CHEM 231: Molecular Structure and Acid–Base Fundamentals
1.1 Orbitals take up three-dimensional space
- Electron cloud surrounds the nucleus; electrons occupy orbitals that have specific shapes and orientations in three dimensions.
- Hybridization concepts are central to understanding geometry and bonding in this course.
- Hybrids of orbital types (e.g., s and p) are the primary focus for predicting bonding patterns and shapes.
1.2 Ionic bonds are not the focus of this class
- Ionic bonds arise from electrostatic attraction between ions with opposite charges.
- Components: cations (+) and anions (-).
- Characteristics:
- High melting points (example: NaCl ≈ 800°C).
- Tend to be soluble in water; insoluble in most organic solvents.
- Crystalline in the solid state.
1.3 Bonding: Valence Bond model vs Molecular Orbital model
- Valence Bond (VB) picture for dihydrogen (H₂):
- Uses the 1s orbitals of two hydrogen atoms.
- Each 1s orbital contains one electron.
- In-phase overlap of two 1s orbitals forms a bonding orbital that encompasses both hydrogens and contains two electrons.
- Molecular Orbital (MO) picture for H₂:
- Construct MOs from the combination of atomic orbitals (AOs).
- Bonding MO (in-phase) results in energy stabilization.
- Antibonding MO (out-of-phase) costs energy; node between A and B.
- Energy diagrams indicate increasing energy for antibonding configurations.
- Key concepts:
- Bond order, stabilization vs destabilization via constructive vs. destructive interference of AOs.
- Nodes and energy of MOs determine bond strength and reactivity.
1.4 Molecular geometries are dictated by orbitals
- VSEPR-inspired geometry arises from repulsions between electron domains (bonding and lone pairs).
- Example geometries with approximate angles:
- Methane (CH₄): tetrahedral, ~109.5°.
- Water (H₂O): bent, ~104.5° (due to two lone pairs).
- Ammonia (NH₃): trigonal pyramidal, ~107° (lone pair repulsion).
- Other illustrated examples show ~107°, ~105°, etc., depending on lone-pair/bonding-pair repulsions.
- Concept of repulsions:
- Bonded pair–bonded pair: least repulsive
- Bonded pair–unshared pair: intermediate
- Unshared pair–unshared pair: most repulsive
- Context: these geometries reflect the arrangement of electron domains around the central atom.
1.5 Polar covalent bonds, electronegativity, and bond dipoles
- Electronegativity (Pauling scale) governs how electrons are shared in a bond.
- Bond dipole moments arise from differences in electronegativity between atoms in a bond.
- Examples of dipole moments (in Debye, D):
- H–F ≈ 1.7 D
- C–F ≈ 1.4 D
- H–C ≈ 0.3 D (C more electronegative end is negative in polar C–H)
- Increasing number of bonds generally increases the overall molecular dipole moment (more polarity contributions).
- Direction of a bond dipole is toward the more electronegative atom.
- Implication: bond polarity contributes to molecular polarity when dipoles do not cancel in a symmetric molecule.
1.6 Polar molecules and net dipole moment
- Molecular dipole moment μ is the vector sum of individual bond dipoles.
- If molecule is highly symmetric (e.g., CO₂), dipoles cancel and μ = 0 (nonpolar molecule).
- Example: H–C–Cl has a net dipole toward Cl; Cl–C dipole magnitude cited as μ ≈ 1.87 D (illustrative example).
- Nonzero net dipole → polar molecule; zero net dipole → nonpolar molecule.
1.7 Resonance; electron delocalization: a first approach
- Ozone (O₃) as an example of resonance:
- Two major resonance contributors depict electron delocalization across the O–O–O framework.
- Resonance hybrid represents a blended distribution of electrons.
- Resonance notation:
- Dashed-line structures indicate resonance contributors.
- The actual structure is a resonance hybrid of all valid contributors.
1.8 Curved arrows (Electron movement)
- Curved arrows depict movement of electrons, not a reaction step.
- Rules (summary):
- Move electrons from electron-rich sources (lone pairs or bonds) to electron-poor targets.
- Do not move electrons from a positively charged center to a more charged center inappropriately.
- Correct arrow-pushing is developed with practice.
- Example themes:
- Representing resonance contributors (major vs minor) via arrow-pushing.
