Compounds and Stoichiometry

Stink Bug Compounds

  • Stink bugs produce a solution of volatile compounds that smells bad.
  • The main compounds are hydrogen cyanide (toxic, inhibits cytochrome c oxidase, blocking aerobic respiration) and benzoyl benzaldehyde.
  • Benzaldehyde vaporizes at room temperature.
  • At low concentrations, benzaldehyde smells like toasted almonds, but at high concentrations, it smells like rotten almonds and irritates the skin, eyes, and respiratory tract.
  • Benzaldehyde is a compound with 7 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom.
  • One mole of benzaldehyde has a mass of about 106 grams.

Compounds

  • Compounds are pure substances composed of two or more elements in a fixed proportion.
  • Compounds can be broken down chemically.
  • Compounds are characterized by their physical and chemical properties.

Topics Covered

  • Representing compounds using empirical and molecular formulas and percent composition is covered.
  • Major classes of chemical reactions are briefly reviewed and will be examined more closely later.
  • Balancing chemical equations, identifying limiting reagents, and calculating reaction yields are recapped.

Molecules and Moles

  • A molecule is a combination of two or more atoms held together by covalent bonds.
  • Molecules are the smallest units of compounds that display their identifying properties.
  • Molecules can be composed of two or more atoms of the same element (e.g., N<em>2N<em>2, O</em>2O</em>2) or different elements (e.g., CO<em>2CO<em>2, COCl</em>2COCl</em>2, C<em>6H</em>5CHOC<em>6H</em>5CHO).
  • Reactions usually involve a large number of molecules, so compounds are measured in moles or grams.
  • Molar mass is used to interconvert between moles and grams.

Ionic Compounds

  • Ionic compounds do not form true molecules because of how oppositely charged ions arrange in the solid state.
  • Solid NaCl is a coordinated lattice where each Na+Na^+ ion is surrounded by ClCl^- ions, and each ClCl^- ion is surrounded by Na+Na^+ ions.
  • The term formula unit, representing the empirical formula, is used instead of molecule.
  • Molecular weight is meaningless, so the term formula weight is used instead.

Molecular Weight

  • Atomic weight is a weighted average of the masses of naturally occurring isotopes.
  • Molecular weight is the sum of the atomic weights of all atoms in a molecule, measured in atomic mass units (amu) per molecule.
  • The formula weight of an ionic compound is found by adding the atomic weights of the constituent ions according to its empirical formula, also in AMU per molecule.
Example: Molecular Weight of SOCl2SOCl_2
  • One S: 1×32.1AMU=32.1AMU1 \, \times \, 32.1 \, \text{AMU} = 32.1 \, \text{AMU}
  • One O: 1×16AMU=16AMU1 \, \times \, 16 \, \text{AMU} = 16 \, \text{AMU}
  • Two Cl: 2×35.5AMU=71AMU2 \, \times \, 35.5 \, \text{AMU} = 71 \, \text{AMU}
  • Total: 32.1+16+71=119.1AMU per molecule32.1 + 16 + 71 = 119.1 \, \text{AMU per molecule}

Mole

  • A mole is a quantity of any substance equal to the number of particles in 12 grams of carbon-12 (126C\frac{12}{6}C).
  • This number is Avogadro's number (NA=6.022×1023mol1N_A = 6.022 \times 10^{23} \, mol^{-1}).
  • One mole of a compound has a mass in grams equal to the molecular or formula weight in AMU.
    • Example: One molecule of carbonic acid (H<em>2CO</em>3H<em>2CO</em>3) has a mass of 62 AMU, and one mole has a mass of 62 grams.
  • The mass of one mole of a compound is called its molar mass, in grams per mole.
  • Molecular weight is measured in amu/molecule, not grams/mol.
  • Formula for determining the number of moles:
    • Moles=Mass of Sample (g)Molar Mass (g/mol)\text{Moles} = \frac{\text{Mass of Sample (g)}}{\text{Molar Mass (g/mol)}}
Example: Moles in 9.53 grams of MgCl2MgCl_2
  1. Find the molar mass of MgCl2MgCl_2: 1×24.3g/mol+2×35.5g/mol=95.3g/mol1 \times 24.3 \, g/mol + 2 \times 35.5 \, g/mol = 95.3 \, g/mol
  2. Solve for the number of moles: 9.53g95.3g/mol=0.1molMgCl2\frac{9.53 \, g}{95.3 \, g/mol} = 0.1 \, mol \, MgCl_2

