Study Notes on Acceleration
Quarter 4 Lesson 1: Acceleration
Introduction to Acceleration
Definition: Acceleration is the rate at which an object's velocity changes, which can occur in terms of:
Magnitude (speed)
Direction of motion
Types of Acceleration:
Constant Acceleration: An object's velocity changes by a constant amount over time.
Changing Acceleration: The object’s velocity varies over time.
Types of Movement:
Linear Acceleration: Movement in a straight line while changing speed.
Curvilinear Acceleration: Movement along non-linear paths, e.g., circular motion.
Forces and Acceleration
Cause of Acceleration:
An unbalanced force acting on an object causes acceleration.
Mathematical Expression of Acceleration:
The formula for acceleration is: a = \frac{v}{t} where:
a = acceleration
v = change in velocity
t = change in time
Interpretation: This equation illustrates the relationship between acceleration and changes in speed.
Positive and Negative Acceleration
Positive Acceleration: Occurs when an object speeds up.
Negative Acceleration (Deceleration): Occurs when an object slows down.
Examples of Acceleration
Common instances of acceleration include:
A car accelerating on a flat road at a constant rate.
A block sliding on a horizontal surface experiencing a constant force.
Types:
Uniform Acceleration: Velocity changes at a constant rate.
Non-Uniform Acceleration: Velocity changes by non-constant intervals over time.
Understanding Accelerating and Non-Accelerating Objects
Accelerating (A)
An object is accelerating if there is a change in velocity, which can manifest as:
Change in speed (speeding up or decelerating).
Change in direction (turning or moving in a curve).
Example: Even if speed remains constant, if the direction changes, the object is still accelerating.
Not Accelerating (NA)
An object is not accelerating if:
It is at rest (not moving).
It moves at a constant speed in a straight line (same speed and same direction).
True or False Assessments
Assess statements regarding acceleration by marking True or False:
An object accelerates when an unbalanced force is acting on it. (True)
Acceleration is defined as the rate of change of an object's velocity. (True)
A car moving at a constant speed on a straight road is accelerating. (False)
Non-uniform acceleration is characterized by a constant change in velocity over equal time intervals. (False)
An example of uniform acceleration is a roller coaster that speeds up and slows down throughout the ride. (False)
Vector vs Scalar Quantities
Vector Quantity:
Has both magnitude and direction.
Examples: acceleration, velocity, weight.
Scalar Quantity:
Has only magnitude.
Examples: speed, mass, volume.
Acceleration Formulas and Examples
Fundamental Formulas
Acceleration Formula: a = \frac{v{f} - v{i}}{t} where:
v_{f} = final velocity
v_{i} = initial velocity
t = time elapsed
Worked Examples
Sample Problem 1: A jeepney changes its velocity from 17 m/s to 23 m/s in 5 seconds.
Given:
v_{i} = 17 \, \text{m/s}
v_{f} = 23 \, \text{m/s}
t = 5 \text{ s}
Solution:
a = \frac{23 - 17}{5} = 1.2 \, \text{m/s}^2Answer: The jeepney's acceleration is 1.2 m/s².
Sample Problem 2: A car accelerates at a rate of 3.0 m/s² from an initial velocity of 8.0 m/s to a final velocity of 25.0 m/s.
Given:
a = 3.0 \, \text{m/s}^2
v_{i} = 8.0 \, \text{m/s}
v_{f} = 25.0 \, \text{m/s}
Required:
t = ?
Formula:
t = \frac{v{f} - v{i}}{a}Solution:
t = \frac{25.0 - 8.0}{3.0} = 5.67 \, \text{s}Answer: It takes 5.67 s for the car to accelerate from 8.0 m/s to 25.0 m/s.
Sample Problem 3: An LRT train accelerates from rest at 1.25 m/s² for 20 seconds.
Given:
a = 1.25 \, \text{m/s}^2
v_{i} = 0 \, \text{m/s} (stops from rest)
t = 20 \text{ s}
Formula:
v{f} = v{i} + atSolution:
v_{f} = 0 + (1.25 & \text{m/s}^2 \times 20 \, \text{s}) = 25 \, \text{m/s}Answer: The final velocity is 25 m/s.
Sample Problem 4: During a race, an athlete accelerates at 1.5 m/s² from an initial speed of 3 m/s for 4 seconds.
Given:
a = 1.5 \, \text{m/s}^2
v_{i} = 3 \, \text{m/s}
t = 4 \text{ s}
Formula:
v{f} = v{i} + atSolution:
v_{f} = 3 + (1.5 \times 4) = 3 + 6 = 9 \, \text{m/s}Answer: The final velocity is 9 m/s.
Sample Problem 5: A pedicab accelerates at 2 m/s² from rest to a final speed of 6 m/s.
Given:
a = 2 \, \text{m/s}^2
v_{i} = 0 \, \text{m/s}
v_{f} = 6 \, \text{m/s}
Required:
t = ?
Formula:
t = \frac{v{f} - v{i}}{a}Solution:
t = \frac{6 - 0}{2} = 3 \, \text{s}Answer: It takes 3 seconds to reach that final velocity.
Sample Problem 6: A motorcycle traveling at 25 m/s accelerates at 8 m/s² for 5 seconds.
Given:
v_{i} = 25 \, \text{m/s}
a = 8 \, \text{m/s}^2
t = 5 \, \text{s}
Formula:
v{f} = v{i} + atSolution:
v_{f} = 25 + (8 \times 5) = 25 + 40 = 65 \, \text{m/s}Answer: The final speed is 65 m/s.
Conclusion
Understanding acceleration involves the grasping of fundamental concepts surrounding forces, motion, and the mathematical interpretations that define changes in velocity.
Practical understanding is bolstered through extensive problem-solving and real-world applications.