- Proton transfer or bond-making/breaking steps in mechanisms.
1.9 Curved arrows: additional practice and mechanism steps
- Illustrative bimolecular substitutions (SN2) and acid–base reactions show ARROW- pushing during bond formation/breakage.
- Example sequences:
- HO⁻ attacking a carbon center in S_N2-like steps to form new bonds while displacing leaving groups.
- Proton transfers where a conjugate base abstracts a proton from an acid.
- Formal charge concept helps assign charges to atoms in a Lewis structure.
- Nitromethane example: shows charges on N and O to balance electron ownership.
- Formal charge calculation:
- Electron ownership per atom = valence electrons − electrons owned by the atom (bond electrons are split between bonded atoms).
- Formula: extFormalcharge=V−Eowned where V = valence electrons.
- Example calculations illustrate how to assign charges to achieve the most reasonable Lewis structure.
- Steps to draw reasonable Lewis structures:
- Count total valence electrons from all atoms (adjust for ionic species if applicable).
- Draw a skeleton structure (connect atoms with bonds) to satisfy octets as far as possible.
- Distribute remaining electrons as lone pairs to satisfy octets.
- Calculate formal charges and adjust if needed to minimize charge separation.
- Example: C₂H₆O
- Total valence electrons: from C (group 4A) and O (group 6A) and H (group 1A).
- Two major skeletons: H–C–C–O–H vs H–C–O–C–H; decide based on octets and formal charges.
- If octets are satisfied without charges, that structure is preferred; otherwise assign charges appropriately.
- Key principle: the atom prefers an arrangement that minimizes formal charge separation and obeys octet rules for second-row elements where applicable.
- Double and triple bonds are used to depict multiple bonds between the same two atoms.
- Line-angle drawings: simplified representation of the carbon skeleton.
- Each line endpoint or bend represents a carbon atom.
- Hydrogens bonded to carbons are inferred and not drawn explicitly.
- Explicit heteroatoms (O, N, halogens, etc.) and their hydrogens may be drawn.
- Examples show transformations between Lewis structures and line-angle notations.
1.13 Structure and acidity strength; periodic trends in acidity
- Trend 1: In a column (group), larger conjugate base anion → stronger acid (lower conjugate base stability).
- Examples (pKa values, approximate):
- HF: pKa ≈ 3.1
- HCl: pKa ≈ -3.9
- HBr: pKa ≈ -5.8
- HI: pKa ≈ -10.4
- Strongest acid among the listed in the group is HI (lower pKa).
- Note: The hydrogen is directly bonded to the atom being compared.
- Trend 2: Across a row (period), electronegativity is a strong predictor of acid strength.
- Examples across period: CH₄ (pKa ≈ 50) < NH₃ (pKa ≈ 38) < H₂O (pKa ≈ 15.7) < HF (pKa ≈ 3.1) – more electronegative central atom → stronger acid.
- Additional context examples (pKa values, approximate):
- Hydronium (H₃O⁺) = 0
- Water (H₂O) = 15.7
- Ammonia (NH₃) = 38
- Ammonium ion (NH₄⁺) = 9.3
- Acetic acid (CH₃COOH) = 4.7
- Benzene conjugate acid ≈ 43 (very weak acid)
- Takeaway: acid strength is governed by both electronegativity and conjugate-base stability; the trend is reinforced by inductive effects (neighboring substituents) and delocalization.
1.13 Environmental trend 1: Inductive effects
- Inductive withdrawing/donating groups near the conjugate base atom affect acidity.
- Example: Ethanol vs. 2,2,2-trifluoroethanol (CF₃CH₂OH)
- Ethanol: pKa ≈ 16
- 2,2,2-Trifluoroethanol: pKa ≈ 11.3
- Principle: Electron-withdrawing groups stabilize conjugate bases and lower pKa (increase acidity) via inductive effects.
- Diagrammatic note: inductive effects propagate through sigma bonds and influence stability of charged species.
1.13 Environmental trend 2: Delocalization in the conjugate base (CB)
- Delocalization of negative charge in the CB stabilizes the CB.
- If CB is able to delocalize electrons (resonance, conjugation), the conjugate base is weaker and the corresponding acid is stronger.
