Arithmetic Sequences

Arithmetic vs. Geometric Sequences

  • Arithmetic Sequence: A sequence with a common difference between consecutive terms. The pattern is based on addition or subtraction.

  • Geometric Sequence: A sequence with a common ratio between consecutive terms. The pattern is based on multiplication or division.

Examples

  • Arithmetic Sequence: 3, 7, 11, 15, 19, 23, 27

  • Geometric Sequence: 3, 6, 12, 24, 48, 96, 192

Common Difference (d) in Arithmetic Sequences

  • To find the common difference, subtract any term from its subsequent term.

  • Example: In the sequence 3, 7, 11, 15, …, the common difference d = 7 - 3 = 4.

Common Ratio (r) in Geometric Sequences

  • To find the common ratio, divide any term by its preceding term.

  • Example: In the sequence 3, 6, 12, 24, …, the common ratio r = \frac{6}{3} = 2.

Arithmetic Mean

  • The arithmetic mean is the average of two numbers: \frac{a + b}{2}.

  • In an arithmetic sequence, the arithmetic mean of two terms gives the middle number in the sequence.

Examples

  • The arithmetic mean of 3 and 11 is \frac{3 + 11}{2} = \frac{14}{2} = 7.

  • The arithmetic mean of 7 and 23 is \frac{7 + 23}{2} = \frac{30}{2} = 15.

Geometric Mean

  • The geometric mean of two numbers is the square root of their product: \sqrt{a \times b}.

  • In a geometric sequence, the geometric mean of two terms gives the middle number in the sequence.

Examples

  • The geometric mean of 3 and 12 is \sqrt{3 \times 12} = \sqrt{36} = 6.

  • To find the geometric mean between 6 and 96:
    \sqrt{6 \times 96} = \sqrt{6 \times 6 \times 16} = \sqrt{36 \times 16} = 6 \times 4 = 24

Formula for the nth Term of a Sequence

Arithmetic Sequence

  • The formula to find the n^{th} term (an$) of an arithmetic sequence is: an = a_1 + (n - 1)d where:

    • a_1 is the first term.

    • n is the term number.

    • d is the common difference.

Example

  • Find the 5th term of the arithmetic sequence 3, 7, 11, 15, …

    • a_1 = 3

    • n = 5

    • d = 4

    So, a_5 = 3 + (5 - 1) \times 4 = 3 + 4 \times 4 = 3 + 16 = 19.

Geometric Sequence

The formula for finding the n^{th} term (an) in a geometric sequence is: an = a1^(n−1)​

Example

  • Calculate the 6th term of the geometric sequence 3, 6, 12, 24, 48, …

    • a_1 = 3

    • r = 2

    • n = 6

    So, a_6 = 3 \times 2^{(6 - 1)} = 3 \times 2^5 = 3 \times 32 = 96.

Partial Sum of a Sequence

Arithmetic Sequence

  • The partial sum (Sn) of the first n terms of an arithmetic sequence is given by: Sn = \frac{(a1 + an)}{2} \times n
    This formula calculates the sum by taking the average of the first and last terms and multiplying by the number of terms.

Example
  • Find the sum of the first 7 terms of the arithmetic sequence 3, 7, 11, 15, 19, 23, 27.

    • a_1 = 3

    • a_7 = 27

    • n = 7

    S_7 = \frac{(3 + 27)}{2} \times 7 = \frac{30}{2} \times 7 = 15 \times 7 = 105

Geometric Sequence

  • The partial sum (Sn) of the first n terms of a geometric sequence is given by: Sn = a_1 \times \frac{1 - r^n}{1 - r}

    Where:

    • a_1 is the first term.

    • r is the common ratio.

    • n is the number of terms.

Example
  • Find the sum of the first 6 terms of the geometric sequence 3, 6, 12, 24, 48, 96.

    • a_1 = 3

    • r = 2

    • n = 6

    S_6 = 3 \times \frac{1 - 2^6}{1 - 2} = 3 \times \frac{1 - 64}{-1} = 3 \times \frac{-63}{-1} = 3 \times 63 = 189

Sequences vs. Series

  • Sequence: A list of numbers (e.g., 3, 7, 11, 15, 19).

  • Series: The sum of the numbers in a sequence (e.g., 3 + 7 + 11 + 15 + 19).

Types of Sequences and Series

  • Finite Sequence/Series: Has a beginning and an end (e.g., 3, 7, 11, 15, 19).

  • Infinite Sequence/Series: Continues indefinitely (e.g., 3, 7, 11, 15, 19, …).

    • The presence of dots indicates that the sequence or series goes on to infinity.

Practice Problems: Identifying Sequences and Series

Classify each of the following as a sequence or series, finite or infinite, and arithmetic, geometric, or neither.

  • a. 4, 7, 10, 13, 16, 19:

    • Sequence

    • Finite

    • Arithmetic (common difference of 3)

  • b. 4, 8, 16, 32 …:

    • Sequence

    • Infinite

    • Geometric (common ratio of 2)

  • c. 5 + 9 + 13 + 17 …:

    • Series

    • Infinite

    • Arithmetic (common difference of 4)

  • d. 2 + 6 + 18 + 54 + 162:

    • Series

    • Finite

    • Geometric (common ratio of 3)

  • e. 50, 46, 42, 38 …:

    • Sequence

    • Infinite

    • Arithmetic (common difference of -4)

  • f. 3 + 12 + 48 …:

    • Series

    • Infinite

    • Geometric (common ratio of 4)

  • g. 12 + 18 + 24 + 30 + 36:

    • Series

    • Finite

    • Arithmetic (common difference of 6)

Writing Terms of a Sequence

  • Write the first four terms of the sequence defined by the formula a_n = 3n - 7.

