Forces, Motion, & Energy - Lesson 8 Notes
Forces, Motion, & Energy
- Year 10 Physics
- Lesson 8 focuses on:
- Explaining changes in momentum as caused by a net force: \Delta p = F_{net} \Delta t
- Analysing impulse in an isolated system (collisions between objects moving in a straight line): F \Delta t = m \Delta v
- Investigating and analysing momentum theoretically and practically.
- Area of Study 1
Goal and Success Criteria
- Goal: Describe momentum of moving objects and analyse changes in momentum during collisions.
- Success Criteria:
- Describe momentum quantitatively and qualitatively.
- Calculate the impulse on an object during a collision.
- Apply the theory of conservation of momentum to two objects colliding in a closed system.
- Question: Why do cars crumple & airbags explode?
Key Vocabulary
- Momentum
- Conservation of Momentum
- Mass
- Velocity
- Impulse
Crumple Zones
- Crumple zones are a structural safety feature in vehicles.
- They increase the time over which a change in velocity (and consequently momentum) occurs during a collision through controlled deformation.
Air Bags
- Sensors detect abrupt deceleration during an accident.
- A signal is sent to a heating element in the airbag circuit, causing a small explosion.
- This explosion rapidly fills the nylon airbag with gas, expanding it to act as a cushion.
- Chemical reaction: 2 NaN3 \rightarrow 2 Na + 3 N2
- 130 grams of sodium azide produces 67 liters of nitrogen gas, sufficient to inflate a normal airbag.
Momentum
- All objects with mass, if moving, have momentum.
- Momentum depends on:
- How much "stuff" (mass) is moving.
- How fast the "stuff" is moving (velocity).
Momentum Example
- Truck vs. Sports Car:
- If a truck and a sports car are traveling at the same speed, the truck has more momentum due to its larger mass.
- Police Car vs. Escape Vehicle:
- If a police car and an escape vehicle have the same mass, but the police car is catching up, the police car has more momentum because it has higher velocity.
- Collision Scenario:
- Question: Would you rather be in a collision with a sprinter (mass: 65 kg, speed: 7 ms-1) or a rugby player (mass: 91 kg, speed: 5 ms-1)?
Momentum Equation
- Momentum (p) is calculated as: p = mv
- p = momentum (kg ms-1)
- m = mass (kg)
- v = velocity (ms-1)
Momentum Example (Continued)
- Sprinter:
- Mass = 65 kg
- Speed = 7 ms-1
- Momentum = 455 kg ms-1
- Rugby Player:
- Mass = 91 kg
- Speed = 5 ms-1
- Momentum = 455 kg ms-1
- In this specific scenario, the momentum is the same for both.
Momentum vs. Inertia
- Similarities:
- Both relate to an object's resistance to changes in motion.
- Key Differences:
- Momentum is quantitative (assignable value), while inertia is qualitative (describable with words).
- A stationary object has zero momentum but still possesses inertia.
Momentum Calculation Examples
- Example 1: Calculate the momentum of a 65.0 kg student walking at 3.50 ms-1 east.
- Example 2: Calculate the mass of a car driving at 16.7 ms-1 north with a momentum of 20 500 kg ms-1.
Impulse
- Impulse refers to a fast-acting force or impact.
- Defined as the sudden force acting on an object for a short interval of time.
- Impulse is equal to the change in momentum of an object.
- Impulse is also equal to the net force applied on an object multiplied by the duration the force is applied.
Impulse Equations
- J = \Delta p
- J = impulse
- \Delta p = change in momentum (kg ms-1)
- J = F_{net} \times \Delta t
- F_{net} = Net force (N)
- \Delta t = change in time (s)
- Remember: \Delta = change = final - initial
Force-Time Graph for Impulse
- A force-time graph shows the relationship between the force applied to an object and the time over which it is applied.
- The y-axis represents force (F) in Newtons (N), and the x-axis represents time (t) in seconds (s).
