Unit 4.3.1: Electrode Potentials
3.1.11
Electrochemical cells
Electrochemical cells can be made from two different metals dipped in salt solutions of their own ions (i.e. Fe (s) in Fe2+ (aq) ) and connected by a wire.
There are always two reactions going on: Oxidation and Reduction - making this a redox process
- The metal electrodes below are dipped in a s olution of their respective ions, connected via a salt bridge.
- Zinc loses electrons more easily than copper so is by convention placed on the left.
- This also means that the Zn electrode is more positive than the Cu electrode meaning the Zn(s) is oxidised to Zn2+, the electrons travel to the Cu2+ ions and reduces them to Cu(s)
- The salt bridge allows ions to flow between the half-cells and balance the charges, completeing the circuit.

Electrons flow through the wire from the most reactive to the least reactive.
Cell Potential/Electromotive Force (EMF) - The voltage between two half-cells
You can also have a half-cell involving solutions of 2 aqueous ions of the same element
- A platinum electrode is used because it is inert (wont react)
- The conversion from Fe2+ to Fe3+ happens on the surface of the electrode
Electrode Potentials
The reactions that occur at each electrode in a cell are reversible

The direction the reaction goes in depends on how easily each metal is oxidised
This is measured using electrode potential
More negative electrode potential (V) = more easily oxidised
- Zinc has a more -ve electrode potanital so is oxidised
- Copper has a more +ve electrode potantial so is reduced
Drawing Electrochemical Cells
Theres a shorthand way to drawing those big electrochemical cells:
- | = state separation, you put this between substances of different phases in the same half-cell
- || = salt bridge, you use this to separate the two half-cells
Therefore, this electrochemical cell can be written as
By convention, unless it is Hydrogen, you always put the most negative electrode on the left.
Follow these steps in order to draw electrochemical cells in shorthand:
- Use the electrode potentials to work out which haldf-cell goes on the left and which goes on the right (unless you have Hydrogen, which always goes on the left)
- Write out the left-hand half-equation as an oxidation reaction, and the right-hand half-equation as a reduction equation
- Write out the reactants and products of the oxidation reaction followed by the reactants and products of the reduction reaction
- Add in a salt bridge with || between the oxidation and reduction reactions
- Add in your phase separator, | , between any reagents that have different phases, and a comma between any of the same phase.
- If the element and electrode are separate, put the electrode on the outside and separate using a |
Calculating the cell potential