Integration

Integral as (Signed) Area

- If ff is continuous and positive on [a,b][a,b], abf(t)dt\int_a^b f(t)\,dt is the area under the graph between x=ax=a and x=bx=b.

- If ff changes sign, the integral is the algebraic sum: positive areas where f>0, negative where f<0.

Basic Properties

- Zero interval: aaf(t)dt=0.\int_a^a f(t)\,dt = 0.

- Orientation: abf(t)dt=baf(t)dt.\int_a^b f(t)\,dt = -\int_b^a f(t)\,dt.

- Chasles’ relation: for c[a,b]c\in[a,b], abf(t)dt=acf(t)dt+cbf(t)dt.\int_a^b f(t)\,dt = \int_a^c f(t)\,dt + \int_c^b f(t)\,dt.

- Linearity: for continuous f,gf,g on [a,b][a,b] and λR\lambda\in\mathbb{R},

- ab(f+g)(t)dt=abf(t)dt+abg(t)dt,\int_a^b (f+g)(t)\,dt = \int_a^b f(t)\,dt + \int_a^b g(t)\,dt,

- abλf(t)dt=λabf(t)dt.\int_a^b \lambda f(t)\,dt = \lambda \int_a^b f(t)\,dt.

- Positivity / comparison:

- If f0f\ge 0 on [a,b][a,b], then abf(t)dt0.\int_a^b f(t)\,dt \ge 0.

- If fgf\le g on [a,b][a,b], then abf(t)dtabg(t)dt.\int_a^b f(t)\,dt \le \int_a^b g(t)\,dt.

#Primitive (Antiderivative)

- A primitive of ff on an interval II is a function FF with F(x)=f(x)F'(x)=f(x) for all xIx\in I.

- If FF is one primitive, then all primitives of ff are F+CF+C with CRC\in\mathbb{R}.

- The function F(x)=axf(t)dtF(x)=\int_a^x f(t)\,dt is a primitive of ff on [a,b][a,b] and satisfies F(a)=0F(a)=0 (distinguished primitive).

- Fundamental theorem of calculus: for continuous ff on [a,b][a,b] and any primitive FF, abf(t)dt=F(b)F(a)=[F(x)]ab.\int_a^b f(t)\,dt = F(b) - F(a) = [F(x)]_a^b.

Usual Primitives

- Power functions (ε1\varepsilon\neq -1): xεdx=xε+1ε+1+C.\int x^\varepsilon\,dx = \frac{x^{\varepsilon+1}}{\varepsilon+1} + C.

- Logarithm case: 1xdx=lnx+C.\int \frac{1}{x}\,dx = \ln|x| + C.

- Exponential: exdx=ex+C.\int e^x\,dx = e^x + C.

- Trigonometric: cosxdx=sinx+C,sinxdx=cosx+C.\int \cos x\,dx = \sin x + C,\qquad \int \sin x\,dx = -\cos x + C.

- Arctangent: 11+x2dx=arctanx+C.\int \frac{1}{1+x^2}\,dx = \arctan x + C.

Integration by Parts

- Based on (fg)=fg+fg.(fg)' = f'g + fg'.

- Primitive form: f(x)g(x)dx=f(x)g(x)f(x)g(x)dx.\int f'(x)g(x)\,dx = f(x)g(x) - \int f(x)g'(x)\,dx.

- Definite integral form: abf(x)g(x)dx=[f(x)g(x)]ababf(x)g(x)dx.\int_a^b f'(x)g(x)\,dx = [f(x)g(x)]_a^b - \int_a^b f(x)g'(x)\,dx.

- Typical strategy: choose gg to simplify when differentiated and ff' to be easily integrable.

# Example: Primitive of lnx\ln x

- On (0,+)(0,+\infty): lnxdx=xlnxx+C,\int \ln x\,dx = x\ln x - x + C, via integration by parts with f(x)=1f'(x)=1, g(x)=lnxg(x)=\ln x.

Change of Variables (Substitution)

- General theorem: if u:[a,b]Iu:[a,b]\to I is C1\mathcal{C}^1 with continuous derivative and ff is continuous on II, then abf(u(t))u(t)dt=u(a)u(b)f(x)dx.\int_a^b f(u(t))u'(t)\,dt = \int_{u(a)}^{u(b)} f(x)\,dx.

- Careful: the bounds must also be transformed: a,bu(a),u(b)a,b \mapsto u(a),u(b).

- Primitive version: f(u(x))u(x)dx=F(u(x))+C,\int f(u(x))u'(x)\,dx = F(u(x)) + C, where FF is a primitive of ff.

Translation / Affine Change of Variable

- Translation: abf(x+x0)dx=a+x0b+x0f(t)dt.\int_a^b f(x+x_0)\,dx = \int_{a+x_0}^{b+x_0} f(t)\,dt.

- General affine change u(x)=px+x0u(x)=px+x_0 (p0p\neq0):

- Primitive: f(px+x0)dx=1pF(px+x0)+C,\int f(px+x_0)\,dx = \frac{1}{p}F(px+x_0)+C, where F=fF' = f.

- Definite integral: abf(px+x0)dx=1ppa+x0pb+x0f(x)dx.\int_a^b f(px+x_0)\,dx = \frac{1}{p}\int_{pa+x_0}^{pb+x_0} f(x)\,dx.

“Physicist’s Method” Notation

- Write t=u(x)t = u(x), compute dtdx\dfrac{dt}{dx}, rearrange symbolically as dx=dtdx = \cdots\,dt to do substitution quickly.

- Same idea as rigorous change of variable, but with differential notation.

Example Types

- Integral of tett e^{-t} on [0,T][0,T] by parts; shows a limit as T+T\to+\infty equal to 11 (generalized integral): 0Ttetdt.\int_0^T t e^{-t}\,dt.

- Substitution examples such as 1911+xdx,\int_1^9 \frac{1}{1+\sqrt{x}}\,dx, with t=xt=\sqrt{x}.

- Completing the square and substitution for rational functions like dxx2+4x+8.\int \frac{dx}{x^2+4x+8}.

Applied Example – River Discharge

- A discharge function q(t)q(t) models water flow rate (e.g. in millions of m3\text{m}^3 per day).

- Total volume over [0,T][0,T] is v(T)=0Tq(t)dt.v(T) = \int_0^T q(t)\,dt.

- In the example, q(t)q(t) is given in terms of a logistic-type expression, and recognizing it as q(t)=cu(t)u(t)2q(t) = c\,\frac{-u'(t)}{u(t)^2} allows finding a primitive analytically.