- The area under the curve of a force versus time graph represents the impulse delivered to an object.
Impulse and Collision Time
- For any collision with a fixed change in momentum, if the time of contact is increased, the peak force is reduced.
Impulse and Newton's Second Law
- F_{net} = ma = m \frac{\Delta v}{\Delta t}
- F_{net} \times \Delta t = m \times \Delta v
- F_{net} = \frac{\Delta p}{\Delta t}
- Where:
- F_{net} = Net force (N)
- m = mass of the object (kg)
- a = acceleration (ms-2)
- v = velocity (ms-1)
- t = time (s)
- p = momentum (kg ms-1)
- \Delta = change = final - initial
- Where:
Impulse Calculation Examples
- Example 3: Calculate the impulse of a 9.50 kg dog that changes its velocity from 2.5 ms-1 north to 6.25 ms-1 south.
- Example 4: The momentum of a ball of mass 125g changes by 0.075 kg ms-1 south. If its initial velocity was 3.00 ms-1 north, what is its final velocity?
- Example 5: A 45.0 kg mass changes its velocity from 2.45 ms-1 east to 12.5 ms-1 east in a period of 3.50 s.
- Calculate the change in momentum of the mass.
- Calculate the impulse of the mass.
- Calculate the force that causes the impulse of the mass.
- Extension: A student drops a 105g pool ball onto a concrete floor from a height of 2.00m. Just before it hits the floor, the velocity of the ball is 6.26 ms-1 down. Before it bounces back up, there is an instant in time where its velocity is zero. The time it takes for the ball to change its velocity is 5.02 milliseconds.
- Calculate the impulse of the pool ball.
- Calculate the average net force that acts to cause the impulse.
Conservation of Momentum
- Momentum is conserved in an interaction or collision between objects.
- The total momentum before a collision equals the total momentum after the collision in a closed system.
Conservation of Momentum Equation
- \Sigma pi = \Sigma pf
- m1u1 + m2u2 = m1v1 + m2v2
- Where:
- p = momentum (kg ms-1)
- m = mass of the object (kg)
- u = initial velocity (ms-1)
- v = final velocity (ms-1)
- Where:
Conservation of Momentum Examples
- Example 6: Ball A (2.0 kg, 2.0 ms-1 west) collides with Ball B (4.0 kg, 1.0 ms-1 west). After the collision, Ball A moves westward at 1.0 m/s. What is the velocity of Ball B after the collision?
- Example 7: A 0.50 kg ball at 6.0 ms-1 east collides head-on with a 1.00 kg ball at 12.0 ms-1 west. After the collision, the 0.50 kg ball moves away at 14 ms-1 west. Find the velocity of the second ball after the collision.
- Example 8: A railroad car (30 000 kg, 2.2 ms-1 east) collides with another railroad car (30 000 kg) at rest. If they stick together, what is the velocity of the two cars?
Practice Questions
- Choose your Goldilocks questions:
- Discover: I need to practice.
- Develop: I’m starting to get it.
- Deepen: I’m ready for a challenge.
- Instructions:
- Choose a level that's not too easy or too hard.
- Start at one level and adjust as needed.
- Write out the question and answer, including all working.
- Remember to include the equation and full substitution for full marks.
Your Turn - Questions
Discover
- Question 1: A 5 kg bowling ball is rolled with a velocity of 10 ms-1. What is its momentum?
- Question 2: A 155g baseball is incoming at a velocity of 25 ms-1 towards the batter… What is the magnitude of the impulse acting on the ball during the hit?
Develop
- Question 1: Determine the momentum of: a 110 kg professional fullback running across the line at 9.2 ms-1, a 360 000 kg passenger plane taxiing down a runway at 1.5 ms-1.
- Question 2: Calculate the momentum of a 110 kg football player running at 8.0 ms-1 Compare the player’s momentum with the momentum of a 0.410 kg football thrown hard at a speed of 25 ms-1
Review
- Explain how crumple zones or airbags keep people safe in a car crash.