Study Notes on Relative Velocity and Constraint Motion

Fundamentals of Relative Velocity

  • Relative Velocity Definition:

    • The velocity of a particle AA with respect to a particle BB is defined as the velocity of AA as observed from the reference frame of BB.
    • Vector Expression: vAB=vAvB=vA+(vB)\vec{v}_{AB} = \vec{v}_A - \vec{v}_B = \vec{v}_A + (-\vec{v}_B).
  • General Vector Subtraction and Resultants:

    • If the angle between two vectors A\vec{A} and B\vec{B} is θ\theta, the magnitude of the resultant vector R=A+BR = A + B is typically given by A2+B2+2ABcos(θ)\sqrt{A^2 + B^2 + 2AB \cos(\theta)}.
    • When calculating relative velocity magnitudes, the subtraction logic applies: vAB=vA2+vB22vAvBcos(θ)v_{AB} = \sqrt{v_A^2 + v_B^2 - 2v_A v_B \cos(\theta)}.

The Rain-Umbrella Problem

  • Problem Setup:

    • A person is moving with velocity vm\vec{v}_m and rain is falling with velocity vr\vec{v}_r.
    • The person must hold an umbrella at a specific angle to avoid getting wet, which corresponds to the direction of the velocity of rain relative to the man (vrm\vec{v}_{rm}).
  • Governing Equation:

    • vrm=vrvm=vr+(vm)\vec{v}_{rm} = \vec{v}_r - \vec{v}_m = \vec{v}_r + (-\vec{v}_m).
  • Calculating the Angle:

    • If the rain falls vertically and the man moves horizontally, the angle θ\theta with the vertical at which the umbrella should be tilted is found using trigonometry:     tan(θ)=vmvr\tan(\theta) = \frac{v_m}{v_r}θ=tan1(vmvr)\theta = \tan^{-1}(\frac{v_m}{v_r})
  • Relative Magnitude:

    • The speed of rain as perceived by the man is:     vrm=vr2+vm2v_{rm} = \sqrt{v_r^2 + v_m^2}

River Boat Problem

  • Variables and Notation:

    • SS: Width of the river.
    • uu: Velocity of the river flow (drift velocity).
    • vv: Velocity of the boat in still water (or relative to the water).
    • θ\theta: The angle the boat's velocity vector makes with the normal (vertical) to the river bank.
  • Time Taken to Cross the River:

    • Crossing depends only on the velocity component perpendicular to the bank:     t=Svcos(θ)t = \frac{S}{v \cos(\theta)}
  • Drift of the Boat (dd):

    • Drift is the horizontal displacement along the bank caused by the river flow and the boat's horizontal component:     d=(uvsin(θ))td = (u - v \sin(\theta))td=(uvsin(θ))Svcos(θ)d = (u - v \sin(\theta)) \frac{S}{v \cos(\theta)}

Relative Velocity of Multiple Particles and Shortest Distance

  • Relative Velocity between Two Particles:

    • For two particles 1 and 2 moving in a plane, the velocity of 1 relative to 2 is: v12=v1v2=v1+(v2)\vec{v}_{12} = \vec{v}_1 - \vec{v}_2 = \vec{v}_1 + (-\vec{v}_2).
  • Minimum Distance (dmind_{min}):

    • To find the minimum distance between two moving particles, the problem is analyzed in the relative frame (typically making particle 2 stationary).
    • Particle 1 moves along a straight line in the relative frame. The shortest distance is the perpendicular length from the stationary particle 2 to the relative velocity vector line of particle 1.

Connected and Constraint Motion

  • Principles of Constraint:

    • This topic deals with systems connected by ropes, chains, or rods.
    • Key assumptions: The connector is inextensible, massless, and remains stretched.
  • Velocity Constraint Principle:

    • The velocity of each particle along the length of the rope, rod, or chain must be the same to prevent the connector from stretching or breaking.
    • If two points AA and BB are on a rigid rod, and vAv_A and vBv_B are their respective velocities making angles with the rod's length, then:     vAcos(θ1)=vBcos(θ2)v_A \cos(\theta_1) = v_B \cos(\theta_2)

Numerical Examples in Kinematics

  • Example 1: Rod Moving Against a Wall:

    • A rod is leaned against vertical and horizontal axes. One end moves with velocity vv at an angle of 5353^\circ to the vertical. The other end moves at 5m/s5\,m/s at an angle of 3737^\circ to the horizontal.
    • Using the constraint equation:     vcos(53)=5cos(37)v \cos(53^\circ) = 5 \cos(37^\circ)v×35=5×45v \times \frac{3}{5} = 5 \times \frac{4}{5}v=203m/s6.67m/sv = \frac{20}{3}\,m/s \approx 6.67\,m/s
    • Note: In specific handwritten annotations (Page 7-8), alternate results like v=25m/sv = 25\,m/s or v=20m/sv = 20\,m/s are noted based on different input values (e.g., 15m/s15\,m/s instead of 5m/s5\,m/s).
  • Example 2: Simple Pulley System:

    • Calculation for a moving pulley where vp=v1+v22v_p = \frac{v_1 + v_2}{2}.
    • Given: Pulley moves up at 5m/s5\,m/s (vp=+5v_p = +5), one block moves up at 2m/s2\,m/s (v1=+2v_1 = +2).
    • Calculation:     5=2+v225 = \frac{2 + v_2}{2}10=2+v210 = 2 + v_2v2=8m/sv_2 = 8\,m/s
  • Example 3: Complex Pulley and Block Configuration:

    • Analysis of multiple blocks and pulleys where the total length of the string is constant (l=x1+x2+...l = x_1 + x_2 + ...).
    • For a block and pulley system (Page 11):     v=10m/sv = 10\,m/s (given as a specific instance).     Formula for length derivative: vicos(θi)=0\sum v_i \cos(\theta_i) = 0
  • Example 4: Relative Displacement Calculation (Page 9):

    • Finding a final velocity or displacement where 2v=1.6m/s2v = 1.6\,m/s suggests v=0.8m/sv = 0.8\,m/s (labeled as 1.61.6 in some contexts).