Comprehensive Guide to Summations, Aggregations, and Symmetric Polynomial Systems

Foundations of Discrete Summations

  • Fundamental Definition and Analogy to Integration:

    • Summations represent the discrete counterparts of continuous integrals.
    • Given a sequence of terms xa,xa+1,…,xbx_a, x_{a+1}, \dots, x_b, the sum xa+xa+1+⋯+xbx_a + x_{a+1} + \dots + x_b is represented compactly in summation notation as ∑i=abxi\sum_{i=a}^b x_i.
    • The large jagged summation symbol ∑\sum is an enlarged version of the uppercase Greek letter sigma.
    • The notation designates ii as the index of summation, aa as the lower limit or lower bound, and bb as the upper limit or upper bound.
    • Conceptually, summation notation functions identically to a programming for loop, iterating through all integer values of the index variable from the lower bound aa up to the upper bound bb inclusive, evaluating and adding the body expression for each iteration.
  • Empty Sum Convention:

    • If the upper limit is strictly less than the lower limit (b<ab < a), the summation is defined to evaluate to zero (00).
    • Example demonstrating the empty sum rule:     ∑i=0−52isin⁡(i)i3=0\sum_{i=0}^{-5} \frac{2^i \sin(i)}{i^3} = 0
    • This boundary convention ensures that general summation identities remain mathematically consistent at boundary extremes. For instance, the identity for the sum of the first nn positive integers:     ∑i=1ni=n(n+1)2\sum_{i=1}^n i = \frac{n(n + 1)}{2}     remains valid when n=0n = 0 (evaluating to 00) and when n=−1n = -1 (evaluating to 00), though it fails when n=−2n = -2.
  • Purpose and Expressive Power:

    • Summation notation provides compactness (laziness), replacing verbose expansions such as 1+3+5+7+⋯+(2n+1)1 + 3 + 5 + 7 + \dots + (2n + 1) with the concise expression ∑i=0n(2i+1)\sum_{i=0}^n (2i + 1).
    • It guarantees mathematical precision by explicitly defining the general ii-th term and exact index boundaries.
  • Formal Recursive Definitions for Finite Sums:

    • Finite summations are formally defined through recurrence relations in two equivalent ways:
    • Recurrence from the left (stripping the initial term):∑i=abf(i)={0if b<af(a)+∑i=a+1bf(i)otherwise\sum_{i=a}^b f(i) = \begin{cases} 0 & \text{if } b < a \\ f(a) + \sum_{i=a+1}^b f(i) & \text{otherwise} \end{cases}
    • Recurrence from the right (stripping the trailing term):∑i=abf(i)={0if b<af(b)+∑i=ab−1f(i)otherwise\sum_{i=a}^b f(i) = \begin{cases} 0 & \text{if } b < a \\ f(b) + \sum_{i=a}^{b-1} f(i) & \text{otherwise} \end{cases}
    • Computationally, these formulations correspond to isolating either the first or last term of the sequence and recursively computing the sum of the remaining n−1n - 1 terms.

Index Variables, Scoping, and Index Sets

  • Variable Selection and Index Shifting:

    • Common index variable choices include ii, jj, and kk.
    • To avoid semantic ambiguity, index variables should not collide with variables defined outside the scope of the summation. While the expression ∑n=0nn=∑i=0ni\sum_{n=0}^n n = \sum_{i=0}^n i possesses a formally well-defined meaning, the version using the distinct variable ii avoids confusion.
    • Indices can be systematically shifted provided the bounds are adjusted accordingly. For instance, letting j=i−1j = i - 1 enables rewriting:     ∑i=1n(i−1)=∑j=0n−1j\sum_{i=1}^n (i - 1) = \sum_{j=0}^{n-1} j
  • Syntactic Scope of the Summation Operator:

