CHM 151 Practice Cumulative Final Notes

Significant Figures

  • Question 1: How many significant figures are in the number 2.0×1042.0 \times 10^4?

    • Answer: (B) 2

Unit Conversions

  • Question 2: Which of the following is equivalent to 5.0 cm?

    • (A) 50,000. nm

    • (B) 50.0 mm

    • (C) 0.50 m

    • (D) 0.00050 km

    • Answer: (A) 50,000. nm

Significant Figures and Volume Calculation

  • Question 3: Determining the volume of a cube:

    • Side length measured in inches: 1.25 in

    • Side length in cm: 3.175 cm

    • Calculator result after cubing: 32.005984375

    • Reported volume with correct significant figures?

    • (A) 32 cm3

    • (B) 32.0 cm3

    • (C) 32.01 cm3

    • (D) 32.006 cm3

    • Answer: (B) 32.0 cm3

Moles and Caffeine Consumption

  • Question 4: Caffeine content in a cup of coffee: 95 mg (C8H10N4O2, molar mass = 194.19 g/mol)

    • How many cups to ingest 0.00352 moles of caffeine?

    • (A) 0.0035 cups

    • (B) 0.68 cups

    • (C) 7.2 cups

    • (D) 65 cups

    • Answer: (C) 7.2 cups

Dosage Calculation

  • Question 5: Dosage calculation based on body weight:

    • Person weighs 145 lb

    • Recommended dosage: 10.0 mg per kilogram of body weight

    • (1 lb = 454 g)

    • (A) 6.6 mg

    • (B) 32 mg

    • (C) 319 mg

    • (D) 658 mg

    • Answer: (D) 658 mg

    • Convert pounds to grams, then grams to kilograms, then multiply by the dosage.

Atomic Measurement

  • Question 6: Bismuth (Bi) atom diameter: approximately 320. picometers (pm)

    • How many bismuth atoms to span 1.00 cm side-by-side?

    • (1 pm = 1×10121 \times 10^{-12} m)

    • (A) 3.13×10173.13 \times 10^{-17} atoms

    • (B) 3.20×1083.20 \times 10^{-8} atoms

    • (C) 3.13×1073.13 \times 10^7 atoms

    • (D) 3.20×10123.20 \times 10^{12} atoms

    • Answer: (C) 3.13×1073.13 \times 10^7 atoms

Percent Error in Density Measurement

  • Question 7: Density measurement by students:

    • Tina: 0.8029 g/mL

    • Bill: 0.7915 g/mL

    • Jordan: 0.7938 g/mL

    • Actual density: 0.7892 g/mL

    • Group’s percent error?

    • (A) 0.87%

    • (B) 8.7%

    • (C) 9.9%

    • (D) 87%

    • Answer: (A) 0.87%

    • Calculate the average density, then use the percent error formula: experimental valueactual valueactual value×100\frac{|\text{experimental value} - \text{actual value}|}{\text{actual value}} \times 100.

States of Matter and Temperature

  • Question 8: Substance that exists as a gas at room temperature:

    • (A) melting point below room temperature, boiling point above room temperature

    • (B) melting point above room temperature, boiling point below room temperature

    • (C) both melting point and boiling point below room temperature

    • (D) both melting point and boiling point above room temperature

    • Answer: (C) both its melting point and its boiling point are below room temperature

Solutions

  • Question 9: Correct description of a solution:

    • (A) A heterogeneous mixture of two or more substances.

    • (B) A homogeneous mixture of two or more substances.

    • (C) May be gaseous, solid, or liquid.

    • (D) answers (B) and (C) are both correct

    • Answer: (D) answers (B) and (C) are both correct

Electromagnetic Radiation

  • Question 10: Statements about electromagnetic radiation (light):

    • (A) shorter wavelengths correspond to higher frequencies

    • (B) shorter wavelengths correspond to lower energies

    • (C) higher energies correspond to lower frequencies

    • (D) none of the above statements are correct
      *Answer: (A) shorter wavelengths correspond to higher frequencies
      *Recall that: c=λνc = \lambda \nu E=hνE = h \nu

Nuclear Symbol

  • Question 11: Correct nuclear symbol for atom with atomic number 13 and mass number 27:

    • (A) Al$\frac{27}{13}$

    • (B) Co$\frac{27}{13}$

    • (C) Al$\frac{13}{27}$

    • (D) Co$\frac{13}{27}$

    • Answer: (A) Al$\frac{27}{13}$

    • Atomic number is the subscript, mass number is the superscript, and Al is the element symbol for Aluminum.

