Vectors, 2D Motion, Units, and Dimensional Scaling Notes

Course Administration and Study Resources

  • Assignments: Students should begin work on the MasterPlan (MP) assignment immediately. While it is due on Thursday night, it is described as being quite long.

  • Support Systems: For physics-related questions, students are encouraged to use the following resources:     * Piazza: For online discussion and queries.     * Visiting Hours: For direct instructor engagement.     * Studio Sessions: Questions can be asked during scheduled studio time.

One-Dimensional Motion Example: Free Fall

  • Scenario: A pebble is thrown upward and released from a height of 1.5m1.5\,m above the ground. It ascends to a maximum height and then falls until it hits the ground.

  • Data Provided:     * Release Height (y0y_0): 1.5m1.5\,m     * Total Time (tt): 1.8s1.8\,s from release until impact.

  • Questions to Solve:     * How high above the ground did the pebble rise at its maximum?     * What was its speed upon impact with the ground?

  • Assumptions: Air drag is neglected.

  • Calculated Results:     * Maximum Height: The pebble rises 3.25m3.25\,m above the release point. The total height above the ground is calculated as 1.5m+3.25m=4.75m1.5\,m + 3.25\,m = 4.75\,m.     * Impact Velocity (vv): 9.65m/s-9.65\,m/s at the ground.     * Impact Speed: 9.65m/s9.65\,m/s (the magnitude of the velocity).

Introduction to Vectors in Two Dimensions

  • Definition of Position: The location of a point in space is represented as a vector. Vectors are directional line segments.

  • Vector Characteristics:     * Position Vector: An arrow drawn from the origin to the location of the object in space.     * Magnitude: The length of the segment, denoted as r|\vec{r}| or simply rr.     * Direction: The direction in which the arrow points.     * Equality: Two vectors are considered equal if they have the same magnitude (length) and point in the same direction (parallel).

  • Vector Notation:     * In 2-D, a vector can be written as: r=xx^+yy^\vec{r} = x\hat{x} + y\hat{y}     * Alternatively, it can be written in coordinate form: r=(x,y)\vec{r} = (x, y)

  • Unit Vectors:     * x^=(1,0)\hat{x} = (1, 0)     * y^=(0,1)\hat{y} = (0, 1)

Vector Components and Trigonometry

  • Defining Components: Vector components represent how much of the position arrow lies along the xx and yy axes.

  • Trigonometric Relationships: Given an angle θ\theta (which can often be chosen freely by the user):     * sin(θ)=oppositehypotenuse=ryr\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{r_y}{|\vec{r}|}     * cos(θ)=adjacenthypotenuse=rxr\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{r_x}{|\vec{r}|}     * ry=rsin(θ)r_y = r\sin(\theta)     * rx=rcos(θ)r_x = r\cos(\theta)

  • Pythagorean Theorem: The magnitude of the vector is related to its components by: r=r=rx2+ry2|\vec{r}| = r = \sqrt{r_x^2 + r_y^2}

  • Angle Calculation: The angle can be found using the inverse tangent: θ=tan1(ryrx)\theta = \tan^{-1}(\frac{r_y}{r_x})

Vector Addition and Subtraction: Geometrical Method

  • Addition (A+B\vec{A} + \vec{B}):     * Place the tail of vector B\vec{B} onto the head of vector A\vec{A}.     * The resultant (green vector) connects the tail of A\vec{A} to the head of B\vec{B}.

  • Special Cases for Addition:     * Equality (maximum magnitude) occurs if A\vec{A} and B\vec{B} are in the same direction.     * Minimum magnitude occurs if A\vec{A} and B\vec{B} are in opposite directions.

  • Vector Subtraction: To subtract, add the negative of the vector: AB=A+(B)\vec{A} - \vec{B} = \vec{A} + (-\vec{B}).

  • Triangle Inequality: If C=A+B\vec{C} = \vec{A} + \vec{B}, then: ABCA+BA - B \leq C \leq A + B

Motion in More Than One Dimension

  • Position Vector: The time-dependent location is represented by a 3-dimensional vector r(t)\vec{r}(t).

  • Velocity (v\vec{v}): Defined as the derivative of position with respect to time:     * v=limΔt0ΔrΔt=drdt\vec{v} = \lim_{\Delta t \rightarrow 0} \frac{\Delta \vec{r}}{\Delta t} = \frac{d\vec{r}}{dt}     * For small time intervals: Δr=vΔt\Delta \vec{r} = \vec{v}\Delta t     * Direction: The velocity vector is always aligned with the path of the object.