    • The scope of a summation extends to the first addition (++) or subtraction (−-) symbol that is not enclosed within parentheses or embedded inside a larger algebraic construct (such as the numerator of a fraction).
    • Scope precedence behavior:     ∑i=1ni2+1=(∑i=1ni2)+1=1+∑i=1ni2≠∑i=1n(i2+1)\sum_{i=1}^n i^2 + 1 = \left(\sum_{i=1}^n i^2\right) + 1 = 1 + \sum_{i=1}^n i^2 \neq \sum_{i=1}^n (i^2 + 1)
    • To avoid ambiguity, the body of the summation should be wrapped in parentheses or trailing constants should be positioned before the sigma symbol.
    • When adding multiple summations, the boundary between terms is visually unambiguous because the second sigma clearly signals the termination of the first sum:     ∑i=1ni2+∑i=1n2i=(∑i=1ni2)+(∑i=1n2i)\sum_{i=1}^n i^2 + \sum_{i=1}^{n^2} i = \left(\sum_{i=1}^n i^2\right) + \left(\sum_{i=1}^{n^2} i\right)
  • Summations Over Arbitrary Sets and Predicates:

    • Summations can iterate over non-consecutive integers, non-integer values, or abstract mathematical structures by specifying a set membership condition or a logical predicate beneath the sigma symbol.
    • Sum over a discrete set of integers:∑i∈{3,5,7}i2=32+52+72=9+25+49=83\sum_{i \in \{3, 5, 7\}} i^2 = 3^2 + 5^2 + 7^2 = 9 + 25 + 49 = 83
    • Sum over the cardinality of all subsets of a given set SS:∑A⊆S∣A∣\sum_{A \subseteq S} |A|
    • Sum over prime numbers bounded by an upper limit:∑p<1000, p is prime1p\sum_{p < 1000,\, p \text{ is prime}} \frac{1}{p}
    • By convention, a variable is treated as an index of summation if it possesses no predefined meaning outside the scope of the sum, and index variables appear first within the subscript predicate.
    • Sum over strictly ordered index pairs:∑1≤i<j≤nij\sum_{1 \le i < j \le n} i j     (evaluates the product iji j over every unique unordered pair of integers between 11 and nn, each appearing exactly once).
    • Sum over subsets conditioned on element membership:∑x∈A⊆S∣A∣\sum_{x \in A \subseteq S} |A|     (sums the cardinality of all subsets AA of SS that contain the specific element xx, assuming xx and SS are defined externally).
  • Formal Well-Definedness over Finite and Infinite Sets:

    • Summations over an arbitrary set SS are guaranteed to be well-defined if SS is finite. Because a bijection f:{0,…,n−1}↔Sf : \{0, \dots, n-1\} \leftrightarrow S always exists for a finite set of size ∣S∣=n|S| = n, the sum can be mapped to standard integer bounds:     ∑i∈Sxi=∑i=0n−1xf(i)\sum_{i \in S} x_i = \sum_{i=0}^{n-1} x_{f(i)}
    • For a countably infinite set SS, a bijection f:N↔Sf : \mathbb{N} \leftrightarrow S allows expressing the sum as a limit:     ∑i∈Sxi=∑i=0∞xf(i)\sum_{i \in S} x_i = \sum_{i=0}^\infty x_{f(i)}
    • If the terms xix_i have varying signs (positive and negative), the resulting value can vary depending on the chosen bijection ff (conditional convergence). Consequently, summations over infinite index sets must be avoided unless the natural numbers N\mathbb{N} serve as the explicit, ordered index set.
  • Sums Without Explicit Bounds and Summation Conventions:

    • When the range of an index is evident from context, limits are frequently dropped entirely, leaving only the index under the operator: ∑ii2\sum_i i^2.
    • Theoretical physics utilizes the Einstein summation convention, omitting the sigma symbol entirely in specific index contexts.

