Calculus - 2.2 - The Limit of a Function

Limits of Functions

Estimating Limits

  • Graphical Estimation:
    • Observe the behavior of y=f(x)y = f(x) as xx approaches a certain value (e.g., x=1x = 1).
    • Estimate the limit limxaf(x)\lim_{x \to a} f(x) by looking at what y-value the graph approaches.
    • Example: If as xx gets close to 1, yy gets close to 2, then limx1f(x)=2\lim_{x \to 1} f(x) = 2.
  • Numerical Estimation:
    • Create a table of values for f(x)f(x) for xx values close to the value of interest.
    • Examine the table to see what value f(x)f(x) approaches as xx gets closer to the target.
    • Example: Estimate limx2(x2+1)\lim_{x \to 2} (x^2 + 1) by plugging in xx values close to 2 (e.g., 1.9, 1.99, 2.01, 2.1) and observing that f(x)f(x) approaches 5.
  • Important Note:
    • The limit of f(x)f(x) as xx approaches aa is NOT necessarily the same as the value of f(a)f(a).
    • limxaf(x)\lim_{x \to a} f(x) depends on the behavior of f(x)f(x) near x=ax = a, not necessarily at x=ax = a.
    • It's entirely possible that f(a)f(a) is undefined, but limxaf(x)\lim_{x \to a} f(x) still exists.
    • When finding limxaf(x)\lim_{x \to a} f(x), we should NEVER consider x=ax = a.

Minimum Required Steps for Graphing Problems

  1. State Equation(s): Explicitly state the equation(s) you are graphing (e.g., y1=x2+1,y2=y1 = x^2 + 1, y2 = …).
  2. Sketch the Graph: Draw a sketch of the graph.
  3. State the Viewing Window: Specify the viewing window used (e.g., [X<em>min,X</em>max,X<em>scl]×[Y</em>min,Y<em>max,Y</em>scl][X<em>{min}, X</em>{max}, X<em>{scl}] \times [Y</em>{min}, Y<em>{max}, Y</em>{scl}]).
  4. Identify the Solution: Clearly indicate where on the graph you found the solution.
  5. State the Final Answer: Provide the final answer to the problem.

Minimum Required Steps for Numerical Problems (Tables)

  1. State Equation(s): Explicitly state the equation(s) you are using to generate the table (e.g., y1=,y2=y1 = …, y2 = …).
  2. Table of Values: Create a table including several points on both sides of the value you are approaching.
  3. State the Final Answer: Provide the final answer to the problem.

Limit Definition

  • We write limxaf(x)=L\lim_{x \to a} f(x) = L and say "the limit of f(x)f(x) as xx approaches aa, equals LL if we can make the values of the function f(x)f(x) arbitrarily close to LL (as close to LL as we like) by taking xx sufficiently close to aa (on either side) but not equal to aa.

Examples

  • Example 1:

    • Consider a function f(x)f(x) where f(1)=1f(1) = -1 and limx1f(x)=2\lim_{x \to 1} f(x) = 2.
    • This illustrates that the limit as xx approaches 1 can be different from the function's value at x=1x = 1.
  • Example 2: limx0sin(x)x=1\lim_{x \to 0} \frac{\sin(x)}{x} = 1

    • This is a fundamental limit that is important to memorize.
    • The table of values shows that as xx approaches 0, sin(x)x\frac{\sin(x)}{x} approaches 1.
  • Example 3: Piecewise Function

  • Example 4:

    • Given f(x)={xx,amp;x0 1,amp;x=0f(x) = \begin{cases} \frac{x}{x}, &amp; x \neq 0 \ 1, &amp; x = 0 \end{cases}
    • a) lim<em>x0f(x)=lim</em>x0xx=1\lim<em>{x \to 0^-} f(x) = \lim</em>{x \to 0^-} \frac{x}{x} = 1
    • b) lim<em>x0+f(x)=lim</em>x0+xx=1\lim<em>{x \to 0^+} f(x) = \lim</em>{x \to 0^+} \frac{x}{x} = 1
    • However, limx03x\lim_{x \to 0} \frac{3}{x} DNE because the left and right limits aren't equal.
    • c) f(0)=1f(0) = 1

Finding x values within a range

  • Given f(x)=x2x+2f(x) = x^2 - x + 2, find the values of x, where f(x)f(x) is within 0.1 of 4.
  • That is, find x such that 3.9 < f(x) < 4.1
  • Graph y1=x2x+2y1 = x^2 - x + 2, y2=3.9y2 = 3.9 and y3=4.1y3 = 4.1
  • The intersections occur at (1.966, 3.9) and (2.033, 4.1).

Pitfalls and Considerations

  • Guessing the Limit:
    • Guessing limits from calculated values can be misleading.
    • Calculators and computers can sometimes give wrong answers.
    • Tables and graphs only provide estimates of the limit.
  • Algebraic Methods:
    • Algebraic methods are more foolproof for finding limits.
      Example: Find the limit limx0sin(1x)\lim_{x \to 0} \sin(\frac{1}{x})
    • The limit DNE because sin(1x)\sin(\frac{1}{x}) oscillates and does not approach a fixed number.

One-Sided Limits

  • Left-Hand Limit:
    • limxaf(x)=L\lim_{x \to a^-} f(x) = L means the limit of f(x)f(x) as xx approaches aa from the left equals LL.
    • We can make the values of f(x)f(x) arbitrarily close to LL by taking xx sufficiently close to aa and x < a.
  • Right-Hand Limit:
    • limxa+f(x)=L\lim_{x \to a^+} f(x) = L means the limit of f(x)f(x) as xx approaches aa from the right equals LL.
    • We can make the values of f(x)f(x) arbitrarily close to LL by taking xx sufficiently close to aa and x > a.

*Heaviside function: H={0amp;if tlt;0 1amp;if t0H = \begin{cases} 0 &amp; \text{if } t &lt; 0 \ 1 &amp; \text{if } t \geq 0 \end{cases}
*Limit from the left: Approaches 0*
Limit from the right: approaches 1