Reinforced and Prestressed Concrete Design: Singly Reinforced Beam Analysis

Principles of Reinforcement Detailing

  • General Detailing Rules (CENG325):

    • Continuous and Discontinuous Ends: Specific bar placements are required for top and bottom reinforcement at supports and midspans.

    • Clearance and Cover: Typical cover for reinforcement is specified as 40mm40\,mm.

    • Cantilevers: Requirements include top bars at the cantilever's discontinuous end and bottom bars at the discontinuous end.

    • Spacing and Development:

      • Span length is designated as LL (Clear Distance).

      • Top bars at support: L1/3L1/3.

      • Top bars at midspan: L1/2L1/2.

      • Bottom bars at support: L1L1 with splice lengths as per specific tables.

      • Cantilever bars: LoLo, marked by 3/4Lo3/4 Lo or L1/4L 1/4 (where the greater value governs).

    • Hoop Reinforcement Spacing:

      • Maximum at support: 50mm50\,mm.

      • S1=4×50mmS1 = 4 \times 50\,mm.

      • S2=4×100mmS2 = 4 \times 100\,mm.

      • S3=Rest 150mmS3 = \text{Rest } 150\,mm.

Fundamental Assumptions in Flexural Analysis

  • Assumption 1: The maximum concrete strain (ϵc\epsilon_c) at the extreme compression fiber shall be assumed equal to 0.0030.003.

  • Assumption 2: The tensile strength of concrete shall be neglected in flexural calculations.

  • Assumption 3: The relationship between concrete compressive stress and strain may be represented by a rectangular, trapezoidal, parabolic, or any other shape that predicts strength in agreement with compressive test results.

  • Assumption 4: A uniform concrete stress of 0.85fc0.85 f'_c shall be assumed. This stress is distributed over an equivalent compression zone bounded by the cross-section and a line parallel to the neutral axis, located at a distance aa from the fiber of maximum compressive strain.

  • Assumption 5: The distance from the maximum compressive strain fiber to the neutral axis is denoted as cc, measured perpendicular to that axis. The relationship between the stress block depth (aa) and the neutral axis depth (cc) is defined as:

    • a=βca = \beta c

Mechanics and Notations of Singly-Reinforced Beams

  • Notation Definitions:

    • AsA_s: Area of steel reinforcement.

    • dd: Effective depth (distance from extreme compression fiber to the centroid of tension reinforcement).

    • bb: Width of the beam.

    • fcf'_c: Specified compressive strength of concrete.

    • cc: Depth from the extreme compression fiber to the neutral axis.

    • aa: Depth of the equivalent rectangular stress block.

    • ϵs\epsilon_s: Strain in the steel reinforcement.

    • ϵc\epsilon_c: Strain in the concrete (0.0030.003 at ultimate limit state).

    • EsE_s: Modulus of elasticity of steel, taken as 200,000MPa200,000\,MPa (also noted as 200,000GPa200,000\,GPa in some slides).

    • fyf_y: Specified yield strength of steel reinforcement.

    • fsf_s: Actual stress in the steel.

  • Equilibrium and Force Vectors:

    • Compression Force (CC): C=0.85fcabC = 0.85 f'_c a b

    • Tension Force (TT): T=AsfsT = A_s f_s

    • Summation of Horizontal Forces: C=TC = T

    • 0.85fcab=Asfs0.85 f'_c a b = A_s f_s

Moment Capacity Equations

  • Nominal Moment Capacity (MnM_n):

    • The nominal moment can be calculated via summation of moments at the level of the steel or concrete resultant force.

    • Lever arm between CC and TT is (da2)(d - \frac{a}{2}).

    • Mn=C(da2)M_n = C(d - \frac{a}{2})

    • Mn=T(da2)M_n = T(d - \frac{a}{2})

    • Substituting force definitions:

      • Mn=0.85fcab(da2)M_n = 0.85 f'_c a b (d - \frac{a}{2})

      • Mn=Asfs(da2)M_n = A_s f_s (d - \frac{a}{2})

Strain Compatibility and Steel Stress

  • Strain-Stress Relationship: Strain=StressModulus of ElasticityStrain = \frac{Stress}{\text{Modulus of Elasticity}}.

  • Compatibility Analysis (Ratio and Proportion):

    • Using the strain diagram: 0.003c=ϵsdc\frac{0.003}{c} = \frac{\epsilon_s}{d - c}

    • Substituting ϵs=fs200,000\epsilon_s = \frac{f_s}{200,000}:

    • fs200,000=0.003(dcc)\frac{f_s}{200,000} = 0.003 \left( \frac{d - c}{c} \right)

    • fs=600(dcc)f_s = 600 \left( \frac{d - c}{c} \right)

  • Yielding Criteria:

    • If fsfyf_s \geq f_y: The steel has yielded. Use fyf_y in strength calculations.

    • If f_s < f_y: The steel has not yielded. Use the actual computed value of fsf_s.

Types of Failure and Steel Ratios

Failure types are determined by the percentage of steel in the section relative to the concrete.