Valence Electrons and Noble Gas Configuration

  • Question 12: How many valence electrons must a selenium (Se) atom gain or lose to obtain a noble gas configuration?

    • (A) gain two

    • (B) gain three

    • (C) lose two

    • (D) lose three

    • Answer: (A) gain two

    • Selenium is in group 16, hence, it needs to gain two electrons to have a full octet like noble gases

Metal Ion and Orbital Filling Diagram

  • Question 13: Metal ion consistent with orbital filling diagram:

    • (A) Mo2+\text{2+}

    • (B) Mn3+\text{3+}

    • (C) Ru2+\text{2+}

    • (D) Tc3+\text{3+}

    • Answer: (B) Mn3+\text{3+}

Atoms of Phosphorus in P2O5

  • Question 14: How many atoms of phosphorus are in 1.28 grams of P2O5?

    • (A) 5.43×10215.43 \times 10^{21} atoms of phosphorus

    • (B) 1.09×10221.09 \times 10^{22} atoms of phosphorus

    • (C) 3.28×10223.28 \times 10^{22} atoms of phosphorus

    • (D) 2.19×10262.19 \times 10^{26} atoms of phosphorus

    • Answer: (B) 1.09×10221.09 \times 10^{22} atoms of phosphorus

Average Atomic Mass

  • Question 15: Two isotopes of an element:

    • Abundance of one isotope: 93.26%, atomic mass: 38.964 amu

    • Atomic mass of the second isotope: 40.962 amu
      *Determine the average (unified) atomic mass of this element.

    • Answer: (B) 39.099 amu

First Ionization Energies

  • Question 16: Which group have the highest first ionization energies?

    • (A) Alkali metals

    • (B) Transition metals

    • (C) Halogens

    • (D) Alkaline earth metals

    • (E) Noble gases

    • Answer: (E) Noble gases

Electron Configuration

  • Question 17: Which of the following is the electron configuration of an atom in the ground state?

    • (A) 1s1\text{s}^{1} 2s2\text{s}^{2}

    • (B) 1s2\text{s}^{2} 2s1\text{s}^{1}

    • (C) 1s2\text{s}^{2} 2s1\text{s}^{1} 2p6\text{p}^{6}

    • (D) 1s2\text{s}^{2} 2s2\text{s}^{2} 2p5\text{p}^{5} 3s2\text{s}^{2}

    • (E) 1s2\text{s}^{2} 2s2\text{s}^{2} 2p6\text{p}^{6} 3s2\text{s}^{2} 3p6\text{p}^{6} 4s0\text{s}^{0} 3d5\text{d}^{5}

    • Answer: (B) 1s2\text{s}^{2} 2s1\text{s}^{1}

Molecular Geometry of NH3

  • Question 18: Given the Lewis structure of NH3, what is the molecular geometry of NH3?

    • (A) T-shaped

    • (B) trigonal planar

    • (C) square planar

    • (D) tetrahedral

    • (E) trigonal pyramidal

    • Answer: (E) trigonal pyramidal

Polyatomic Ion for Perchlorate

  • Question 19: What is the correct polyatomic ion for perchlorate?

    • (A) ClO21\text{2}^{-1}

    • (B) ClO31\text{3}^{-1}

    • (C) ClO41\text{4}^{-1}

    • (D) ClO32\text{3}^{2-}

    • Answer: (C) ClO41\text{4}^{-1}

Naming Ionic Compounds

  • Question 20: The correct name for Cu3(PO4)2 is

    • (A) tricupric diphosphate

    • (B) copper phosphate

    • (C) copper(III) diphosphate

    • (D) copper(III) phosphate

    • (E) copper(II) phosphate

    • Answer: (E) copper(II) phosphate

Formula for Potassium Nitride

*Question 21: The formula for potassium nitride is

  • (A) P3N\text{P}_{3}\text{N}

  • (B) K3N\text{K}_{3}\text{N}

  • (C) KNO3\text{KNO}_{3}

  • (D) KNO2\text{KNO}_{2}

  • (E) PN\text{PN}

  • Answer: (B) K3N\text{K}_{3}\text{N}

Sigma and Pi Bonds in Acrolein

  • Question 22: Determine the number of sigma (σ) and pi (π) bonds in acrolein:

    • (A) 7 sigma, 2 pi

    • (B) 9 sigma, 2 pi

    • (C) 2 sigma, 7 pi

    • (D) 5 sigma, 2 pi

    • (E) 5 sigma, 4 pi

    • Answer: (A) 7 sigma, 2 pi

Non-Polar Molecules

  • Question 23: Which one of the following molecules is overall non-polar?

