L6 - Nernst Equation and Eh-pH Diagrams

Redox Reactions Continued

Review of Redox Reactions

  • Recap of yesterday's topics:

    • Introduction to redox reactions.

    • Oxidation number: calculation and significance.

    • Balancing redox reactions.

    • Potential or electromotive force (EMF): measure of electrochemical energy in redox reactions.

      • Related to Gibbs free energy.

      • Convenient way to measure energy flow associated with electron transfer.

    • Standard hydrogen potential: potential of a half-reaction coupled with the standard hydrogen electrode.

    • Redox reactions in natural environments.

Today's Focus

  • Introducing the Nernst equation: its derivation, meaning, and usage.

  • Eh-pH diagrams: their utility in aqueous geochemistry.

    • Analogous to mineral stability diagrams (covered last week).

    • Two-dimensional diagrams with Eh (redox potential) as one axis and pH as the other.

The Nernst Equation

  • Derivation:

    • Based on known equations.

    • Relationship between Gibbs free energy and potential (from yesterday):

      • ΔG=nFE\Delta G = -nFE

    • Under standard conditions (25°C, 1 bar, activities = 1):

      • ΔG0=nFE0\Delta G^0 = -nFE^0

    • Relationship between free energy, standard free energy, and reaction quotient (from earlier lectures):

      • ΔG=ΔG0+RTlnQ\Delta G = \Delta G^0 + RT \ln{Q}

    • Combining these equations gives the Nernst equation.

  • Nernst Equation:

    • E=E0RTnFlnQE = E^0 - \frac{RT}{nF} \ln{Q}

  • Simplified version (at 25°C, converting to base-10 logarithm):

    • E=E00.0592nlog10QE = E^0 - \frac{0.0592}{n} \log_{10}{Q}

Uses of the Nernst Equation

  • Calculates the potential of a redox reaction under non-standard conditions.

  • Example: Reduction of iron(III) to iron(II) by hydrogen gas.

    • Fe3++12H2Fe2++H+Fe^{3+} + \frac{1}{2}H_2 \rightleftharpoons Fe^{2+} + H^{+}

    • Calculate the standard potential (E0E^0) from standard free energies of formation.

      • E0E^0 (for this reaction) = 0.77 V0.77\text{ V}.

    • Nernst equation:

      • E=E0RTnFlnQE = E^0 - \frac{RT}{nF} \ln{Q}

      • E=E0RTnFlnaFe2+aH+aFe3+PH2E=E^0-\frac{RT}{nF}\ln{\frac{a_{Fe^{2+}}\cdot a_{H^+}}{a_{Fe^{3+}}\cdot\sqrt{P_{H_2}}}}

      • If you measure concentration of iron, pH, and hydrogen partial pressure, then you can estimate the potential.

Standard Hydrogen Potential

  • Potential of a redox couple (half-reaction) measured against the standard hydrogen electrode.

  • Standard hydrogen electrode: solution with protons at 1 mol/L and hydrogen gas at 1 atm.

  • For the Fe3+/Fe2+Fe^{3+}/Fe^{2+} couple:

    • EH=EH0RTnFlnaFe3+aFe2+E_{H}=E_{H}^0-\frac{RT}{nF}\ln{\frac{a_{Fe^{3+}}}{a_{Fe^{2+}}}}

      • Subscript H indicates measurement against standard hydrogen electrode.

  • Generalized form:

    • EH=E0+RTnFlnactivity product of oxidized speciesactivity product of reduced speciesE_{H} = E^0 + \frac{RT}{nF} \ln{\frac{\text{activity product of oxidized species}}{\text{activity product of reduced species}}}

    • aea_{e^-} is equal to 1.

    • EH=E0+0.0592nlogactivity product of oxidized speciesactivity product of reduced speciesE_{H} = E^0 + \frac{0.0592}{n} \log{\frac{\text{activity product of oxidized species}}{\text{activity product of reduced species}}}

    • Note that the fraction in the log has been flipped because of the sign change.

  • Example application:

    • Reducing environment (e.g., sediments): Measure EH=0.2V{E}_{H} = -0.2 V

      • Means massively more iron(II) than iron(III).

    • Oxidizing environment (e.g., surface seawater): Measure EH=0.8V\text{E}_{H} = 0.8 V

      • Means more iron(III) than iron(II).

Eh-pH Diagrams

  • Eh and pH are important environmental variables.

    • pH: Controls proton concentration; important for acid-base reactions, carbonate systems, mineral precipitation/dissolution.

    • Eh: Indicates how oxidized or reducing the environment is; controls distribution and concentration of redox-sensitive elements.

  • Construction:

    • Similar to mineral stability diagrams.

    • Lines represent equilibrium between species.

    • Diagrams are drawn for a specific pressure and temperature (typically 25°C and 1 bar).

    • Always include stability limits of water.

      • Water is stable within a certain range of Eh and pH conditions.

      • Limits are determined by the oxidation of water to oxygen.

