Question addressed: How do we know which species is oxidized or reduced? → Use reduction potentials.
Reduction Potentials (General)
Reduction potential (E)
Electrical potential (measured in volts, V) assigned to a half-reaction written as a reduction.
Specifies the intrinsic “tendency” of a species to gain electrons.
Reference electrode: Standard Hydrogen Electrode (SHE)
Conventional value: ESHE=0V
Interpretation of sign/magnitude
More positive Ered → stronger drive to be reduced.
Less positive (or negative) Ered → species is more easily oxidized (acts as anode in a galvanic cell).
Standard Conditions
All tabulated "standard" values assume:
Temperature: 25∘C(298K)
Pressure: 1atm
Concentrations: 1M for all aqueous species.
Choosing Anode vs. Cathode with Ered
Galvanic cell (spontaneous)
Electrode with more positiveEred → cathode
Electrode with less positiveEred → anode
Overall cell free energy: \Delta G < 0
Electrolytic cell (non-spontaneous, driven by external voltage)
External source forces the electrode with the more positive Ered to be oxidized → becomes anode.
Electrode with the less positive Ered is forced to be reduced → cathode.
\Delta G > 0
Converting Reduction ↔ Oxidation Potentials
Oxidation potential = negative of the reduction potential for the reverse reaction.
Reverse the half-reaction and change the sign.
Example (from transcript)
Reduction: Ti++e−→TiEred=−0.34V
Oxidation: Ti→Ti++e−Eox=+0.34V
MCAT & most tables supply only Ered; convert as needed.
Example 1 – Ag⁺ / Ti⁺ Half-Cells (Galvanic)
Given half-reactions (all as reductions):
Ag++e−→AgEred=+0.80V
Ti++e−→TiEred=−0.34V
Analysis
Ag⁺ has the more positive reduction potential → will be reduced (cathode).
Ti(s) will be oxidized to Ti+ (anode).
Net ionic equation (spontaneous): Ag++Ti(s)→Ti++Ag(s)
Electromotive Force (EMF)
Definition: Voltage difference between two half-cells under standard conditions.
Formula (standard): E<em>cell∘=E</em>red,cathode∘−Ered,anode∘
Do not multiply potentials by stoichiometric coefficients—potential depends on identity, not quantity, of species.
Example 2 – Sm³⁺ vs. RhCl63−
Given Ered values
Sm3++3e−→SmEred=−2.41V
RhCl<em>63−+3e−→Rh+6Cl−E</em>red=+0.44V
Half-reaction roles as written in transcript’s equation
Sm3+ is reduced.
Rh (within RhCl63− framework) is oxidized.
EMF calculation:
Ecell∘=(−2.41V)−(+0.44V)=−2.85V
Negative EMF → electrolytic under stated orientation.
Reversing the reaction (making it galvanic) would give +2.85V and proceed spontaneously in the opposite direction.
Practical & Conceptual Notes
Lead–acid and nickel–cadmium batteries (mentioned) employ the same sign conventions—tables usually list reduction potentials, even when oxidation half-reactions are discussed.
In calculations of ΔG for electrochemical cells:
ΔG∘=−nFEcell∘
n = moles of electrons transferred
F = Faraday constant ≈96,485Cmol−1
Ethical / safety implication: Knowing EMF and directionality guides safe battery charging/discharging and electrolysis operations.
Philosophical note: The arbitrary zero point (SHE) illustrates convention-driven measurement systems—absolute potentials aren’t measurable, only differences.