Energy for buildings is the most important sector of energy demand in the United States
Energy for building operations accounts for 40% of U.S. primary energy demand
Transportation accounts for 28% and the industrial sector accounts for 32%
The total energy demand for the building sector grows to almost half of all U.S. primary energy when embodied energy is included
Buildings are responsible for almost 40% of all U.S. carbon emissions
Better windows, insulation, building envelopes, and ducts can reduce the energy demand for heating and cooling in buildings
Solar energy can be used to heat buildings in the winter, provide natural daylight, and supply energy for water heating
Almost two-thirds of the total energy demand in buildings is for space heating and cooling, lighting, and water heating
Controlling plug loads is an emerging challenge in terms of total energy demand and peak power demand
Residential buildings have higher energy demands than commercial buildings
Commercial buildings have different energy characteristics, such as higher illumination levels and higher internal thermal gains
Site energy refers to the energy consumed at the building site, while primary energy includes the energy losses in power generation and transmission
Primary energy accounts for all the energy inputs needed to deliver a unit of energy to the site
Site energy ignores losses in power generation and transmission
Electricity delivered to the site can be expressed in kWhe (kilowatt-hours electrical) to differentiate it from other energy streams
Subscript "e" indicates electricity, and subscript "t" indicates on-site fuel for heating the building.
Two units of site energy and four units of primary energy in the example.
Primary energy is a better measure for characterizing the overall energy efficiency of a building.
The primary energy metric allows for normalized efficiency ratings for individual buildings.
The Passive House Institute uses an overall efficiency measure of 120 kWh/m2 of primary energy per year for household space heating, water heating, and domestic electricity for certification.
Space heating is the largest energy demand category in U.S. buildings, accounting for almost one-quarter of all building energy.
Improving the energy efficiency of the building envelope can significantly reduce heating demands.
Passive solar ideas and efficient heating and cooling systems can help minimize energy demand.
Heat loss occurs through walls, windows, doors, ceiling, floors, and infiltration.
Infiltration refers to air leakage through cracks and holes, while ventilation is intentional fresh air intake.
Heat loss rate through each component of the building envelope is calculated using the equation qtot = qwalls + qwindows + qceiling + qfloor + qdoors + qinfiltration.
The U-value represents the thermal conductance and is used to calculate the heat loss rate.
Site energy and primary energy are two different ways to characterize building energy demand.
Site energy considers the energy used on-site, while primary energy accounts for the energy used at the power plant and grid losses.
A comparison is made between two identical houses with different heating systems.
The gas furnace house uses 100 units of fuel at 90% efficiency to deliver 90 units of heat.
The electric resistance heating house requires 90 units of site electricity to deliver 90 units of heat.
Using the 3:2:1 ratio, 270 units of heat are needed at the power plant to deliver 90 units of electricity to the electric house.
When using site energy, the electric house appears more efficient, but when considering primary energy, the gas furnace is more efficient, using only 100 units compared to 270 units for the electric heater.