- Example schematic ideas (not all shown here): delocalized CB charges across multiple atoms lead to greater stability.
1.14 Acid–Base Equilibria
- Concept: Reactions proceed to form the weaker acid or base (weaker acid + stronger base on one side).
- Rule: Compare pKa values of the acids involved to predict direction of equilibrium.
- Example 1 (bromide and water):
- Reaction: HBr + H₂O ⇄ Br⁻ + H₃O⁺
- pKa(HBr) ≈ -4.0 to -5.0; pKa(H₃O⁺) ≈ 0
- Equilibrium favors the side with the weaker acid (HBr has the stronger acidity, so the equilibrium lies to the left, toward Br⁻ and H₂O).
- Example 2 (acetic acid vs. water):
- Reaction: CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺
- pKa(CH₃COOH) ≈ 4.7; pKa(H₂O) ≈ 15.7
- Equilibrium favors the weaker acid side (acetic acid is weaker than hydronium, so the reaction lies toward products if comparing conjugate partners in a generalized sense; in a comparative acid-base sense, acetate is a stronger base than water).
- Example 3 (ammonia vs. acetic acid):
- Ammonia (NH₃) has pKa ≈ 38 as an acid (very weak); ammonium (NH₄⁺) has pKa ≈ 9.3 as an acid.
- Acid-base strength comparison can be used to reason about equilibrium direction in proton transfers.
1.16 Lewis acid–base equilibria
- Definitions:
- Lewis acid: electron pair acceptor.
- Lewis base: electron pair donor.
- Example: Boron trifluoride (BF₃) acts as a Lewis acid.
- BF₃ can accept electron density from a Lewis base such as diethyl ether (Et₂O) to form a Lewis acid–base adduct, commonly referred to as the "boron trifluoride etherate":
- BF₃ + Et₂O → BF₃·Et₂O
- Example reaction:
- A-B (Lewis acid A and Lewis base B) forms a Lewis acid–base complex A–B.
- Illustration: BF₃ accepting an electron pair from an ether gives a stable adduct.
1.17 Practice: curved arrows and resonance reasoning (summary ideas)
- Practice questions involve drawing curved arrows to show plausible electron flow leading to products.
- Typical tasks:
- Predict major resonance contributor for a given structure by applying resonance rules.
- Decide if an attempted resonance form is valid by checking octet rule, charge distribution, and electron counts.
- Determine if a proposed curved-arrow sequence leads to stable products without violating fundamental rules (no movement of electrons to create impossible charges, etc.).
1.4 Double and triple bonds: depiction and examples
- Double bonds (alkenes) and triple bonds (alkynes) are depicted by multiple lines between two atoms.
- Examples show how to share electrons to form C=C and C≡C bonds.
- Oxidized species such as carbon dioxide can be shown with multiple bond representations (e.g., O=C=O).
Summary: Connections to concepts and real-world relevance
- Orbitals and hybridization explain three-dimensional shapes of molecules, reactivity, and bonding patterns observed in organic and inorganic chemistry.
- Electronegativity and dipole moments underpin bond polarity, molecular polarity, and properties like solubility and boiling points.
- Resonance and curved arrows explain electron delocalization, stabilization of structures, and reaction mechanisms.
- Formal charges and Lewis structures provide a practical framework for assessing stability and predicting reactivity in molecules.
- Acidity trends (periodic and inductive effects) guide predictions about proton transfer, reaction equilibria, and the strength of acids and bases in different environments.
- Lewis acids and bases extend beyond Bronsted definitions to include electron-pair interactions, enabling explanations of complexation and catalysis.
Key equations and constants to remember
- Formal charge: extFormalcharge=V−Eextowned
- where V is the number of valence electrons for the atom and E_owned is the number of electrons assigned to that atom in the Lewis structure.
- pKa relation: pK<em>a=−extlog</em>10Ka
- Dipole moment direction: toward the more electronegative atom in a bond; vector sum determines molecular polarity.
- Resonance rules (summary):
- Connectivity remains the same
- Total number of electrons and net charge unchanged
- Number of unpaired electrons unchanged
- Octet rule should be satisfied for second-row elements
- Lewis acid–base adducts: BF₃ + Et₂O → BF₃·Et₂O (illustrative example of Lewis acid-base interaction)