Integration

Integral as (Signed) Area

- If ff is continuous and positive on [a,b][a,b], ∫abf(t) dt\int_a^b f(t)\,dt is the area under the graph between x=ax=a and x=bx=b.

- If ff changes sign, the integral is the algebraic sum: positive areas where f>0f>0, negative where f<0f<0.

Basic Properties

- Zero interval: ∫aaf(t) dt=0.\int_a^a f(t)\,dt = 0.

- Orientation: ∫abf(t) dt=−∫baf(t) dt.\int_a^b f(t)\,dt = -\int_b^a f(t)\,dt.

- Chasles’ relation: for c∈[a,b]c\in[a,b], ∫abf(t) dt=∫acf(t) dt+∫cbf(t) dt.\int_a^b f(t)\,dt = \int_a^c f(t)\,dt + \int_c^b f(t)\,dt.

- Linearity: for continuous f,gf,g on [a,b][a,b] and λ∈R\lambda\in\mathbb{R},

- ∫ab(f+g)(t) dt=∫abf(t) dt+∫abg(t) dt,\int_a^b (f+g)(t)\,dt = \int_a^b f(t)\,dt + \int_a^b g(t)\,dt,

- ∫abλf(t) dt=λ∫abf(t) dt.\int_a^b \lambda f(t)\,dt = \lambda \int_a^b f(t)\,dt.

- Positivity / comparison:

- If f≥0f\ge 0 on [a,b][a,b], then ∫abf(t) dt≥0.\int_a^b f(t)\,dt \ge 0.

- If f≤gf\le g on [a,b][a,b], then ∫abf(t) dt≤∫abg(t) dt.\int_a^b f(t)\,dt \le \int_a^b g(t)\,dt.

#Primitive (Antiderivative)

- A primitive of ff on an interval II is a function FF with F′(x)=f(x)F'(x)=f(x) for all x∈Ix\in I.

- If FF is one primitive, then all primitives of ff are F+CF+C with C∈RC\in\mathbb{R}.

- The function F(x)=∫axf(t) dtF(x)=\int_a^x f(t)\,dt is a primitive of ff on [a,b][a,b] and satisfies F(a)=0F(a)=0 (distinguished primitive).

- Fundamental theorem of calculus: for continuous ff on [a,b][a,b] and any primitive FF, ∫abf(t) dt=F(b)−F(a)=[F(x)]ab.\int_a^b f(t)\,dt = F(b) - F(a) = [F(x)]_a^b.

Usual Primitives

- Power functions (ε≠−1\varepsilon\neq -1): ∫xε dx=xε+1ε+1+C.\int x^\varepsilon\,dx = \frac{x^{\varepsilon+1}}{\varepsilon+1} + C.

- Logarithm case: ∫1x dx=ln⁡∣x∣+C.\int \frac{1}{x}\,dx = \ln|x| + C.

- Exponential: ∫ex dx=ex+C.\int e^x\,dx = e^x + C.

- Trigonometric: ∫cos⁡x dx=sin⁡x+C,∫sin⁡x dx=−cos⁡x+C.\int \cos x\,dx = \sin x + C,\qquad \int \sin x\,dx = -\cos x + C.

- Arctangent: ∫11+x2 dx=arctan⁡x+C.\int \frac{1}{1+x^2}\,dx = \arctan x + C.

Integration by Parts

- Based on (fg)′=f′g+fg′.(fg)' = f'g + fg'.

- Primitive form: ∫f′(x)g(x) dx=f(x)g(x)−∫f(x)g′(x) dx.\int f'(x)g(x)\,dx = f(x)g(x) - \int f(x)g'(x)\,dx.

- Definite integral form: ∫abf′(x)g(x) dx=[f(x)g(x)]ab−∫abf(x)g′(x) dx.\int_a^b f'(x)g(x)\,dx = [f(x)g(x)]_a^b - \int_a^b f(x)g'(x)\,dx.

- Typical strategy: choose gg to simplify when differentiated and f′f' to be easily integrable.

# Example: Primitive of ln⁡x\ln x

- On (0,+∞)(0,+\infty): ∫ln⁡x dx=xln⁡x−x+C,\int \ln x\,dx = x\ln x - x + C, via integration by parts with f′(x)=1f'(x)=1, g(x)=ln⁡xg(x)=\ln x.

Change of Variables (Substitution)

- General theorem: if u:[a,b]→Iu:[a,b]\to I is C1\mathcal{C}^1 with continuous derivative and ff is continuous on II, then ∫abf(u(t))u′(t) dt=∫u(a)u(b)f(x) dx.\int_a^b f(u(t))u'(t)\,dt = \int_{u(a)}^{u(b)} f(x)\,dx.

- Careful: the bounds must also be transformed: a,b↦u(a),u(b)a,b \mapsto u(a),u(b).

- Primitive version: ∫f(u(x))u′(x) dx=F(u(x))+C,\int f(u(x))u'(x)\,dx = F(u(x)) + C, where FF is a primitive of ff.

Translation / Affine Change of Variable

- Translation: ∫abf(x+x0) dx=∫a+x0b+x0f(t) dt.\int_a^b f(x+x_0)\,dx = \int_{a+x_0}^{b+x_0} f(t)\,dt.

- General affine change u(x)=px+x0u(x)=px+x_0 (p≠0p\neq0):

- Primitive: ∫f(px+x0) dx=1pF(px+x0)+C,\int f(px+x_0)\,dx = \frac{1}{p}F(px+x_0)+C, where F′=fF' = f.

- Definite integral: ∫abf(px+x0) dx=1p∫pa+x0pb+x0f(x) dx.\int_a^b f(px+x_0)\,dx = \frac{1}{p}\int_{pa+x_0}^{pb+x_0} f(x)\,dx.

“Physicist’s Method” Notation

- Write t=u(x)t = u(x), compute dtdx\dfrac{dt}{dx}, rearrange symbolically as dx=⋯ dtdx = \cdots\,dt to do substitution quickly.

- Same idea as rigorous change of variable, but with differential notation.

Example Types

- Integral of te−tt e^{-t} on [0,T][0,T] by parts; shows a limit as T→+∞T\to+\infty equal to 11 (generalized integral): ∫0Tte−t dt.\int_0^T t e^{-t}\,dt.

- Substitution examples such as ∫1911+x dx,\int_1^9 \frac{1}{1+\sqrt{x}}\,dx, with t=xt=\sqrt{x}.

- Completing the square and substitution for rational functions like ∫dxx2+4x+8.\int \frac{dx}{x^2+4x+8}.

Applied Example – River Discharge

- A discharge function q(t)q(t) models water flow rate (e.g. in millions of m3\text{m}^3 per day).

- Total volume over [0,T][0,T] is v(T)=∫0Tq(t) dt.v(T) = \int_0^T q(t)\,dt.

- In the example, q(t)q(t) is given in terms of a logistic-type expression, and recognizing it as q(t)=c −u′(t)u(t)2q(t) = c\,\frac{-u'(t)}{u(t)^2} allows finding a primitive analytically.