  • Acceleration (a\vec{a}): Defined as the derivative of velocity with respect to time:     * a(t)=dvdt\vec{a}(t) = \frac{d\vec{v}}{dt}     * Direction: Acceleration is aligned with the direction of change in velocity.

Turning Motion and Acceleration Components

  • Velocity Update Equation: vf=vi+aΔt\vec{v}_f = \vec{v}_i + \vec{a}\Delta t

  • Tangential Acceleration (aa_{\parallel}): This is the component of acceleration parallel to the velocity.     * It changes the speed of the object.     * If a_{\parallel} > 0, speed increases.     * If a_{\parallel} < 0, speed decreases.     * Defined as the rate of change of speed: a=dvdta_{\parallel} = \frac{dv}{dt}

  • Centripetal Acceleration (aa_{\perp}): This is the component of acceleration perpendicular to the instantaneous velocity.     * It changes the direction of v\vec{v} but does not change the speed.     * The particle turns in the direction of aa_{\perp}.     * Magnitude: a=v2Ra_{\perp} = \frac{v^2}{R}, where RR is the radius of curvature at that moment.

Examples: Motion and Acceleration

  • Bacterium Movement: A bacterium moves along a curved path with steadily increasing speed at point PP.     * The total acceleration a\vec{a} is the vector sum of aa_{\perp} (pointing toward the center of the curve) and aa_{\parallel} (pointing along the path of motion in the direction of travel).

  • Merry-Go-Round Calculation:     * Data: Diameter = 3.0m3.0\,m (Radius R=1.5mR = 1.5\,m). Acceleration experienced at the edge = 0.5g=4.9m/s20.5g = 4.9\,m/s^2.     * Task: Find the time (TT) for one revolution, assuming constant speed.     * Solution:         1. Use a=v2R4.9=v21.5a_{\perp} = \frac{v^2}{R} \Rightarrow 4.9 = \frac{v^2}{1.5}.         2. Calculated Speed (vv) = 2.7m/s2.7\,m/s.         3. Period (TT) = circumferencev=2π(1.5)2.7\frac{\text{circumference}}{v} = \frac{2\pi(1.5)}{2.7}.         4. Calculated Period (TT) = 3.5s3.5\,s.

Projectile Motion (2D)

  • Projectile motion is a combination of two independent behaviors:     1. Horizontal Motion: Constant velocity (vx=constantv_x = \text{constant}, because ax=0a_x = 0).     2. Vertical Motion: Constant downward acceleration (ay=ga_y = -g).

  • The update equation remains: vf=vi+aΔt\vec{v}_f = \vec{v}_i + \vec{a}\Delta t

Base Dimensions

  • Physical quantities are expressed using a set of base dimensions:     * Length: [L][L] (Units: meter, mm, cm, etc.)     * Mass: [M][M] (Units: kg, g, etc.)     * Time: [T][T] (Units: second, hour, etc.)     * Amount of Substance (mols): [N][N]     * Thermodynamic Temperature: [Θ][\Theta]     * Current: [I][I]     * Luminous Intensity: [J][J]

Derived Dimensions Examples

  • Area: Length ×\times Length = [L2][L^2]

  • Volume: Length ×\times Length ×\times Length = [L3][L^3]

  • Speed: Length / Time = [LT1][LT^{-1}]

  • Density: Mass / Volume = [ML3][ML^{-3}]

Rules of Dimensional Analysis

  1. Homogeneity: Every term in an expression must have identical dimensions.

  2. Equality: Both sides of an equation must share the same dimensions.     * Example (Consistent): vf2=vi2+2aΔxv_f^2 = v_i^2 + 2a\Delta x ([L2T2]=[L2T2]+[LT2][L][L^2T^{-2}] = [L^2T^{-2}] + [LT^{-2}][L])     * Non-example (Inconsistent): x=vt2+12at3x = vt^2 + \frac{1}{2}at^3

  3. Dimensionless Functions: Trigonometric functions (sin\sin, cos\cos), exponentials (exe^x), and logarithms (ln\ln), as well as their arguments, must be dimensionless.     * Example: In y(x,t)=Acos(kxωt)y(x,t) = A\cos(kx - \omega t), the argument (kxωt)(kx - \omega t) must be dimensionless.