Infinite and Multidimensional Summations

  • Rigorous Definition of Infinite Series:

    • An infinite summation, such as:     ∑i=0∞1i2\sum_{i=0}^\infty \frac{1}{i^2}     is defined as the limit of the sequence of partial sums sns_n, where each sns_n represents the sum of the first nn terms.
    • Formally, the series converges to a value xx if for every real ϵ>0\epsilon > 0, there exists an integer NN such that for all n>Nn > N:     ∣sn−x∣<ϵ|s_n - x| < \epsilon
  • Double and Multiple Summations:

    • Summations can be nested, corresponding directly to nested loops in computer programming.
    • Non-negative integer multiplication defined via nested summations:     a×b=def∑i=1a∑j=1b1a \times b \stackrel{\text{def}}{=} \sum_{i=1}^a \sum_{j=1}^b 1
    • Nested summations where the inner limit depends on the outer summation index:     ∑i=0n∑j=0i(i+1)(j+1)\sum_{i=0}^n \sum_{j=0}^i (i + 1)(j + 1)
    • Evaluating this expression for the base case n=1n = 1:     (0+1)(0+1)+(1+1)(0+1)+(1+1)(1+1)=(1)(1)+(2)(1)+(2)(2)=1+2+4=7(0 + 1)(0 + 1) + (1 + 1)(0 + 1) + (1 + 1)(1 + 1) = (1)(1) + (2)(1) + (2)(2) = 1 + 2 + 4 = 7

Standard Summation Formulas and Algebraic Identities

  • Core Standard Closed-Form Formulas:

    • Sum of constants:∑i=1n1=n\sum_{i=1}^n 1 = n
    • Sum of the first nn integers (arithmetic series):∑i=1ni=n(n+1)2\sum_{i=1}^n i = \frac{n(n + 1)}{2}
    • Finite geometric series:∑i=0nri=1−rn+11−r\sum_{i=0}^n r^i = \frac{1 - r^{n+1}}{1 - r}     (valid for all r≠1r \neq 1; when r=1r = 1, the formula yields the indeterminate form 0/00/0, but the sum reduces directly to the constant series ∑i=0n1=n+1\sum_{i=0}^n 1 = n + 1).
  • Derivations of Standard Formulas:

    • Rigorous formal proofs for these identities proceed by mathematical induction on nn.
    • Gauss's bidirectional pairing trick for arithmetic series:     Write the sum SS forward and backward, then sum the two equations vertically term by term:     S=1+2+3+⋯+nS = 1 + 2 + 3 + \dots + nS=n+(n−1)+(n−2)+⋯+1S = n + (n-1) + (n-2) + \dots + 12S=(n+1)+(n+1)+(n+1)+⋯+(n+1)=n(n+1)2S = (n + 1) + (n + 1) + (n + 1) + \dots + (n + 1) = n(n + 1)     Dividing both sides by 22 produces the closed form:     S=n(n+1)2S = \frac{n(n + 1)}{2}
    • Infinite and finite geometric series derivation:     For an infinite geometric series with ratio ∣r∣<1|r| < 1:     S=∑i=0∞riS = \sum_{i=0}^\infty r^i     Multiplying by rr yields:     rS=∑i=0∞ri+1=∑i=1∞rirS = \sum_{i=0}^\infty r^{i+1} = \sum_{i=1}^\infty r^i     Subtracting rSrS from SS isolates the initial term:     S−rS=r0=1S - rS = r^0 = 1S(1−r)=1  ⟹  S=11−rS(1 - r) = 1 \implies S = \frac{1}{1 - r}     The finite sum up to nn is obtained by subtracting the truncated tail starting at rn+1r^{n+1}:     ∑i=0nri=∑i=0∞ri−rn+1∑i=0∞ri=11−r−rn+11−r=1−rn+11−r\sum_{i=0}^n r^i = \sum_{i=0}^\infty r^i - r^{n+1} \sum_{i=0}^\infty r^i = \frac{1}{1 - r} - \frac{r^{n+1}}{1 - r} = \frac{1 - r^{n+1}}{1 - r}     This resulting finite identity holds algebraically for all values of r≠1r \neq 1, including r>1r > 1.
    • Comprehensive summation references include textbooks by Rosen and Graham, Knuth, and Patashnik (Concrete Mathematics), particularly in discussions on generating functions.
  • Linearity and Structural Manipulation Identities:

