Week 8: Solutions, Concentrations, Body Fluids & Properties of Gases and Respiration
Characteristics of Solutions
- A solution is a homogeneous mixture where each substance retains its chemical identity.
- It contains two components:
Solvents and Solutes
- Solvent: Present in the greatest amount.
- Solute: Present in a smaller amount relative to the solvent.
Properties of Solutions
- Contain a solvent and one or more solutes.
- Have variable composition (ratio of solute to solvent can vary).
- Dissolved solutes are present as individual substances (molecules, atoms, or ions).
- Solutes remain uniformly distributed.
Examples of Solutions
- Sports Drinks:
- Solvent: Water
- Solutes: Sugars, salts (ions), and vitamins
- Isotonic drinks
- Isotonic Saline Drip Bags:
- Solvent: Water
- Solutes: NaCl and glucose
Types of Gaseous Solutions
- Gas dissolved in gas: Dry air (oxygen and other gases in nitrogen).
- Liquid dissolved in gas: Wet air (water vapor in air).
- Solid dissolved in gas: Moth repellent sublimed in air.
Liquid Solutions
- Gas dissolved in liquid: Carbonated beverage (carbon dioxide in water).
- Liquid dissolved in liquid: Cordial in water.
- Solid dissolved in liquid: Salt dissolved in water.
Solid Solutions
- Gas dissolved in solid: Hydrogen in platinum.
- Liquid dissolved in solid: Dental filling (mercury in silver).
- Solid dissolved in solid: Sterling silver (copper in silver).
- Requires attraction between solute and solvent for uniform dispersion.
- Without attraction, solute particles stay together, not mixing with the solvent.
Water Solutions
- Water is the universal solvent because it is polar.
- Forms solutions with ionic and/or polar solutes.
- Ionic Compounds: Water molecules surround and hydrate ions (e.g., NaCl).
Covalent Compounds (Molecules) in Water
- Polar molecules (e.g., sucrose, ethanol, methanol) dissolve well in water.
- Nonpolar molecules (e.g., fat, oil, grease, iodine) do not dissolve in water.
Polarity and Solutions
- Polar solvents will not form a solution with a nonpolar solute.
Solubility
- "Like Dissolves Like": Polar molecules dissolve in polar solvents, nonpolar in nonpolar.
- Sucrose in water (polar).
- Grease in kerosene (nonpolar).
- Solubility: Maximum amount of solute that dissolves in a given amount of solvent, usually in grams per 100g of solvent, and is temperature-dependent.
Saturated Solutions
- Unsaturated solution: Less solute than the maximum amount is dissolved.
- Saturated solution: Contains the maximum amount of solute that can be dissolved under the given conditions.
Saturated Solutions in the Body
- Gout:
- Uric acid concentration exceeds its solubility (7 mg/100mL) in blood plasma at 37°C.
- Uric acid crystals form in cartilage, tendons, and soft tissues, causing painful attacks.
- Kidney Stones:
- Excessive mineral ingestion and insufficient water intake cause mineral salts (e.g., calcium phosphate, calcium oxalate) to exceed their solubility.
- Kidney stones cause pain and discomfort when passing through the urinary tract.
Concentration of Solutions
- Specifying solution composition involves specifying solute concentrations.
- Concentration: Amount of solute in a specified amount of solution.
- Concentrated solution: Contains a large amount of solute.
- Dilute solution: Contains a small amount of solute.
Percent Concentration
- Amount of solute expressed as a percentage.
- Example: 5% dextrose solution = 5g dextrose/100mL solution.
- Formula: \text{Percent conc. (%)} = \frac{\text{Mass of solute (g)}}{\text{Volume of solution (mL)}} \times 100
Percent Concentration Problem
- Problem 1: What is the percent concentration of a Gatorade sports drink that contains 4.5g glucose in 250 mL?
- Percent conc. (%) = 250mL4.5g×100=1.8%
Percent Concentration Problem 2
- Problem 2: How many grams of salt (NaCl) are in 1000 mL of a 0.9% intravenous saline (salt) solution?
- 0.9%=1000mLx×100
- x=1000.9×1000=9.0grams of NaCl
Ratio Concentration
- Expressed as the ratio of solute to solution (e.g., 1:20).
- Example: A 1:1000 saline solution means 1g of saline in 1000 mL of water.
- Problem 3: Chlorhexidine is used as a 1:2000 solution for a general antiseptic; how many grams are required to make up 500 mL of this chlorhexidine solution?
Ratio Concentration
- Ratio concentration (strength) = 1:2000 ; We want to make up a solution of 500 mL how much do we need
- Need: xg in 500 mL
- Given strength: 1g in 2000 mL
- Calculation:
- 500mLxg=2000mL1g
- xg=2000mL500mL×1g
- xg=0.25g
Molar Concentration
- States the number of moles of solute in 1 litre of solution.
