Stoichiometric Calculations for Magnesium Reaction
Stoichiometric Calculations
Weight of Magnesium Reacted
- Chemical Reaction:
- The balanced chemical equation for the reaction of magnesium with oxygen is:
- [ 2 \text{Mg} + \text{O}_2 \rightarrow 2 \text{MgO} ]
Molar Mass of Reactants
- Molar Mass Calculations:
- Magnesium (Mg): 24.3 g/mol
- Oxygen (O): 16.0 g/mol
Calculation of Magnesium Reacted
- To find the weight of magnesium that has reacted, consider the molar ratio from the balanced equation:
- 2 moles of Mg react with 1 mole of O₂ to produce 2 moles of MgO.
- This indicates that the molar amount of Mg used corresponds directly to the amount of O₂ reacted.
- Significant Figures: Always provide answers in accordance with significant figures.
- In this problem, based on the given molar mass of magnesium (24.3 g/mol), the answer must reflect the correct significant figures.
Scientific Notation Requirement
- When presenting the final answer, it should be in scientific notation, specifically E notation.
- Format: Use 1 digit before the decimal point.
- Example Format: 2.5e5 (which is equivalent to 2.5 x 10^5).
Example of Calculation (Hypothetical)
- If 3.0 moles of Mg reacted:
- Weight of Mg = Number of moles × Molar mass
- Weight of Mg = 3.0 moles × 24.3 g/mol = 72.9 g
- In significant figures, this would be presented as 7.29e1 g (as 72.9 has three significant figures, resulting in the format).
Final Answer Presentation
- The response must be formatted correctly based on the input requirements and show the weight of reacted Mg in scientific notation with the correct significant figures.