5. Helicopter Forces Given: Weight W = 53 , 800 W=53,800 N Lift force L L at 21 ∘ 21 ∘ from vertical Constant horizontal velocity → equilibrium (a) Free Body Diagram Lift L L at 21 ∘ 21 ∘ Weight W = 53 , 800 W=53,800 N downward Air resistance R R horizontally left (b) Find Lift Force L L Vertical equilibrium: L y = W L y ​ =W L cos ⁡ 21 ∘ = 53 , 800 Lcos21 ∘ =53,800 L = 53 , 800 cos ⁡ 21 ∘ = 53 , 800 0.9336 = 57 , 647  N L= cos21 ∘ 53,800 ​ = 0.9336 53,800 ​ =57,647 N (c) Find Air Resistance R R R = L sin ⁡ 21 ∘ = 57 , 647 × 0.3584 = 20 , 670  N R=Lsin21 ∘ =57,647×0.3584=20,670 N Final Answer: Lift = 57,647 N Air Resistance = 20,670 N 5. Helicopter Forces Given: Weight W = 53 , 800 W=53,800 N Lift force L L at 21 ∘ 21 ∘ from vertical Constant horizontal velocity → equilibrium (a) Free Body Diagram Lift L L at 21 ∘ 21 ∘ Weight W = 53 , 800 W=53,800 N downward Air resistance R R horizontally left (b) Find Lift Force L L Vertical equilibrium: L y = W L y ​ =W L cos ⁡ 21 ∘ = 53 , 800 Lcos21 ∘ =53,800 L = 53 , 800 cos ⁡ 21 ∘ = 53 , 800 0.9336 = 57 , 647  N L= cos21 ∘ 53,800 ​ = 0.9336 53,800 ​ =57,647 N (c) Find Air Resistance R R R = L sin ⁡ 21 ∘ = 57 , 647 × 0.3584 = 20 , 670  N R=Lsin21 ∘ =57,647×0.3584=20,670 N Final Answer: Lift = 57,647 N Air Resistance = 20,670 N