Year-13 Physics — Rotational Dynamics & Banked Curves
Banked-Curve & Circular-Motion Applications
Design question 5
- Required banking angle for a roadway when
- Design speed v = 13.2\,\text{m\,s}^{-1}
- Curve radius r = 48.0\,\text{m}
- Friction-free condition implies
\tan\theta = \frac{v^{2}}{rg} - Used in road safety, racetrack design, aviation (tilted wings).
Design question 6 (race-track)
- Two limiting radii on a concrete, friction-free, banked oval
- Inner lane r_{\min}=112\,\text{m}
- Outer lane r_{\max}=165\,\text{m}
- Wall height h = 18\,\text{m} allows determination of banking angle by simple trigonometry (rise/run). Once \theta is fixed the usable speed range is
v{\min}=\sqrt{rg\tan\theta}\,,\qquad v{\max}=\sqrt{rg\tan\theta}\,\Big|{r=r{\max}} - Shows how a single surface can be safe for different radii.
Design question 7 (Ferris wheel)
- Child mass m=40\,\text{kg}, radius r=10\,\text{m}, constant speed v=3\,\text{m\,s}^{-1}.
- Forces on rider
- Bottom: N_{\text{bottom}}=mg+\frac{mv^{2}}{r} (heavier feeling)
- Top: N_{\text{top}} = mg-\frac{mv^{2}}{r} (lighter feeling).
- Demonstrates interplay of apparent weight and centripetal requirement.
Rotational Dynamics — Motivation
- Extended bodies (wheels, planets, motors) cannot be analysed as point masses because their particles have differing linear speeds.
- Need rotational analogues of displacement, velocity, acceleration, force.
Angular Variables
Angular Displacement \theta
- Measured in radians: \theta = \frac{s}{r} (arc length over radius).
- One revolution =2\pi\,\text{rad}.
Angular Velocity \omega
- Rate of change of angular displacement: \omega = \frac{d\theta}{dt} (units \text{rad\,s}^{-1}).
- Linear connection: v = r\omega.
- Frequency relation: \omega = 2\pi f.
Angular Acceleration \alpha
- Rate of change of angular velocity: \alpha=\frac{d\omega}{dt} (units \text{rad\,s}^{-2}).
- If \omega changes uniformly: \alpha = \frac{\omega{f}-\omega{i}}{\Delta t}.
- Linear link: a_{t}=r\alpha (tangential acceleration).
Uniform Angular Acceleration — Kinematic Equations
- Exact analogues of linear s,u,v,a,t equations.
- \omega{f}=\omega{i}+\alpha t
- \theta = \omega_{i}t + \tfrac12 \alpha t^{2}
- \omega{f}^{2}=\omega{i}^{2}+2\alpha\theta
Linear↔Angular Variable Table
- Speed: u,v\;\leftrightarrow\;\omega{i},\omega{f}
- Displacement: s\;\leftrightarrow\;\theta
- Acceleration: a\;\leftrightarrow\;\alpha
Worked Example 1.13 — Photographic Record
- Starts from rest, reaches 45\,\text{rev\,min}^{-1} (i.e. 4.71\,\text{rad\,s}^{-1}) in 5\,\text{s}.
- Angular acceleration \alpha=0.94\,\text{rad\,s}^{-2}.
- Revolutions covered in this startup =11.75\,\text{rev}.
Practice Problems (Exercise 1.5)
- Convert Earth’s orbital period T=3.156\times10^{7}\,\text{s} to \omega_{\text{earth}}.
- Wheel speed on a moving bicycle, v=7.5\,\text{m\,s}^{-1}, r=0.30\,\text{m}.
- Flywheel deceleration from 500\,\text{Hz} to rest in 5\,\text{s}.
- Car wheel slowdown: r=0.36\,\text{m}, v=18\,\text{m\,s}^{-1}, N=25\,\text{turns}.
- etc.
Moment of Inertia I
- Rotational analogue of mass: I=\sum m{i} r{i}^{2}.
- Depends on mass distribution relative to axis.
- Units \text{kg\,m}^{2}.
Standard Shapes (about stated axes)
- Hoop / thin cylindrical shell: I = MR^{2}.
- Solid cylinder/disc: I = \tfrac12 MR^{2}.