- A 1.0 molar solution (1.0 M) has 1.0 mole of solute in 1.0 litre of solution.
Dilutions
- Diluting a solution of known concentration (stock solution) to a lower concentration.
- Dilution: Adding more solvent to a stock solution to lower its concentration.
- The amount of solute remains constant.
- Volume increases, causing the concentration to decrease.
- C<em>1×V</em>1=C<em>2×V</em>2
- $C_1$ = concentration of stock solution
- $V_1$ = volume of stock solution
- $C_2$ = concentration of diluted solution
- $V_2$ = volume of diluted solution
- The concentration units for C<em>1 and C</em>2 must be the same.
- The volume units for V<em>1 and V</em>2 must be the same.
Dilution Calculations
- Problem 4: What is the final concentration if 80.0 mL of a 2.0% stock glucose solution is diluted to 400.0 mL?
- 2.0%×80.0mL=C2×400.0mL
- C2=400.0mL2.0%×80.0mL
- C2=0.4%
Fluid Compartments of the Body
- Intracellular fluid volume = 25 L, 40% body weight
- Total body water volume = 40 L, 60% body weight
- Extracellular fluid volume = 15 L, 20% body weight
- Interstitial fluid volume 12 L, 80% of ECF
- Plasma volume = 3 L, 20% of ECF
- Fluid compartments of the body, are complex solutions transporting many solutes around the body, examples include;
- Gases; e.g. O<em>2, CO</em>2
- Ions; e.g. Na+, Cl−, K+, Ca2+, HCO3−
- Nutrients; e.g. glucose
- Proteins; e.g. hormones insulin
- Wastes, etc.
Gases and the Respiratory System
- The major function of the respiratory system is to supply the body with oxygen (O<em>2) and to dispose of carbon dioxide (CO</em>2). As cells use oxygen, they produce carbon dioxide as a waste product.
Properties of Gases
- Gas particles are far apart.
- A gas has no definite shape or volume, filling any container.
- A gas is less dense and can be compressed.
Kinetic Theory of Gases
- A gas is composed of very small particles (molecules and atoms).
- The particles of a gas are very far apart.
- Gas particles move rapidly, colliding with each other and the container walls.
- Gas particles do not attract or repel one another.
- The kinetic energy of gas particles is related to the temperature; motion increases with temperature.
Properties of Gases
- Important properties related to gases:
- Pressure (P)
- Volume (V)
- Temperature (T)
Pressure
- Pressure of a gas is the force created when gas particles hit the container wall.
- Typical pressure units:
- Pascal (Pa) - the SI unit
- Atmosphere (atm)
- Millimeters of mercury (mmHg)
Volume
- The volume of a gas is equal to the volume of the container.
- Typical volume units:
- Litre (L) - the metric unit
- Millilitre (mL)
Temperature
- All calculations with gases use the Kelvin temperature scale.
- K=°C+273
- Absolute zero (0 K) means particles would have no energy or motion.
Atmospheric Pressure
- The air covering the Earth's surface contains many gas molecules, exerting atmospheric pressure due to their mass and gravity.
- Atmospheric pressure can be measured using a barometer. At 1 atm, mercury in the glass tube would be 760 mm high.
- Standard atmospheric pressure is 1 atm or 760 mmHg.
Atmospheric Pressure Variation
- Atmospheric pressure varies at different heights and depths.
- Sea level: 1 atm
- 10 m below: 2 atm
- 20 m below: 3 atm
- 30 m below: 4 atm
- 5 km high: 0.5 atm
- Mount Everest (8.9 km high): 0.35 atm
Boyle’s Law
- Volume (V) of a gas changes inversely with the pressure (P), as long as temperature and amount of gas are constant.
- P<em>1×V</em>1=P<em>2×V</em>2
- Where:
- P is the gas pressure
- V is the gas volume
- Subscript 1 is initial conditions
- Subscript 2 is final conditions
Boyle's Law Example 1
- A balloon contains 500 mL of gas at 760 mmHg. It rises to an altitude where its pressure becomes 380 mmHg. What is its new volume? (Assume temperature is constant).
- P<em>1×V</em>1=P<em>2×V</em>2
- (760mmHg×500mL)=(380mmHg×V2)
- V2=380(760×500)
- V2=1000mL
- (the volume has doubled)
The Mechanics of Breathing and Boyle’s Law
- During inspiration, lung volume increases, decreasing air pressure in the lungs. Air flows in from outside (high pressure) to equalize pressure.
- During expiration, lung volume decreases, increasing lung pressure. Air flows out to equalize pressure.