Electric Current & DC Circuit Summary

Attention-Grabbers & Context

  • “ELECTRIFYING!!!, SHOCKING BUT TRUE!!!!, You will be ex-static!” – motivational phrases used to introduce the topic and signal excitement in Physics 11 (Mr. Stephenson, 2019).
  • Focus: Direct-current (DC) electricity, its physical basis, and quantitative laws used for circuit analysis.

Fundamental Law of Electric Charges

  • Key postulates:
    • Opposite charges attract; like charges repel.
    • Charged objects may attract neutral objects (polarization effects).
  • Elementary charges:
    • Electron charge: qe=1.6×1019Cq_e=-1.6\times10^{-19}\,\text{C}
    • Proton charge: qp=+1.6×1019Cq_p=+1.6\times10^{-19}\,\text{C}
    • Neutron: qn=0q_n = 0
  • All matter comprises protons, neutrons, electrons.
  • Coulomb (C) = unit of electric charge.

Voltage (Electric Potential Difference)

  • A battery’s internal chemical reaction separates charge, creating positive & negative terminals.
  • Definition: Voltage (V) = electric potential energy per unit charge.
    • V=EpotentialQV = \dfrac{E_{\text{potential}}}{Q}
    • Unit: volt (V); 1V=1J/C1\,\text{V}=1\,\text{J}/\text{C}
  • Provides electrons in the external circuit with electric potential energy that can be converted to other forms by loads.

Electric Current

  • Two conventions:
    • Conventional current: flow of positive charge from + to –.
    • Electron flow (the physical reality): electrons move from – to +.
  • Definition: I=QtI = \dfrac{Q}{t}
    • Unit: ampere (A); 1A=1C/s1\,\text{A}=1\,\text{C}/\text{s}
  • Charge–electron conversion example:
    • Number of electrons in 1C-1\,\text{C}:
      1C1.6×1019C/e¯6.2×1018electrons\dfrac{-1\,\text{C}}{-1.6\times10^{-19}\,\text{C/e¯}} \approx 6.2\times10^{18}\,\text{electrons}

Resistance (R)

  • Opposes the flow of electric charge; arises from collisions between charge carriers and lattice atoms.
  • Consequences: charges lose electric potential energy → thermal energy, light, etc.
  • Unit: ohm (Ω).
  • Physical examples: light-bulb filament, stove heating element; commercial resistors with color-code bands.

Ohm’s Law

  • Relationship between voltage, current, resistance:
    • V=IRV = IR
    • Linear for ohmic materials; slope in an I–V graph equals resistance.

Worked Examples (Ohm’s Law)

  • Light bulb, R=20Ω,  V=5.0VR=20\,\Omega,\;V=5.0\,\text{V}:
    • I=VR=5.020=0.25AI = \dfrac{V}{R} = \dfrac{5.0}{20}=0.25\,\text{A}
  • Motor, R=75Ω,  V=12VR=75\,\Omega,\;V=12\,\text{V}:
    • I=1275=0.16AI = \dfrac{12}{75}=0.16\,\text{A}
  • Unknown battery voltage, I=0.80A,  R=25ΩI=0.80\,\text{A},\;R=25\,\Omega:
    • V=IR=0.80×25=20VV = IR =0.80\times25 = 20\,\text{V}

Standard Circuit Symbols (Table 3.1 excerpts)

  • Cell: long line = +, short line = – ; represents a source of electric potential.
  • Battery: several cells in series.
  • Conducting wire: straight line.
  • Load/Resistor: zig-zag line (R, Ω).
  • Switch (open/closed): break or continuous line with pivot.
  • Voltmeter: circle with V (measures VV).
  • Ammeter: circle with A (measures II).

Types of Circuits

Series Circuits
  • Single path for current.
  • Laws:
    • Current: I<em>S=I</em>1=I<em>2=I</em>3I<em>S = I</em>1 = I<em>2 = I</em>3 (same everywhere).
    • Voltage: V<em>S=V</em>1+V<em>2+V</em>3V<em>S = V</em>1 + V<em>2 + V</em>3.
    • Equivalent resistance: R<em>T=R</em>1+R<em>2+R</em>3R<em>T = R</em>1+R<em>2+R</em>3.
    • Overall: I<em>S=V</em>SRTI<em>S = \dfrac{V</em>S}{R_T}.
Parallel Circuits
  • Two or more independent paths; current splits at junctions.
  • Laws:
    • Voltage: V<em>S=V</em>1=V<em>2=V</em>3V<em>S = V</em>1 = V<em>2 = V</em>3 (same across each branch).
    • Current: I<em>S=I</em>1+I<em>2+I</em>3I<em>S = I</em>1 + I<em>2 + I</em>3.
    • Equivalent resistance: 1R<em>P=1R</em>1+1R<em>2+1R</em>3\dfrac{1}{R<em>P}=\dfrac{1}{R</em>1}+\dfrac{1}{R<em>2}+\dfrac{1}{R</em>3}.
    • Overall: I<em>S=V</em>SRPI<em>S = \dfrac{V</em>S}{R_P}.
Combination (Series–Parallel)
  • Real-world circuits often mix both configurations; analyze by reducing step-wise to a single equivalent resistance.

