with |xn − ℓ1| < ε/2 and |xn − ℓ2| < ε/2 for n ≥ max(m1, m2). Then |ℓ1 − ℓ2| ≤ |xn − ℓ1| + |xn − ℓ2| < ε, hence ℓ1 = ℓ2
- Examples continued
- If a ∈ R and xn ≡ a, then xn → a
- If an = 2/(n^2 + 1), then |an| ≤ 2/n^2 → 0, so a_n → 0
- Remark: Divergence and convergence notions
- If a sequence does not converge to any real number, it diverges
- Classic divergent example: a_n = (−1)^n
- Definition 9 (Bounded sequence)
- A sequence (xn) is bounded if {x1, x2, …} is bounded, i.e., ∃M > 0 with |xn| ≤ M for all n
- If not bounded, the sequence is unbounded
- Examples of bounded/unbounded sequences
- (xn) = (−1)^n and (yn) = 1/n are bounded
- (an) = n and (bn) = n^2/(n+1) are unbounded
Basic convergence properties and the Sandwich Principle
- Theorem 2.3 (Convergent ⇒ bounded)
- If (xn) → ℓ, then ∃ε > 0 such that ∃m with |xn − ℓ| < ε for n ≥ m, hence x_n is bounded
- Remark 2.4 (Converse false)
- There exist bounded sequences that do not converge (e.g., (−1)^n)
- Remark 2.5
- If a sequence is unbounded, it cannot converge
- Theorem 2.6 (Algebraic limits of convergent sequences)
- If xn → a and yn → b, then:
1) xn + yn → a + b
2) xn − yn → a − b
3) xn yn → ab
4) xn / yn → a/b if b ≠ 0
5) If xn ≤ yn for all n, then a ≤ b
- Theorem 2.7 (Sandwich Theorem)
- If there exist sequences an ≤ cn ≤ bn for all large n and lim an = lim bn = c, then lim cn = c
- Remark 2.8 (Dominated sub-sequences and limits)
- If |bn| ≤ cn for all n ≥ m and cn → 0, then bn → 0
- Example class: convergence of geometric-like sequences
- Let a ∈ R and an = a^n. Then (an) converges iff −1 < a ≤ 1
- Cases:
- a = 0: a_n ≡ 0 → 0
- a = 1: a_n ≡ 1 → 1
- a = −1: a_n oscillates between −1 and 1 (not convergent)
- 0 < |a| < 1: set r = 1/|a| > 1; then |a|^n = 1/r^n → 0 (via binomial/estimates)
- |a| > 1: sequence is unbounded (diverges)
- Additional example type (limit to 0)
- a_n = (n^3 + 3n^2 + 4n^4 + 8n^2 + 2)/n^k (illustrative forms in notes)
- Another common example: an = (1/n) sin(1/n) with 0 ≤ |an| ≤ 1/n → 0
Monotone sequences and convergence criteria
- Definition 10 (Monotone sequences)
- A sequence is increasing if an ≤ a{n+1} for all n
- A sequence is decreasing if an ≥ a{n+1} for all n
- A sequence is monotonic if it is either increasing or decreasing
- Examples: an = 1/n is decreasing; bn = (n+1)/n is increasing; (−1)^n is not monotonic
- Theorem 2.9 (Monotone Convergence Criterion)
- An increasing sequence that is bounded above converges to sup{a_n : n ∈ N}
- Sketch of proof: use well-ordering (supremum) and the definition of boundedness to show x_n → s
- Remark 2.10 (Decreasing sequences)
- A decreasing sequence that is bounded below converges to inf{a_n : n ∈ N}
- Example (Babylonian iteration for √2)
- Let a1 = 3/2 and a{n+1} = 1/2 (an + 2/an)
- All a_n > 0, so the sequence is bounded below by 0
- a{n+1} − an = (2 − an^2)/(2 an)
- One can show a_n is decreasing for all n and bounded below by 0, hence convergent
- If an → ℓ, then ℓ satisfies ℓ = (ℓ + 2/ℓ)/2 ⇒ 2ℓ^2 = ℓ^2 + 2 ⇒ ℓ^2 = 2 ⇒ ℓ = √2 (positive sequence), so an → √2
Summary connections and implications
- Real numbers are a complete ordered field: every nonempty set bounded above has a supremum, and every nonempty set bounded below has an infimum
- Completeness distinguishes R from Q; Q is not complete
- The Archimedean property ensures there are integers between any two reals after appropriate scaling, underlines convergence proofs like 1/n → 0
- Convergence, boundedness, and monotonicity are foundational for analysis, providing tools like the Sandwich Theorem and Monotone Convergence Criteria for proving limits
- The examples illustrate how to apply definitions to concrete sequences and how to reason about limits, convergence, and divergence