5. Helicopter Forces
Given:
Weight
W
=
53
,
800
W=53,800 N
Lift force
L
L at
21
∘
21
∘
from vertical
Constant horizontal velocity → equilibrium
(a) Free Body Diagram
Lift
L
L at
21
∘
21
∘
Weight
W
=
53
,
800
W=53,800 N downward
Air resistance
R
R horizontally left
(b) Find Lift Force
L
L
Vertical equilibrium:
L
y
=
W
L
y
=W
L
cos
21
∘
=
53
,
800
Lcos21
∘
=53,800
L
=
53
,
800
cos
21
∘
=
53
,
800
0.9336
=
57
,
647
N
L=
cos21
∘
53,800
=
0.9336
53,800
=57,647 N
(c) Find Air Resistance
R
R
R
=
L
sin
21
∘
=
57
,
647
×
0.3584
=
20
,
670
N
R=Lsin21
∘
=57,647×0.3584=20,670 N
Final Answer:
Lift = 57,647 N
Air Resistance = 20,670 N 5. Helicopter Forces
Given:
Weight
W
=
53
,
800
W=53,800 N
Lift force
L
L at
21
∘
21
∘
from vertical
Constant horizontal velocity → equilibrium
(a) Free Body Diagram
Lift
L
L at
21
∘
21
∘
Weight
W
=
53
,
800
W=53,800 N downward
Air resistance
R
R horizontally left
(b) Find Lift Force
L
L
Vertical equilibrium:
L
y
=
W
L
y
=W
L
cos
21
∘
=
53
,
800
Lcos21
∘
=53,800
L
=
53
,
800
cos
21
∘
=
53
,
800
0.9336
=
57
,
647
N
L=
cos21
∘
53,800
=
0.9336
53,800
=57,647 N
(c) Find Air Resistance
R
R
R
=
L
sin
21
∘
=
57
,
647
×
0.3584
=
20
,
670
N
R=Lsin21
∘
=57,647×0.3584=20,670 N
Final Answer:
Lift = 57,647 N
Air Resistance = 20,670 N