    • Factoring out constants (homogeneity):∑i∈Saxi=a∑i∈Sxi\sum_{i \in S} a x_i = a \sum_{i \in S} x_i
    • Distributing over addition (additivity):∑i∈S(xi+yi)=∑i∈Sxi+∑i∈Syi\sum_{i \in S} (x_i + y_i) = \sum_{i \in S} x_i + \sum_{i \in S} y_i
    • Order exchange in multiple summations:     When the bounds of the inner summation are independent of the outer index, the summation order can be swapped:     ∑i∈S∑j∈Txij=∑j∈T∑i∈Sxij\sum_{i \in S} \sum_{j \in T} x_{ij} = \sum_{j \in T} \sum_{i \in S} x_{ij}
    • Product of independent single sums:     The product of two independent sums transforms into a double summation of term-wise products:     (∑i∈Sxi)(∑j∈Tyj)=∑i∈S∑j∈Txiyj\left(\sum_{i \in S} x_i\right) \left(\sum_{j \in T} y_j\right) = \sum_{i \in S} \sum_{j \in T} x_i y_j

Verification and Asymptotic Estimation Strategies

  • The Guess-and-Verify Method:

    • When analytical transformations are non-obvious, write out initial values for small bounds to deduce a pattern, then formally verify via induction.
    • Example problem:S(n)=∑k=1n(2k−1)S(n) = \sum_{k=1}^n (2k - 1)
    • Construct a table of values:
    • For n=0n = 0: S(0)=0S(0) = 0
    • For n=1n = 1: S(1)=1S(1) = 1
    • For n=2n = 2: S(2)=1+3=4S(2) = 1 + 3 = 4
    • For n=3n = 3: S(3)=1+3+5=9S(3) = 1 + 3 + 5 = 9
    • For n=4n = 4: S(4)=1+3+5+7=16S(4) = 1 + 3 + 5 + 7 = 16
    • For n=5n = 5: S(5)=1+3+5+7+9=25S(5) = 1 + 3 + 5 + 7 + 9 = 25
    • Identify the pattern: S(n)=n2S(n) = n^2.
    • Inductive verification:
    • Base case: holds for n=0n = 0 since 02=00^2 = 0.
    • Inductive step: assuming S(n−1)=(n−1)2S(n-1) = (n-1)^2:       S(n)=S(n−1)+(2n−1)=(n−1)2+2n−1=n2−2n+1+2n−1=n2S(n) = S(n-1) + (2n - 1) = (n - 1)^2 + 2n - 1 = n^2 - 2n + 1 + 2n - 1 = n^2
    • The closed form S(n)=n2S(n) = n^2 is verified.
  • Strategies for Asymptotic Bounding in Algorithm Analysis:

