CFR14 Solubility Equilibria

Page 1: Introduction to CFR

  • Title: Cardiovascular System, Biological Fluids, Renal Function (CFR)

  • Focus: Understanding solubility equilibria in biological systems.

Page 2: Chemical Equilibrium

  • Definition of Equilibrium:

    • Reactants convert to products and vice versa.

    • The rate of forward reaction equals the rate of reverse reaction.

  • Dynamics at Equilibrium:

    • Both reactions (forward and reverse) are continuously occurring.

    • Concentrations of reactants and products remain constant over time.

Page 3: Equilibrium Constant

  • Example Reaction:

    • 2 NH3(g) ⇌ N2(g) + 3 H2(g)

  • Equilibrium constant expression (K):

    • K = [N2][H2]^3 / [NH3]^2

  • Characteristics:

    • Concentrations of each species raised to the power of their stoichiometric coefficients.

    • K is unit-less and varies with reaction and temperature.

Page 4: Equilibrium Constant Expressions

  • Role of Solids:

    • Solids do not contribute to K since their concentrations are constant (fixed by density).

  • Example

  • Reaction: Fe(s) + 5 CO(g) ⇌ Fe(CO)5(g)

    • K = [Fe(CO)5] / [Fe][(CO)]^5

  • Important Note:

    • Only concentrations of gaseous or aqueous species are included in the equilibrium expression.

Page 5: Equilibrium Constant for liquids

  • Pure Liquids:

    • Concentration of pure liquids does not change and can be omitted from K.

  • Example: CH3CO2H(aq) + H2O(l) ⇌ CH3COO-(aq) + H3O+(aq)

    • K = [CH3CO2-][H3O+] / [CH3CO2H]

Page 6: Relationship Between K and Reaction Direction

  • Forward and Reverse Reactions Relation:

    • For the reaction 2 SO2(g) + O2(g) ⇌ 2 SO3(g):

      • K_forward = [SO3]^2 / [SO2]^2[O2]

      • K_reverse = [SO2]^2[O2] / [SO3]^2

    • K_forward and K_reverse are reciprocals of each other.

Page 7: Interpreting Equilibrium Constant

  • Situations:

    • K >> 1 indicates more products at equilibrium (favoring products).

    • K << 1 indicates more reactants at equilibrium (favoring reactants).

  • Examples:

    • For CH3CO2H + H2O ⇌ CH3COO- + H3O+, K = 1.8 x 10^-5.

    • For 2 H2 + O2 ⇌ 2 H2O, K = 3.5 x 10^81.

Page 8: Equilibrium Constant Recap

  • NH3(g) ⇌ N2(g) + 3 H2(g):

    • K determination involves raising concentrations to stoichiometric coefficients.

  • K is specific to the reaction and temperature, unit-less.

Page 9: Solids and K Definition

  • Solid Phase Contributions:

    • Not included in the equilibrium constant calculations.

    • Example: For the reaction, K remains dependent only on reactants and products in solution.

Page 10: Le Chatelier’s Principle

  • Definition:

    • A system at equilibrium will shift to minimize the effects of a stress applied to it.

  • Types of stress:

    • Change in concentration of reactants or products.

    • Change in pressure or volume in a gaseous system.

    • Change in temperature.

Page 11: Effect of Concentration Changes

  • Reaction: A + B ⇌ C + D

  • Changes to Consider:

    • Increase in [A] or [B]: shifts equilibrium to the right (towards products).

    • Decrease in [A] or [B]: shifts equilibrium to the left (towards reactants).

    • Increase in [C] or [D]: shifts equilibrium to the left.

    • Decrease in [C] or [D]: shifts equilibrium to the right.

Page 12: Learning Outcomes

  • Key Concepts to Understand:

    • Define the solubility product.

    • Calculate solubility product from molar solubility.

    • Understand common ion effects on solubility.

    • Analyze the impact of pH on solubility.

    • Recognize applications of the solubility product principle.

Page 13: Solubility Equilibria Phenomena

  • Example: Precipitation and Dissolution of calcium carbonate (CaCO3):

    • Process leads to formation of stalactites and stalagmites.

    • Interactions between Ca2+ and CO32- and their dynamics in dissolution or precipitation.

Page 14: Importance of Solubility

  • Biological Importance:

    • Key for absorption of nutrients and mineralization processes.

    • Significant for drug delivery and diagnostic processes.

  • Example Reaction: NaCl ⇌ Na+ + Cl-

Page 15: Dynamics in Saturated Solutions

  • Characteristics of Saturated Solutions:

    • Dynamic equilibrium exists between undissolved solids and dissolved ions.

    • Rate of dissolution equals rate of precipitation.

    • Ion concentrations remain constant.

Page 16: Dissolution of Ionic Solids

  • Consideration of Equilibrium with Initiation of Dissolution:

    • Example: CaF2 dissolving into Ca2+ and F-

    • The process increases ion concentrations and probability of collisions leading to precipitation.

