Stoichiometric Relationships & The Mole Concept

Stoichiometric Relationships

  • Stoichiometry: Describes the relationships between the amounts of reactants and products during chemical reactions.

  • Matter is conserved during chemical change.

  • Stoichiometry is a form of book-keeping at the atomic level.

  • It helps chemists determine the correct amounts of substances for reactions and predict product yields.

  • Chemical equations are the universal language of chemistry.

  • The mole is the unit of amount.

Introduction to the Particulate Nature of Matter and Chemical Change

  • Atoms of different elements combine in fixed ratios to form compounds.

  • Compounds have different properties than their component elements.

  • Mixtures contain more than one element or compound that are not chemically bonded.

  • Mixtures retain individual properties.

  • Mixtures can be homogeneous (uniform composition) or heterogeneous (non-uniform composition).

Chemical equations

  • Chemical equations show reactants and products using chemical symbols.

  • State symbols: (s), (l), (g), and (aq) indicate solid, liquid, gas, and aqueous states, respectively.

  • Balancing equations: ensure the same number of atoms of each element on both sides.

  • Example: Thermal decomposition of sodium hydrogencarbonate: 2NaHCO<em>3(s)Na</em>2CO<em>3(s)+H</em>2O(g)+CO2(g)2NaHCO<em>3(s) \rightarrow Na</em>2CO<em>3(s) + H</em>2O(g) + CO_2(g)

Balancing chemical equations

  • Decomposition: CuCO<em>3(s)CuO(s)+CO</em>2(g)CuCO<em>3(s) \rightarrow CuO(s) + CO</em>2(g)

  • Combustion: 2Mg(s)+O2(g)2MgO(s)2Mg(s) + O_2(g) \rightarrow 2MgO(s)

  • Neutralization: H<em>2SO</em>4(aq)+2NaOH(aq)Na<em>2SO</em>4(aq)+2H2O(l)H<em>2SO</em>4(aq) + 2NaOH(aq) \rightarrow Na<em>2SO</em>4(aq) + 2H_2O(l)

  • Synthesis: N<em>2(g)+3H</em>2(g)2NH<em>3(g)N<em>2(g) + 3H</em>2(g) \rightarrow 2NH<em>3(g) Combustion of methane: CH</em>4(g)+2O<em>2(g)CO</em>2(g)+2H2O(g)CH</em>4(g) + 2O<em>2(g) \rightarrow CO</em>2(g) + 2H_2O(g)

  • Other examples:

    • 2K(s)+2H<em>2O(l)2KOH(aq)+H</em>2(g)2K(s) + 2H<em>2O(l) \rightarrow 2KOH(aq) + H</em>2(g)

    • C<em>2H</em>5OH(l)+3O<em>2(g)2CO</em>2(g)+3H2O(g)C<em>2H</em>5OH(l) + 3O<em>2(g) \rightarrow 2CO</em>2(g) + 3H_2O(g)

    • Cl<em>2(g)+2KI(aq)2KCl(aq)+I</em>2(s)Cl<em>2(g) + 2KI(aq) \rightarrow 2KCl(aq) + I</em>2(s)

    • 4CrO<em>3(s)2Cr</em>2O<em>3(s)+3O</em>2(g)4CrO<em>3(s) \rightarrow 2Cr</em>2O<em>3(s) + 3O</em>2(g)

    • Fe<em>2O</em>3(s)+3C(s)3CO(g)+2Fe(s)Fe<em>2O</em>3(s) + 3C(s) \rightarrow 3CO(g) + 2Fe(s)

    • 2C<em>4H</em>10(g)+13O<em>2(g)8CO</em>2(g)+10H2O(g)2C<em>4H</em>{10}(g) + 13O<em>2(g) \rightarrow 8CO</em>2(g) + 10H_2O(g)

    • 4NH<em>3(g)+5O</em>2(g)4NO(g)+6H2O(g)4NH<em>3(g) + 5O</em>2(g) \rightarrow 4NO(g) + 6H_2O(g)

    • 3Cu(s)+8HNO<em>3(aq)3Cu(NO</em>3)<em>2(aq)+2NO(g)+4H</em>2O(l)3Cu(s) + 8HNO<em>3(aq) \rightarrow 3Cu(NO</em>3)<em>2(aq) + 2NO(g) + 4H</em>2O(l)

    • H<em>2O</em>2(aq)+N<em>2H</em>4(aq)N<em>2(g)+4H</em>2O(l)+O2(g)H<em>2O</em>2(aq) + N<em>2H</em>4(aq) \rightarrow N<em>2(g) + 4H</em>2O(l) + O_2(g)

    • 4C<em>2H</em>7N(g)+15O<em>2(g)8CO</em>2(g)+14H<em>2O(g)+2N</em>2(g)4C<em>2H</em>7N(g) + 15O<em>2(g) \rightarrow 8CO</em>2(g) + 14H<em>2O(g) + 2N</em>2(g)

Atom Economy

  • Formula: % atom economy=mass of desired producttotal mass of products×100\% \text{ atom economy} = \frac{\text{mass of desired product}}{\text{total mass of products}} \times 100

  • A higher atom economy indicates a more efficient and less wasteful process.