    • (A) CH3I\text{CH}_{3}\text{I}

    • (B) CHBr3\text{CHBr}_{3}

    • (C) CH<em>2Cl</em>2\text{CH}<em>{2}\text{Cl}</em>{2}

    • (D) CF4\text{CF}_{4}

    • (E) CO\text{CO}

    • Answer: (D) CF4

Ionic Compound

  • Question 24: Which one of the following would you expect to be an ionic compound?

    • (A) MgBr2\text{MgBr}_{2}

    • (B) SBr2\text{SBr}_{2}

    • (C) NBr3\text{NBr}_{3}

    • (D) CBr4\text{CBr}_{4}

    • Answer: (A) MgBr2

Polar Covalent Bond

  • Question 25: A polar covalent bond would be expected to form between which of the following pairs of atoms?

    • (A) H and H

    • (B) Cl and C

    • (C) Na and F

    • (D) Fe and F

    • Answer: (B) Cl and C

Molecular Geometry of SCl2

  • Question 26: What is the molecular geometry of sulfur dichloride (SCl2), given that sulfur is the central atom?

    • (A) linear

    • (B) bent

    • (C) tetrahedral

    • (D) trigonal planar

    • Answer: (B) bent

Molecular Formula Determination

  • Question 27: The percent composition by mass of a compound is 76.0% C, 12.8% H, and 11.2% O. The molar mass of this compound is 284.5 g/mol. What is the molecular formula of the compound?

    • (A) C10H6O

    • (B) C9H18O

    • (C) C20H12O2

    • (D) C18H36O2

    • Answer: (D) C18H36O2

Balancing Chemical Equations

  • Question 28: When the reaction below is properly balanced using the smallest set of whole-number coefficients, what is the coefficient on Cl2? __ CH4 + __ Cl2 → __ CCl4 + __ HCl

    • (A) 1

    • (B) 2

    • (C) 4

    • (D) 6

    • (E) 8

    • Answer: (C) 4

Percent Yield Calculation

  • Question 29: If the reaction of 150 g of ammonia with 150 g of oxygen gas according to the following reaction yields 87 g of nitric oxide, what is the percent yield of this reaction? 4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (g)

    • (A) 100%

    • (B) 77%

    • (C) 62%

    • (D) 49%

    • (E) 33%

    • Answer: (D) 49%

Strong Electrolytes

  • Question 30: Which of the following is a strong electrolyte?

    • (A) HCl (hydrochloric acid)

    • (B) C6H12O6 (glucose)

    • (C) HC2H3O2 (acetic acid)

    • (D) CH3OH (methanol)

    • (E) N2 (nitrogen gas)

    • Answer: (A) HCl (hydrochloric acid)

Classifying Reactions

  • Question 31: Classify the following reaction: CaBr2 (aq) + H2SO4 (aq) → CaSO4 (s) + 2 HBr (aq)

    • (A) Acid-base reaction

    • (B) Precipitation reaction

    • (C) Dissociation reaction

    • (D) Combustion reaction

    • (E) Single-displacement reaction

    • Answer: (B) Precipitation reaction

Products of Combustion Reaction

  • Question 32: Choose two possible products of a combustion reaction.

    • (A) ammonia & water

    • (B) carbon dioxide & water

    • (C) an acid & a base

    • (D) oxygen gas & hydrogen gas

    • (E) water & a salt

    • Answer: (B) carbon dioxide & water

Molarity of a Solution

  • Question 33: What is the molarity of a NaOH solution made by diluting 20.0 mL of a 1.50 M NaOH solution to a final volume of 50.0 mL?

    • (A) 0.015 M

    • (B) 0.60 M

    • (C) 3.75 M

    • (D) 24.0 M

    • Answer: (B) 0.60 M

Grams of Precipitate Formed

  • Question 34: Calcium chloride (CaCl2) reacts with potassium carbonate (K2CO3) in a double-replacement reaction, part of which is shown below. CaCl2 (aq) + K2CO3 (aq) → How many grams of precipitate are formed when a solution containing 8.94 grams of calcium chloride is mixed with a solution containing excess potassium carbonate?

