Study Notes on Implicit Differentiation, Derivatives, and Limits
Key Concepts of Implicit Differentiation and Derivatives
Defining Functions
Explicit vs. Implicit Definitions
Example: y = x² + 3x - 4 defines y explicitly.
Rearranging to x² + 3x - y = 4 defines y implicitly.
Derivatives of Functions
For y = x² + 3x - 4:
Derivative: y' = 2x + 3 (explicit differentiation).
Applying Implicit Differentiation:
For x² + 3x - y = 4:
Derivative:
d/dx of x² is 2x.
d/dx of 3x is 3.
d/dx of y is y'.
d/dx of 4 is 0.
Collecting terms:
y' = 2x + 3.
Working with Circular Functions
For x² + y² = 4:
Solve for y: y = ±√(4 - x²).
Positive root covers the upper half-circle; negative root covers the lower half.
Derivative (implicit differentiation):
2x + 2yy' = 0.
Solve for y': y' = -x/y.
Example Values:
If x = 1, then y = ±√3 → corresponding points (1, √3) and (1, -√3).
Second Derivatives
To find y'':
Derivative of y' = -x/y.
Use quotient rule:
Apply to original function or explicit form, results in the same derivative.
Simplified second derivative: y'' = -4/(y²).
General Principles
Remember to apply the chain rule for every instance of y:
If y = f(x), then dy/dx = f'(x)y'.
Formulas & Connections:
y' obtained through implicit differentiation should correlate with explicit derivative results, even if not visually identical.
Practical Applications
Example Problem: x + x²y³ = 4y + 1
Find the tangent line at the point (1, 2): Calculate slope y' using implicit differentiation.
y' = -17/8: Write the tangent line equation.
Absolute Value Inequalities
Handle using interval notation:
Solve |4x - 3| ≤ 11.
Result is -2 ≤ x ≤ 7/2.
Quadratic Inequalities
Solve by transforming to zero:
Setup x² + 6x - 7 < 0 to factor or apply quadratic formula, determining ranges.
Continuity of Functions
Definition involves three conditions:
Function defined at c.
The limit exists at c.
Limit equals function value at c.
Example: Identify removable discontinuities (fixable by redefining functions).
Limits and Derivatives
Limit Definitions:
For polynomial functions, limits often straightforward.
Use L'Hôpital's rule judiciously in indeterminate forms (0/0).
Apply transformation to recognize behaviors as x approaches certain points.
Conclusion
Review implicit differentiation and limit processes to be prepared for exams.