    • Algorithm analysis generally requires asymptotic behavior (Θ\Theta, OO, Ω\Omega) rather than closed-form expressions.
    • Strategy 1: Pull out constant factors:     Factor out all quantities independent of the index:     ∑i=1nni=n∑i=1n1i=nHn=Θ(nlog⁡(n))\sum_{i=1}^n \frac{n}{i} = n \sum_{i=1}^n \frac{1}{i} = n H_n = \Theta(n \log(n))
    • Strategy 2: Bound using known benchmark series:
    • Geometric series:∑i=0nxi=1−xn+11−x\sum_{i=0}^n x^i = \frac{1 - x^{n+1}}{1 - x}∑i=0∞xi=11−x\sum_{i=0}^\infty x^i = \frac{1}{1 - x}       Characterized by a constant ratio between adjacent terms. When the base xx is a constant not equal to 11, the entire sum is big-Theta of its largest term:       ∑i=1n2i=Θ(2n)\sum_{i=1}^n 2^i = \Theta(2^n)       (exact value: 2n+1−22^{n+1} - 2).       ∑i=1n2−i=Θ(1)\sum_{i=1}^n 2^{-i} = \Theta(1)       (exact value: 1−2−n1 - 2^{-n}). This dominance property forms the theoretical basis of the Master Theorem for solving recurrences.
    • Constant series:∑i=1n1=n\sum_{i=1}^n 1 = n
    • Arithmetic series:       Base form:       ∑i=1ni=n(n+1)2=n(n+12)\sum_{i=1}^n i = \frac{n(n + 1)}{2} = n \left(\frac{n + 1}{2}\right)       (represented conceptually as the number of terms times their average value). Characterized by a constant difference between adjacent terms. General form:       ∑i=1n(ai+b)=a∑i=1ni+∑i=1nb=an(n+1)2+bn\sum_{i=1}^n (ai + b) = a \sum_{i=1}^n i + \sum_{i=1}^n b = a \frac{n(n + 1)}{2} + bn
    • Harmonic series:∑i=1n1i=Hn=Θ(nlog⁡(n))\sum_{i=1}^n \frac{1}{i} = H_n = \Theta(n \log(n))       (the nn-th harmonic number).
    • Strategy 3: Bound a portion of the sum:     Isolate the upper half of the terms to obtain tight asymptotic bounds without full evaluation. For ∑i=1ni3\sum_{i=1}^n i^3:     ∑i=1ni3≤∑i=1nn3=n⋅n3=O(n4)\sum_{i=1}^n i^3 \le \sum_{i=1}^n n^3 = n \cdot n^3 = O(n^4)∑i=1ni3≥∑i=n/2ni3≥∑i=n/2n(n2)3=(n2)(n38)=n416=Ω(n4)\sum_{i=1}^n i^3 \ge \sum_{i=n/2}^n i^3 \ge \sum_{i=n/2}^n \left(\frac{n}{2}\right)^3 = \left(\frac{n}{2}\right) \left(\frac{n^3}{8}\right) = \frac{n^4}{16} = \Omega(n^4)     Matching bounds establish that the sum is Θ(n4)\Theta(n^4).
    • Strategy 4: Integral bounding:     If f(x)f(x) is a non-decreasing function, the summation is bounded above and below by continuous integrals:     ∫a−1bf(x) dx≤∑i=abf(i)≤∫ab+1f(x) dx\int_{a-1}^b f(x)\,dx \le \sum_{i=a}^b f(i) \le \int_a^{b+1} f(x)\,dx     This provides tight Θ\Theta-bounds for nearly all monotonic functions encountered in algorithm analysis.
    • Strategy 5: Grouping terms:     Demonstrating that the harmonic series diverges to infinity by grouping terms into successive powers of two:     1+12+13+14+15+16+17+18+⋯≥1+12+(14+14)+(18+18+18+18)+…1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} + \frac{1}{7} + \frac{1}{8} + \dots \ge 1 + \frac{1}{2} + \left(\frac{1}{4} + \frac{1}{4}\right) + \left(\frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8}\right) + \dots=1+12+12+12+⋯=∞= 1 + \frac{1}{2} + \frac{1}{2} + \frac{1}{2} + \dots = \infty
    • Strategy 6: Handling mixed polynomial-exponential sums:     The summation ∑i=1naii\sum_{i=1}^n a^i i exhibits three distinct behaviors depending on the parameter aa:
    • If a<1a < 1: The sum converges to a constant upper bound, evaluating to Θ(1)\Theta(1). The infinite series closed-form is:       ∑i=1∞aii=a(1−a)2\sum_{i=1}^\infty a^i i = \frac{a}{(1 - a)^2}
    • If a=1a = 1: The expression reduces to a standard arithmetic series, evaluating to Θ(n2)\Theta(n^2).
    • If a>1a > 1: The largest term dominates, yielding Θ(ann)\Theta(a^n n). To prove the upper bound O(ann)O(a^n n), rewrite using decreasing powers and bound by a geometric series:       ∑i=0n−1an−i(n−i)≤∑i=0n−1an−in≤ann1−a−1=O(ann)\sum_{i=0}^{n-1} a^{n-i} (n - i) \le \sum_{i=0}^{n-1} a^{n-i} n \le \frac{a^n n}{1 - a^{-1}} = O(a^n n)
    • General Algorithmic Rules of Thumb:
    • For exponential bodies f(n)f(n), the summation is bounded by a geometric series and dominated by its largest term.
    • For polynomial bodies f(n)f(n), where f(n/2)=Θ(f(n))f(n/2) = \Theta(f(n)), the summation evaluates to Θ(nf(n))\Theta(n f(n)), established by the lower bound ∑i=n/2nf(n)=Ω(nf(n))\sum_{i=n/2}^n f(n) = \Omega(n f(n)).