Introduction of the concept of the R-value of a building component
The R-value is the inverse of the U-value
Equation 6.3: q = UA∆T = 1/A∆T R
This equation relates heat transfer rate (q) to the R-value, surface area (A), and temperature difference (∆T)
Comparison of Eq. 6.3 to an electrical equivalent
Example calculation of heat loss rate through a wall using Eq. 6.3
The R-value summarizes heat transfer mechanisms including radiation, convection, and conduction
Introduction of the three basic heat transfer processes: radiation, convection, and conduction
Four temperatures to track: inside air temperature (Ti), outside air temperature (Ta), surface temperatures of the wall or window on the room side (T1), and surface temperatures on the ambient side (T2)
Thermal resistances represented by nodes in a series combination
Figure 6.7 shows thermal and electrical analogies
Figure 6.8 illustrates heat transfer through a window
Total resistance to heat flow can be modeled as a series combination of conduction, convection, and radiation thermal resistances
Equation 6.5: Conductive resistance (RC) = t/k
RC is a measure of thermal resistance
R-value per inch thickness of a material is 1/k
Table 6.2 provides R-values per inch for common building materials
Example of using R-value for conductive resistance calculation
Concrete conducts heat well but has a low R-value
Comparison of concrete wall thickness to a fiberglass-insulated wall framed with two-by-fours
Introduction of heat transfer by convection
Warm molecules in a fluid transfer heat to cooler objects
Example of convection in the window example from Figure 6.8
Table 6.1 provides thermal conductivity values for selected materials
Convective heat transfer in buildings
Air in contact with cold window surface transfers heat to the window
Cools the air and increases its density
Cold, dense air falls toward the floor
Warmer room air moves toward the window and dumps heat onto the window surface
Creates convective air currents in the room
Can cause discomfort and drafts
Factors influencing convective heat transfer
Speed of air movement along the surface
Faster-moving air transfers heat more easily
Heating and cooling calculations based on assumed windspeeds
Direction of heat flow (easier through the ceiling than at the cold floor)
Surface roughness (bumpy surfaces encourage heat transfer)
Radiation heat transfer
Occurs even in a vacuum
Every object radiates energy to its surroundings
Rate of radiation is proportional to emissivity, surface area, and temperature raised to the fourth power
Objects in a room radiate energy that can be absorbed by surrounding surfaces
Absorptivity for thermal radiation is usually above 90% for typical surfaces
Shiny, metallic surfaces reflect outgoing radiation back into the room
Insulating materials and low-e windows use reflective surfaces to reduce heat loss
Combined convective-radiative R-value
Convective and radiative components of heat transfer lumped into a single R-value
Rcvi for indoor surfaces and Rcvo for outside surfaces
Standard values for Rcvo: 0.17 hr-ft2-°F/Btu for winter, 0.25 hr-ft2-°F/Btu for summer
Rcvi values depend on direction of heat flow and surface properties
Ordinary surfaces (emissivity e ≈ 0.9)
Reflective surfaces (e ≈ 0.20)
Shiny surfaces (e ≈ 0.05)
Total R-value for a building surface is the sum of R-values due to conduction, convection, and radiation
Table 6.3 summarizes convective-radiative R-values for various building surfaces
Figure 6.9 illustrates the application of convective-radiative heat transfer coefficients in a building
Heat loss through windows is a major concern in buildings
Single-pane windows are the biggest source of heat loss
New construction uses double-glazed windows
Cold windows can cause discomfort and condensation problems
The indoor surface temperature of the glass can be very cold
The heat loss rate from the room to the inside surface of the glass can be calculated using the formula: q = A(Ti - T1) = A(Ti - Ta)/Rtot
Condensation problems are more associated with the window frame than the glass itself
The dew point is the temperature below which air can no longer hold moisture
Improving the R-value of windows
Double-pane windows with low-e coatings improve the R-value from about R-2 to R-3
Filling the air gap with argon or krypton gas further improves the R-value
High-performance glazing systems with suspended polyester films and low-emissivity coatings achieve exceptionally high R-values
Window heat losses are complicated by edge effects associated with the window frame
The choice of window framing materials can negate the advantages of high-efficiency glazing systems
Center-of-glass R-values and edge effects need to be considered in the heat loss analysis of windows
Comparing the room-side surface temperature of single-pane and low-e, double-pane windows
The single-pane window has a room-side surface temperature of 35°F
The low-e, double-pane window has a room-side surface temperature of 60°F
Fiberglass frame for a window increases overall R-value compared to an aluminum frame
Example of high-performance windows with low-e coatings and krypton gas fillings
Heat transfer pathways in windows: frame, glass area near the frame, and center-of-glass (COG) area
Analysis of R-value impacts for a double-glazed window with different frames
Importance of the frame in maintaining R-value
Energy advantage of bigger windows compared to smaller windows
Heat loss calculations for walls, ceilings, and floors are more complicated than windows
Walls have parallel conduction paths through framing members and wall cavities
Introduction of U-values for analyzing heat loss rate in walls
Formulas for calculating average U-value and R-value for walls
Changes in wall framing can reduce wood materials and increase cavity area for insulation
Example of wall R-value calculations for a typical wall and an improved wall
Use of two-by-sixes on 24-inch centers and exterior insulating sheathing to increase R-value
Solution box with calculations for finding the overall R-value of a wall with two-by-fours on 16-inch centers and R-11 fiberglass insulation
Heat loss through a vaulted or cathedral ceiling is an extension of wall calculations.
