Vectors and Scalars

Scalar Quantities

  • Definition: A scalar is any quantity in physics that possesses magnitude only and no inherent direction.

    • Magnitude = numerical value + proper units.

  • Common scalar examples (with magnitudes shown in the transcript):

    • Speed – 20 m/s20\ \text{m/s}

    • Distance – 10 m10\ \text{m}

    • Age – 15 years15\ \text{years}

    • Heat (energy) – 1000 calories1000\ \text{calories}

  • Conceptual importance:

    • Scalars are added/subtracted by ordinary arithmetic because direction does not matter.

    • Many everyday measurements (time, temperature, mass) are scalars and require no directional notation.

Vector Quantities

  • Definition: A vector is any quantity in physics that has both magnitude and direction.

  • Standard notation

    • Printed in bold‐face italic with an arrow overhead, e.g. v\vec{v}, F\vec{F}.

    • Direction indicated by arrow orientation; magnitude by arrow length (graphically) or by a numerical value + units (algebraically).

  • Transcript examples (magnitude, then direction):

    • Velocity – 20 m/s, North20\ \text{m/s, North}

    • Acceleration – 10 m/s2, East10\ \text{m/s}^2\text{, East}

    • Force – 5 N, West5\ \text{N, West}

  • Anatomy of a drawn vector arrow

    • Tail → starting point

    • Head → arrow-point indicating direction

    • Arrow shaft length → proportional to magnitude

  • Compass convention for angles/directions (all eight forms listed):

    • N of E,<br>E of N,<br>S of W,<br>W of S,<br>N of W,<br>W of N,<br>S of E,<br>E of S\text{N of E,<br>E of N,<br>S of W,<br>W of S,<br>N of W,<br>W of N,<br>S of E,<br>E of S}

  • Sample directional statements (from Page 6 diagram):

    • Vector A → due North

    • Vector B → 4040^{\circ} North of West

    • Vector C → 3535^{\circ} East of South

    • Vector D → 3030^{\circ} North of East

Vector Addition & Subtraction in One Dimension

  • Same direction → add magnitudes

    • Example: Walk 54.5 m East+30 m East=84.5 m East54.5\ \text{m East} + 30\ \text{m East} = 84.5\ \text{m East}

    • Key observation: Arrow lengths add head-to-tail, overall arrow points East.

  • Opposite directions → subtract magnitudes

    • Example: Walk 54.5 m East+30 m West54.5\ \text{m East} + 30\ \text{m West}

    • Net: 24.5 m East24.5\ \text{m East} (direction of larger component)

Right-Angle (Perpendicular) Vector Addition

  • If vectors are perpendicular, construct a right triangle and use Pythagoras:

    • Resultant magnitude: R=(x‐component)2+(y‐component)2R = \sqrt{(x\text{‐component})^2 + (y\text{‐component})^2}

    • Components (legs) lie head-to-toe.

  • Transcript example

    • Walk 95 km East95\ \text{km East} then 55 km North55\ \text{km North}.

    • Magnitude: R=952+552km=109.8 kmR = \sqrt{95^2 + 55^2}\,\text{km} = 109.8\ \text{km}

    • Direction (angle from East toward North):
      θ=tan1!(5595)30\theta = \tan^{-1}!\left(\dfrac{55}{95}\right) \approx 30^{\circ}

    • Complete answer: 109.8 km, 30 N of E109.8\ \text{km, }30^{\circ}\text{ N of E}

  • General trig relations for right triangles (with xx horizontal, yy vertical):

    • cosθ=xR    x=Rcosθ\cos \theta = \dfrac{x}{R} \;\Rightarrow\; x = R\cos \theta

    • sinθ=yR    y=Rsinθ\sin \theta = \dfrac{y}{R} \;\Rightarrow\; y = R\sin \theta

    • tanθ=yx\tan \theta = \dfrac{y}{x} (used when RR is not yet known)

Naming and Measuring Angles

  • A direction label like “North of East” must be paired with an exact angle for complete specification.

  • Always state from-compass referencetoward-rotation (e.g.
    30 N of E30^{\circ}\ \text{N of E} means rotate 3030^{\circ} from East toward North).

  • Angles on full 360° circle often measured counter-clockwise from +x (East) for coordinate calculations.