Page 17: Reach Equilibrium in CaF2

  • Equilibrium Dynamics:

    • Forward and reverse reactions occur consistently without changing dissolved ion concentrations.

    • At equilibrium, the solution is saturated with no concentration change.

Page 18: Solubility Product Expression

  • Basic Formulation:

    • Ksp = [Ca2+][F-]^2 for CaF2 ⇌ Ca2+ + 2F-

    • Reflects relationship between solid form and its dissolved ions in saturated solutions.

Page 19: Ksp and Solid Concentration

  • Understanding absence of solids in Ksp calculations:

    • More solid increases surface area leading to higher solubility and reforming ion precipitation.

Page 20: Solubility Product Example

  • Copper Arsenate Reaction:

    • Cu3(AsO4)2(s) ⇌ 3Cu2+(aq) + 2AsO43-(aq)

    • Ksp = [Cu2+]^3[AsO43-]^2.

Page 21: Ksp Characteristics

  • Unique Ksp Values:

    • Solubility product is constant for a given substance at a specific temperature.

    • Solubility may vary infinitely under different conditions (pH, common ions).

Page 22:

Page 23: Molar Solubility Concept

  • Definition:

    • Number of moles of a substance that can dissolve in 1 liter of solution at saturation.

    • Expressed in mol/L and calculable from Ksp and stoichiometric coefficients.

Page 24: Calculating Ksp

  • Example Calculation with CaF2:

    • Molar solubility of CaF2 is 3.4 x 10^-4 mol/L.

    • Ksp = [Ca2+][F-]^2 = [3.4 x 10^-4][2 x 3.4 x 10^-4]^2 = 1.57 x 10^-10.

Page 25: Ksp and Molar Solubility Reliability

  • Comparison of Ksp and solubility in salts:

    • Ksp relates to solubility dependent on ionic counts produced:

      • Salt examples: AgI (Ksp = 1.5 x 10^-16), CuI (Ksp = 5.0 x 10^-12), CaSO4 (Ksp = 6.1 x 10^-5).

    • General trend: larger Ksp translates to larger molar solubility.

Page 26: Salts with Different Ion Counts

  • Reliability of Ksp Comparisons:

    • Ksp cannot directly compare solubility of salts yielding different numbers of ions:

    • Salts comparison: CuS (Ksp = 8.5 x 10^-45) shows less molar solubility than Bi2S3 (Ksp = 1.1 x 10^-72).

Page 27: Common Ions Influence

  • Impact of Common Ions on Solubility:

    • Analyzing Ag2CrO4 in two scenarios with and without common ions affects dissolution.

    • Le Chatelier’s principle applies to shifts in equilibrium based on common ions.

Page 28:

  • Initial conditions tracked for salt dissolution and its equilibrium when in solutions containing common ions.

Page 29: Common Ion Effect Variations

  • Different scenarios in salt dissolution:

    • Comparison highlights reduced solubility when common ions present impacting equilibrium concentrations.

Page 30: pH Influence on Solubility

  • Example with Mg(OH)2:

    • pH changes influence solubility — Increased pH reduces solubility while decreased pH increases it.

Page 31: Solubility of Ag3PO4

  • pH interactions:

    • PO43- reacts with H+ ions; decreased pH increases solubility by decreasing PO43- concentration.

Page 32:

Page 33:

Page 34: Applications of Solubility

  • The importance of modifying solubility in drug development and dental health.

Page 35: Low Molar Solubility Use

  • Clinical Importance of Low Solubility:

    • Example: Barium sulfate as a radio contrast agent due to its low solubility and toxicity management.

Page 36: Tooth Decay Mechanism

  • Impact of low pH on tooth enamel:

    • Hydroxyapatite dissolution leads to cavities; remineralization occurs but is slower under acidic conditions.

Page 37: Fluoridation Benefits

  • Calcium fluoride enhances remineralization of enamel, creating less soluble fluorapatite, thereby reducing tooth decay.

Page 38: Drug Solubility Alterations

  • Drug formation through salt modes increases solubility; effects differ by counter ions as well.

Page 39: Salt Form and Solubility

  • The types of counter ions impact solubility of drugs, specifically in formulations for oral consumption.

Page 40: Doxycycline Common Ion Impact

  • Doxycycline’s solubility adjustments in acidic versus basic environments highlight its specific ion response behavior.

Page 41: Calculating Molar Solubility of PbI2

  • Example Calculation Summary:

    • Ksp = 7.1 x 10^-9; determination from dissociation equations leads to molar solubility outcome.

Page 42: Learning Outcomes Repeat

  • Reiteration of key concepts in solubility and product calculations details.

Page 43: Contact Information

  • For more information contact: Dr. Darren Griffith

  • Email: dgriffith@rcsi.com.