Thermodynamics 2: Le Chatelier's Principle and Additivity of Free Energy

Overview of Objectives

  • Predict how changes in concentration influence the direction and magnitude of reactions (Le Chatelier’s Principle).

  • Balance equations for two sequential biochemical reactions.

  • Calculate the overall riangleGoriangle G^o for two sequential biochemical reactions.

  • Calculate the overall riangleGriangle G for two sequential biochemical reactions.

Le Chatelier's Principle

  • Definition:

    • "When equilibrium is disturbed the reaction will respond to nullify the disturbance."

  • Scope:

    • Applies to reversible reactions.

  • Disturbances that can affect equilibrium include:

    • Change in temperature.

    • Change in pH.

    • Change in concentrations of [reactants] or [products].

Temperature Effects on Exothermic Reactions

  • Exothermic Reactions:

    • Heat is released as a product.

    • Example Reaction:

    • NO<em>2(g)N</em>2O4(g)+heatNO<em>2 (g) \rightleftharpoons N</em>2O_4 (g) + \text{heat}

    • Color Change: Brown to Colorless

    • Enthalpy Change: riangleH=13.6kcal/moleriangle H = -13.6 \text{kcal/mole}

  • Effect of Temperature:

    • Adding heat can reverse the direction of the reaction.

    • Removing heat will favor the forward reaction.

pH Changes and Buffer Responses

  • Buffers:

    • Substances that minimize changes in pH.

  • Situations:

    • If pH increases:

    • Conjugate acid (HA) releases [H+].

    • Consequence: [HA] decreases; [A-] increases.

    • If pH decreases:

    • Conjugate base (A-) picks up [H+].

    • Consequence: [HA] increases; [A-] decreases.

Response to Changes in Concentration

  • Example of Sugar Interconversion:

    • In glycolysis, the interconversion of glucose-6-phosphate (G6P) and fructose-6-phosphate (F6P) is a vital reaction.

    • If initially [G6P]=[F6P][G6P] = [F6P], reaction direction based on concentration changes:

    • If [F6P][F6P] increases: Reaction proceeds to the right (toward G6P).

    • If [G6P][G6P] decreases: Reaction proceeds to the left (toward F6P).

    • Equilibrium Constant: Keq=1.97K_{eq} = 1.97.

Practical Limitations of Reversible Reactions

  • Some reactions may be theoretically reversible, but practically irreversible under biological conditions.

  • Example:

    • Glucose Oxidation:

    • C<em>6H</em>12O<em>6+6O</em>26CO<em>2+6H</em>2OC<em>6H</em>{12}O<em>6 + 6O</em>2 \rightarrow 6CO<em>2 + 6H</em>2O

    • Gibbs Free Energy Change: riangleGo=686kcal/moleriangle G^o = -686 \text{kcal/mole}.

Additivity of Free Energy

  • In cellular processes, the oxidation of glucose to CO2 and H2O is executed in multiple smaller reactions.

    • Total free energy from these steps accounts for the overall free energy of glucose oxidation.

    • Total Reaction Gibbs Free Energy Change: riangleGo=686kcal/molriangle G^o = -686 \text{kcal/mol} for the entire process from Glucose to CO2 and H2O.

Multiplying/Dividing KeqK_{eq} and Adding/Subtracting Free Energy

  • When modifying equilibrium constants or free energy:

    • Multiplying KeqK_{eq}:

    • RTln(Keq<em>1Keq</em>2)=Go<em>1+Go</em>2-RT \ln (Keq<em>1 \cdot Keq</em>2) = \triangle G^o<em>1 + \triangle G^o</em>2

    • Dividing KeqK_{eq}:

    • RTln(Keq<em>1Keq</em>2)=Go<em>1Go</em>2-RT \ln \left( \frac{Keq<em>1}{Keq</em>2} \right) = \triangle G^o<em>1 - \triangle G^o</em>2

  • Properties of logarithms used here:

    • Adding Exponents = Adding Logs:

    • log<em>10(102102)=log</em>10(102)+log10(102)\log<em>{10}(10^2 \cdot 10^2) = \log</em>{10}(10^2) + \log_{10}(10^2)

    • Subtracting Exponents = Subtracting Logs:

    • log<em>10(105/102)=log</em>10(105)log10(102)\log<em>{10}(10^5/10^2) = \log</em>{10}(10^5) - \log_{10}(10^2).

Relationship Between Equilibrium Constants and Free Energy Changes

  • A 10-fold change in K<em>eqK<em>{eq} or Q</em>cQ</em>c corresponds to a change in free energy Go\triangle G^o or G\triangle G of:

    • 1.36kcal/mol1.36 \text{kcal/mol}.

  • Additional Information:

    • Conversion factor: 1kcal=4.184kJ1 \text{kcal} = 4.184 \text{kJ}.

Sequential Biochemical Reactions and Additivity of Free Energy

  • Overcoming Unfavorable Reactions:

    • Phosphorylation of glucose, a part of glycolysis, is endergonic:

    • Balanced Overall Equation:

    • Glucose+Piglucose-6-phosphate\text{Glucose} + \text{Pi} \rightarrow \text{glucose-6-phosphate}

    • Go=+3.3kcal/mole\triangle G^o = +3.3 \text{kcal/mole}

    • Coupling Reaction:

    • ATPADP+Pi\text{ATP} \rightarrow \text{ADP} + \text{Pi}

    • Go=7.3kcal/mole\triangle G^o = -7.3 \text{kcal/mole}

  • Importance of Coupling:

    • This coupling is essential in driving endergonic reactions forward by harnessing energy from exergonic reactions such as ATP hydrolysis.

Conclusion

  • Acknowledgments:

    • Thank you for your attention!

    • Focus on the principles of Le Chatelier's Principle and additivity of free energy to master the dynamics of biochemical reactions.