Calc BC 2018 Free-Response Questions

AP Calculus BC 2018 Free-Response Questions

Section II, Part A

  • Time allocated: 30 minutes

  • Number of questions: 2

  • Calculator: A graphing calculator is required for these questions.

Question 1: Escalator Line Model
  • Function Modeling Rate of People Entry:

    • The rate function is defined as:


    r(t) = \begin{cases}
    \frac{t}{3} +4 \quad & \text{for } 0 \leq t \leq 300\ \
    \frac{100 - t}{300} & \text{for } t > 300 \ \
    0 & \text{otherwise}
    \end{cases}

    • Variables:

    • r(t)r(t) is measured in people per second.

    • tt is measured in seconds.

  • Constant Exit Rate: People exit the line at a constant rate of 0.7 person per second.

  • Initial Condition: There are 20 people in line at time t=0t = 0.

Parts of Question 1:
  1. (a) Total People Entering Line (0 ≤ t ≤ 300):

    • To find the number of people entering the line over this interval, integrate the rate function:

      <br>Total Entry=0300r(t) dt<br><br>\text{Total Entry} = \int_0^{300} r(t) \ dt<br>

  2. (b) People in Line at t = 300:

    • At time t=300t = 300, calculate the number of people still in line:

      <br>N(t)=N(0)+0300r(t) dt0.7300<br><br>N(t) = N(0) + \int_0^{300} r(t) \ dt - 0.7 \cdot 300<br>

    • Where N(0)=20N(0) = 20 is the initial count.

  3. (c) When is the Line Empty (t > 300):

    • Set the equation for the line to zero, solve for tt:

      <br>N(t)=N(300)0.7(t300)=0<br><br>N(t) = N(300) - 0.7(t - 300) = 0<br>

  4. (d) Minimum Line Count:

    • Find the minimum number of people in line while 0t3000 ≤ t ≤ 300:

    • Justification involves evaluating critical points where N(t)=0N'(t) = 0.

    • Minimize how many people are in line by considering both entry and exit rates.


Question 2: Plankton Cell Investigation
  • Context: Researchers are studying plankton cells at various underwater depths.

  • Density Function:

    • Density of plankton cells given by:


    p(h) = \begin{cases}
    0.2h e^{-0.0025h} \quad & \text{for } 0 \leq h \leq 30 \ \
    f(h) \quad & \text{for } h \geq 30
    \end{cases}

Parts of Question 2:
  1. (a) Rate of Change at Depth (h = 25):

    • Compute the derivative p(25)p'(25):

    • Interpret the result in terms of plankton density and depth.

  2. (b) Total Cells in Column (h = 0 to 30):

    • Volume of column: 3 square meters constant area.

    • Total number of plankton cells:

      <br>Total Cells=030p(h)3dh<br><br>\text{Total Cells} = \int_0^{30} p(h) \cdot 3 \, dh<br>

    • Round to the nearest million cells.

  3. (c) Expression for Cells in Column (h ≥ 30):

    • Expression to calculate total cells in depth KK, where K > 30:

      <br>N=<em>30Kf(h)dh+</em>030p(h)dh<br><br>N = \int<em>{30}^{K} f(h) \, dh + \int</em>0^{30} p(h) \, dh<br>

    • Justification: Explain why this value is ≤ 2000 million due to density function constraints.

  4. (d) Boat Movement:

    • Position of the boat given by:

      <br>(x(t),y(t)) where x(t)=662sin(5t), y(t)=880cos(6t)<br><br>(x(t), y(t)) \text{ where } x'(t) = 662 \sin(5t), \ y'(t) = 880 \cos(6t)<br>

    • Calculate total distance traveled in the interval 0t10 \leq t \leq 1:

      <br>D=01(x(t))2+(y(t))2dt<br><br>D = \int_0^{1} \sqrt{(x'(t))^2 + (y'(t))^2} \, dt<br>


Section II, Part B

  • Time allocated: 1 hour

  • Number of questions: 4

  • Calculator: No calculator allowed for these questions.

Question 3: Function g and its Derivative
  • Continuous function: g defined as piecewise linear for -5 \leq x < 3 and g(x)=4x2+2g(x) = -4x^2 + 2 for 3x63 \leq x \leq 6.

Parts of Question 3:
  1. (a) Value of f(-5):

    • Given that f(1)=3f(1)=3, find f(5)f(-5) by integrating g(x)g(x).

  2. (b) Evaluate Integral from 1 to 6:

    • Compute:

      <br>16g(x)dx<br><br>\int_1^{6} g(x) \, dx<br>

  3. (c) Increase and Concavity:

    • Identify intervals where ff is both increasing and concave up.

    • Reasoning must include the behavior of gg and its derivative ff'.

  4. (d) Points of Inflection:

    • To find points of inflection, set the second derivative of ff to zero and identify intervals where concavity changes.


Question 4: Tree Height Model
  • Function H(t): Height of a tree modeled as a twice-differentiable function.

Parts of Question 4:
  1. (a) Estimate H'(6):

    • Use data from a table to estimate and interpret H(6)H'(6) with appropriate units.

  2. (b) Intermediate Value Theorem:

    • Justify the existence of a time tt such that H(t)=2H'(t) = 2 for 2 < t < 10 using continuity.

  3. (c) Average Height:

    • Approximate the average height using the trapezoidal sum based on table values:

      <br>Average Height=1baabH(t)dt<br><br>\text{Average Height} = \frac{1}{b-a} \int_a^{b} H(t) \, dt<br>

  4. (d) Model G: Height G(x)G(x) related to diameter:

    • Given by G(x)=100x1+xG(x) = \frac{100x}{1 + x} with xx measured in meters.

    • Find the rate of change of height with respect to time when H=50H = 50 meters.


Question 5: Polar Curves
  • Polar Curves: Given curves r=4r = 4 and r=2+3extcos(θ)r = 2 + 3 ext{cos}(\theta) intersecting points θ=π3\theta = \frac{\pi}{3} and θ=5π3\theta = \frac{5\pi}{3}.

Parts of Question 5:
  1. (a) Area of the Region R:

    • Write area expression for region R:

      <br>A=<em>θ</em>1θ<em>2(12(r</em>12r22))dθ<br><br>A = \int<em>{\theta</em>1}^{\theta<em>2} \left(\frac{1}{2}(r</em>1^2 - r_2^2)\right) d\theta<br>

  2. (b) Slope of Tangent Line:

    • Find the slope of the tangent line for r(θ)r(\theta) at intersection points.

  3. (c) Particle Movement:

    • Derive the rate of change of angle θ\theta with respect to time at a specific point on the curve, given the constant increase in distance from the origin:

      dθdt\frac{d\theta}{dt} depending on angular position and radial distance rate.


Conclusion
  • This study guide encapsulates key concepts and detailed calculations from the 2018 AP Calculus BC Free-Response Questions. Each section builds a comprehensive understanding necessary for successfully tackling similar problems in exams.