CHM1046 Module 1

Molecular Comparison of States of Matter

  • Physical States of Water:

    • Gas (Steam):

      • Temperature: 100oC100^\text{o}\text{C}

      • Density at 1 atm1\text{ atm}: 5.90×10−4 g/cm35.90 \times 10^{-4}\text{ g/cm}^3

      • Molar Volume: 30.5 L30.5\text{ L}

      • Molecular arrangement: Widely spaced molecules moving rapidly and independently in space.

    • Liquid (Water):

      • Temperature: 20oC20^\text{o}\text{C}

      • Density at 1 atm1\text{ atm}: 0.998 g/cm30.998\text{ g/cm}^3

      • Molar Volume: 18.0 mL18.0\text{ mL}

      • Molecular arrangement: Closely spaced molecules that remain in contact but are free to slide past one another.

    • Solid (Ice):

      • Temperature: 0oC0^\text{o}\text{C}

      • Density at 1 atm1\text{ atm}: 0.917 g/cm30.917\text{ g/cm}^3

      • Molar Volume: 19.6 mL19.6\text{ mL}

      • Molecular arrangement: Closely spaced molecules locked into a fixed three-dimensional framework.


The Three States of Water
  • Fundamental Properties of the States of Matter:

    • Gas:

      • Density: Low

      • Shape: Indefinite (takes the shape of its container)

      • Volume: Indefinite (expands to fill its container)

      • Intermolecular Forces Strength (Relative to Thermal Energy): Weak

      • Compressibility: Highly compressible because molecules are separated by large distances.

    • Liquid:

      • Density: High

      • Shape: Indefinite (assumes the shape of its container)

      • Volume: Definite (resists volume changes)

      • Intermolecular Forces Strength (Relative to Thermal Energy): Moderate

      • Compressibility: Not easily compressible because molecules are already in close contact.

    • Solid:

      • Density: High

      • Shape: Definite (rigid shape)

      • Volume: Definite (resists volume changes)

      • Intermolecular Forces Strength (Relative to Thermal Energy): Strong

      • Compressibility: Not easily compressible due to tight particle packing.


Compressibility of Liquids and Gases
  • Structural Classification of Solids:

    • Crystalline Solids:

      • Definition: Solids whose constituent particles (atoms, ions, or molecules) are arranged in an orderly, repeating, three-dimensional geometric pattern exhibiting long-range order.

      • Examples: Sodium chloride (table salt) and diamond.

    • Amorphous Solids:

      • Definition: Solids whose constituent particles do not possess a regular repeating geometric pattern over a long range.

      • Examples: Plastics and glass.


Crystalline Solid vs Amorphous Solid

Fundamental Nature and Types of Intermolecular Forces

  • Origin of Intermolecular Forces:

    • Intermolecular forces arise from electrostatic interactions between full charges, partial charges, or temporary induced charges on neighboring molecules, atoms, or ions.

    • Intermolecular Forces vs. Intramolecular Bonding:

      • Intramolecular bonding (covalent, ionic, metallic bonds) holds atoms together within a molecule or compound and is governed directly by Coulomb's Law (E=kq1q2rE = \frac{k q_1 q_2}{r}).

      • Intermolecular forces occur between separate molecules and are generally significantly weaker than intramolecular chemical bonds because charges are typically smaller and distances (rr) are larger.

  • Dispersion Forces (London Dispersion Forces):

    • Definition & Mechanism:

      • Present in all atoms and molecules.

      • Caused by fluctuations in the electron distribution within atoms or nonpolar molecules, creating an instantaneous (temporary) dipole.

      • An instantaneous dipole on one atom induces a corresponding dipole on a neighboring atom, resulting in an attractive force.


Dispersion Force Mechanism in Helium Atoms


Induced Instantaneous Dipoles Across Neighboring Atoms
*   **Effect of Molecular Size / Molar Mass**:
    *   Larger electron clouds are more polarizable (easier to distort), leading to stronger dispersion forces and higher boiling points.


Boiling Points of Noble Gases
*   **Effect of Molecular Shape / Surface Area**:
    *   Elongated molecules have a larger surface area of interaction, resulting in stronger dispersion forces than spherical molecules of equal molar mass.