Worked Example 1 – Multi-Leg Displacement (Bear)

  1. Path segments (with direction & magnitude)

    • 35 m East35\ \text{m East}

    • 20 m North20\ \text{m North}

    • 12 m West12\ \text{m West}

    • 6 m South6\ \text{m South}

  2. Combine East–West components

    • 3512=23 m East35−12 = 23\ \text{m East}

  3. Combine North–South components

    • 206=14 m North20−6 = 14\ \text{m North}

  4. Resultant magnitude
    R=232+142m=26.93 mR = \sqrt{23^2 + 14^2}\,\text{m} = 26.93\ \text{m}

  5. Direction
    θ=tan1!(1423)=31.3\theta = \tan^{-1}!\left(\dfrac{14}{23}\right) = 31.3^{\circ} (North of East)

  6. Final displacement: 26.93 m, 31.3 N of E26.93\ \text{m, }31.3^{\circ}\text{ N of E}

Worked Example 2 – Relative Velocity (Boat + River)

  1. Boat velocity in still water: 15 m/s, North15\ \text{m/s, North}

  2. River current: 8.0 m/s, West8.0\ \text{m/s, West}

  3. Components

    • vx=8.0 m/sv_x = −8.0\ \text{m/s} (West negative)

    • vy=+15 m/sv_y = +15\ \text{m/s} (North positive)

  4. Resultant speed
    R=(8.0)2+152m/s17 m/sR = \sqrt{(-8.0)^2 + 15^2}\,\text{m/s} \approx 17\ \text{m/s}

  5. Direction
    θ=tan1!(8.015)=28.1\theta = \tan^{-1}!\left(\dfrac{8.0}{15}\right) = 28.1^{\circ} West of North

  6. Report: 17 m/s, 28.1 W of N17\ \text{m/s, }28.1^{\circ}\text{ W of N}

Rectangular Coordinate System (Reference)

  • Positive xx → East (right); Positive yy → North (up).

  • Quadrants numbered counter-clockwise (I: +x,+y; II: −x,+y; III: −x,−y; IV: +x,−y).

  • Angles often quoted from +x axis: standard position.

Vector Components – Resolving a Single Force

  • Generic formulas (magnitude FF, angle θ\theta measured from +x):

    • Fx=FcosθF_x = F \cos \theta

    • Fy=FsinθF_y = F \sin \theta

  • Example A (57 N @ 4343^{\circ} above +x)

    • Fx=57cos43=41.69 NF_x = 57\cos 43^{\circ} = 41.69\ \text{N}

    • Fy=57sin43=38.87 NF_y = 57\sin 43^{\circ} = 38.87\ \text{N}

  • Example B (103 N @ 6565^{\circ} above –x)

    • First convert to standard angle: 18065=115180^{\circ}−65^{\circ}=115^{\circ}

    • Fx=103cos115=43.53 NF_x = 103\cos 115^{\circ} = −43.53\ \text{N} (negative → West)

    • Fy=103sin115=93.35 NF_y = 103\sin 115^{\circ} = 93.35\ \text{N} (positive → North)

  • Sign convention: Component signs tell quadrant automatically.

General Problem-Solving Strategy for Vectors

  • Draw a clear scaled diagram; label all known magnitudes and directions.

  • Break each vector into xx and yy components when NOT colinear.

  • Add algebraically: ΣF<em>x\Sigma F<em>x, ΣF</em>y\Sigma F</em>y (or Σv<em>x,Σv</em>y\Sigma v<em>x, \Sigma v</em>y etc.).

  • Compute resultant magnitude with Pythagoras.

  • Determine direction using inverse trig; specify with proper compass language.

  • Check limiting cases: If one component ≈0, final angle should approach 0° or 90° accordingly.

Conceptual & Real-World Relevance

  • Scalars vs. vectors distinction underpins virtually all areas of physics (kinematics, dynamics, electromagnetism).

  • Navigation (aviation, maritime) relies on vector addition of velocities (wind/current corrections).

  • Engineering uses vector components to determine stresses and forces in multiple dimensions.

  • Ethical / safety angle: precise vector calculations prevent accidents in transportation and construction by ensuring correct magnitudes and headings.

Key Equations (Quick Reference)

  • Pythagorean Theorem (2-D): R=a2+b2R = \sqrt{a^2 + b^2}

  • Component Formulas: x=Rcosθ,  y=Rsinθx = R\cos \theta\,,\; y = R\sin \theta

  • Inverse Tangent for Angle: θ=tan1!(yx)\theta = \tan^{-1}!\left(\dfrac{y}{x}\right)

  • Colinear Addition/Subtraction: R=±(A±B)R = \pm (A \pm B) (sign from dominant direction)

Common Pitfalls & Tips

  • Always attach units to magnitudes; an un-unitized number is physically meaningless.

  • Draw vectors head-to-tail when adding; tail-to-tail only when constructing components.

  • When giving directions, never write just “North of East” – include the numeric angle.

  • Use a consistent sign convention; switching mid-solution causes sign errors.

  • Approximations: keep at least two extra significant figures in intermediate steps; round final answer responsibly.