Trigonometric Functions and Pythagorean Identities

Trigonometric Functions and Identities

Relationships Between Trigonometric Functions

  • Six trigonometric functions are interconnected.
  • Reciprocal relationships:
    • csc(θ)=1sin(θ)\csc(\theta) = \frac{1}{\sin(\theta)}
    • sec(θ)=1cos(θ)\sec(\theta) = \frac{1}{\cos(\theta)}
    • cot(θ)=1tan(θ)\cot(\theta) = \frac{1}{\tan(\theta)}
  • Tangent in terms of sine and cosine: tan(θ)=sin(θ)cos(θ)\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} (y-coordinate divided by x-coordinate on the unit circle).

The Unit Circle and Pythagorean Identity

  • Equation of the unit circle: x2+y2=1x^2 + y^2 = 1
  • For a point on the unit circle corresponding to angle θ\theta:
    • x-coordinate: cos(θ)\cos(\theta)
    • y-coordinate: sin(θ)\sin(\theta)
  • Therefore, (cos(θ))2+(sin(θ))2=1(\cos(\theta))^2 + (\sin(\theta))^2 = 1

Notation

  • Shorthand notation:
    • cos2(θ)\cos^2(\theta) means (cos(θ))2(\cos(\theta))^2 (find cosine of theta, then square).
    • sin2(θ)\sin^2(\theta) means (sin(θ))2(\sin(\theta))^2 (find sine of theta, then square).
  • Important distinction:
    • sin2(θ)\sin^2(\theta) is not the same as sin(θ2)\sin(\theta^2)

Pythagorean Identity

  • The identity: cos2(θ)+sin2(θ)=1\cos^2(\theta) + \sin^2(\theta) = 1
  • Based on the Pythagorean theorem applied to the unit circle: (adjacent)2^2 + (opposite)2^2 = (hypotenuse)2^2, with hypotenuse = 1.

Applications of the Pythagorean Identity

  • If the cosine of an angle is known, the sine can be found (within a ±\pm sign), and vice versa.

Alternative Forms of the Pythagorean Identity

  • Dividing the original identity by sin2(θ)\sin^2(\theta):
    • cos2(θ)sin2(θ)+sin2(θ)sin2(θ)=1sin2(θ)\frac{\cos^2(\theta)}{\sin^2(\theta)} + \frac{\sin^2(\theta)}{\sin^2(\theta)} = \frac{1}{\sin^2(\theta)}
    • cot2(θ)+1=csc2(θ)\cot^2(\theta) + 1 = \csc^2(\theta)
  • Dividing the original identity by cos2(θ)\cos^2(\theta):
    • cos2(θ)cos2(θ)+sin2(θ)cos2(θ)=1cos2(θ)\frac{\cos^2(\theta)}{\cos^2(\theta)} + \frac{\sin^2(\theta)}{\cos^2(\theta)} = \frac{1}{\cos^2(\theta)}
    • 1+tan2(θ)=sec2(θ)1 + \tan^2(\theta) = \sec^2(\theta)

Naming Conventions

  • The "co" in trigonometric function names (cosine, cotangent, cosecant) follows a pattern in the identities: "co" goes with "co", and "not co" goes with "not co".
    • 1+tan2(θ)=sec2(θ)1 + \tan^2(\theta) = \sec^2(\theta)
    • 1+cot2(θ)=csc2(θ)1 + \cot^2(\theta) = \csc^2(\theta)

Using Trigonometric Identities to Solve Problems

  • If some information about an angle is known, trigonometric identities can be used to determine other trigonometric function values.

Example

  • Given: Angle θ\theta in the second quadrant, and cos(θ)=0.3\cos(\theta) = -0.3
  • Goal: Find sin(θ)\sin(\theta), tan(θ)\tan(\theta), cot(θ)\cot(\theta), sec(θ)\sec(\theta), and csc(θ)\csc(\theta).
  • Using the Pythagorean identity: cos2(θ)+sin2(θ)=1\cos^2(\theta) + \sin^2(\theta) = 1
    • (0.3)2+sin2(θ)=1(-0.3)^2 + \sin^2(\theta) = 1
    • 0.09+sin2(θ)=10.09 + \sin^2(\theta) = 1
    • sin2(θ)=10.09=0.91\sin^2(\theta) = 1 - 0.09 = 0.91
    • sin(θ)=±0.91\sin(\theta) = \pm\sqrt{0.91}
  • Since θ\theta is in the second quadrant, sin(θ)\sin(\theta) is positive. Therefore, sin(θ)=0.91\sin(\theta) = \sqrt{0.91}.
  • Now that both sin(θ)\sin(\theta) and cos(θ)\cos(\theta) are known, the other trigonometric functions can be found using their definitions.
    • tan(θ)=sin(θ)cos(θ)\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}
    • cot(θ)=1tan(θ)\cot(\theta) = \frac{1}{\tan(\theta)}
    • sec(θ)=1cos(θ)\sec(\theta) = \frac{1}{\cos(\theta)}
    • csc(θ)=1sin(θ)\csc(\theta) = \frac{1}{\sin(\theta)}

Key Takeaways

  • The Pythagorean identity (and its variations) is crucial for relating trigonometric functions.
  • Knowing one trigonometric function value often allows you to find all the others.