    • Upper limit:

      • H2O12O2+2H++2eH_2O \rightleftharpoons \frac{1}{2}O_2 + 2H^+ + 2e^-

      • The upper limit is constrained by the oxidation of water to dioxygen

  • Stability limits of water can be represented by equation. The upper and lower limits of water in the environment are:

    • Upper Limit: EH,H2OUpper=1.230.0592pHE^{Upper}_{H,H_2O}=1.23-0.0592pH

    • Lower Limit: EH,H2OLower=0.0592pHE^{Lower}_{H,H_2O} = -0.0592pH

Example: Eh-pH Diagram for Iron-Oxygen-Water System

  • System: Iron, oxygen, and water at 25°C and 1 bar.

  • Minerals considered: Magnetite (Fe3O4Fe3O4) and Hematite (Fe2O3Fe2O3).

  • Dissolved species: Fe2+Fe^{2+} and Fe3+Fe^{3+}.

  • Total activity of the dissolved Fe species: aFe=106a_{Fe}=10^{-6}

  • Gibbs energy of formation for all species:

  • Assume a total activity of dissolved iron species (e.g., 10610^{-6} mol/L).

Steps to Build the Diagram
  • Boundary between Fe2+Fe^{2+} and Fe3+Fe^{3+}

  • Oxidation numbers are different, so it's a redox reaction.

    1. Half-reaction: Fe3++eFe2+Fe^{3+} + e^- \rightleftharpoons Fe^{2+}

    2. Calculate standard free energy of the reaction:

      • ΔG0=ΔGf0(Fe2+)ΔGf0(Fe3+)=73.3 kJ/mol\Delta G^0 = \Delta G_f^0(Fe^{2+}) - \Delta G_f^0(Fe^{3+}) = -73.3 \text{ kJ/mol}

    3. Calculate standard potential:

      • EH0=ΔG0nF=73300 J/mol(1)(96485 C/mol)=0.76 VE_H^0 = -\frac{\Delta G^0}{nF} = \frac{73300 \text{ J/mol}}{(1)(96485 \text{ C/mol})} = 0.76 \text{ V}

    4. Apply the Nernst equation:

      • EH=EH0+0.0592nlogaFe3+aFe2+E_H = E_H^0 + \frac{0.0592}{n} \log{\frac{a_{Fe^{3+}}}{a_{Fe^{2+}}}}

      • Looking at this equation, we can see that

    5. Boundary condition: activities of Fe3+Fe^{3+} and Fe2+Fe^{2+} are equal, so the log term equals 0

      • E=0.76 VE=0.76\text{ V}

      • Horizontal line on the Eh-pH diagram.

    6. Fe3+Fe^{3+} stable above the line (more oxidizing conditions), Fe2+Fe^{2+} stable below.

  • Boundary between Magnetite and Hematite

    • Oxidation numbers of iron are different, so it's a redox reaction.

    • Balanced redox reaction:

      • 3Fe2O3+2H++2e2Fe3O4+H2O3Fe_2O_3 + 2H^+ + 2e^- \rightleftharpoons 2Fe_3O_4 + H_2O

    • Calculate standard free energy of reaction using standard free energy of formations.

    • Calculate the standard potential: EH0=0.152 VE_H^0 = 0.152 \text{ V}

    • Apply the Nernst equation:

      • EH=EH0+0.0592nlogaH+2E_H = E_H^0 + \frac{0.0592}{n} \log{a_{H^+}^2}

      • E=0.1520.0592pHE = 0.152 - 0.0592pH

    • Plot line: y-intercept = 0.152, negative slope with pH.

    • Hematite is more oxidized, so it's above the line; magnetite is below.

  • Boundary between Fe3+Fe^{3+} and Hematite

    • Oxidation number of iron is the same in both species (Fe(III)), so it's not a redox reaction. This means that the reaction is independent of EHE_H

    • Mineral dissolution reaction: Fe2O3+6H+2Fe3++3H2OFe_2O_3 + 6H^+ \rightleftharpoons 2Fe^{3+} + 3H_2O

    • Calculate the free energy using ΔGr0=RTlnK\Delta G_r^0=-RT \ln{K} and rearranging for K.

    • Write law of mass action:

      • K=aFe3+2aH+6K = \frac{a_{Fe^{3+}}^2}{a_{H^+}^6}

      • log(K)=2log(aFe3+)+6pHlog(K) = 2log(a_{Fe^{3+}}) + 6pH

    • Boundary condition: activity of Fe3+Fe^{3+} equals total dissolved iron activity.

    • Solve for pH to plot the vertical line.

    • Hematite stable at high Ph.

  • Boundary between Fe2+Fe^{2+} and Hematite

    • Redox or not?

    • Apply Nernst equation.

    • Remember that at the boundary I have this boundary condition where the activity of the solute is 10 to the -6.

Uses of Eh-pH Diagrams

  • Predict what is likely to happen in a system.

  • Determine conditions in the geological record.