Equivalent Weight

  • Certain elements or compounds act more potently in certain reactions.
  • One mole of HCl donates one mole of H+H^+ ions.
  • One mole of H<em>2SO</em>4H<em>2SO</em>4 donates two moles of H+H^+ ions.
  • One mole of H<em>3PO</em>4H<em>3PO</em>4 donates three moles of H+H^+ ions.
  • One mole of sodium donates one mole of electrons.
  • One mole of magnesium donates two moles of electrons.
  • Equivalence: How many moles of protons, hydroxide ions, electrons, or ions will one mole of a given compound produce?
  • Gram equivalent weight: The mass of a compound (in grams) that produces one equivalent of the particle of interest.
  • Formula:
    • Gram Equivalent Weight=Molar Massn\text{Gram Equivalent Weight} = \frac{\text{Molar Mass}}{n}, where n is the number of particles of interest produced or consumed per molecule.
    • Example: Need 31g31 \, g of H<em>2CO</em>3H<em>2CO</em>3 (molar mass 62g/mol62 \, g/mol) to produce one equivalent of hydrogen ions because each molecule donates two hydrogen ions (n=2n = 2).
  • The equivalent weight of a compound is the mass that provides one mole of the particle of interest.
  • Formula to determine equivalents:
    • Equivalents=Mass of Compound (g)Gram Equivalent Weight (g)\text{Equivalents} = \frac{\text{Mass of Compound (g)}}{\text{Gram Equivalent Weight (g)}}

Normality

  • Normality (N) is a measure of concentration in units of equivalents per liter (equivalentsL\frac{\text{equivalents}}{L}).
  • Commonly used for hydrogen ion concentration.
  • A 1 N solution of acid contains 1 mole of H+H^+ ions per liter.
  • A 2 N solution of acid contains 2 moles of H+H^+ ions per liter.
  • The actual concentration of the acidic compound may differ due to varying numbers of donatable hydrogen ions.
    • In 1 N HCl, the molarity of HCl is 1 M (monoprotic).
    • In 1 N H<em>2CO</em>3H<em>2CO</em>3, the molarity of H<em>2CO</em>3H<em>2CO</em>3 is 0.5 M (diprotic).
  • Normality calculations assume a reaction proceeds to completion.
    • Even though carbonic acid doesn't fully dissociate, it can react with enough base to give up both protons.
  • Conversion from normality to molarity:
    • Molarity=Normalityn\text{Molarity} = \frac{\text{Normality}}{n}, where n is the number of protons, hydroxide ions, electrons, or ions produced or consumed.
Benefit of Using Equivalents and Normality
  • Allows direct comparison of quantities of interest (e.g.,H+H^+ or OHOH^-).
  • One equivalent of acid (H+H^+) neutralizes one equivalent of base (OHOH^-).
  • One mole of HCl will not completely neutralize one mole of Ca(OH)<em>2Ca(OH)<em>2 because one mole of HCl donates one equivalent of acid, but Ca(OH)</em>2Ca(OH)</em>2 donates two equivalents of base.
Example: Gram Equivalent Weight of Sulfuric Acid (H<em>2SO</em>4H<em>2SO</em>4)
  1. Find the molar mass of H<em>2SO</em>4H<em>2SO</em>4:
    • (2×1.0)+(1×32.1)+(4×16)=98.1g/molH<em>2SO</em>4(2 \times 1.0) + (1 \times 32.1) + (4 \times 16) = 98.1 \, g/mol \, H<em>2SO</em>4
  2. Identify the equivalents (protons, H+H^+), since these are transferred in acid-base reactions. The number of protons in sulfuric acid (nn) is 2.
  3. Calculate the gram equivalent weight:
    • Gram Equivalent Weight=Molar Massn=98.1g/molH<em>2SO</em>42molH+/molH<em>2SO</em>4=49.05g/molH+\text{Gram Equivalent Weight} = \frac{\text{Molar Mass}}{n} = \frac{98.1 \, g/mol \, H<em>2SO</em>4}{2 \, mol \, H^+/mol \, H<em>2SO</em>4} = 49.05 \, g/mol \, H^+
Example: Normality of a 2 M Mg(OH)2Mg(OH)_2 Solution
  1. Identify the number of equivalents (nn). There are two hydroxide ions (OHOH^-) for each molecule of Mg(OH)2Mg(OH)_2.
  2. Calculate the normality:
    • Normality=Molarity×n=2M×2equivOH/molMg(OH)<em>2=4NMg(OH)</em>2\text{Normality} = \text{Molarity} \times n = 2 \, M \times 2 \, equiv \, OH^-/mol \, Mg(OH)<em>2 = 4 \, N \, Mg(OH)</em>2