Exam Prep Recap: Rational & Radical Equations, Intro to Graphing

Course Administration and Exam Preparation

  • Module Progress and Grades:

    • Module 3 (Student Rights) is an essential part of the course, often taking 101410-14 hours to complete.

    • Progress on modules outside of class time has been checked, with some students still needing to catch up.

    • Modules (blue part) and knowledge checks (green part) together account for 35%35\% (approximately one-third) of the overall course grade.

    • The remaining grade comes from exams.

    • It is crucial to work concurrently on module (blue) and knowledge check (green) parts as they are closely related despite differing question counts (e.g., 2424 questions for Module 3 blue, 2525 for Module 3 green).

  • First Exam:

    • The first exam is scheduled for two weeks from today (from the lecture's date, which was the 21st21^{st}).

    • Students can discuss taking the exam earlier individually.

    • There are no other modules due this current week.

  • Knowledge Checks:

    • Knowledge checks can be reset to restore the ALEKS Pie if results indicate mastered topics or areas for review.

    • A knowledge check on Module 4 content will be available next Tuesday.

  • ALEKS Access and Resources:

    • Solution sheets (blank and filled) for modules are available on Brightspace under "Learning Content" -> "Module Lesson Pages."

    • Direct ALEKS access is at the very bottom of the Brightspace page.

  • Practice Test:

    • A practice test with approximately 4040 questions will be available after scheduled Knowledge Check 2.

    • Paper will be provided for working out solutions (not for submission for credit, but for personal use).

    • Students are allowed one full page of reference notes during the exam.

    • Calculators are permitted and required, but not provided by the instructor; graphics calculators are highly recommended if not explicitly required by the course material.

    • Exams will likely require a lockdown browser and be password-protected.

Key Mathematical Concepts: Rational and Radical Equations

  • Overview of Difficult Concepts:

    • Rational equations are generally considered more challenging than radical equations due to the reliance on common denominators and prevalent application problems.

    • Radical equations involve eliminating square roots or other roots.

  • Rational Equations:

    • Goal: Eliminate denominators.

    • Common Denominator Method:

      • Find the lowest common denominator (LCD) which is often a combination of all unique parts in the denominators.

      • Multiply all terms (including whole numbers, treated as fractions over 11) by the LCD to clear denominators.

      • Example: For an expression with denominators 44 and (b+8)(b+8), the LCD would be 4(b+8)4(b+8).

      • Extraneous Solutions: Always check for values that make the original denominator zero (b8b \ne -8 in the example) as these are invalid solutions.

    • Cross-Multiplication Method:

      • Applicable only when there is exactly one fraction (or rational expression) on each side of the equation.

      • It achieves the same result as multiplying by the common denominator but can be quicker for this specific scenario.

      • If there are more than two terms (e.g., a fraction plus a whole number), combine terms or move them to isolate single fractions on each side before cross-multiplying.

    • Solving Steps:

      • After clearing denominators, solve the resulting linear or quadratic equation.

      • For quadratic equations (b2b^2 terms), use factoring or the quadratic formula.

    • Application Problems:

      • Often involve scenarios like "two computers doing a job together."

      • Example: If two computers together do a job in 44 minutes, they complete 1/4th1/4^{th} of the job per minute. If one takes 1414 minutes, rate is 1/141/14 per minute. If the faster one takes xx minutes, rate is 1/x1/x per minute. The equation would be 1/4=1/14+1/x1/4 = 1/14 + 1/x. The LCD would be 28x28x.

      • Watch for extraneous solutions where x=0x=0 or any other value makes a denominator zero.

    • Equations with Multiple Letters (Literal Equations):

      • Treat other letters as constants/numbers and isolate the target variable.

      • Example: For E=IRE = IR, to solve for II, you divide by RR, resulting in I=E/RI = E/R.

      • Common Error in Inputting Answers: When a solution involves multiple terms, ensure correct fraction grouping. For example, if the solution is (A/(KB))N(A/(KB)) - N, it should be entered as such, not (AN)/(KB)(A-N)/(KB), as NN does not share the (KB)(KB) denominator.

      • Similarly, for the quadratic formula, the entire numerator (b±b24ac-b \pm \sqrt{b^2-4ac}) should be divided by 2a2a, not just the square root part.

  • Radical Equations:

    • Goal: Get the radical term by itself on one side of the equation.

    • Eliminating the Radical: Raise both sides of the equation to the power corresponding to the root (e.g., square both sides for a square root, cube for a cube root).

    • Algebraic Caution: If there are multiple terms on the non-radical side (e.g., u+1u+1), remember to expand (FOIL) them when squaring or cubing.

    • Checking Solutions: It's often possible and advisable to plug the found solution back into the original equation to verify it.

    • Fractional Exponents:

      • An expression like (Z+10)3/4=3(-Z+10)^{3/4} = 3 can be solved by raising both sides to the reciprocal power, which is 4/34/3. This cancels the original exponent, leaving Z+10=34/3-Z+10 = 3^{4/3}.

      • Alternatively, convert to radical form: the denominator of the exponent is the root (e.g., 4th4^{th} root), and the numerator is the power (e.g., (Z+10)34=3\sqrt[4]{(-Z+10)^3} = 3).

      • Solving Approach:

        1. Isolate the term with the fractional exponent or radical.

        2. Raise both sides to a power to remove the root (e.g., raise to the 4th4^{th} power to remove a 4th4^{th} root), leaving the remaining exponent inside if applicable (e.g., leaving a 3rd3^{rd} power).

        3. Raise both sides to the power corresponding to the remaining exponent (e.g., take the cube root to remove a 3rd3^{rd} power).

      • Simplifying Radical Answers: If a cube root of 8181 is obtained, simplify it if possible (e.g., 3333\sqrt[3]{3}) but do not combine it with integers (e.g., 81310\sqrt[3]{81} - 10 remains as is, rather than a decimal, unless specified).

Introduction to Module 4: Graphing

  • Focus: Graphing linear equations.

  • Linear Equations: Represent straight lines.

  • Plotting Points:

    • Only two distinct points ((x<em>1,y</em>1)(x<em>1, y</em>1) and (x<em>2,y</em>2)(x<em>2, y</em>2)) are needed to graph a straight line.

    • Choose convenient xx values (e.g., 0,1,50, -1, -5) and calculate their corresponding yy values.

  • ALEKS Graphing Tool:

    • The "line tool" can be used (pencil, eraser, line options).

    • Slope-Intercept Form (y=mx+by = mx+b):

      • The bb value is the y-intercept, where the line crosses the y-axis (point (0,b)(0, b)).

      • The mm value is the slope (rise over run).

      • Example: For y=(1/3)x+5y = (1/3)x + 5, the y-intercept is (0,5)(0, 5). From this point, rise 11 unit (positive y-direction) and run 33 units (positive x-direction) to find a second point.

    • "Plot a Point" Feature:

      • A very useful ALEKS tool that allows users to directly type in (x,yx, y) coordinates.

      • This is especially helpful when exact placement on the grid is difficult, when coordinates are not whole numbers, or for more complex graphs in later units (parabolas, rational/radical graphs).

  • Future Topics in Module 4 (to be covered on Thursday):

    • Distance formula and Midpoint formula.

    • Graphing vertical and horizontal lines.

    • Finding intercepts.

    • Real-world applications of linear equations.

    • Determining and calculating slopes (positive, negative, zero, undefined for vertical lines).

    • Parallel lines.