For homes with ventilated attic spaces, heat loss calculation is complicated by heat loss from the room into the attic and from there to the outdoors.
The attic can be assumed to be at the same temperature as ambient for simple calculations.
Heat loss calculations for floors are complicated due to different ways of building them.
Heat loss through floors is only a modest fraction of the total heat loss.
For a floor built over a crawl space, the heat loss rate is determined by the R-value of the flooring, insulation, and the crawl space itself.
Adding R-6 to the insulation R-value accounts for the impact of the crawl space.
For unheated basements, adding R-6 provides a reasonable first approximation.
For small slab-on-grade floors, heat transfer is dominated by losses through the perimeter of the slab to ambient.
Slabs are often insulated along the perimeter to reduce heat losses.
The equation used to estimate slab losses is based on the linear feet of perimeter rather than floor area.
The heat loss factor F2 depends on the R-value of the insulation and the vertical dimension of that insulation.
Infiltration losses occur when cold air leaks into the house while warm indoor air leaks out.
Infiltration losses are driven by the temperature difference and pressure differences caused by wind.
Stack-driven infiltration is caused by warm indoor air rising and creating higher pressure indoors, drawing in cold air near the floor.
Wind-driven infiltration is caused by pressure differences and is most important to plug in the walls.
The most important leaks to plug for stack-driven infiltration are near the ceiling and floor.
For wind-driven infiltration, the leaks in the walls are most important.
Provides examples of the F2 factor for different slab surfaces and insulation levels.
Estimating Infiltration Rate (Blower-Door Approach)
qinf = rcnV(Ti −Ta)
qinf: heat loss due to infiltration (Btu/hr)
r: density of air (0.075 lb/ft3)
c: specific heat of air (0.24 Btu/lb-°F)
n: number of air changes per hour (ach)
V: volume of air per air change (ft3/ac)
qinf = 0.018 nV(Ti −Ta)
Estimating n (number of air changes per hour)
Infiltration rates:
Years ago: 1.5 ach
Good, tight new home: 0.5 ach
Below 0.35 ach, indoor air quality becomes an issue
Measurement of infiltration rates:
Artificially pressurizing or depressurizing a house using a large fan and nylon door insert
Air change rate at 50 Pa (ACH50) = Airflow rate at 50 Pa / House volume
Rule of thumb for estimating annual average infiltration: n (ach) ≈ ACH50
How Tight Is "Too Tight" for Healthful Indoor Air Quality?
Guideline for healthful indoor air: 15 cfm of fresh air per person
Calculation for air changes per hour needed: n = 15 ft3/min-person × 60 min/hr × 4 people / (2000 ft2 × 8 ft)/ac
Minimum fresh air requirements can be reduced using construction techniques
Passive House Institute requires less than 0.6 air changes per hour at the full 50-Pa blower door test pressure
Example of estimating heat loss caused by infiltration using ACH50
Blower door test on a 2000-square-foot house showed 4000 cfm of airflow was needed to pressurize the house to 50 Pa
ACH50 = 15 ach
Heat loss rate due to infiltration at specified temperatures: qinf = 0.018 Btu × 0.75 air change × 2000 ft2 × 8 ft × (70−30)°F = 8640 Btu/hr
Impact of Tightness on Indoor Air Quality and Energy Efficiency
Tightness without mechanical ventilation creates unhealthful indoor conditions
Heat recovery ventilator (HRV) helps address the problem by transferring heat from warm exhaust air to cool incoming air
Energy recovery ventilators or enthalpy wheels can capture both sensible and latent heat
Test based on indoor CO2 concentration to determine if enough fresh air is present
Indoor air with less than about 1000 ppm of CO2 meets the 15 cfm per person fresh air guideline
HVAC systems in large buildings can control ventilation using the CO2 test
Relationship between measured indoor CO2 and fresh air per person in the room
Testing the ventilation guideline that suggests an indoor CO2 concentration exceeding 1000 ppm means the room is getting less than 15 cfm of fresh air per person.