Units and Scientific Notation

  • SI System: The standard system of units (International System of Units).     * Length: meter (mm)     * Mass: kilogram (kgkg)     * Time: second (ss)     * Amount: mole (molmol)     * Temperature: Kelvin (KK)

  • Handling Scale:     * Scientific Notation: Useful for extremely small/large numbers.         * Example: Planck's constant h=6.63×1034kgm2/sh = 6.63 \times 10^{-34}\,kg\,m^2/s.     * Unit Prefixes:         * centi- (c): 10210^{-2}         * milli- (m): 10310^{-3}         * micro- (\mu): 10610^{-6}         * nano- (n): 10910^{-9}         * pico- (p): 101210^{-12}         * kilo- (k): 10310^3         * mega- (M): 10610^6         * giga- (G): 10910^9

Unit Conversion Examples

  • Volume Conversion: How many cubic centimeters (cccc) in a cubic meter?     * (100cm=1m100\,cm = 1\,m), so (100cm)3=(1m)3106cm3=1m3(100\,cm)^3 = (1\,m)^3 \Rightarrow 10^6\,cm^3 = 1\,m^3.

  • Acre-foot Conversion: Express 0.850.85 acre-feet in m3m^3     * Conversion Facts:         * 1acre=4,840yards21\,\text{acre} = 4,840\,\text{yards}^2         * 1yard=3feet=36inches1\,\text{yard} = 3\,\text{feet} = 36\,\text{inches}         * 1inch=2.54cm=0.0254m1\,\text{inch} = 2.54\,cm = 0.0254\,m

Proportional Reasoning and Scaling

  • Definition: yy is proportional to xx if y=cxpy = cx^p (yxpy \propto x^p).     * Direct/Linear Proportionality (p=1p = 1): y=cxy = cx     * Inverse Proportionality (p=1p = -1): y=c/xy = c/x

  • Utility: Allows solving problems without exact relations, simplifies math by canceling constants, and provides a check for typos.

  • Isomorphic Changes: Occur when all linear length dimensions change by the same factor (same shape, different size).     * If two objects are isomorphic:         * VL3V \propto L^3         * AL2A \propto L^2     * Example: If V1=1.0m3V_1 = 1.0\,m^3, A1=8.0m2A_1 = 8.0\,m^2, and V2=0.50m3V_2 = 0.50\,m^3, calculate A2A_2.         * V2/V1=(L2/L1)30.5=(L2/L1)3L2/L1=(0.5)1/3V_2/V_1 = (L_2/L_1)^3 \Rightarrow 0.5 = (L_2/L_1)^3 \Rightarrow L_2/L_1 = (0.5)^{1/3}.         * A2=A1×(L2/L1)2=8.0×(0.5)2/35.04m2A_2 = A_1 \times (L_2/L_1)^2 = 8.0 \times (0.5)^{2/3} \approx 5.04\,m^2.

Intensive vs. Extensive Quantities

  • Context: Mass/Volume relationship.

  • Formula: ρ=mV\rho = \frac{m}{V}.

  • Scaling: If mass increases by a factor of 3 at constant density, volume also increases by a factor of 3 (V2=3V1V_2 = 3V_1).

  • Extensive Quantities: Depend on the amount of matter (e.g., mass, volume).

  • Intensive Quantities: Independent of the size or amount of matter (e.g., density).

Dimensional Analysis Example: Pendulum Period

  • Observation: The period (TT) of a simple pendulum depends only on the length of the string (ll) and the acceleration due to gravity (gg).

  • Dimensional Goal: Find the relationship using dimensions.     * [T]=[L]a[LT2]b[T] = [L]^a [LT^{-2}]^b     * [T1]=[La+bT2b][T^1] = [L^{a+b} T^{-2b}]     * Equating exponents for TT: 1=2bb=1/21 = -2b \Rightarrow b = -1/2     * Equating exponents for LL: 0=a+ba=b=1/20 = a + b \Rightarrow a = -b = 1/2     * Result: TlgT \propto \sqrt{\frac{l}{g}}

Questions & Discussion

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  • Question 3: Dimensional consistency check for various expressions of ss and vv.

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  • Example Problem (Ball on Incline): A ball rolls down an incline with constant acceleration from rest.     * Formula: x=12at2x = \frac{1}{2}at^2.     * Given: It takes 5s5\,s to travel the length of 1 rod (x1x_1).     * Question: How long (t2t_2) to travel 3 rods (x2=3x1x_2 = 3x_1)?     * Proportionality: xt2txx \propto t^2 \Rightarrow t \propto \sqrt{x}.     * Solution: t2=t1x2x1=538.66st_2 = t_1 \sqrt{\frac{x_2}{x_1}} = 5\sqrt{3} \approx 8.66\,s.