Effect of Molecular Shape on Dispersion Forces
*   Trend in Straight-Chain Alkanes


Boiling Points of n-Alkanes Graph
  • Dipole-Dipole Forces:

    • Definition:

      • Attractive forces present exclusively between polar molecules possessing permanent dipole moments.

      • The positive end (δ+\text{δ}+) of one polar molecule is electrostatically attracted to the negative end (δ−\text{δ}-) of a neighboring polar molecule.


Dipole-Dipole Interaction
*   **Effect of Dipole Moment on Boiling Point** (for molecules of similar molar mass):


Dipole Moment and Boiling Point Correlation
  • Hydrogen Bonding:

    • Definition & Mechanism:

      • An exceptionally strong type of dipole-dipole force occurring when a hydrogen atom is directly bonded to a highly electronegative atom (O\text{O}, N\text{N}, or F\text{F}).

      • The electronegative atom strongly pulls electron density away from hydrogen. Because hydrogen has no inner-shell shielding electrons, its nucleus becomes de-shielded, leaving an exposed proton.

      • This highly concentrated center of positive charge (δ+\text{δ}+) strongly attracts electron pairs on electronegative atoms (O\text{O}, N\text{N}, or F\text{F}) of neighboring molecules.


Hydrogen Bonding in Water and Ethanol
*   **Anomalous Boiling Points in Group 6A Hydrides vs. Group 4A Hydrides**


Boiling Points of Group 4A and 6A Hydrides
  • Ion-Dipole Forces:

    • Definition:

      • Occurs when an ionic compound is mixed with a polar compound.

      • The electrostatic attraction between a full ionic charge (cation or anion) and the partial charge (δ+\text{δ}+ or δ−\text{δ}-) of a polar molecule.

      • Responsible for the hydration and dissolution of ionic solids in water: positive ions (Na+\text{Na}^+) attract the oxygen end (δ−\text{δ}-) of H2O\text{H}_2\text{O}, while negative ions (Cl−\text{Cl}^-) attract the hydrogen end (δ+\text{δ}+) of H2O\text{H}_2\text{O}.


Ion-Dipole Forces
  • Summary Ranking of Intermolecular Forces Strength:

    • Dispersion Force: Present in all molecules/atoms; weakest relative strength.

    • Dipole-Dipole Force: Present in polar molecules; moderate relative strength.

    • Hydrogen Bonding: Present in molecules containing H\text{H} bonded to F\text{F}, O\text{O}, or N\text{N}; strong relative strength.

    • Ion-Dipole Force: Present in mixtures of ionic compounds and polar compounds; strongest relative intermolecular force.


Summary of Intermolecular Forces

Intermolecular Forces in Action: Liquid Properties

  • Surface Tension:

    • Definition: The energy required to increase the surface area of a liquid by a given amount, or the quantitative measure of the elastic force at the surface of a liquid.

    • Molecular Mechanism:

      • Interior molecules experience intermolecular attractions in all directions, yielding no net force.

      • Surface molecules experience attractions only downward and sideways into the liquid, yielding a net inward force pulling surface molecules toward the interior.

      • To maximize interior interactions, liquids minimize their surface area, assuming spherical droplets.

    • Specific Value: Surface tension of water is 0.073 J/m20.073\text{ J/m}^2 at room temperature.


Surface Tension Molecular Diagram


Paperclip Supported by Surface Tension
  • Viscosity:

    • Definition: The resistance of a liquid to flow.

    • Units: 1 poise=1 P=1 g cm−1s−11\text{ poise} = 1\text{ P} = 1\text{ g}\text{ cm}^{-1}\text{s}^{-1}. Commonly expressed in centipoise (cP\text{cP}).

    • Dependence on Temperature:

      • Viscosity decreases as temperature increases because higher thermal energy overcomes intermolecular forces.