Kirchhoff’s Laws (Advanced Circuit Analysis)

  • Kirchhoff’s Current Law (KCL):
    • At any junction, I<em>in=I</em>out\sum I<em>{\text{in}} = \sum I</em>{\text{out}}.
  • Kirchhoff’s Voltage Law (KVL):
    • For any closed loop, (ΔV)=0\sum (\Delta V) = 0 (sum of rises and drops is zero).
  • Together with Ohm’s law and series/parallel RR rules, allow complete solution of complex circuits.

Effects of Adding Loads & Safety Considerations

  • Adding resistors in parallel ↓ RTR_T → ↑ total current.
  • Excessive current risks:
    • Device damage, wire overheating, fire.
    • Mitigation: fuses & circuit breakers (open the circuit if current exceeds a preset threshold).
  • Short circuit = unintended low-resistance path → very high II, causing shock & burns.

Electric Power

  • Definition: P=EtP = \dfrac{E}{t}.
  • Unit: watt (W); 1W=1J/s1\,\text{W}=1\,\text{J/s}.
  • Electrical expressions:
    • Basic: P=VIP = VI.
    • Substitutions via Ohm’s Law:
    • P=I2RP = I^2 R (replace VV).
    • P=V2RP = \dfrac{V^2}{R} (replace II).
  • Dimensional check: (J/C)×(C/s)=J/s=W(J/C)\times(C/s)=J/s=W.
Power Examples
  • 9 V battery, I=0.20AI=0.20\,\text{A}:
    • P=VI=9×0.20=1.8WP = VI = 9\times0.20 = 1.8\,\text{W}.
  • Wire loss, I=50A,  R=0.10ΩI=50\,\text{A},\;R=0.10\,\Omega:
    • P=I2R=(50)2×0.10=250WP = I^2R=(50)^2\times0.10 = 250\,\text{W}.

Electric Energy & Billing

  • Kilowatt-hour (kWh): energy used when P=1kWP=1\,\text{kW} for 1h1\,\text{h}.
    • 1kWh=1000W×3600s=3.6×106J1\,\text{kWh} = 1000\,\text{W}\times3600\,\text{s}=3.6\times10^{6}\,\text{J}.
  • Energy calculation: E=PtE = P t (convert units as needed).
  • Example: Hair-dryer P=1200W=1.2kWP=1200\,\text{W}=1.2\,\text{kW}, run 20 min = 13h\tfrac{1}{3}\,\text{h}.
    • E=1.2kW×13h=0.40kWhE = 1.2\,\text{kW}\times\tfrac{1}{3}\,\text{h}=0.40\,\text{kWh}.
    • Cost at 0.25$/kWh:0.40×0.25=$0.100.25\,\$/\text{kWh}: 0.40\times0.25=\$0.10.

Electromotive Force (emf), Internal Resistance & Terminal Voltage

  • emf (symbol ε\varepsilon or ξ\xi): open-circuit voltage of a source (no current drawn).
  • Real sources possess internal resistance rr.
  • When current II flows, internal drop IrI r lowers terminal voltage VabV_{ab}:
    • Vab=εIrV_{ab}=\varepsilon - I r.
  • Diagram conventions: positive terminal at higher potential; internal rr in series with ideal emf source.
emf Example (Page 22)
  • Given battery ε=12.0V\varepsilon = 12.0\,\text{V}, internal r=0.50Ωr=0.50\,\Omega, external load RL=10.0ΩR_L = 10.0\,\Omega (labeled 10.5 Ω total when including r):
    1. Total resistance: R<em>tot=R</em>L+r=10.0+0.50=10.5ΩR<em>{\text{tot}}=R</em>L + r = 10.0 + 0.50 = 10.5\,\Omega.
    2. Current: I=εRtot=12.010.5=1.14AI = \dfrac{\varepsilon}{R_{\text{tot}}} = \dfrac{12.0}{10.5}=1.14\,\text{A}.
    3. Terminal voltage: Vab=εIr=12.0(1.14)(0.50)=11.4VV_{ab}=\varepsilon - I r = 12.0 - (1.14)(0.50)=11.4\,\text{V}.

Practical & Ethical Considerations

  • Understanding circuit behavior is critical to safe household wiring, appliance design, and prevention of electrical hazards.
  • Engineers must weigh efficiency (minimizing I2RI^2 R losses) against safety and cost.
  • Awareness of internal resistance helps in battery selection for sensitive electronics.

Quick Reference: Key Equations

  • I=QtI = \dfrac{Q}{t}  V=IRV = IR  R<em>Tseries=R</em>iR<em>T^{\text{series}} = \sum R</em>i  1R<em>P=1R</em>i\dfrac{1}{R<em>P}=\sum \dfrac{1}{R</em>i}
  • P=VI=I2R=V2RP = VI = I^2 R = \dfrac{V^2}{R}  E=PtE = P t  Vab=εIrV_{ab}=\varepsilon - I r