Honors Algebra 1 Final Review Notes

Solving Linear Equations

  • Example: Solve 3(2x5)=74x-3(2x-5)=7-4x
    • Expand: 6x+15=74x-6x+15=7-4x
    • Add 6x6x to both sides: 15=7+2x15 = 7 + 2x
    • Subtract 7 from both sides: 8=2x8 = 2x
    • Divide by 2: x=4x = 4
  • Using Desmos to find the solution: Find the intersection point of the two lines.

Types of Solutions for Systems of Equations

  • One Solution: The lines intersect at one point.
  • No Solution: The lines are parallel (same slope, different y-intercepts).
  • Infinite Solutions: The lines are the same (identical equations).
  • Example 1:
    • I. 42x=2(2x)42x=42x4-2x=2(2-x) \Rightarrow 4-2x=4-2x (Infinite solutions)
    • II. 4x3=2x54x-3=2x-5 (One solution)
    • III. 8x=5x+38x=5x+3 (One solution)
    • IV. 123x=63x12-3x=6-3x (No solution)
  • Example 2:
    • I. 2(2x1)+7=2(2x)+54x+5=4x+52(2x-1)+7=2(2x)+5 \Rightarrow 4x + 5 = 4x + 5 (Infinite solutions)
    • II. 3x+8=2(3x+2)3x3x+8=6x+43x3x+8=3x+43x+8=2(3x+2)-3x \Rightarrow 3x+8=6x+4-3x \Rightarrow 3x+8=3x+4 (No solution)
    • III. 8x2=2(4x1)8x2=8x28x-2=2(4x-1) \Rightarrow 8x-2=8x-2 (Infinite solutions)
    • IV. 7(x3)=2x+3x7x21=x+37(x-3)=2x+3-x \Rightarrow 7x-21 = x + 3 (One solution)

Domain and Range

  • Domain: The set of all possible x-values.
  • Range: The set of all possible y-values.
  • For a relation given as a set of ordered pairs, list the x-values for the domain and the y-values for the range. Remember not to repeat any values.
    • Example: Given the relation (2,2),(3,2),(2,3),(1,4){(2,2), (3,2), (2,3), (1,4)}, the domain is 2,3,1{2, 3, 1} and the range is 2,3,4{2, 3, 4}.
    • Example: Given the relation (4,5),(3,4),(0,1),(2,2),(3,4){(-4,5), (-3,4), (0,-1), (2,2), (3,-4)}, the range is 5,4,1,2,4{5, 4, -1, 2, -4}.
  • For a graphed function:
    • Domain: Read the x-values from left to right.
    • Range: Read the y-values from bottom to top.
    • Use inequality notation to express the domain and range.
    • Closed dots indicate inclusion (\leq or \geq), while open dots indicate exclusion (<< or >>).
    • Example: Domain: 4x4-4 \leq x \leq 4; Range: 5y3-5 \leq y \leq 3

Solving Formulas

  • To solve a formula for a specific variable, isolate that variable using reverse PEMDAS.
  • Example: Solve a(mr)+t=sa(m-r) + t = s for aa.
    • Subtract tt from both sides: a(mr)=sta(m-r) = s - t
    • Divide by (mr)(m-r): a=stmra = \frac{s-t}{m-r}

Linear Functions

  • Zero of a function: The x-intercept (where the graph crosses the x-axis).
  • Value of the function when x=0: The y-intercept (where the graph crosses the y-axis).

Graphing Linear Equations

  • Convert to slope-intercept form (y=mx+by = mx + b), where mm is the slope and bb is the y-intercept.
  • Plot the y-intercept on the y-axis.
  • Use the slope to find other points on the line (rise over run).
  • Use Desmos to check the work.
  • Example: 5x3y=155x - 3y = 15
    • 3y=5x+15-3y = -5x + 15
    • y=53x5y = \frac{5}{3}x - 5

Ordered Pairs on a Line

  • To check if an ordered pair lies on a line, substitute the x and y values into the equation. If the equation holds true, the point lies on the line.
  • Alternatively, put the equation in Desmos and create a table to find if the points are valid.
  • Example: Check which ordered pair lies on 3x+5y=243x + 5y = 24
    • Convert to slope-intercept form: y=35x+245y = -\frac{3}{5}x + \frac{24}{5}
    • Points (1, 4.2), (4, 2.4), (5, 1.8), and (8, 0) can be checked. Given the solutions, one can create a table on Desmos with the equation to check.

