Lattice enthalpy

Chemical bonds

  • How can you compare the strength of a covalent bond? What data do you use?

    • Bond enthalpy

  • What would the equivalent be for an ionic bond? What is the added complication for an ionic bond?

    • You have to allow for the giant ionic lattice with an ionic compound

  • For an ionic compound we use lattice enthalpy

  • Lattice enthalpy is a measure of the strength of the ionic bonding in a giant lattice

Lattice enthalpy of formation, ΔLH0

  • Is the standard enthalpy change when one mole of a solid ionic compound is formed from its gaseous ions

  • e.g. Li+(g) + Cl-(g) → LiCl(s)

  • Lattice enthalpies of formation are always exothermic, i.e. have negative values

  • Lattice enthalpies cannot be determined directly, they must be determined using other data

  • To calculate lattice enthalpies we need to use a range of other pieces of data

Lattice enthalpy of dissociation, ΔLH0

  • Is the standard enthalpy change when 1 mole of a solid ionic compound dissociated into its gaseous ions

  • e.g. LiCl(s) → Li+(g) + Cl-(g)

  • Lattice enthalpies of dissociation are always endothermic i.e. have positive values

  • Lattice enthalpy of dissociation has the same magnitude as lattice enthalpy of formation but the opposite sign

  • Read question carefully to determine which one it’s referring to

Standard molar enthalpy change of formation, ΔfH0

  • Is the enthalpy change when 1 mole of a compound is formed from its constituent elements under standard conditions, all reactants and products in their standard states.

  • e.g.

    • Li(s) + 1/2Cl2(g) → LiCl(s) -408.6kJmol-1

Standard enthalpy change of atomisation, ΔatH0

  • Is the enthalpy change which accompanies the formation of 1 mole of gaseous atoms from the element in its standard state under standard conditions

  • e.g.

    • Li(s) → Li(g) +159.4kJmol-1

    • 1/2Cl2(g) → Cl(g) +121.7kJmol-1

  • For a covalent element, the enthalpy change is ½ of the bond enthalpy of the element.

First ionisation energy, ΔLH0

  • The standard enthalpy change when one mole of gaseous atoms is converted into a mole of gaseous atoms each with a singe positive charge

  • e.g.

    • Li(g) → Li+(g) + e- +520kJmol-1

  • If you have a metal that wpuld be a 2+ ion then you would have to also use the 2nd ionisation energy as well

  • e.g.

    • M+(g) → M2+(g) + e-

First electron affinity ΔEAH0

  • The standard enthalpy change when a mole of gaseous atoms is converted to a mole of gaseous ions, each with a single negative charge

  • e.g.

    • Cl(g) + e- → Cl-(g) -348.8kJmol-1

  • Is a 2- ion then do the same as first ionisation energy - use 2nd electron affinity as well.

    • Note: whilst the first electron affinity is negative, all subsequent ones will be positive

Born Haber cycles

  • Hess’ law states that the overall energy change is the same no matter which route is taken

  • Born-Haber cycles are just an extension of this with more steps

  • An enthalpy scale is drawn on the Y-axis with higher enthalpies at the top

  • An endothermic reaction will have an arrow pointing upwards

  • An exothermic reaction will have an arrow pointing downwards

  • Every step in the Born-Haber cycle must be thoroughly labelled, with state symbols etc.

  • Use travelling pathway - get the answer -860.9kJmol-1