  • Relevant to green and sustainable chemistry.

Mixtures

  • Mixtures: substances combined without chemical interaction.

  • Components retain individual properties.

  • Composition is not fixed (e.g., air: 20% oxygen in, 16% oxygen out).

  • Homogeneous mixture: uniform composition (e.g., air, salt water, bronze).

  • Heterogeneous mixture: non-uniform composition (e.g., water and oil).

Separation Techniques

  • Sand and salt: solubility in water, use solution and filtration.

  • Hydrocarbons in crude oil: boiling point, use fractional distillation.

  • Iron and sulfur: magnetism, use a magnet.

  • Pigments in food colouring: adsorption to solid phase, use paper chromatography.

  • Different amino acids: net charge at a fixed pH, use gel electrophoresis.

States of Matter

  • Matter exists in different states (solid, liquid, gas) determined by temperature and pressure.

  • Kinetic theory of matter: average kinetic energy of particles is related to temperature.

  • Liquids and gases are fluids (they flow).

  • Diffusion: particles of a substance become evenly distributed due to random movements.

    • Kinetic Energy: KE=12mv2KE = \frac{1}{2}mv^2

  • State symbols: (s), (l), (g), (aq) for solid, liquid, gas, aqueous.

  • Balancing equations including state symbols, e.g., 2Na(s)+2H<em>2O(l)2NaOH(aq)+H</em>2(g)2Na(s) + 2H<em>2O(l) \rightarrow 2NaOH(aq) + H</em>2(g)

Homogeneous or Heterogeneous

  • Sand and water: heterogeneous.

  • Smoke: heterogeneous.

  • Sugar and water: homogeneous.

  • Salt and iron filings: heterogeneous.

  • Ethanol and water in wine: homogeneous.

  • Steel: homogeneous.

State Changes

  • Sublimation: solid to gas.

  • Melting: solid to liquid.

  • Vaporization: liquid to gas (evaporation and boiling).

  • Freezing: liquid to solid.

  • Condensation: gas to liquid.

  • Deposition: gas to solid.

  • Temperature remains constant during state changes as energy is used to break inter-particle forces.

  • Evaporation occurs only at the surface and takes place at temperatures below the boiling point

  • Boiling occurs at a volume phenomenon, particles leaving throughout the body of the liquid – which is why bubbles occur. Boiling occurs at a specifi c temperature, determined by when the vapour pressure reaches the external pressure.

Kinetic Energy

  • KE=12mv2KE = \frac{1}{2}mv^2

Refrigeration Example

  • Propane (C3H8): boiling point -42°C

  • Butane (C4H10): boiling point -1°C

  • Butane is unsuitable for very cold climates.

Thermal Energy Formula Understanding

  • a–b: Solid heated, vibrational energy increases, temperature increases.

  • b–c: Melting point reached, energy breaks inter-particle forces, temperature constant.

  • c–d: Liquid heated, kinetic energy increases, temperature increases.

  • d–e: Boiling point reached, energy breaks all inter-particle forces, temperature constant.

  • e–f: Gas heated, kinetic energy increases, temperature increases.

The Mole Concept

  • The mole is a fixed number of particles and defines the amount, n, of a substance.

    • Avogadros constant, L=6.02×1023mol1L = 6.02 \times 10^{23} mol^{-1}

  • Relative atomic mass (Ar): the weighted average of one atom of an element relative to one-twelfth of an atom of carbon-12.

  • Relative formula/molecular mass (Mr): the sum of the weighted average of the masses of the atoms in a formula unit relative to one-twelfth of an atom of carbon-12.

  • Molar mass (M): mass of one mole of a substance, expressed in g mol-1.
    Empirical formula: the simplest ratio of atoms in a compound.

  • Molecular formula: the actual number of atoms present in a molecule.

  • IUPAC guidelines for naming and notation.

Avogadro's Constant and Moles

  • Converting between number of particles (N) and number of moles (n): N=n×LN = n \times L

Mass and Moles Formula

  • m = mass in grams.

  • M = molar mass in g. Mol-1

    Molar Mass Formula:

     amount=massmolarmassamount = {mass \over molar mass}n(mol)=m(g)M(gmol1)n(mol) = {m(g) \over M(gmol^{-1})}
Molar Mass Conversion Formula:
    amount=massmolarmassn(mol)=m(g)M(gmol1)amount = {mass\over molar mass} n(mol) = {m(g)\over M(gmol^{-1})}

HOW TO CONVERT FROM PARTICLES TO MASS IN GRAMS FORMAL #

  • Converting between the number of particles and the mass in grams amount=massmolarmassamount = {mass\over molar mass}

Number of particles: MASS IN GRAMS FORMULA

amount,n X avogadroes contant,L \ divide by molar mass, M
divide by Avagadro contast,L Multiply by molar mass,M