      • Viscosity of Water at Various Temperatures:

        • 20oC20^\text{o}\text{C}: 1.002 cP1.002\text{ cP}

        • 40oC40^\text{o}\text{C}: 0.653 cP0.653\text{ cP}

        • 60oC60^\text{o}\text{C}: 0.467 cP0.467\text{ cP}

        • 80oC80^\text{o}\text{C}: 0.355 cP0.355\text{ cP}

        • 100oC100^\text{o}\text{C}: 0.282 cP0.282\text{ cP}

    • Dependence on Molecular Structure / Molar Mass:

      • Viscosity increases with higher molar mass and longer molecular chains due to increased dispersion forces and molecular entanglement.

      • Viscosity of nn-Hydrocarbons at 20oC20^\text{o}\text{C}:

        • n-Pentanen\text{-Pentane} (C5H12\text{C}_5\text{H}_{12}): Molar mass = 72.15 g/mol72.15\text{ g/mol}, Viscosity = 0.240 cP0.240\text{ cP}

        • n-Hexanen\text{-Hexane} (C6H14\text{C}_6\text{H}_{14}): Molar mass = 86.17 g/mol86.17\text{ g/mol}, Viscosity = 0.326 cP0.326\text{ cP}

        • n-Heptanen\text{-Heptane} (C7H16\text{C}_7\text{H}_{16}): Molar mass = 100.2 g/mol100.2\text{ g/mol}, Viscosity = 0.409 cP0.409\text{ cP}

        • n-Octanen\text{-Octane} (C8H18\text{C}_8\text{H}_{18}): Molar mass = 114.2 g/mol114.2\text{ g/mol}, Viscosity = 0.542 cP0.542\text{ cP}

        • n-Nonanen\text{-Nonane} (C9H20\text{C}_9\text{H}_{20}): Molar mass = 128.3 g/mol128.3\text{ g/mol}, Viscosity = 0.711 cP0.711\text{ cP}

  • Capillary Action:

    • Definition: The ability of a liquid to flow against gravity up a narrow tube.

    • Interplay of Forces:

      • Cohesive Forces: Intermolecular attractions between liquid molecules themselves.

      • Adhesive Forces: Attractions between liquid molecules and the surface of the tube.

    • Meniscus Shapes in Glass Tubes:

      • Water: Forms a concave meniscus because adhesive forces between water and glass (silicate surfaces) are stronger than cohesive forces among water molecules.

      • Mercury: Forms a convex meniscus because cohesive metallic bonding forces among mercury atoms are stronger than adhesive forces between mercury and glass.


Capillary Action and Meniscus Formation in Water vs Mercury

Vaporization, Vapor Pressure, and Thermodynamics

  • Process of Vaporization (Evaporation):

    • Molecules in a liquid are in constant kinetic motion.

    • Thermal energy determines the kinetic energy distribution of molecules (described by Maxwell-Boltzmann distributions).

    • Only molecules at the liquid surface with kinetic energy exceeding the minimum threshold needed to overcome intermolecular attractions can escape into the gas phase.

    • Temperature Effect: Higher temperature shifts the kinetic energy distribution to higher values, increasing the fraction of surface molecules capable of evaporating.


Thermal Energy Distribution and Escape Threshold
  • Volatility:

    • Volatile Liquids: Liquids that evaporate easily due to weak intermolecular forces (e.g., acetone, diethyl ether).

    • Nonvolatile Liquids: Liquids that do not evaporate easily due to strong intermolecular forces (e.g., motor oil, glycerol).

  • Heat of Vaporization (ΔHvapΔH_\text{vap}):

    • Definition: The enthalpy change required to vaporize one mole of liquid to gas at constant temperature and pressure.

    • Vaporization is endothermic (ΔHvap>0ΔH_\text{vap} > 0); condensation is exothermic (ΔHcond=−ΔHvapΔH_\text{cond} = -ΔH_\text{vap}).