- Hollow cylinder: I = \tfrac12 M\left(R{1}^{2}+R{2}^{2}\right).
- Thin rod (centre): I = \tfrac1{12} ML^{2}.
- Thin rod (end): I = \tfrac13 ML^{2}.
- Solid sphere: I = \tfrac25 MR^{2}.
- Thin spherical shell: I = \tfrac23 MR^{2}.
- Rectangular plate (axis through centre, perpendicular): I = \tfrac1{12}M(a^{2}+b^{2}).
Examples
- Point mass m=2\,\text{kg} on string r=0.6\,\text{m} ⇒ I=0.72\,\text{kg\,m}^{2}.
- Two-mass dumb-bell: m{1}=2\,\text{kg}, m{2}=3\,\text{kg}, L=1\,\text{m}. About midpoint ⟂ to rod:
I = m{1}\left(\tfrac12L\right)^{2}+m{2}\left(\tfrac12L\right)^{2}=1.25\,\text{kg\,m}^{2}.
Torque \tau
- Rotational effectiveness of a force: \tau = rF_{\perp} = I\alpha (units \text{N\,m}).
- Produced by string tension in falling-mass apparatus, figure-of-eight belts, engine crankshafts.
Torque–Acceleration Derivation (Example 1.15)
- Uniform disc I=\tfrac12 m r^{2} hanging by wrapped string.
- Translational mg - T = ma; rotational \tau = Tr = I\alpha with a=r\alpha.
- Solve ⇒ linear acceleration a = \tfrac23 g(i.e., two-thirds of free fall).
- Demonstrates energy sharing: some gravitational PE goes to rotational KE.
Angular Momentum L
- For rigid body: L = I\omega.
- For point mass: L = r m v = m r^{2} \omega (direction via right-hand rule).
- Units \text{kg\,m}^{2}\,\text{s}^{-1}.
Conservation Principle
- If external torque \sum \tau{\text{ext}} = 0, then L{\text{initial}} = L_{\text{final}}.
- Enables ice-skater spin-ups, neutron-star dynamo predictions, merging-disk problems.
Worked Examples (1.16)
- Wheel accelerated by \tau=100\,\text{N\,m} from rest to \omega=20\,\text{rad\,s}^{-1} over \theta=10\,\text{rad}.
- Using \omega^{2}=2\alpha\theta ⇒ \alpha=20\,\text{rad\,s}^{-2}.
- Moment of inertia from \tau=I\alpha ⇒ I=5\,\text{kg\,m}^{2}.
- Angular momentum gained \Delta L = I\omega = 100\,\text{kg\,m}^{2}\text{s}^{-1}.
- Two coaxial disks couple (clutch problem).
- Disk A: I{1}=2\,\text{kg\,m}^{2}, \omega{1}=10\,\text{rad\,s}^{-1}.
- Disk B: I{2}=3\,\text{kg\,m}^{2}, \omega{2}=0.
- After drop: \omega{f}=\tfrac{I{1}\omega{1}+I{2}\omega{2}}{I{1}+I_{2}}=4\,\text{rad\,s}^{-1}.
Additional Exercises (1.6)
- Turntable–record coupling, I{1}=0.09, I{2}=0.03\,\text{kg\,m}^{2}.
- Cylindrical spacecraft attitude control via expelled gas: each puff m=0.4\,\text{kg}, v=100\,\text{m\,s}^{-1} at r=2\,\text{m}.
- Linear momentum per puff p=mv.
- Angular momentum delivered L=rp, conserve to find craft’s \Delta\omega.
Conceptual & Real-World Connections
- Banking removes dependence on tyre friction ⇒ higher safety margins.
- Ferris-wheel apparent-weight changes underpin design of safe lap-bars.
- Disk-clutch coupling is mechanical analogue of perfectly inelastic collision.
- Moment of inertia critical in flywheels (energy storage) & figure-skating (artistic spins).
- Torque link to power P=\tau\omega governs engine ratings.
- Conservation of angular momentum fundamental in astrophysics (planet formation, pulsars).
Ethical & Practical Notes
- Proper banking saves lives by reducing skidding accidents.
- Amusement-ride designers must account for human tolerance to varying normal forces.
- Rocket attitude thrusters must conserve propellant while delivering required angular impulse.