What is the pH of 0.5 M HCl solution?
pH ≈ 0.30
Calculation: pH = -log[0.5] = 0.30
What is the pH of 0.75 M NaOH solution?
pH ≈ 13.1
Calculation:
pOH = -log(0.75) = 0.12
pH = 14 - 0.12 = 13.1
Hydrogen ion concentration of HCl solution with a pH of 3.0?
Hydrogen ion concentration: 0.001 M
Calculation:
pH = -log[H+]
[H+] = 10^(-3) = 0.001 M
pH of 0.50 M HC2H3O2 and 0.25 M NaC2H3O2?
Given: Ka of HC2H3O2 = 1.8 x 10^-5
Calculation:
pKa = -log(1.8 x 10^-5) = 4.74
pH = pKa + log{[NaC2H3O2]/[HC2H3O2]}
pH = 4.74 + log(0.25/0.5) = 4.74 - 0.301 = 4.439 ~ 4.44
pH of 0.25 M NH4Cl and 2.5 M NH3?
Given: Kb of NH3 = 1.8 x 10^-5; Pkb = -log(1.8 x 10^5) = 4.74
Calculation:
pH = pKb + log{[NH4Cl]/[NH3]}
pH = 4.74 + log(0.25/2.5) = 4.74 + 0.1 = 4.84
Abstract:
Objective: Prepare various buffer solutions and determine their buffer capacity.
Experiment involved adding HCl and NaOH to a buffer solution at pH 5.
Noted changes in pH:
HCl lowered pH
NaOH raised pH
Importance: Knowing which chemicals maintain pH in buffer solutions is crucial for efficiency.
Introduction:
Field: Analytical Chemistry
Focuses on extraction, identification, quantification of unknown samples.
Critical for science and industry, ensuring precision and accuracy.
Practical skills developed include handling and preparing chemical solutions.
Buffer Solutions:
Resist pH changes with additions of acids/bases.
Experiments assess buffer capacity and effectiveness.
Materials:
Acetic Acid (0.10M, 0.5M)
Sodium Acetate
Standard buffer solutions (pH 4 & 7)
100 ml volumetric flask
pH meter, buret clamp, burets, stir bar, 250 ml beakers, universal indicator
Procedure:
First solution: 1.52g sodium acetate + 100ml 0.1M acetic acid
Resulting pH of sodium acetate and acetic acid: 5.04
Added HCl: pH = 4.99 (24.5°C)
Added NaOH: pH = 5.11 (25.7°C)
Comparison using tap water:
pH of tap water: 7.91 (30.4°C)
Added NaOH: pH = 12.84 (27.8°C)
Added HCl: pH = 2.88 (31.4°C)
Addition of HCl and NaOH minimally affected pH of buffer solution, confirming buffer capacity.
pH of buffer solution (0.1M Acetic Acid, 0.05M Sodium Acetate):
pH = pKa + log{[NaC2H3O2]/[HC2H3O2]}
pH = 4.74 + log(0.1/0.05)
pH = 4.74 + 0.301 = 5.04
Moles Calculations:
Moles of Acetic Acid: 100ml x 0.100 moles/1000ml = 0.0100 moles
Moles of Sodium Acetate: 152ml x 0.05moles/1000ml = 0.0076 moles
Moles of HCl: 1.00ml x 1.00moles/1000ml = 0.001moles
Moles of NaOH: 1.00ml x 1.00moles/1000ml = 0.001moles
pH after adding HCl/NaOH to buffer:
pH = 5.04 + log(0.0076 - 0.001)/(0.01 + 0.001) = 5.04 + log(0.0066)/(0.011)
Final pH = 4.81
Buffer Capacity:
pH = 4.74 + log(1/10) → pH = 3.74
pH = 4.74 + log(10/1) → pH = 5.74
Experiment successfully created a buffer solution with sodium acetate and acetic acid.
The added chemicals (NaOH and HCl) did not raise or lower the pH beyond the buffer's capacity range.