    • Comparison of Heats of Vaporization:

      • Water (H2O\text{H}_2\text{O}): Normal boiling point = 100oC100^\text{o}\text{C}, ΔHvapΔH_\text{vap} at boiling point = 40.7 kJ/mol40.7\text{ kJ/mol}, ΔHvapΔH_\text{vap} at 25oC25^\text{o}\text{C} = 44.0 kJ/mol44.0\text{ kJ/mol}

      • Rubbing alcohol / Isopropyl alcohol (C3H8O\text{C}_3\text{H}_8\text{O}): Normal boiling point = 82.3oC82.3^\text{o}\text{C}, ΔHvapΔH_\text{vap} at boiling point = 39.9 kJ/mol39.9\text{ kJ/mol}, ΔHvapΔH_\text{vap} at 25oC25^\text{o}\text{C} = 45.4 kJ/mol45.4\text{ kJ/mol}

      • Acetone (C3H6O\text{C}_3\text{H}_6\text{O}): Normal boiling point = 56.1oC56.1^\text{o}\text{C}, ΔHvapΔH_\text{vap} at boiling point = 29.1 kJ/mol29.1\text{ kJ/mol}, ΔHvapΔH_\text{vap} at 25oC25^\text{o}\text{C} = 31.0 kJ/mol31.0\text{ kJ/mol}

      • Diethyl ether (C4H10O\text{C}_4\text{H}_{10}\text{O}): Normal boiling point = 34.6oC34.6^\text{o}\text{C}, ΔHvapΔH_\text{vap} at boiling point = 26.5 kJ/mol26.5\text{ kJ/mol}, ΔHvapΔH_\text{vap} at 25oC25^\text{o}\text{C} = 27.1 kJ/mol27.1\text{ kJ/mol}

  • Dynamic Equilibrium & Vapor Pressure:

    • In a closed container, vaporization occurs until the concentration of gas-phase molecules reaches a level where the rate of condensation equals the rate of evaporation.

    • Dynamic Equilibrium Equation: Rate of Evaporation=Rate of Condensation\text{Rate of Evaporation} = \text{Rate of Condensation}

    • Vapor Pressure: The pressure exerted by a gas in dynamic equilibrium with its liquid phase.

    • Disturbance of Dynamic Equilibrium (Le Chatelier's Principle):

      • Volume Increase: Pressure drops, rate of vaporization exceeds condensation rate until equilibrium pressure is restored.

      • Volume Decrease: Pressure rises, rate of condensation exceeds vaporization rate until equilibrium pressure is restored.


Dynamic Equilibrium Establishment


Disturbance of Dynamic Equilibrium by Volume Changes
  • Boiling Point and Vapor Pressure Curves:

    • Boiling Point: Temperature at which the liquid's vapor pressure equals the external pressure.

    • Normal Boiling Point: Boiling point under an external pressure of 1 atm1\text{ atm} (760 torr760\text{ torr} or 760 mmHg760\text{ mmHg}).

      • Diethyl ether normal boiling point: 34.6oC34.6^\text{o}\text{C}

      • Ethyl alcohol (ethanol) normal boiling point: 78.3oC78.3^\text{o}\text{C}

      • Water normal boiling point: 100oC100^\text{o}\text{C}


Vapor Pressure Curves of Various Liquids
  • Clausius-Clapeyron Relationship:

    • The non-linear temperature dependence of vapor pressure is expressed linearly by the Clausius-Clapeyron equation:         α(Pvap)=−ΔHvapR×1T+α(β)α(P_\text{vap}) = -\frac{ΔH_\text{vap}}{R}\times \frac{1}{T} + α(β)         where R=8.314 J mol−1K−1R = 8.314\text{ J}\text{ mol}^{-1}\text{K}^{-1}, TT is absolute temperature in Kelvin, and ββ is a chemical constant.

    • Plot Analysis:

      • Plotting α(Pvap)α(P_\text{vap}) on the y-axis vs. 1T\frac{1}{T} on the x-axis yields a straight line with slope m=−ΔHvapRm = -\frac{ΔH_\text{vap}}{R}.

      • Calculated Example from Experimental Data:

        • Slope = −3478 K-3478\text{ K}

        • ΔHvap=−(slope)×R=−(−3478 K)×8.314 J mol−1K−1=28.92×103 J/mol=28.92 kJ/molΔH_\text{vap} = -(\text{slope}) \times R = -(-3478\text{ K}) \times 8.314\text{ J}\text{ mol}^{-1}\text{K}^{-1} = 28.92 \times 10^3\text{ J/mol} = 28.92\text{ kJ/mol}


Clausius-Clapeyron Linear Plot
*   **Two-Point Form of the Clausius-Clapeyron Equation**: