Vector Equilibrium, Matrix Systems, and Desmos Matrix Solutions

Step-by-Step System of Equations and Vector Mechanics Setup

  • Initial Parameters and Vector Definitions:

    • Given tension magnitude value: TAC=826T_{AC} = 826

    • Vector ADAD coordinates and displacement values: 22, 11, 7474

    • Step-by-step vector construction process:

    • Determine the distance/dimension vector from spatial coordinates.

    • Calculate the scalar magnitude of the distance vector.

    • Divide the distance vector by its scalar magnitude to obtain the unit vector.

    • Multiply the unit vector by the scalar force variable to obtain the force vector expression.

  • Equilibrium Equations Formulation:

    • Standard equilibrium condition requires the sum of all vector components along each orthogonal axis to equal zero:

    • ∑Fi=0\sum F_i = 0

    • ∑Fj=0\sum F_j = 0

    • ∑Fk=0\sum F_k = 0

    • System algebraic organization rule:

    • All terms containing unknown variables (TABT_{AB}, TADT_{AD}, PP) remain on the left side of the equation.

    • All known constant numerical terms must be transposed to the right-hand side of the equal sign, reversing their algebraic signs.

    • Writing out this step explicitly on paper prevents sign errors during matrix conversion.

Summation of Vector Components

  • Summation of ii Components (∑Fi=0\sum F_i = 0):

    • Raw component equation:

    • −TAB(20105)+420−TAD(20126)=0-T_{AB} \left(\frac{20}{105}\right) + 420 - T_{AD} \left(\frac{20}{126}\right) = 0

    • Standard form with constant transposed to the right-hand side:

    • −TAB(20105)−TAD(20126)+0⋅P=−420-T_{AB} \left(\frac{20}{105}\right) - T_{AD} \left(\frac{20}{126}\right) + 0 \cdot P = -420

  • Summation of jj Components (∑Fj=0\sum F_j = 0):

    • Physical origin of key values:

    • The value 100100 originates directly from the jj component of the distance vector measurement.

    • Raw component equation:

    • −TAB(100105)−TAD(100126)+1⋅P−700=0-T_{AB} \left(\frac{100}{105}\right) - T_{AD} \left(\frac{100}{126}\right) + 1 \cdot P - 700 = 0

    • Standard form with constant transposed to the right-hand side:

    • −TAB(100105)−TAD(100126)+1⋅P=700-T_{AB} \left(\frac{100}{105}\right) - T_{AD} \left(\frac{100}{126}\right) + 1 \cdot P = 700

  • Summation of kk Components (∑Fk=0\sum F_k = 0):

    • Component terms:

    • Term for TABT_{AB}: 25105\frac{25}{105}

    • Term for TADT_{AD}: −74126-\frac{74}{126} (also recorded as −7426-\frac{74}{26})

    • Constant term: 127127 (transposed as −127-127)

    • Standard form with constant transposed to the right-hand side:

    • TAB(25105)−TAD(74126)+0⋅P=−127T_{AB} \left(\frac{25}{105}\right) - T_{AD} \left(\frac{74}{126}\right) + 0 \cdot P = -127

    • Writing out equations clearly prevents the board work from resembling a CVS receipt.

Matrix Formulation and Desmos Matrix Computation

  • Augmented Matrix Structure:

    • Column structure: Matrix columns correspond sequentially to variables TABT_{AB}, TADT_{AD}, PP, and the augmented right-hand side constant column.

    • Row 1 (ii-component coefficients):

    • TABT_{AB} coefficient: −20105-\frac{20}{105}

    • TADT_{AD} coefficient: −20126-\frac{20}{126}

    • PP coefficient: 00

    • Augmented constant value: −420-420

    • Row 2 (jj-component coefficients):

    • TABT_{AB} coefficient: −100105-\frac{100}{105}

    • TADT_{AD} coefficient: −100126-\frac{100}{126}

    • PP coefficient: 11

    • Augmented constant value: 700700

    • Row 3 (kk-component coefficients):

    • TABT_{AB} coefficient: 25105\frac{25}{105}

    • TADT_{AD} coefficient: −74126-\frac{74}{126}

    • PP coefficient: 00

    • Augmented constant value: −127-127 (entered into Desmos as −126-126)

  • Matrix Solution via Desmos Matrix Tool:

    • Hardware display setup: Use rear display controls configured to the left side to view Screen 2 across back screens.

    • Procedure: Apply Reduced Row Echelon Form (RREF\text{RREF}) to Matrix AA (RREF(A)\text{RREF}(A)).

    • Computed output vector values:

    • TAB=1514.55 NT_{AB} = 1514.55\,\text{N}

    • TAD=828.54 NT_{AD} = 828.54\,\text{N}

    • P=2800 NP = 2800\,\text{N}

    • Physical verification:

    • Force PP is positive (2800 N2800\,\text{N}), confirming that vector PP points vertically upward as originally indicated on the free body diagram.

Questions and Audience Interactions

  • Student seating and identity clarifications:

    • Gabriel: Identified correctly after initial confusion with Logan due to the letter L; sitting near Brandon and Vanessa.

    • Luciana: Seated directly in front of the second Brandon and Vanessa.

    • Julian: Seated adjacent to Gabriel.

  • Distance vector origins and conceptual verification:

    • Question posed to virtual student Anisa: Where did the number 100100 originally originate?

    • Student contribution by Diego: Confirmed that the value 100100 originates from the distance vector measurement corresponding to the jj component.

  • Equation manipulation dialogue:

    • Contribution by Brandon: Identified the step to transpose constant terms (420420) across the equals sign.

    • Correction by Doctor Nicky: Confirmed the constant becomes −420-420 inside the augmented matrix.

    • Contribution by Ryan: Recorded all equations on paper throughout the lecture, earning extra credit.

  • Online vs. In-Person attendance stance:

    • Nicholas Wood (Nick): Attending in-person on Wednesday, stating a personal preference: "I don't trust anything that has a transistor. I'm taking it in person."

Examination Strategy and Administrative Guidelines

  • Equipment and Software Preparation:

    • Ensure computers are fully updated and Desmos Matrix or chosen calculators are downloaded prior to taking exams online or in person.

    • Complete the posted online practice module specifically to verify equipment and software settings beforehand.

  • Written Work and Partial Credit Requirements:

    • Full credit on examinations requires writing out all intermediate steps, component summations, and matrix layouts.

    • Exam problems may be divided into multi-part prompts:

    • Part A: Writing out dimension/distance vectors (such as 6060, 100100, 1818) without calculating full unit vectors.

    • Part B: Formulating force vectors given tension data, summing ii, jj, and kk components, and writing out the full matrix prior to entering terms into a calculator.

  • Course Administration:

    • Section 3.1 Dropbox will be opened; several assignments have already been submitted.

    • Hard copies of pre-class quizzes will be provided following printing delays.