Product Notation and Identity Elements

  • Product Notation (Capital Pi):

    • Multiplicative sequences are written using capital Greek letter pi (∏\prod), adhering to the same indexing conventions, limits, and set bounds as summation notation.
    • Factorial definition for non-negative integers nn:n!=def∏i=1ni=1⋅2⋅⋯⋅nn! \stackrel{\text{def}}{=} \prod_{i=1}^n i = 1 \cdot 2 \cdot \dots \cdot n
  • Identity Elements for Empty Aggregations:

    • An empty sum evaluates to 00, the additive identity (x+0=xx + 0 = x).
    • An empty product evaluates to 11, the multiplicative identity (x⋅1=xx \cdot 1 = x).
    • This algebraic distinction ensures that generalized partitioning rules over disjoint sets (A∩B=∅A \cap B = \emptyset) hold unconditionally:     ∑i∈Af(i)+∑i∈Bf(i)=∑i∈A∪Bf(i)\sum_{i \in A} f(i) + \sum_{i \in B} f(i) = \sum_{i \in A \cup B} f(i)(∏i∈Af(i))⋅(∏i∈Bf(i))=∏i∈A∪Bf(i)\left(\prod_{i \in A} f(i)\right) \cdot \left(\prod_{i \in B} f(i)\right) = \prod_{i \in A \cup B} f(i)
    • If empty collections did not evaluate to their operational identities, separate special-case rules would be required whenever A=∅A = \emptyset or B=∅B = \emptyset.
    • A direct consequence of this convention is the standard mathematical identity:     0!=10! = 1

Aggregate Operators and Index Set Conventions

  • Generalized Large Operators:
    • Big AND (universal quantification over sets):⋀x∈SP(x)≡P(x1)∧P(x2)∧⋯≡∀x∈S:P(x)\bigwedge_{x \in S} P(x) \equiv P(x_1) \land P(x_2) \land \dots \equiv \forall x \in S : P(x)     When evaluated over an empty index set (S=∅S = \emptyset), Big AND yields True (the identity element for logical conjunction).
    • Big OR (existential quantification over sets):⋁x∈SP(x)≡P(x1)∨P(x2)∨⋯≡∃x∈S:P(x)\bigvee_{x \in S} P(x) \equiv P(x_1) \lor P(x_2) \lor \dots \equiv \exists x \in S : P(x)     When evaluated over an empty index set (S=∅S = \emptyset), Big OR yields False (the identity element for logical disjunction).
    • Big Intersection:⋂i=1nAi=A1∩A2∩⋯∩An\bigcap_{i=1}^n A_i = A_1 \cap A_2 \cap \dots \cap A_n     An intersection over an empty collection of sets has no universal identity element within general set theory and is undefined.
    • Big Union:⋃i=1nAi=A1∪A2∪⋯∪An\bigcup_{i=1}^n A_i = A_1 \cup A_2 \cup \dots \cup A_n     When evaluated over an empty collection of sets, Big Union yields the empty set ∅\emptyset (the identity element for set union).

