Study Unit 6: Filter Design - (Part 1) First Order Filters
Study Unit 6: Filter Design - (Part 1) First Order Filters
Lecture Outcomes
- Topics for today’s discussion:
- General filter responses
- First order filters
- Differentiators and integrators
- Low-pass, high-pass, and band-pass filters
- Phase shifters
Common Filter Responses
Ideal Low-Pass Response
- Frequencies below ω are passed.
- Frequencies above ω are rejected.
- Notation:
- Green: Filter response
- Blue: Output components
- Red: Rejected components
- Illustrations:
- Input signal depicts various frequencies.
- Filtered signal shows only frequencies below ω.
Ideal High-Pass Response
- Frequencies above ω are passed.
- Frequencies below ω are rejected.
- Notation:
- Green: Filter response
- Blue: Output components
- Red: Rejected components
- Illustrations:
- Input signal contains various frequencies.
- Filtered signal shows only frequencies above ω.
Ideal Band-Pass Response
- Frequencies between ω<em>L and ω</em>H are passed.
- Frequencies below ωL are rejected.
- Frequencies above ωH are rejected.
- Notation:
- Green: Filter response
- Blue: Output components
- Red: Rejected components
- Illustrations:
- Input signal contains a range of frequencies.
- Filtered signal only contains frequencies within the ω<em>L and ω</em>H range.
Ideal Notch Response
- Frequencies between ω<em>L and ω</em>H are rejected.
- Frequencies below ωL are passed.
- Frequencies above ωH are passed.
- Notation:
- Green: Filter response
- Blue: Output components
- Red: Rejected components
- Illustrations:
- Input signal has a spectrum of frequencies.
- Filtered signal is missing the frequencies between ω<em>L and ω</em>H.
Generic Filter Response and its Characteristics
- The ratio of the output and input is represented as: H(s)=X</em>iX<em>o=V</em>iV<em>o
- Polynomial format:
- H(s)=D(s)N(s)=b<em>nsn+b</em>n−1sn−1+⋯+b<em>1s1+b</em>0a<em>msm+a</em>m−1sm−1+⋯+a<em>1s1+a</em>0
- Rewritten to show roots (zeros and poles):
- H(s)=D(s)N(s)=H<em>0(s−p<em>1)(s−p</em>2)⋯(s−pn)(s−z</em>1)(s−z<em>2)⋯(s−z</em>m)
- Stability:
- Revise these concepts from previous modules (like ELI 220).
Philosophy of the Module
- Comments about the approach:
- Balancing math with intuition and circuit understanding.
- Balancing analysis with design.
- Extremely useful tool for intuitive reasoning: Asymptotic frequency insight:
- Low frequencies (DC): lim<em>ω→0Z</em>C=∞ (i.e., open circuit)
- High frequencies: lim<em>ω→∞Z</em>C=0 (i.e., short circuit)
The Differentiator
Circuit Analysis
- Step 1: Current equations (KCL)
- i<em>1=ZCv</em>in−0
- i<em>2=R0−v</em>out
- Z</em>Cv<em>in=−Rvout
- Step 2: Finding the transfer function
- H(s)=v</em>inv<em>out=−ZCR=−RCs
- Meaning:
- H(jω)=−jωRC=−j(ω/ω<em>0)=(ω/ω</em>0)∠−90∘
- ω0=RC1
The (Miller) Integrator
- Transfer function:
- H(s)=v</em>inv<em>out=−RZC=−RCs1
- Meaning:
- H(jω)=−jωRC1=−j(ω/ω<em>0)1=(ω/ω</em>0)j=(ω/ω0)1∠+90∘
- ω0=RC1
The (Deboo) Integrator
- Transfer function:
- H(s)=v</em>inv<em>out=RCs1
Low-Pass Filter with Gain
- Transfer function:
- H(jω)=−R</em>1R<em>2jωR<em>2C+11=H</em>01+j(ω/ω0)1
- Design equations:
- H<em>0=−R1R</em>2
- ω<em>0=R</em>2C1
High-Pass Filter with Gain
- Transfer function:
- H(jω)=−R</em>1R<em>2jωR</em>1C+1jωR<em>1C=H<em>01+j(ω/ω0)j(ω/ω</em>0)
- Design equations:
- H<em>0=−R1R</em>2
- ω<em>0=R</em>1C1
Band-Pass Filter with Gain
- Transfer function:
- H(jω)=−R</em>1R<em>2jωR<em>1C</em>1+1jωR<em>1C</em>1jωR<em>2C</em>2+11=H<em>01+j(ω/ω<em>L)j(ω/ω</em>L)1+j(ω/ω</em>H)1
- Design equations:
- H<em>0=−R1R</em>2
- ω<em>L=R</em>1C11
- ω<em>H=R</em>2C21
Phase Shifter
- Transfer function:
- H(jω)=jωRC+1−jωRC+1
- Insight into the circuit:
- Consider phase at opamp inputs:
- ∠v+=∠+90∘
- ∠v<em>−=∠v</em>+
- Consider the current through the top branch:
- ∠i<em>R1∝∠R</em>1v</em>i−v<em>−∝∠R10∘−(+90∘)∝∠−90∘