Using stoichiometry to calculate the amount of CO2 emitted per kcal.
C6H12O6 + 6 O2 → 6 CO2 + 6 H2O + 2551 kJ/mole of glucose
264 g CO2 × 4.187 kJ × 24.46 × 103 cm3/mol = 241 cm3 CO2/kcal
Calculating the CO2 emission rate for an "average" 140-lb person at rest.
CO2 emission rate = 140 lb × 0.48 kcal/hr/lb × 241 cm3/kcal = 16,195 cm3 CO2/hr
Determining the CO2 added to the 15 cfm/person of incoming air.
CO2 @ 15 cfm/person = 16,195 cm3 CO2/hr × 35.3 ft3/m2 = 635 ppm
Total indoor concentration of CO2 when 15 cfm of fresh air per person is provided.
Total indoor concentration = 635 ppm + 395 ppm = 1030 ppm
Summing up the contributions of each component (windows, walls, floors, ceilings, doors, infiltration) to calculate the overall heat loss rate of a house.
Using Table 6.5 to obtain typical R-values for each component.
Setting up a spreadsheet approach to evaluate the heat loss rate for the entire building.
Each row in the spreadsheet summarizes a major building element, providing its area, R-value, U-value, UA product (Btu/hr-°F), and its percentage of the total (UA)-value.
Infiltration is treated as the product of a U-value and an area to have the same Btu/hr-°F units as other components.
Infiltration loss can be accounted for in the table by converting it into an equivalent (UA) product using the relationship Eq. 6.19.
(UA)inf = 0.018 nV (Btu/hr-°F)
A heat recovery ventilator (HRV) may be included in tight houses to increase ventilation without losing exhaust heat.
The UA equivalent for the HRV is given by Eq. 6.20.
(UA)HRV = 0.018 nHRV V · (1−ηHRV)
Table 6.6 shows an example of a spreadsheet created for a small, well-insulated house.
The house features two-by-six walls with R-21 insulation, double-pane aluminum frame windows, R-30 insulation in the ceiling, and R-21 floor insulation with one-inch of XPS.
The infiltration rate is 0.6 ach, and there is no HRV.
The dominant sources of heat loss are the windows (37%) and infiltration (27%).
The table also includes a normalized measure of the efficiency of the house called the thermal index.
The thermal index is defined as Eq. 6.21.
Thermal index (Btu) = 24 hr/day × (UA)tot Btu/hr-°F ft2-°F-day / Floor space area (ft2)
The thermal index for this example house is 7.7 Btu/ft2 per degree-day.
Furnaces are sized to deliver enough heat to keep a house at a desired thermostat set point while the ambient temperature drops to the coldest temperature likely for that location.
Furnaces are usually somewhat oversized to ensure an adequate heat supply and to allow for a little extra boost called the pick-up factor.
Furnaces are most efficient if they run continuously rather than turning on and off frequently.
The furnace output needed for a house can be calculated using Eq. 6.22.
qfurnace = (UA)tot (Tset − Tdesign) · pick-up factor ηdistribution
Table 6.7 provides a brief sample of design temperatures for a few U.S. cities along with their heating degree days (HDD).
The table also mentions that furnaces are most efficient if they run continuously and oversizing is often restricted to about 40% above the design load.
The furnace converts fuel to heat that is delivered to the house through a heat distribution system.
