Make predictions using regression lines, keeping in mind the dangers of extrapolation.
Calculate and interpret a residual.
Interpret the slope and y-intercept of a regression line.
Determine the equation of a least-squares regression line using technology or computer output.
Construct and interpret residual plots to assess whether a regression model is appropriate.
Interpret the standard deviation of the residuals and $r^2$ and use these values to assess how well a least-squares regression line models the relationship between two variables.
Describe how the least-squares regression line, standard deviation of the residuals, and $r^2$ are influenced by outliers.
Find the slope and y-intercept of the least-squares regression line from the means and standard deviations of $x$ and $yandtheircorrelation.</p></li></ul></li></ul><h5id="b95f28f0−0734−454a−8e6f−91f805d2304f"data−toc−id="b95f28f0−0734−454a−8e6f−91f805d2304f"collapsed="false"seolevelmigrated="true">RegressionLines</h5><ul><li><p>Linear(straight−line)relationshipsbetweentwoquantitativevariablesarecommon.</p></li><li><p>Aregressionlinesummarizestherelationshipbetweentwovariablesonlyinaspecificsetting:whenonevariablehelpsexplaintheother.</p></li><li><p><strong>Regressionlineequation</strong>:(y^=b<em>0+b</em>1x),where:</p><ul><li><p>(y^)isthepredictedvalueofy$ for a given value of $x.</p></li></ul></li></ul><h5id="ab6f3f7e−8e12−4dd3−9869−847dcee24f46"data−toc−id="ab6f3f7e−8e12−4dd3−9869−847dcee24f46"collapsed="false"seolevelmigrated="true">PredictionExample</h5><ul><li><p>Arandomsampleof16usedFordF−150SuperCrew4×4sselectedfromautotrader.comhastheregressionequation:</p><ul><li><p>(price^=38257−0.1629×miles driven)</p></li></ul></li><li><p>Example:PredictthepriceofaFordF−150thathasbeendriven100,000miles:</p><ul><li><p>(price^=38257−0.1629×100000=21,967)</p></li></ul></li></ul><h5id="2ab4c0ba−9f37−410f−9fad−2d710a33fc56"data−toc−id="2ab4c0ba−9f37−410f−9fad−2d710a33fc56"collapsed="false"seolevelmigrated="true">Extrapolation</h5><ul><li><p>Extrapolationispredictingvaluesoutsidetherangeofdatausedtocreatetheregressionmodel.</p></li><li><p>Caution:predictionsfaroutsidethisintervalcanbeinaccurate.</p></li><li><p>Example:PredictingpriceforaFordF−150with300,000miles:</p><ul><li><p>(price^=38257−0.1629×300000=−10613)(nonsensicalresult,indicatingextrapolationerror).</p></li></ul></li></ul><h5id="585bc3d6−6698−4304−b4a9−3bf9df3deb33"data−toc−id="585bc3d6−6698−4304−b4a9−3bf9df3deb33"collapsed="false"seolevelmigrated="true">Residuals</h5><ul><li><p>Aresidualisthedifferencebetweentheactualvalueofy$ and the predicted value of $y$:
In practice, no line will pass through all points; residuals measure prediction errors in $y.</p></li><li><p>ResidualexampleusingFordF−150driven70,583miles:</p><ul><li><p>Findpredictedprice:</p></li><li><p>(price^=38257−0.1629×70583=26759)</p></li><li><p>Iftheactualpriceis21,994, then:
Residual = 21,994 - 26,759 = -4765.