Got it! I'll combine the explanations and examples with the earlier notes, keeping everything organized. This way, the concepts flow together logically, with examples integrated where appropriate. I'll break it down so you can see how different situations fit within the broader context of limits and continuity.
Graphically, you can estimate the limit of a function at a certain point by looking at the behavior of the function as xx approaches that point from both the left and right sides.
Key Observation: If the left-hand limit and the right-hand limit match at the point, and the function is defined there, then the limit exists and is equal to the function value.
Numerically, you can approximate the limit by substituting values of xx that are increasingly close to the point of interest.
If the limits from the left and right are equal at a point, the limit exists.
If the function behaves differently on the left and right, the limit does not exist.
When you evaluate limits analytically, we follow specific techniques to compute the limit at a point. Here's how we approach different situations:
If you’re evaluating limits where the function is continuous, you can directly substitute the value into the function.
Example: limx→2(x2)=22=4\lim_{x \to 2} (x^2) = 2^2 = 4
If the limit from the left and right are different, the limit does not exist at the point.
Example: f(x)={x2,if x<23,if x=2x+1,if x>2f(x) = \begin{cases} x^2, & \text{if } x < 2 \\ 3, & \text{if } x = 2 \\ x + 1, & \text{if } x > 2 \end{cases}
Left-hand limit at x=2x = 2:
limx→2−f(x)=22=4\lim_{x \to 2^-} f(x) = 2^2 = 4
Right-hand limit at x=2x = 2:
limx→2+f(x)=2+1=3\lim_{x \to 2^+} f(x) = 2 + 1 = 3
Since the left and right limits are different, the limit does not exist at x=2x = 2.
A removable discontinuity occurs when the function is undefined at a point, but the limit exists.
Example: f(x)=x2−1x−1f(x) = \frac{x^2 - 1}{x - 1}
Factor and simplify: f(x)=(x−1)(x+1)x−1=x+1for x≠1f(x) = \frac{(x - 1)(x + 1)}{x - 1} = x + 1 \quad \text{for } x \neq 1
As x→1x \to 1, the limit of f(x)=x+1f(x) = x + 1 is: limx→1f(x)=1+1=2\lim_{x \to 1} f(x) = 1 + 1 = 2
But the function is undefined at x=1x = 1, so it has a removable discontinuity at x=1x = 1.
An infinite discontinuity occurs when the function approaches ∞\infty or −∞-\infty as xx approaches a certain value.
Example: f(x)=1xf(x) = \frac{1}{x}
As x→0+x \to 0^+, f(x)→+∞f(x) \to +\infty.
As x→0−x \to 0^-, f(x)→−∞f(x) \to -\infty.
There is a vertical asymptote at x=0x = 0, and the limit does not exist.
A function f(x)f(x) is continuous at x=cx = c if:
f(c)f(c) is defined.
limx→cf(x)\lim_{x \to c} f(x) exists.
limx→cf(x)=f(c)\lim_{x \to c} f(x) = f(c).
One-sided limits refer to the behavior of a function as xx approaches a point from one direction only (either from the left or from the right).
Left-hand limit: limx→c−f(x)\lim_{x \to c^-} f(x)
Right-hand limit: limx→c+f(x)\lim_{x \to c^+} f(x)
Jump Discontinuity: Occurs when the left-hand limit and right-hand limit at a point are not equal, and the function has a sudden jump at that point.
Example: f(x)={x+1,if x<23,if x=2x−1,if x>2f(x) = \begin{cases} x + 1, & \text{if } x < 2 \\ 3, & \text{if } x = 2 \\ x - 1, & \text{if } x > 2 \end{cases}
The left-hand limit at x=2x = 2 is 3, and the right-hand limit is 1, so the function is not continuous at x=2x = 2.
Removable Discontinuity: The function is undefined at a point, but the limit from both sides exists and is equal.
Example: f(x)=x2−1x−1f(x) = \frac{x^2 - 1}{x - 1}
The limit as x→1x \to 1 is 2, but the function is undefined at x=1x = 1, so it has a removable discontinuity.
Infinite limits occur when a function approaches +∞+\infty or −∞-\infty as xx approaches a certain point.
Vertical Asymptote:
Example: f(x)=1xf(x) = \frac{1}{x}
As x→0+x \to 0^+, f(x)→+∞f(x) \to +\infty.
As x→0−x \to 0^-, f(x)→−∞f(x) \to -\infty.
There is a vertical asymptote at x=0x = 0, meaning the limit does not exist in a finite sense.
Jump Discontinuity: Left-hand and right-hand limits are not equal.
Removable Discontinuity: Left-hand and right-hand limits exist and are equal, but the function is undefined or not equal to the limit at the point.
Infinite Discontinuity (Vertical Asymptote): As the function approaches a point, it goes to +∞+\infty or −∞-\infty.
Left-hand and right-hand limits are different.
Example: A function with a jump discontinuity.
Oscillatory behavior: The function does not settle to a single value (e.g., sin(1x)\sin\left(\frac{1}{x}\right)).
Continuous: Limit from the left and right are equal and match the function’s value.
Jump Discontinuity: Left-hand and right-hand limits are not equal.
Removable Discontinuity: Limit exists but the function is undefined or not equal to the limit.
Infinite Discontinuity: The function approaches ∞\infty or −∞-\infty as xx approaches a point.
Limit Does Not Exist: Either the left-hand and right-hand limits are different, or the function oscillates and does not approach a single value.
I hope this makes the information clearer and more organized for you! This combined approach should help you understand what to look for when dealing with limits and continuity in various situations. Let me know if you'd like to dive deeper into any part or need more examples!