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Definition: Monosaccharides are the simplest form of carbohydrates, consisting of single sugar units.
Blood Sugar: The monosaccharide referred to as blood sugar is glucose (Answer: c).
- Options Provided:
- a) ribulose
- b) galactose
- c) glucose
- d) ribose

Aldoses: Monosaccharides with an aldehyde group.
Ketoses: Monosaccharides with a ketone group.
Question: All of the following monosaccharides are aldoses except _.
- Correct Answer: fructose (Answer: a).
- Options Provided:
- a) fructose
- b) ribose
- c) xylose
- d) galactose

Ribose: Identify Ribose's classification.
Answer: Ribose is a(n) aldopentose (Answer: b).
- Options Provided:
- a) aldotetrose
- b) aldopentose
- c) ketotriose
- d) ketohexose

Chiral Carbon: A carbon atom attached to four different groups, leading to non-superimposable mirror images.
Question: Identify the chiral carbon in the provided molecule.
- Correct Answer: The green carbon (Answer: a).
- Options Provided:
- a) The red carbon
- b) The blue carbon
- c) The green carbon
- d) The yellow carbon

D and L Isomers: Determined by the position of the hydroxyl group (-OH) on the chiral carbon furthest from the carbonyl group.
Question: In the Fischer projection, which chiral carbon determines whether the sugar is D or L?
- Correct Answer: The green carbon (Answer: a).
- Options Provided:
- a) The green carbon
- b) The yellow carbon
- c) The blue carbon
- d) The red carbon

Question: In the Fischer projection shown, is this the D or L isomer?
- Correct Answer: L, because the OH is on the left (Answer: c).
- Options Provided:
- a) D, because the OH is on the left
- b) D, because the OH is on the right
- c) L, because the OH is on the left
- d) L, because the OH is on the right

Anomers: Isomers that differ only in configuration at the anomeric carbon in a cyclic form of sugar.
Question: Is this Haworth structure the a or b anomer?
- Correct Answer: b, because the OH is above the plane of the ring (Answer: d).
- Options Provided:
- a) a, because the OH is below the plane of the ring
- b) a, because the OH is above the plane of the ring
- c) b, because the OH is below the plane of the ring
- d) b, because the OH is above the plane of the ring

Reducing Sugars: Any sugar that can act as a reducing agent due to a free aldehyde or ketone group.
Question: Which of the following is not a reducing sugar?
- Correct Answer: sucrose (Answer: d).
- Options Provided:
- a) fructose
- b) glucose
- c) maltose
- d) sucrose

Lactose: The disaccharide found in milk and milk products.
- Correct Answer: lactose (Answer: b).
- Options Provided:
- a) cellobiose
- b) lactose
- c) maltose
- d) sucrose

Disaccharide Formation: Linking glucose and fructose together produces sucrose (Answer: d).
- Options Provided:
- a) galactose
- b) maltose
- c) lactose
- d) sucrose

Glycosidic Bond: A type of covalent bond that links carbohydrates (sugars) together.
Question: What type of glycosidic bond is linking these monosaccharides together?
- Correct Answer: a (1g4) (Answer: a).
- Options Provided:
- a) a (1g4)
- b) a (1g6)
- c) b (1g4)
- d) a,b (1g2)

Complete Hydrolysis: The breakdown of a compound by water into its constituent components.
Question: Which of the following yields a sugar other than glucose upon complete hydrolysis?
- Correct Answer: lactose (Answer: a).
- Options Provided:
- a) lactose
- b) maltose
- c) starch
- d) cellulose

Partial Hydrolysis: The incomplete breakdown of a compound into simpler substances.
Question: Which of the following carbohydrates would not yield maltose if partially hydrolyzed?
- Correct Answer: cellulose (Answer: b).
- Options Provided:
- a) amylose
- b) cellulose
- c) glycogen
- d) starch

Highly Branched Polysaccharide: Glycogen is known to be the most highly branched polysaccharide.
- Correct Answer: glycogen (Answer: d).
- Options Provided:
- a) amylopectin
- b) amylose
- c) cellulose
- d) glycogen

Indigestible Polysaccharides: Cellulose is not digestible by humans due to its structural properties.
- Correct Answer: cellulose (Answer: b).
- Options Provided:
- a) glycogen
- b) cellulose
- c) amylose
- d) amylopectin

Structural Feature: The type of linkages between the units of a polysaccharide can prevent human digestion.
Question: Which structural feature prevents the human digestion of cellulose?
- Correct Answer: The b form of the linkages (Answer: c).
- Options Provided:
- a) The length of the polysaccharide
- b) The branches formed in the polysaccharide
- c) The b form of the linkages
- d) The galactose units in the polysaccharide

Alpha Linkages: Present in polysaccharides that can be digested by humans.
Question: In which of the following are monosaccharide units not joined by alpha linkages?
- Correct Answer: cellulose (Answer: d).
- Options Provided:
- a) maltose
- b) amylose
- c) glycogen
- d) cellulose

β (1→4) Linkage: A type of glycosidic linkage present in certain polysaccharides.
Question: Which compound contains a β (1→4) linkage?
- Correct Answer: lactose (Answer: c).
- Options Provided:
- a) amylose
- b) glycogen
- c) lactose
- d) maltose

Glycogen Structure: Presence of both α (1→4) and α (1→6) linkages contributes to its highly branched structure.
Question: Which compound contains both α (1→4) and α (1→6) linkages?
- Correct Answer: glycogen (Answer: c).
- Options Provided:
- a) amylose
- b) cellulose
- c) glycogen
- d) sucrose