Section 5.3.3: Cross Product of Vectors and Matrix Determinants

Activity 5.10: Preliminary Questions on Vector Operations and Determinants

  • Question 1: Foundational Knowledge   - The activity begins by prompting students to reflect on their existing knowledge regarding the cross product of vectors: "What do you know about cross product of vectors?"
  • Question 2: Evaluation of a 2×22 \times 2 Determinant   - Find det(A)det(A) given the matrix: A=(2amp;5 1amp;3)A = \begin{pmatrix} 2 & 5 \ -1 & 3 \end{pmatrix}
  • Question 3: Evaluation of a 3×33 \times 3 Determinant   - Find det(A)det(A) given the matrix: A=(4amp;5amp;1 0amp;3amp;6 2amp;1amp;4)A = \begin{pmatrix} 4 & 5 & 1 \ 0 & -3 & 6 \ -2 & 1 & 4 \end{pmatrix}

Determinant Calculation for 2×22 \times 2 and 3×33 \times 3 Matrices

  • Definition of a 2×22 \times 2 Determinant   - Recalling from the previous unit, the determinant of a 2×22 \times 2 matrix is defined as follows:   - Given a matrix with components u1u_1, u2u_2 in the first row and v1v_1, v2v_2 in the second row, the determinant is represented as: det(u1amp;u2 v1amp;v2)=u1v2u2v1det \begin{pmatrix} u_1 & u_2 \ v_1 & v_2 \end{pmatrix} = u_1 v_2 - u_2 v_1
  • Expansion of a 3×33 \times 3 Determinant   - A 3×33 \times 3 determinant can be defined in terms of contributing 2×22 \times 2 determinants through the following expansion rule:   - det(u1amp;u2amp;u3 v1amp;v2amp;v3 w1amp;w2amp;w3)=u1v2amp;v3 w2amp;w3u2v1amp;v3 w1amp;w3+u3v1amp;v2 w1amp;w2det \begin{pmatrix} u_1 & u_2 & u_3 \ v_1 & v_2 & v_3 \ w_1 & w_2 & w_3 \end{pmatrix} = u_1 \begin{vmatrix} v_2 & v_3 \ w_2 & w_3 \end{vmatrix} - u_2 \begin{vmatrix} v_1 & v_3 \ w_1 & w_3 \end{vmatrix} + u_3 \begin{vmatrix} v_1 & v_2 \ w_1 & w_2 \end{vmatrix}
  • Structural Observations in Expansion   - Each term on the right side of the above equation involves a number from the first row of the determinant (u1u_1, u2u_2, or u3u_3).   - Any specific number uiu_i is multiplied by a 2×22 \times 2 determinant.   - This 2×22 \times 2 determinant is obtained by deleting the specific row and column in which the multiplier uiu_i appears.

Definition of the Standard Basis Vectors and Vector components

  • Standard Basis Vectors   - The cross product is defined in conjunction with the standard basis vectors for three-dimensional space:     - i=(1,0,0)i = (1, 0, 0)     - j=(0,1,0)j = (0, 1, 0)     - k=(0,0,1)k = (0, 0, 1)
  • Vector Representation   - These basis vectors allow we to represent vectors uu and vv as linear combinations:     - u=u1i+u2j+u3ku = u_1 i + u_2 j + u_3 k     - v=v1i+v2j+v3kv = v_1 i + v_2 j + v_3 k

The Cross Product of Two Vectors

  • Determinant Form of the Cross Product   - The cross product of vectors uu and vv, denoted as u×vu \times v, is defined using the following determinant structure, where the first row consists of the basis vectors ii, jj, and kk:   - u×v=iamp;jamp;k u1amp;u2amp;u3 v1amp;v2amp;v3u \times v = \begin{vmatrix} i & j & k \ u_1 & u_2 & u_3 \ v_1 & v_2 & v_3 \end{vmatrix}
  • Sub-Determinant Expansion of the Cross Product   - Expanding this determinant yields the following expression in terms of 2×22 \times 2 determinants:   - u×v=u2amp;u3 v2amp;v3iu1amp;u3 v1amp;v3j+u1amp;u2 v1amp;v2ku \times v = \begin{vmatrix} u_2 & u_3 \ v_2 & v_3 \end{vmatrix} i - \begin{vmatrix} u_1 & u_3 \ v_1 & v_3 \end{vmatrix} j + \begin{vmatrix} u_1 & u_2 \ v_1 & v_2 \end{vmatrix} k
  • Component-Wise Formula   - Performing the arithmetic for the 2×22 \times 2 determinants results in the final cross product formula:   - u×v=(u2v3u3v2)i(u1v3u3v1)j+(u1v2u2v1)ku \times v = (u_2 v_3 - u_3 v_2) i - (u_1 v_3 - u_3 v_1) j + (u_1 v_2 - u_2 v_1) k

Geometric Interpretation and Spatial Context

  • Orthogonality   - The result of the cross product, the vector u×vu \times v, is defined as a vector that is at right angles (orthogonal) to both original vectors uu and vv.
  • Dimensionality   - It is explicitly noted that the operation of the cross product happens exclusively within the three-dimensions (3D space).