Furnace sizing depends on output, not efficiency
Furnaces are rated by their output (Btu/hr)
Internal heat gains are not included in furnace sizing
Furnace has to provide enough heat even when no one is home
Goal is to estimate economic value gained by improving house efficiency
Need to consider local climate and cost of fuel
People and appliances in homes provide internal heat gains
Example: 3 people contribute 350 Btu/hr each, appliances contribute 500 kWh/mo
Internal gains help heat the house depending on the (UA) value of the house
Example of sizing a furnace for a house in Blacksburg, Virginia
(UA)tot = 482 Btu/hr-°F heat loss factor
75%-efficient forced-air heat distribution system
70°F thermostat set point and a 1.4 pick-up factor
qfurnace = 67,620 Btu/hr
Internal gains of 3000 Btu/hr raise indoor temperature above ambient by 6°F
Balance point temperature (Tb or Tbal) is the temperature the furnace has to raise the house to, with internal gains providing the rest
Tb = Tset - qint / (UA)tot
Heating degree-days (HDD) and cooling degree-days (CDD) are indicators of climate
HDD are accumulated on days when average temperature is less than 65°F
CDD are accrued on days when average temperature is above 65°F
Equation 6.25 relates HDD and CDD to average annual ambient temperature for a site
Adjusting the base temperature for HDD
Degree-day tables for other base temperatures are available on the web
Empirically derived adjustment formula: HDD (Tb) = HDD65 − (0.021 · HDD65 + 114) · (65 − Tb)
Example calculation for Denver using base temperature of 60°F
HDD60 = 6016 − (0.021 · 6016 + 114) · (65−60) = 4814°F-day/yr
Calculation of annual heating load
Formula: Qdel = 24 (UA) × HDD(Tb)
Qdel represents the total amount of heat needed (Btu/yr)
"24" refers to hours per day
HDD is at the base temperature Tb
Calculation of fuel needed
Formula: Qfuel = Qdel / (ηfurnace · ηdistribution)
Qfuel represents the fuel needed
ηfurnace represents the furnace efficiency
ηdistribution represents the distribution efficiency
Spreadsheet analysis for evaluating home heating costs
Spreadsheet allows for easy modification of assumptions and immediate determination of implications
Example spreadsheet provided in Table 6.10
Exploration of energy savings through construction modifications
Efficiency improvements in windows, furnace, distribution system, house tightness, and heat recovery ventilator
Spreadsheet analysis allows for easy determination of energy savings
Heating and cooling degree-days
Table 6.8 illustrates heating and cooling degree-days at a base temperature of 65°F
Rough costs of home heating fuels
Table 6.9 provides unit costs for commonly used home heating fuels
Annual fuel consumption and furnace sizing spreadsheet
Table 6.10 shows the annual fuel consumption and furnace sizing spreadsheet for a specific home in Blacksburg, Virginia
Includes values for total (UA) value, fuel price, furnace efficiency, distribution efficiency, internal gains, indoor set point, HDD65, Tdesign, and furnace pick-up factor
Calculations are performed to determine balance point temperature, HDD at the balance point, Qdel, Qfuel, annual fuel bill, and furnace output
Energy for Sustainability value for Blacksburg house reduced from 482 Btu/hr-°F to 236 Btu/hr-°F
Table 6.12 shows additional heating system improvements for the new house, resulting in an 80% reduction in the original annual fuel bill
Step-by-step approach starting with fixing leaky ducts and replacing the furnace saves 30% of the original energy demand
Calculations include balance point temperature, HDDTb, Qdel, Qfuel, annual fuel bill, and furnace output
Efficiency improvements in the Blacksburg house are listed in Table 6.11
Marginal benefit of each additional efficiency measure is diminished when done in a step-by-step basis
Treating the whole set of measures together may make more sense, especially for new construction
Forced-air central heating systems are popular in the United States, with advantages such as rapid heat delivery and versatility
Ducts in forced-air systems can be a weak link, often poorly insulated and plagued by leaks
Hydronic systems use boilers and pumps to distribute hot water, with small, efficient pumps and negligible distribution losses
Compressive air conditioning systems are based on the principle of compressed gas expanding and getting cold
Duct losses in forced-air systems can account for 20%–30% of heating bills
Hydronic systems are described as the most comfortable heating systems available
Hydronic systems can use baseboard radiator/convectors or tubing embedded in subflooring or concrete floor slabs
Radiant floor slab systems provide stable indoor temperatures due to their thermal flywheel effect
Boilers used in radiant systems have slightly lower efficiencies but make up for it with higher distribution efficiencies and lower thermostat settings
Compressive air conditioning systems work by allowing compressed gas to expand and get cold
Components of an air conditioner:
Compressor
Condenser coil
Expansion valve
Cold evaporator coil
Types of air conditioning systems:
Packaged systems
Split systems
Cooling capacity of air conditioners is measured in "tons of cooling"
Description of a split system air conditioner
Efficiency ratings for air conditioners:
Energy efficiency ratio (EER)
Seasonal energy efficiency ratio (SEER)
Different approaches to cooling:
Evaporative coolers
Absorption cycle air conditioners
Introduction to heat pumps and their operation
Efficiency measures for heat pumps:
SEER (as an air conditioner)
Heating season performance factor (HSPF) (as a heater)
Energy efficiency standards for split-system heat pumps
Coefficient of performance (COP) as a measure of efficiency
Comparison of air conditioner costs using SEER ratings and running costs
Calculation of simple payback period for a more efficient air conditioner
Equations 6.33 and 6.34 provide conversions for energy and thermodynamic evaluations.
