Notes on Humidity, Vapor Pressure, Partial Pressure, Evaporation, Condensation, and Dew Point

Key concepts

  • Humidity: the amount of water vapor present in the air.

  • Relative humidity (RH): a percentage describing how much water vapor is in the air relative to the maximum amount the air can hold at a given temperature. It varies from 0% to 100% (and can exceed 100% in supersaturated situations).

  • Partial pressure of water, p<em>H</em>2Op<em>{H</em>2O}: the actual pressure contributed by water vapor in the air.

  • Vapor pressure of waterpsat(T)p_{sat}(T): the maximum partial pressure of water vapor that air can hold at temperatureTT; it depends on temperature. It increases with temperature.

  • Evaporation: liquid water → water vapor (in the gas phase).

  • Condensation: water vapor → liquid water (gas to liquid).

  • Dew point: the temperature at which the air becomes saturated (i.e., the partial pressure of water equals the vapor pressure, p<em>H</em>2O=psat(T)p<em>{H</em>2O} = p_{sat}(T)). At the dew point, RH = 100% and condensation can begin if the temperature is lowered further.

  • Saturated, unsaturated, and supersaturated:

    • Unsaturated: p{H2O} < p_{sat}(T); RH < 100%; the air can hold more water vapor.

    • Saturated: p<em>H</em>2O=psat(T)p<em>{H</em>2O} = p_{sat}(T); RH = 100%; the rate of evaporation equals the rate of condensation.

    • Supersaturated: p{H2O} > p_{sat}(T); RH > 100%; condensation tends to occur to reduce water vapor.

Relative humidity: definition and interpretation

  • Relative humidity is defined as
    RH=racp<em>H</em>2Opsat(T)imes100%.RH = rac{p<em>{H</em>2O}}{p_{sat}(T)} imes 100\%.

  • It represents the ratio of how much water vapor is actually in the air to how much water vapor the air can hold at that temperature.

  • Examples based on given values:

    • At 30°C, if p<em>H</em>2O=18 extTorrp<em>{H</em>2O} = 18\ ext{Torr} and psat(30°C)=31.8 Torrp_{sat}(30°C) = 31.8\ \text{Torr}, then
      RH=1831.8×100%56.6%.RH = \frac{18}{31.8} \times 100\% \approx 56.6\%.

    • If p<em>H</em>2O=0 Torrp<em>{H</em>2O} = 0\ \text{Torr}, then RH=0%.RH = 0\%.

    • If p<em>H</em>2O=psat(T)p<em>{H</em>2O} = p_{sat}(T), then RH=100%.RH = 100\%.

Vapor pressure vs partial pressure

  • Vapor pressure is a property of water that depends only on temperature: it is the pressure at which water in liquid form is in equilibrium with water in vapor form.

  • Partial pressure p<em>H</em>2Op<em>{H</em>2O} depends on how much water vapor is actually present in the air.

  • At a fixed temperature, as water evaporates, p<em>H</em>2Op<em>{H</em>2O} rises until it approaches (or equals) p<em>sat(T)p<em>{sat}(T); if you have more water evaporating than condensing, p</em>H2Op</em>{H_2O} climbs toward that limit.

Evaporation, condensation, and equilibrium (using three beakers)

  • Beaker A (evacuated gas inside, only liquid water):

    • Initial state: no water vapor in the air, so p<em>H</em>2O=0p<em>{H</em>2O}=0.

    • The temperature is 30°C, so psat(30°C)=31.8 Torr.p_{sat}(30°C) = 31.8\ \text{Torr}.

    • Evaporation occurs (liquid water→gas); some water vapor enters the air, raising p<em>H</em>2Op<em>{H</em>2O} (example value given: ≈ 10 Torr).

    • Condensation cannot occur yet because there are almost no water molecules in the air, so the rate of condensation is effectively zero.

    • Evaporation rate > condensation rate (the arrows show more coming up than going down).

    • Result: p{H2O} < p_{sat}(T), so RH < 100% (for this case, RH1031.8×100%31%RH\approx \frac{10}{31.8} \times 100\% \approx 31\%).

  • Beaker B:

    • p<em>H</em>2O=10 Torrp<em>{H</em>2O} = 10\ \text{Torr}, same temperature (30°C) and same psatp_{sat}.

    • Evaporation still dominates (more water vapor entering the gas phase than condensing).

    • p<em>H</em>2Op<em>{H</em>2O} continues to rise toward 31.8 Torr.

  • Beaker C:

    • Water vapor has accumulated until p<em>H</em>2O=31.8 Torr=psat(30°C).p<em>{H</em>2O} = 31.8\ \text{Torr} = p_{sat}(30°C).

    • Now the rate of evaporation equals the rate of condensation.

    • At this point, the air is saturated: p<em>H</em>2O=psat(T)p<em>{H</em>2O} = p_{sat}(T), so RH=100%.RH = 100\%.

  • Summary of the roles:

    • Partial pressure measures how much water vapor is actually in the air.

    • Vapor pressure is the maximum amount of water vapor the air can hold at a given temperature.

    • When p{H2O} < p{sat}, evaporation dominates; when p{H2O} > p{sat}, condensation dominates; when they are equal, you have equilibrium.

The dew point and 100% relative humidity

  • Dew point is the temperature at which the partial pressure equals the vapor pressure:
    p<em>H</em>2O=p<em>sat(T</em>dp).p<em>{H</em>2O} = p<em>{sat}(T</em>{dp}).

