Compounds and Stoichiometry
Stink Bug Compounds
- Stink bugs produce a solution of volatile compounds that smells bad.
- The main compounds are hydrogen cyanide (toxic, inhibits cytochrome c oxidase, blocking aerobic respiration) and benzoyl benzaldehyde.
- Benzaldehyde vaporizes at room temperature.
- At low concentrations, benzaldehyde smells like toasted almonds, but at high concentrations, it smells like rotten almonds and irritates the skin, eyes, and respiratory tract.
- Benzaldehyde is a compound with 7 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom.
- One mole of benzaldehyde has a mass of about 106 grams.
Compounds
- Compounds are pure substances composed of two or more elements in a fixed proportion.
- Compounds can be broken down chemically.
- Compounds are characterized by their physical and chemical properties.
Topics Covered
- Representing compounds using empirical and molecular formulas and percent composition is covered.
- Major classes of chemical reactions are briefly reviewed and will be examined more closely later.
- Balancing chemical equations, identifying limiting reagents, and calculating reaction yields are recapped.
Molecules and Moles
- A molecule is a combination of two or more atoms held together by covalent bonds.
- Molecules are the smallest units of compounds that display their identifying properties.
- Molecules can be composed of two or more atoms of the same element (e.g., N<em>2, O</em>2) or different elements (e.g., CO<em>2, COCl</em>2, C<em>6H</em>5CHO).
- Reactions usually involve a large number of molecules, so compounds are measured in moles or grams.
- Molar mass is used to interconvert between moles and grams.
Ionic Compounds
- Ionic compounds do not form true molecules because of how oppositely charged ions arrange in the solid state.
- Solid NaCl is a coordinated lattice where each Na+ ion is surrounded by Cl− ions, and each Cl− ion is surrounded by Na+ ions.
- The term formula unit, representing the empirical formula, is used instead of molecule.
- Molecular weight is meaningless, so the term formula weight is used instead.
Molecular Weight
- Atomic weight is a weighted average of the masses of naturally occurring isotopes.
- Molecular weight is the sum of the atomic weights of all atoms in a molecule, measured in atomic mass units (amu) per molecule.
- The formula weight of an ionic compound is found by adding the atomic weights of the constituent ions according to its empirical formula, also in AMU per molecule.
Example: Molecular Weight of SOCl2
- One S: 1×32.1AMU=32.1AMU
- One O: 1×16AMU=16AMU
- Two Cl: 2×35.5AMU=71AMU
- Total: 32.1+16+71=119.1AMU per molecule
Mole
- A mole is a quantity of any substance equal to the number of particles in 12 grams of carbon-12 (612C).
- This number is Avogadro's number (NA=6.022×1023mol−1).
- One mole of a compound has a mass in grams equal to the molecular or formula weight in AMU.
- Example: One molecule of carbonic acid (H<em>2CO</em>3) has a mass of 62 AMU, and one mole has a mass of 62 grams.
- The mass of one mole of a compound is called its molar mass, in grams per mole.
- Molecular weight is measured in amu/molecule, not grams/mol.
- Formula for determining the number of moles:
- Moles=Molar Mass (g/mol)Mass of Sample (g)
Example: Moles in 9.53 grams of MgCl2
- Find the molar mass of MgCl2: 1×24.3g/mol+2×35.5g/mol=95.3g/mol
- Solve for the number of moles: 95.3g/mol9.53g=0.1molMgCl2
Equivalent Weight
- Certain elements or compounds act more potently in certain reactions.
- One mole of HCl donates one mole of H+ ions.
- One mole of H<em>2SO</em>4 donates two moles of H+ ions.
- One mole of H<em>3PO</em>4 donates three moles of H+ ions.
- One mole of sodium donates one mole of electrons.
- One mole of magnesium donates two moles of electrons.
- Equivalence: How many moles of protons, hydroxide ions, electrons, or ions will one mole of a given compound produce?
- Gram equivalent weight: The mass of a compound (in grams) that produces one equivalent of the particle of interest.
- Formula:
- Gram Equivalent Weight=nMolar Mass, where n is the number of particles of interest produced or consumed per molecule.
- Example: Need 31g of H<em>2CO</em>3 (molar mass 62g/mol) to produce one equivalent of hydrogen ions because each molecule donates two hydrogen ions (n=2).
- The equivalent weight of a compound is the mass that provides one mole of the particle of interest.
- Formula to determine equivalents:
- Equivalents=Gram Equivalent Weight (g)Mass of Compound (g)
Normality
- Normality (N) is a measure of concentration in units of equivalents per liter (Lequivalents).
- Commonly used for hydrogen ion concentration.
- A 1 N solution of acid contains 1 mole of H+ ions per liter.
- A 2 N solution of acid contains 2 moles of H+ ions per liter.
- The actual concentration of the acidic compound may differ due to varying numbers of donatable hydrogen ions.
- In 1 N HCl, the molarity of HCl is 1 M (monoprotic).
- In 1 N H<em>2CO</em>3, the molarity of H<em>2CO</em>3 is 0.5 M (diprotic).
- Normality calculations assume a reaction proceeds to completion.
- Even though carbonic acid doesn't fully dissociate, it can react with enough base to give up both protons.
- Conversion from normality to molarity:
- Molarity=nNormality, where n is the number of protons, hydroxide ions, electrons, or ions produced or consumed.
Benefit of Using Equivalents and Normality
- Allows direct comparison of quantities of interest (e.g.,H+ or OH−).
- One equivalent of acid (H+) neutralizes one equivalent of base (OH−).
- One mole of HCl will not completely neutralize one mole of Ca(OH)<em>2 because one mole of HCl donates one equivalent of acid, but Ca(OH)</em>2 donates two equivalents of base.
Example: Gram Equivalent Weight of Sulfuric Acid (H<em>2SO</em>4)
- Find the molar mass of H<em>2SO</em>4:
- (2×1.0)+(1×32.1)+(4×16)=98.1g/molH<em>2SO</em>4
- Identify the equivalents (protons, H+), since these are transferred in acid-base reactions. The number of protons in sulfuric acid (n) is 2.
- Calculate the gram equivalent weight:
- Gram Equivalent Weight=nMolar Mass=2molH+/molH<em>2SO</em>498.1g/molH<em>2SO</em>4=49.05g/molH+
Example: Normality of a 2 M Mg(OH)2 Solution
- Identify the number of equivalents (n). There are two hydroxide ions (OH−) for each molecule of Mg(OH)2.
- Calculate the normality:
- Normality=Molarity×n=2M×2equivOH−/molMg(OH)<em>2=4NMg(OH)</em>2