Eq. 6.33: COP = HSPF (Btu heat per Wh electricity) = HSPF * 3.412 Btu/Wh
Eq. 6.34: COP = SEER (Btu/hr cooling per W of electricity) = SEER * 3.412 Btu/Wh
Sadi Carnot developed efficiency limits for heat pumps in the 19th century.
Eq. 6.35: COP (heating) ≤ TH = 1 / (TH - TC) * (1 - TC/TH)
Eq. 6.36: COP (cooling) ≤ TC = 1 / (TH - TC) * (TH/TC - 1)
Higher efficiencies are possible for heating systems with modest delivery temperatures.
Heat pumps run at constant power, so as the ambient temperature drops, the COP and heating output decrease.
Heat pumps may require electric resistance heating strips in cold climates, reducing overall efficiency.
Geothermal heat pumps (GHPs) have better efficiencies by utilizing more constant underground temperatures.
GHPs can be 40%–60% more efficient than conventional air-source heat pumps.
Ductless mini-split heat pumps have no ducts and can reduce energy losses.
Mini-splits have individual indoor units with their own heat exchangers and fans.
A new generation of mini-splits with adjustable-speed drives addresses cold weather limitations.
Mini-splits have a single outdoor unit and one or more indoor units.
Refrigerant lines connect the indoor and outdoor units.
Inverter-driven mini-splits deliver rated heating capacity at temperatures well below freezing.
Geothermal heat pumps have one of their heat exchangers located in the earth, either in deep boreholes or shallow horizontal arrays.
Mini-splits are energy-efficient heating and cooling systems for buildings.
They have inverter-driven compressors that convert AC power to DC power and then back to variable-frequency AC power.
Each indoor unit has its own controls, allowing occupants to heat or cool specific spaces.
They can be easily retrofitted without replacing existing inefficient furnaces, ducts, and controls.
Mini-splits can be used in conjunction with rooftop photovoltaics to create a carbon-free home heating and cooling system.
Buildings account for nearly half of all energy consumed in the United States.
The residential sector accounts for slightly more energy consumption than the commercial sector.
Buildings also account for approximately three-fourths of electricity demand and contribute to carbon emissions and other power-related environmental problems.
By implementing best-building practices, heating bills in a simple house can be reduced by over two-thirds.
The key areas for improvement are better windows, lower infiltration rates, and reduced distribution system losses.
Tightening up a building can potentially lead to poor indoor air quality.
Monitoring indoor CO2 levels can help determine if fresh air is needed.
Demand-controlled ventilation, such as heat recovery ventilators, can effectively improve indoor air quality in large commercial buildings.
Conventional fossil fuel-fired forced-air systems in the residential sector can be significantly improved, but the goal is to replace them with electricity-driven heat pumps.
The combination of photovoltaics on the roof and heat pumps or mini-splits can create eco-friendly