Physics Notes: Linear Momentum and Collisions
Linear Momentum
Definition: Linear momentum (P) of a mass (m) moving with velocity (v) is given by:
P m vMomentum is a vector quantity. The direction of momentum (p) is the same as the direction of the velocity (v).
Units: [p] = kg·m/s (no special name assigned).
The symbol P for momentum is used due to the unavailability of the letter "m" (already defined for mass).
Total Momentum:
For multiple masses, the total momentum can be expressed as:
p{tot} P = P1 + P2 + P3 + … = Sum m v
Conservation of Momentum:
Momentum is conserved in a system isolated from external forces. This principle states:
Momentum cannot be created or destroyed, only transferred from one object to another.
Implications similar to Conservation of Energy, always true without exceptions.
Proofs of momentum conservation to follow later.
Collision Illustration:
For two colliding objects A and B:
Before collision:
p{tot,before} = mA vA + mB v_BAfter collision:
p{tot,after} = mA v'A + mB v'_BMomentum conservation ensures
p{tot,before} = p{tot,after}Individual velocities change during the collision, but total momentum remains constant.
Types of Collisions
Elastic Collision:
Definition: Total kinetic energy (KE) is conserved. (KE before = KE after)
Example: A rubber ball bouncing on concrete shows minimal energy loss; KE is converted to elastic potential energy (PE) upon compression and back to KE while decompressing.
Inelastic Collision:
Some kinetic energy is lost to other forms of energy (thermal, sound, etc.).
Perfectly Inelastic Collision:
Two objects collide and stick together post-collision.
Note: All macroscopic collisions are inelastic (some kinetic energy is always lost). However, atomic-level collisions can be elastic, as in the case of air molecules.
One-Dimensional Collisions
Direction Representation:
Direction of velocities (v) in one dimension uses signs:
(+) = right
(-) = left
Example velocities:
v_A = +2 m/s (moving right)
v_B = -3 m/s (moving left)
Caution with Notation:
The symbol "v" may represent speed (always positive) in some contexts but represents velocity (whose sign can be either positive or negative) in 1D collision problems.
Collisions Example (Perfectly Inelastic):
Objects A (moving) and B (at rest) collide and stick together:
Total momentum before collision:
p{tot,before} = mA vA + mB(0) = mA vATotal momentum after collision:
p{tot,after} = (mA + m_B)v'Setting them equal gives:
mA vA = (mA + mB)v'Therefore:
v' = rac{mA}{(mA + mB)} vANote that ( v' < vA ) since ( rac{mA}{(mA + mB)} < 1 ).
Recoil Example (Gun Firing)
Situation: A Gun (mass M) fires a bullet (mass m) with velocity ( vb ). Calculating recoil velocity of the gun (vG ) yields:
p{tot, before}=0 = m vb + M v_GSolving gives:
M vG = -m vbTherefore:
vG = - rac{m}{M} vbGiven (vb = 500 m/s), (m = 0.01 kg), and (M = 3 kg): vG = - rac{0.01 kg imes 500 m/s}{3 kg} = -0.167 m/s
Interpretation: recoil occurs (gun’s backward motion when bullet is fired).
Rocket Functionality Explanation: Rockets function based on this principle of momentum transfer (mass ejected backward causes forward propulsion).
Impulse and Momentum Conservation
Impulse: A concept relating force to the change in momentum. Defined as:
J = F_{net} imes ext{time}Newton emphasized the relationship:
F_{net} = rac{dp}{dt}The net force is the rate of change of momentum.
Impulse Equation with Variable Force:
J = ext{net} F_{avg} imes ext{d}t = rac{d}{dt}igg( ext{Force} imes t igg) = ext{net} rac{ ext{d}p}{ ext{d}t}Example with Baseball:
Given a baseball (mass 0.30 kg), and a collision duration ( igtriangleup t = 0.01s ): impact forces yield:
Initial velocity (vi = -42 m/s), final (vf = 80 m/s):
Impulse calculation yields:
J = ext{mass} imes (vf - vi) = 0.30 kg imes (80m/s - (-42m/s))
Therefore:
J hickapprox 37 kg imes m/s
• Impulse direction is to the right (indicating net directional momentum).Average force exerted during the collision is calculated as:
F = rac{J}{igtriangleup t} hickapprox 3700 N
Proof of Momentum Conservation in Collisions
Proof Overview:
When objects A and B collide, each experiences equal and opposite forces (Newton’s Third Law).
Change in momentum of A equals the negative change in momentum of B:
igtriangleup pA = -igtriangleup pB
Total momentum change in isolated system:
igtriangleup (pA + pB) = 0 ext{ gives } p_{tot} = constant
Note: Momentum conservation holds if the system is isolated (without external forces affecting).
Ballistic Pendulum Example
Description: Used to measure bullet speed: consists of a hanging block hitting a bullet, which embeds into it and swings upwards.
Momentum and KE Analysis:
Initial Momentum:
m v1 = (M + m)v2Initial KE is partially converted to thermal energy.
After swinging, calculate max height reached (h), using:
KE{initial} = PE{final} ext{ and } h = rac{KE}{M+m ext{g}}
Elastic Collisions
Eulerian References:
For both momentum (p) and kinetic energy (KE), conservation laws apply:
mA vA + mB vB = mA v'A + mB v'B (momentum)
rac{1}{2} mA vA^2 + rac{1}{2} mB vB^2 = rac{1}{2} mA (v'A)^2 + rac{1}{2} mB (v'B)^2 (kinetic energy)
Key Equation: For elastic collisions, relative speeds before and after the collision relate via:
(vA - vB) = -(v'A - v'B)Practical Solution: Using these principles can let one solve for final velocities easily.
Example Collision: When mass (10m) with velocity collides with resting mass (m) yields:
Applying conservation principles:
AA = 10m vA + 0 = 10m vA' + m vB'Followed with elastic collision relationship, yields:
Final calculation gives values for velocities after the collision.Summary of final velocities may be stated as:
vA' = rac{(mA - mB)vA + 2mB v{B}}{(mA + mB)}
vB' = rac{(mB - mA)vB + 2mA v{A}}{(mA + mB)}
Center of Mass of Extended Objects
Definition: The point that behaves as if all mass were located at this point. Given by:
RM = rac{1}{M} ext{ ext{Sum}}{i=1}^{N} mi r_iFor an extended object with many particles, it simplifies computation.
Location Calculation: Given a set of four masses in a square, through weighted averages define center of mass.
Velocity and Acceleration: Defined as:
Velocity of c.m.:
V = rac{ ext{Sum}{i=1}^{N} mi v_i}{M}Acceleration of c.m.:
A = rac{ ext{Sum}{i=1}^{N} mi a_i}{M}Dynamics governing c.m. equivalent to point mass dynamics.
Overall Dynamics: The total external forces acting on a system affect the motion of the center of mass, while internal forces cancel out.
Practical Example: Upon explosion during trajectories and projectiles, c.m. behaves akin to the point mass pre-explosion.
Conclusion
The principles of momentum conservation apply rigorously for both isolated systems and particles subject to collective interactions, with practical examples ranging from classical mechanics to real-world applications like rocket propulsion and collision analyses.