Symmetric Polynomials and Power Sum Systems

System of symmetric polynomial equations

  • System Specification:

    • Consider the system of power sums in three variables aa, bb, and cc:     a+b+c=4a + b + c = 4a2+b2+c2=10a^2 + b^2 + c^2 = 10a3+b3+c3=22a^3 + b^3 + c^3 = 22a4+b4+c4=?a^4 + b^4 + c^4 = ?
  • Formal Definitions of Symmetric Functions:

    • Let pkp_k denote the kk-th power sum symmetric polynomial:     pk=ak+bk+ckp_k = a^k + b^k + c^k     with given values p1=4p_1 = 4, p2=10p_2 = 10, and p3=22p_3 = 22.
    • Let eke_k denote the elementary symmetric polynomials in variables a,b,ca, b, c:     e1=a+b+ce_1 = a + b + ce2=ab+bc+cae_2 = ab + bc + cae3=abce_3 = abc
  • Newton's Sums (Newton-Girard Identities):

    • For monic polynomials with roots a,b,ca, b, c, the power sums pkp_k and elementary symmetric polynomials eke_k are related by the recurrence:     pk−e1pk−1+e2pk−2−e3pk−3+⋯+(−1)kkek=0p_k - e_1 p_{k-1} + e_2 p_{k-2} - e_3 p_{k-3} + \dots + (-1)^k k e_k = 0
    • Specifically, for degree n=3n = 3:
    • For k=1k = 1:       p1−e1=0  ⟹  e1=p1=4p_1 - e_1 = 0 \implies e_1 = p_1 = 4
    • For k=2k = 2:       p2−e1p1+2e2=0p_2 - e_1 p_1 + 2e_2 = 0
    • For k=3k = 3:       p3−e1p2+e2p1−3e3=0p_3 - e_1 p_2 + e_2 p_1 - 3e_3 = 0
    • For k≥4k \ge 4:       pk−e1pk−1+e2pk−2−e3pk−3=0p_k - e_1 p_{k-1} + e_2 p_{k-2} - e_3 p_{k-3} = 0
  • Step-by-Step Derivation of the Quartic Power Sum:

    • Step 1: Compute e2e_2 using the k=2k = 2 identity:p2−e1p1+2e2=0p_2 - e_1 p_1 + 2e_2 = 010−(4)(4)+2e2=010 - (4)(4) + 2e_2 = 010−16+2e2=010 - 16 + 2e_2 = 0−6+2e2=0  ⟹  2e2=6  ⟹  e2=3-6 + 2e_2 = 0 \implies 2e_2 = 6 \implies e_2 = 3
    • Step 2: Compute e3e_3 using the k=3k = 3 identity:p3−e1p2+e2p1−3e3=0p_3 - e_1 p_2 + e_2 p_1 - 3e_3 = 022−(4)(10)+(3)(4)−3e3=022 - (4)(10) + (3)(4) - 3e_3 = 022−40+12−3e3=022 - 40 + 12 - 3e_3 = 0−6−3e3=0  ⟹  3e3=−6  ⟹  e3=−2-6 - 3e_3 = 0 \implies 3e_3 = -6 \implies e_3 = -2
    • Step 3: Evaluate p4=a4+b4+c4p_4 = a^4 + b^4 + c^4 using the k=4k = 4 recurrence:p4−e1p3+e2p2−e3p1=0p_4 - e_1 p_3 + e_2 p_2 - e_3 p_1 = 0p4−(4)(22)+(3)(10)−(−2)(4)=0p_4 - (4)(22) + (3)(10) - (-2)(4) = 0p4−88+30+8=0p_4 - 88 + 30 + 8 = 0p4−50=0p_4 - 50 = 0p4=50p_4 = 50
    • The value of the fourth power sum is a4+b4+c4=50a^4 + b^4 + c^4 = 50.