Stress on Inclines

Instructor Information

  • Instructor: Hongsoo Choi, Ph. D.
  • Email: hongsoochoi@umass.edu
  • Course Code: BMED-ENG 241: Strength of Materials
  • Semester: Spring 2026

Teaching Assistants (TAs) Information

  • Seva Plotnichenko
    • Email: vvplotnichen@umass.edu
    • Office Hours: Fridays 2:30 PM - 3:30 PM
  • Julian Lopez Ward
    • Email: jmlopez@umass.edu
    • Office Hours: Mondays 1:25 PM - 2:15 PM
  • Location for Both TA Hours: Hasbrouck Lab Addition room 104A

Important Announcements

  • Quiz 1:
    • Date: Monday, February 24, 2026
    • Time: 10:30 AM – 10:50 AM
    • Lecture will conclude by 10:10 AM, with a 10-minute preparation period before the quiz begins.
    • Accommodations:
    • If accommodations are needed, schedule at the Exam Proctoring Center through ClockWork. Contact your Access Coordinator to arrange testing.

Stresses on Inclined Sections

  • This section builds on previous classes that examined normal, shear, and bearing stresses on planes that are parallel and perpendicular to axially loaded members.
  • Focus now shifts to stresses acting on planes that are inclined with respect to the axis of an axially loaded bar.

Fundamental Concepts

  • A prismatic bar subjected to an axial force PP applied at its centroid is under uniaxial loading.
  • The normal stress on a cross section that is perpendicular to the axis is uniform and is given as follows:
    • Resultant Normal Stress:
    • Equal to the applied load PP, acting along the bar's axis.
  • Shear Stress:
    • No shear stress develops on this perpendicular cross section since the force acts normal to the surface.

Analysis of Inclined Sections

  • Section a–a:
    • This is the only surface directly perpendicular to the applied force PP; thus, inclined sections also necessitate consideration.
  • Equilibrium Maintenance:
    • On inclined sections, stresses remain uniformly distributed to maintain equilibrium.
  • Angle of Inclination:
    • Defined by angle θ\theta, measured between the bar axis (x-axis) and the normal to the plane (n-axis).

Force Component Resolution

  1. Applied Force PP:
    • Resolved into two components:
    • Normal Force (N):
      • N=PcosθN = P \cos \theta (perpendicular to the plane)
    • Shear Force (V):
      • V=PsinθV = -P \sin \theta (parallel to the plane)
  2. Area of the Inclined Plane:
    • The area of the inclined plane is greater than the cross-sectional area and is expressed as:
      • An=AcosθA_n = \frac{A}{\cos \theta}
  3. Calculation of Stresses:
    • Normal and shear stresses on the inclined plane are computed as follows:
      • Normal Stress (σn\sigma_n):
      • σ<em>n=NA</em>n=PcosθA/cosθ=Pcos2θA\sigma<em>n = \frac{N}{A</em>n} = \frac{P \cos \theta}{A/\cos \theta} = \frac{P \cos^2 \theta}{A}
      • Shear Stress (τnt\tau_{nt}):
      • τ<em>nt=VA</em>n=PsinθA/cosθ=PsinθcosθA\tau<em>{nt} = \frac{V}{A</em>n} = \frac{-P \sin \theta}{A/\cos \theta} = -\frac{P \sin \theta \cos \theta}{A}

Stress Behavior with Angle

  • Both normal stress (σ<em>n\sigma<em>n) and shear stress (τ</em>nt\tau</em>{nt}) depend on angle θ\theta.
  • Maximum Stress Conditions:
    • Maximum normal stress occurs at angles θ=0\theta = 0^{\circ} and 180180^{\circ}.
    • Maximum shear stress occurs at angles θ=45\theta = 45^{\circ} and 135135^{\circ}.
    • Moreover, the maximum shear stress is equal to one-half of the maximum normal stress.

Critical Planes and Stress States

  • Normal stress is at maximum or minimum on planes where shear stress is zero.
  • Conversely, shear stress is zero on planes where normal stress reaches its maximum or minimum.
  • The concept of maximum normal stress and maximum shear stress extends to more general loading cases.
  • The sign of shear stress changes when angle θ\theta exceeds 9090^{\circ}.
  • The magnitude of shear stress at angle θ\theta equals that at angle 90+θ90^{\circ} + \theta; only the direction changes.

Example Applications

  • Discussion includes MecMovies 1.11.
  • Context: An axially loaded prismatic bar is analyzed to understand stress behavior.
    • The load PP acts through the centroid, producing centric (uniaxial) loading.
    • Even under simple axial loading, multiple combinations of normal and shear stresses occur.
    • Stress magnitude and direction depend on the orientation of the plane in question.
    • A cut at section aaa–a is performed for internal stress examination:
    • Since the surface is perpendicular to the applied force PP, the stress is exclusively normal stress.
    • Normal stress is calculated as:
      • σ=PA\sigma = \frac{P}{A}
    • Equilibrium dictates that the resultant internal force matches the applied force PP, with no shear stress present due to the perpendicularity of the surface.

Stresses at Arbitrary Planes

  • A cut at section bbb–b assesses stresses on an arbitrary internal plane.
    • The free-body diagram reveals the internal forces on the inclined plane.
    • Stresses acting on the inclined surface maintain uniform distribution and must equate to the applied force PP for equilibrium, irrespective of the incline of the surface.
  • Force Components on the Inclined Plane:
    • The orientation at this inclined surface is again defined by angle θ\theta between the x-axis and the normal (n-axis).
    • Positive θ\theta measures counterclockwise from the x-axis to the n-axis.
  • The normal force component is given by:
    • N=PcosθN = P \cos \theta (acting in the n-direction)
    • The shear force component is:
    • V=PsinθV=-P \sin \theta (acting in the t-direction)

Changing Cross-sectional Area

  • The cross-sectional area of the inclined plane alters as the angle θ\theta changes.
    • The inclined area increases compared to the vertical cross-sectional area.
    • This area enlarges as the plane inclines further relative to the bar axis, affecting normal and shear stress magnitudes accordingly.

Engineering Considerations

  • Numerous combinations of normal stress (σ<em>n\sigma<em>n) and shear stress (τ</em>nt\tau</em>{nt}) may appear at any material point.
    • The magnitude and direction of these stresses hinge upon the orientation of the evaluated plane.
  • When designing components, engineers must consider all potential stress combinations.
  • Material Behavior:
    • Brittle materials generally fail due to high normal stress, fracturing on planes perpendicular to the load.
    • Ductile materials are more affected by shear stress, fracturing typically on planes at approximately 45°, where shear stress peaks.

Review Notes

  • Reviewed the topic of stresses on inclined sections
  • Emphasized the importance of selecting appropriate area, direction, and angle when assessing stresses
  • Next discussion: Reading of section 1.6
  • Topic for next class: Equality of Shear Stresses on Perpendicular Planes