Ch7: Half Life

Practical Importance of Half-Life

  • Dating artifacts
    • Carbon-14 half-life enables archaeologists to estimate the age of historical items in households or excavation sites.
  • Radioactive-waste management
    • Knowing an isotope’s half-life tells engineers how long waste must be stored before it is safe.
    • Rule of thumb discussed: “A radioactive sample is considered safe after 10 half-lives.”
    • Example: Iodine-131, t_{1/2}=8\text{ days} ⇒ safe after 10\times8=80\text{ days}.
    • Example: Plutonium-239, t_{1/2}=24\,000\text{ yr} ⇒ must be stored for \approx 240\,000\text{ yr} (≈ millions when rounded for policy discussions).
  • Medical applications
    • Physicians select radio-tracers whose half-lives strike a balance between diagnostic usefulness and minimal long-term exposure.

Definition of Half-Life

  • “Time required for the amount (or activity) of a radioactive sample to drop to one-half of its initial value.”
  • Can be framed in terms of mass or radiation intensity.

Visualizing Decay (Plutonium-239 Example)

  • t_{1/2}=24\,000\text{ yr}
    • After 1 half-life (24,000 yr): 50 % remains.
    • After 2 half-lives (48,000 yr): 50\%\times\tfrac12=25\% remains.
    • After 3 half-lives (72,000 yr): 25\%\times\tfrac12=12.5\% remains.
    • Continues to 6.25 %, 3.13 %, etc.
  • Safety implication: Waiting for plutonium to reach trace safety thresholds requires geologic time scales.

Generic Half-Life Table (Decay vs. Remaining)

  • Provided logic (can be rebuilt without memorizing):
    • 1 half-life → 50 % decay / 50 % remain.
    • 2 half-lives → 75 % decay / 25 % remain.
    • 3 half-lives → 87.5 % decay / 12.5 % remain.
    • 4 half-lives → 93.75 % decay / 6.25 % remain.
    • 5 half-lives → 96.875 % decay / 3.125 % remain.

Extreme Half-Life Spectrum (Selected Isotopes)

  • Uranium-238: 4.5\times10^9\text{ yr} (age of Earth scale)
  • Potassium-40: 1.3\times10^9\text{ yr}
  • Uranium-235: 7\times10^8\text{ yr}
  • Plutonium-239: 2.4\times10^4\text{ yr}
  • Iodine-131: 8\text{ days}
  • Polonium (specific isotope unspecified): 1.6\times10^{-4}\text{ s} (fractions of a millisecond)

Worked Example 1 – Remaining Percentage

Question: “Element X has t_{1/2}=10\text{ days}. After 30 days, what % of the original amount remains?”

  • Strategy: Assume an initial 100 g (any convenient mass).
  • Number of half-lives elapsed: \frac{30\text{ d}}{10\text{ d}} = 3.
  • Sequential halving:
    • After 1st half-life: 100\text{ g}\to50\text{ g}
    • After 2nd: 50\text{ g}\to25\text{ g}
    • After 3rd: 25\text{ g}\to12.5\text{ g}
  • Remaining %: \frac{12.5}{100}\times100=12.5\%
  • Complement (decayed %): 100\%-12.5\%=87.5\% (if asked).

Worked Example 2 – Determining Half-Life

Question: “After 42 days only 25 % of Element Y remains. What is t_{1/2}?”

  • Observed reduction: 100\%\to25\% corresponds to two halvings (100 %→50 %→25 %).
  • Number of half-lives = 2.
  • Total time = 42 days.
  • Therefore t_{1/2}=\frac{42\text{ d}}{2}=21\text{ days}.

Ethical & Policy Connections

  • Long-lived isotopes (e.g., Pu-239, U-238) raise inter-generational storage obligations—ethical debates around nuclear energy center on this timeframe.
  • Short-lived medical isotopes minimize patient exposure but require rapid synthesis and logistics.
  • Decision frameworks for nuclear vs. alternative energy sources often invoke half-life tables to communicate risk.

Links to Previous Lecture

  • Previous session introduced categories of nuclear waste; current half-life discussion provides quantitative tool for predicting when each category transitions from high- to low-level waste.
  • Reinforces the importance of isotope selection in nuclear medicine, first mentioned earlier.

Key Equations & Concepts Recap

  • Exponential decay formula (not explicitly given in transcript but implied): N(t)=N0\left(\tfrac12\right)^{t/ t{1/2}} where:
    • N_0 = initial amount/activity
    • t = elapsed time
    • t_{1/2} = half-life
  • Safety criterion: t{\text{safety}} \approx 10\,t{1/2}
  • “Percent remaining” after n half-lives: \left(\tfrac12\right)^n\times100\%