  • At the dew point, RH = 100%; if you cool further, condensation dominates and you start to see dew, fog, clouds, or precipitation.

  • Practical takeaway: to measure dew point, gradually cool the air until condensation just begins.

  • Conceptual link: the dew point is the temperature at which the air becomes fully saturated for that amount of water vapor present.

Condensation, saturation, and supersaturation explained

  • If the partial pressure of water is less than the vapor pressure (e.g., $p{H2O} = 0$ or 10 Torr with $p_{sat} = 31.8$ Torr), the air is unsaturated and can hold more water vapor; RH < 100%.

  • If the partial pressure equals the vapor pressure, the air is saturated; RH = 100%.

  • If the partial pressure exceeds the vapor pressure, the air is supersaturated; RH > 100% and condensation occurs to bring the system back toward equilibrium.

  • In general, unsaturated ⇔ RH < 100%, saturated ⇔ RH = 100%, supersaturated ⇔ RH > 100% (for the same temperature).

Supersaturation: how it happens and what it means

  • Suppose the temperature is 30°C (psat = 31.8 Torr) and the current partial pressure is pH2O = 27 Torr (still below saturation).

  • If the temperature is rapidly lowered to 20°C (psat(20°C) ≈ 17.5 Torr) while pH2O remains 27 Torr, then p{H2O} > p_{sat}(20°C)

    • The air cannot hold all this water vapor at 20°C, so condensation occurs.

    • This is a transient supersaturated state: the system moves toward equilibrium by forming liquid water.

  • Dwell point (dew point) is the temperature where the vapor pressure would equal the actual partial pressure, i.e., where p<em>sat(T</em>dp)=p<em>H</em>2O=27 Torrp<em>{sat}(T</em>{dp}) = p<em>{H</em>2O} = 27\ \text{Torr}. This lies somewhere between 20°C and 30°C; a rough estimate might be around 27°C in this illustration, but the exact value depends on the water-vapor saturation curve.

  • Once the temperature drops below the dew point, condensation proceeds and visible droplets form (fog, dew).

Practical relationships and takeaways

  • Relationships:

    • As temperature increases, it P(sat )increases. For a fixed amount of water vapor, increasing temperature lowers RH.

    • As water vapor increases (higher p<em>H</em>2Op<em>{H</em>2O}) at a fixed temperature, RH increases.

    • Dew point is the temperature at which the current p<em>H</em>2Op<em>{H</em>2O} would equal the new psatp_{sat}; condensation begins if you cool past that point.

  • Real-world relevance:

    • Weather patterns: fog, dew, clouds form when air reaches or exceeds its dew point.

    • Indoor climate control (HVAC): heating or cooling air changes psatp_{sat} and thus RH, impacting comfort and comfort-related systems.

    • Humidity management affects sweating and cooling; dry air supports faster evaporation of sweat, humid air slows it, making it feel hotter in humid conditions.

Quick reference formulas and definitions

  • Relative humidity:
    RH=p<em>H</em>2Opsat(T)×100%.RH = \frac{p<em>{H</em>2O}}{p_{sat}(T)} \times 100\%.

  • Vapor pressure vs partial pressure:

    • psat(T)p_{sat}(T): temperature-dependent maximum partial pressure of water vapor.

    • p<em>H</em>2Op<em>{H</em>2O}: actual partial pressure of water vapor in air.

  • Equilibrium (evaporation = condensation):
    p<em>H</em>2O=psat(T).p<em>{H</em>2O} = p_{sat}(T).

  • Dew point: the temperature T<em>dpT<em>{dp} at which p{H2O} = p{sat}(T_{dp}).}

Practice reflections and quick questions

  • If at 25°C you measure p<em>H</em>2O=20 Torrp<em>{H</em>2O} = 20\ \text{Torr} and psat(25°C)=31.7 Torrp_{sat}(25°C) = 31.7\ \text{Torr}, what is the RH?

    • Answer: RH=2031.7×100%63%.RH = \frac{20}{31.7} \times 100\% \approx 63\%.

  • What happens if you cool the air from 25°C to 15°C while keeping the same p<em>H</em>2Op<em>{H</em>2O}? Describe the likely condensation behavior.

  • How would increasing the ambient temperature affect the dew point for a fixed amount of water vapor in the air?

Summary of the key ideas

  • Humidity is about water vapor in air; relative humidity compares actual water vapor to what the air can hold at that temperature.

  • Evaporation increases the amount of water vapor in the air until it approaches the vapor pressure; condensation reduces it by turning vapor back into liquid.

  • The dew point is the critical temperature where the air becomes saturated; below this temperature, condensation occurs.

  • Saturation, unsaturation, and supersaturation describe the relationship between the actual water vapor pressure and the vapor pressure at the current temperature, with RH providing a percent measure of proximity to saturation.

  • The concept has broad implications in weather, climate control, human comfort, and various practical environments.

Important glossary recap

  • p_H2O: actual partial pressure of water vapor in air

  • p_sat(T): vapor pressure of water at temperature T

  • RH: relative humidity, a percentage = p<em>H</em>2Opsat(T)×100%\frac{p<em>{H</em>2O}}{p_{sat}(T)} \times 100\%

  • Dew point: the temperature where p<em>H</em>2O=psat(T)p<em>{H</em>2O} = p_{sat}(T) and condensation begins

  • Evaporation vs condensation: kinetic-energy-driven exchange between liquid and gas phases depending on the relation between p<em>H</em>2Op<em>{H</em>2O} and psat(T)p_{sat}(T)