    • (A) 3.01 g

    • (B) 8.06 g

    • (C) 9.91 g

    • (D) 12.02 g

    • Answer: (B) 8.06 g

Mass of NaOH Needed

  • Question 35: Given the reaction of NaOH (sodium hydroxide) and HC2H3O2 (acetic acid) shown below, what mass of NaOH is needed to fully neutralize 35.4 mL of a 1.70 M acetic acid solution? NaOH (aq) + HC2H3O2 (aq) →

    • (A) 0.8329 g

    • (B) 1.5045 g

    • (C) 2.4072 g

    • (D) 5.2059 g

    • Answer: (C) 2.4072 g

Enthalpy Change

  • Question 36: When ammonium chloride is dissolved in water, the reaction vessel turns cold. This means:

    • (A) the process is endothermic.

    • (B) the process is exothermic.

    • (C) the total energy of the system + surroundings has decreased.

    • (D) the energy of both the system and the surroundings has increased.

    • (E) the energy of both the system and the surroundings has decreased.

    • Answer: (A) the process is endothermic.

    • Endothermic process absorbs heat, making the surroundings cold.

Ideal Gas

  • Question 37: Which of the following statements is false for an ideal gas?

    • (A) The volume of an individual gas molecule is negligible compared to the distance between molecules.

    • (B) Gas molecules travel in curved paths, changing directions randomly.

    • (C) Individual gas molecules do not attract or repel one another.

    • (D) Collisions of gas molecules with each other or with the walls of the container are perfectly elastic.

    • Answer: (B) Gas molecules travel in curved paths, changing directions randomly.

    • Ideal gas molecules travel in straight paths until they collide.

Final Volume of Gas

  • Question 38: A sample of an ideal gas with an initial temperature of 21°C at a volume of 12.5 L is cooled to –10°C under constant pressure conditions. What is the final volume of this gas?

    • (A) 5.95 L

    • (B) 11.2 L

    • (C) 13.9 L

    • (D) 26.3 L

    • Answer: (B) 11.2 L
      *Use Charles's Law: V<em>1T</em>1=V<em>2T</em>2\frac{V<em>1}{T</em>1} = \frac{V<em>2}{T</em>2}, where temperatures must be in Kelvin.

Mass of NO Gas

  • Question 39: Calculate the mass in grams of 3.55 L of NO gas at 52°C and 874 mmHg (1 atm = 760 mmHg).

    • (A) 0.153 g

    • (B) 4.59 g

    • (C) 6.53 g

    • (D) 7.04 g

    • (E) 24.24 g

    • Answer: (B) 4.59 g
      *Use the Ideal Gas Law: PV=nRTPV = nRT, then convert moles to grams using the molar mass of NO.

Specific Heat of Metal

  • Question 40: A piece of metal with a mass of 48.342 g at an initial temperature of 108°C is placed into 50.00 g of water initially at 20.3°C. The final equilibrium temperature of the water is 34.6°C. Calculate the specific heat of the metal. (Given that the specific heat of water = 4.184 J/g⋅°C)

    • (A) 0.706 J/g⋅°C

    • (B) 0.788 J/g⋅°C

    • (C) 0.843 J/g⋅°C

    • (D) 1.19 J/g⋅°C

    • Answer: (A) 0.706 J/g⋅°C
      *Use the formula q=mcΔTq = mc\Delta T, where q<em>metal=q</em>waterq<em>{\text{metal}} = -q</em>{\text{water}}

Enthalpy Calculation

*Question 41: Calculate the ΔH\Delta H for the reaction:
NO<em>2(g)+CO(g)CO</em>2(g)+NO(g)\text{NO}<em>{2} (g) + \text{CO} (g) \rightarrow \text{CO}</em>{2} (g) + \text{NO} (g)
using the following standard enthalpies of formation:

*Compound ΔH<em>f\Delta H<em>{f} ° (kJ/mol) *CO (g) –111 *CO2 (g) –394 *NO (g) 90 *NO2 (g) 34 * (A) 339 kJ * (B) 381 kJ * (C) –227 kJ * (D) –339 kJ * (E) 227 kJ * Answer: (C) –227 kJ *Use Hess's Law: ΔH</em>rxn=ΔH<em>fproductsΔH</em>freactants\Delta H</em>{\text{rxn}} = \sum \Delta H<em>{f}^{\text{products}} - \sum \Delta H</em>{f}^{\text{reactants}}