    • a_1 = 3(1) - 7 = -4

    • a_2 = 3(2) - 7 = -1

    • a_3 = 3(3) - 7 = 2

    • a_4 = 3(4) - 7 = 5

    • The first four terms are -4, -1, 2, 5.

Finding the Next Terms in an Arithmetic Sequence

  • Write the next three terms of the arithmetic sequence 15, 22, 29, 36, …

    • Find the common difference: d = 22 - 15 = 7.

    • Add the common difference to the last term to find the next terms:

      • 36 + 7 = 43

      • 43 + 7 = 50

      • 50 + 7 = 57

Writing the First Few Terms of an Arithmetic Sequence

  • Write the first five terms of an arithmetic sequence given a_1 = 29 and d = -4.

    • The first term is 29.

    • Add the common difference to generate subsequent terms:

      • 29 + (-4) = 25

      • 25 + (-4) = 21

      • 21 + (-4) = 17

      • 17 + (-4) = 13

Recursive Formulas

  • Write the first five terms of the sequence defined by the following recursive formulas.

Part a

  • a1 = 3, an = a_{n-1} + 4

    • a2 = a1 + 4 = 3 + 4 = 7

    • a3 = a2 + 4 = 7 + 4 = 11

    • a4 = a3 + 4 = 11 + 4 = 15

    • a5 = a4 + 4 = 15 + 4 = 19

Part b

  • a1 = 2, an = 3 \times a_{n-1} + 2

    • a2 = 3 \times a1 + 2 = 3 \times 2 + 2 = 8

    • a3 = 3 \times a2 + 2 = 3 \times 8 + 2 = 26

    • a4 = 3 \times a3 + 2 = 3 \times 26 + 2 = 80

    • a5 = 3 \times a4 + 2 = 3 \times 80 + 2 = 242

Writing General Formulas

  • Write a general formula (or explicit formula) for the sequences shown below.

Part a

  • 8, 14, 20, 26, …

    • The sequence is arithmetic.

    • a_1 = 8

    • d = 14 - 8 = 6

    • an = a1 + (n - 1)d = 8 + (n - 1)6 = 8 + 6n - 6 = 6n + 2

Part b

  • \frac{2}{3}, \frac{3}{5}, \frac{4}{7}, \frac{5}{9}, \frac{6}{11}, …

    • Separate the numerator and denominator into two sequences.

    • Numerator: 2, 3, 4, 5, 6, … Arithmetic with a1 = 2, d = 1, an = n + 1

    • Denominator: 3, 5, 7, 9, 11, … Arithmetic with a1 = 3, d = 2, an = 2n + 1

Further Problems

Part a

  • 5, 14, 23, 32 ….

    • a_1 = 5

    • d = 9

    • a_n = 5 + (n-1)9

    • a_n = 5 + 9n - 9

    • a_n = 9n - 4

Part b

  • 150, 143, 136, 129

    • a_1 = 150

    • d = -7

    • a_n = 150 + (n-1)(-7)

    • a_n = 150 -7n + 7

    • a_n = 157 - 7n

Part c

Calculate the value of the tenth term of the sequence

  • a_{10} = 9(10) - 4

  • a_{10} = 90 - 4

  • a_{10} = 86

Part d

Calculate the value of the tenth term of the sequence

  • a_{10} = 157 - 7(10)

  • a_{10} = 157 - 70

  • a_{10} = 87

Part e

Find the sum of the first ten terms

  • Sn = (a1 + a_n) / 2 * n

  • S_{10} = (5 + 86) / 2 * 10

  • S_{10} = (91) / 2 * 10

  • S_{10} = 455

Part f

Find the sum of the first ten terms

  • Sn = (a1 + a_n) / 2 * n

  • S_{10} = (150 + 87) / 2 * 10

  • S_{10} = (237) / 2 * 10

  • S_{10} = 1185

Further Practise

Part a

Find the sum of the first three hundred natural numbers

  • Sn = (a1 + a_n) / 2 * n

  • S_{300} = (1 + 300) / 2 * 300

  • S_{300} = (301) / 2 * 300

  • S_{300} = 45150

Part b

Calculate the sum of all even numbers from two to 100 inclusive

  • Sn = (a1 + an) / 2 * n an = a_1 + (n-1)d

  • Calculate n
    100 = 2 + (n-1)2

  • 49 = n - 1

  • n = 50

  • S_{50} = (2 + 100) / 2 * 50

  • S_{50} = (102) / 2 * 50

  • S_{50} = 2550

Part c

Try this one determine the sum of all odd integers from 20 to seventy six

  • Sn = (a1 + an) / 2 * n an = a_1 + (n-1)d

  • Calculate n
    75 = 21 + (n-1)2

  • 27 = n - 1

  • n = 28

  • S_{28} = (21 + 75) / 2 * 28

  • S_{28} = (96) / 2 * 28

  • $$S_{28} = 1344"