X and Y Intercepts

  • X-intercept: (-3, 0)
  • Y-intercept: (0, 3)

Graphing Inequalities

  • Solid line: \leq or \geq
  • Dashed line: << or >>
  • Shade above the line for >> or \geq
  • Shade below the line for << or \leq

Systems of Equations

  • System of equations: A set of two or more equations with the same variables.
  • Example: The length LL of a rectangle is 7 less than 3 times the width WW. The perimeter is 146 meters.
    • L=3W7L = 3W - 7
    • 2(L+W)=1462(L + W) = 146
  • Substitute 3w-7 for L: 146=2((3w7)+w)146 = 2((3w-7)+w)
  • Example: Dustin wants to buy 9 tickets to the circus. Lower balcony tickets cost $20.95, and upper balcony tickets cost $12.50. He spent $146.30.
    • Let xx be the number of lower balcony tickets and yy be the number of upper balcony tickets.
    • x+y=9x + y = 9
    • 20.95x+12.50y=146.3020.95x + 12.50y = 146.30
    • Substituting y = 9-x: 20.95x+12.50(9x)=146.3020.95x + 12.50(9-x) = 146.30

Simplifying Expressions with Exponents

  • Use the laws of exponents.
  • Example: Simplify (3+1)2(32)2(x2)2(3 + 1)^2 (3 - 2)^2 (x^2)^2
    • 4212x44^2 * 1^2 * x^4
    • 161x416 * 1 * x^4
    • 16x416x^4
  • Another example is 5x3y5x2y4\frac{5x^3y^5}{x^2y^4}
    • 5x(32)y(54)5 * x^(3-2) * y^(5-4)
    • 5xy5xy

Area of a Rectangle

  • Area = Length x Width
  • Example: The width of a rectangle is (2x3)(2x - 3), and the length is (3x+7)(3x + 7).
    • A=(3x+7)(2x3)A = (3x + 7)(2x - 3)
    • A=6x29x+14x21A = 6x^2 - 9x + 14x - 21
    • A=6x2+5x21A = 6x^2 + 5x - 21

Factoring Quadratics

  • Example: Factor 6y2y126y^2 - y - 12
    • reverse box method. (2x3)(3x+4)(2x-3)(3x+4)

Lines of Symmetry for Conic Sections

  • Vertical line of symmetry: x=ax = a

Transformations of Functions

  • Vertex form of a quadratic equation: y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex.
  • To translate a graph left by 2 units, replace xx with (x+2)(x + 2).
  • To translate a graph up by 5 units, add 5 to the equation.
  • Example: Translate y=x2y = x^2 left 2 units and up 5 units.
    • y=(x+2)2+5y = (x + 2)^2 + 5

Solving Quadratic Equations

  • Quadratic equations must be set equal to 0 before solving.
  • Solve by factoring or using the quadratic formula.
  • Example: Solve 3x2+2x+5=63x^2 + 2x + 5 = 6
    • 3x2+2x1=03x^2 + 2x - 1 = 0
    • (3x1)(x+1)=0(3x - 1)(x + 1) = 0
    • 3x1=03x - 1 = 0 or x+1=0x + 1 = 0
    • x=13x = \frac{1}{3} or x=1x = -1
  • Quadratic Formula: For ax2+bx+c=0ax^2 + bx + c = 0,
    • x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
  • Example: Solve 4x23x2=04x^2 - 3x - 2 = 0 using the quadratic formula.
    • x=(3)±(3)24(4)(2)2(4)x = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(4)(-2)}}{2(4)}
    • x=3±9+328x = \frac{3 \pm \sqrt{9 + 32}}{8}
    • x=3±418x = \frac{3 \pm \sqrt{41}}{8}

Exponential Growth

  • Formula: y=a(1+r)xy = a(1 + r)^x, where aa is the initial amount, rr is the interest rate, and xx is the number of time periods.
  • Example: Betty has $2000 in her savings account, earning 1.5% interest each year. Find the equation to determine the total amount of money yy after xx years.
    • y=2000(1+0.015)xy = 2000(1 + 0.015)^x
    • y=2000(1.015)xy = 2000(1.015)^x