3 Types of Factorising

  1. Factorise by Grouping

We have seen the distributive law: A(B+C)=AB+ACA\left(B+C\right)=AB+AC.

We have also seen how the distributive applies when the first term is a binomial expression: (A+B)(C+D)=A(C+D)+B(C+D)\left(A+B\right)\left(C+D\right)=A\left(C+D\right)+B\left(C+D\right).

This means that if we have an expression such as y(x+4)+5(x+4)y\left(x+4\right)+5\left(x+4\right), we can write it as a product of two brackets: (y+5)(x+4)\left(y+5\right)\left(x+4\right).

  1. Factorise using Perfect Squares

We’ve seen how to expand perfect squares and use a model to visualise it:

(A+B)2=A2+2AB+B2\left(A+B\right)^2=A^2+2AB+B^2

Model:

When factorising an expression of the type A2+2AB+B2A^2+2AB+B^2:

  • Look for a common factor to both terms first as this can simplify the expression for the remaining steps.

  • Identify values for A and B that satisfy this form.

  • Write in factorised form using the rule (A+B)2=A2+2AB+B2\left(A+B\right)^2=A^2+2AB+B^2.

In our work in quadratics, the first term AA, is often the variable xx, so for the expression x2+4x+4x^2+4x+4, we would identify A=xA=x and B=2B=2, because 22=42^2=4. The middle term 2AB2AB holds true as 2x2=4x2\cdot x\cdot2=4x.

  1. Factorise using Difference of Two Squares

We know that the difference of two squares looks like this: A2B2=(AB)(A+B)A^2-B^2=\left(A-B\right)\left(A+B\right).

When factorising an expression of the type A2B2A^2-B^2:

  • Look for a common factor to both terms first as this can simplify the expression for the remaining steps.

  • Identify the terms that are the squares AA and BB.

  • Write in factorised form using the rule A2B2=(AB)(A+B)A^2-B^2=\left(A-B\right)\left(A+B\right).