  • Tension-Controlled Section:

    • Steel reaches a strain ϵs0.005\epsilon_s \geq 0.005 before concrete reaches its maximum strength.

    • Occurs when there is a small percentage of steel.

    • Failure is characterized as Ductile Failure.

    • Section is considered Under-Reinforced.

  • Balanced Section:

    • Concrete reaches ϵc=0.003\epsilon_c = 0.003 at the exact same time the steel reaches its yielding strain.

    • Steel and concrete fail simultaneously.

  • Compression-Controlled Section:

    • Concrete reaches ϵc=0.003\epsilon_c = 0.003 before the steel reaches its yielding point.

    • Occurs when there is a large percentage of steel.

    • Failure is characterized as Brittle Failure.

    • Section is considered Over-Reinforced.

Strength Reduction Factors and Reinforcement Limits

  • Strength Reduction Factor (ϕ\phi):

    • Tension-Controlled (fs1000f_s \geq 1000 or ϵs0.005\epsilon_s \geq 0.005): ϕ=0.9\phi = 0.9

    • Compression-Controlled (fs400f_s \leq 400 or ϵsϵy\epsilon_s \leq \epsilon_y): ϕ=0.65\phi = 0.65

    • Transition Zone:

      • ϕ=0.65+0.25(ϵsϵy0.005ϵy)\phi = 0.65 + 0.25 \left( \frac{\epsilon_s - \epsilon_y}{0.005 - \epsilon_y} \right)

      • ϕ=0.65+0.25(fsfy1000fy)\phi = 0.65 + 0.25 \left( \frac{f_s - f_y}{1000 - f_y} \right)

  • Balanced Steel Ratio Formula (ρbal\rho_{bal}):

    • cb=(600600+fy)dc_b = \left( \frac{600}{600 + f_y} \right) d

    • ρbal=0.85fcβfy(600600+fy)\rho_{bal} = \frac{0.85 f'_c \beta}{f_y} \left( \frac{600}{600 + f_y} \right)

    • If \rho_{actual} < \rho_{bal}, the steel yields.

    • If \rho_{actual} > \rho_{bal}, the steel does not yield (DNY).

  • Maximum Conditions:

    • Maximum Condition (f_s > f_y): cmax=37dc_{max} = \frac{3}{7}d.

    • Tension-Controlled Limit: ct=38dc_t = \frac{3}{8}d.

    • ρmax=0.85fcβfy(37)\rho_{max} = \frac{0.85 f'_c \beta}{f_y} \left( \frac{3}{7} \right)

    • ρt=0.85fcβfy(38)\rho_t = \frac{0.85 f'_c \beta}{f_y} \left( \frac{3}{8} \right)

  • Minimum Flexural Reinforcement (As,minA_{s,min}):

    • Ref: NSCP/ACI Section 409.6.1.

    • As,minA_{s,min} is the greater of:

      • (a) 0.25fcfybwd\frac{0.25 \sqrt{f'_c}}{f_y} b_w d

      • (b) 1.4fybwd\frac{1.4}{f_y} b_w d

Worked Examples

Sample Problem 1
  • Given: b=300mmb = 300\,mm, d=500mmd = 500\,mm, 325mm3 - 25\,mm RSB, fc=28MPaf'_c = 28\,MPa, fy=414MPaf_y = 414\,MPa.

  • Results:

    1. Depth of Stress Block (aa): 69.908mm69.908\,mm

    2. Nominal Moment Capacity (MnM_n): 283.5kNm283.5\,kNm

    3. Design Moment Capacity (ϕMn\phi M_n): 255.17kNm255.17\,kNm

    4. Balanced Steel Ratio (ρbal\rho_{bal}): 0.03350.0335

    5. Mode of Design: Tension-Controlled

Sample Problem 2
  • Given: b=300mmb = 300\,mm, d=500mmd = 500\,mm, 928mm9 - 28\,mm RSB, fc=34MPaf'_c = 34\,MPa, fy=414MPaf_y = 414\,MPa.

  • Results:

    1. Balanced Steel Ratio: 0.03330.0333

    2. Actual Steel Ratio: 0.0370.037

    3. Depth of Stress Block (aa): 245.87mm245.87\,mm

    4. Minimum Steel Ratio: 0.0033830.003383

    5. Mode of Design: Compression-Controlled

    6. Nominal Moment Capacity (MnM_n): 803.79kNm803.79\,kNm

    7. Design Moment Capacity (ϕMn\phi M_n): 522.46kNm522.46\,kNm

Sample Problem 3
  • Given: b=300mmb = 300\,mm, d=440mmd = 440\,mm, fc=27.58MPaf'_c = 27.58\,MPa, fy=413.80MPaf_y = 413.80\,MPa, Mu=262.56kNmM_u = 262.56\,kNm.

  • Results:

    1. Maximum Depth of Compression (cc): 165mm165\,mm

    2. Maximum Steel Ratio (ρmax\rho_{max}): 0.018060.01806

    3. Area of Steel Required for MuM_u: 1906.078mm21906.078\,mm^2

    4. Number of 20mm20\,mm RSB: 7PCS7\,PCS