Reversible Reactions and Chemical Equilibrium Study Notes

Reversible Reactions and Dynamic Equilibrium

  • Many reactions proceed in both forward and reverse directions and are termed reversible.
  • For a reaction A+BC+DA + B \rightleftharpoons C + D, equilibrium is established when the rate of the forward reaction equals the rate of the backward reaction.
  • A dynamic equilibrium is characterized by a continual exchange of species with no observable change in concentration.
  • Once established, the concentrations of reactants and products remain constant over time.

The Law of Mass Action

  • Put forward by Guldberg and Waage.
  • It states that at a constant temperature, the rate of a reaction is proportional to the active masses of each reactant.
  • Active mass is interpreted as the concentration of a substance raised to a power corresponding to its stoichiometric coefficient in the balanced equation.
  • For the general reaction aA+bBcC+dDaA + bB \rightleftharpoons cC + dD:
    • Rate of forward reaction: r1=K1[A]a[B]br_1 = K_1[A]^a [B]^b
    • Rate of backward reaction: r2=K2[C]c[D]dr_2 = K_2[C]^c [D]^d
    • At equilibrium (r1=r2r_1 = r_2): K=[C]c[D]d[A]a[B]bK = \frac{[C]^c[D]^d}{[A]^a[B]^b}, where KK is the equilibrium constant.

Homogeneous and Heterogeneous Equilibria

  • Homogeneous Equilibrium: All reactants and products are in the same physical state (e.g., all gases).
  • Heterogeneous Equilibrium: The substances involved are in different phases.
  • In heterogeneous systems, the active mass of a solid is constant at a constant temperature because its vapor pressure is independent of the amount of solid present.
  • The equilibrium constant expression for heterogeneous systems only includes gaseous species; solid and liquid species are omitted.
  • Example: for CaCO3(s)CaO(s)+CO2(g)CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g), the equilibrium constant is determined solely by the pressure of the gas: Kp=P(CO2)K_p = P(CO_2).

Equilibrium Constants KcK_c and KpK_p

  • KcK_c is expressed in terms of molar concentrations (moldm3mol\,dm^{-3}).
  • KpK_p is expressed in terms of partial pressures for gaseous reactions.
  • Relationship between KpK_p and KcK_c derived from the ideal gas equation (PV=nRTPV = nRT):
    • Kp=Kc(RT)ΔnK_p = K_c(RT)^{\Delta n}
    • where Δn=(c+d)(a+b)\Delta n = (c + d) - (a + b), representing the difference in stoichiometric coefficients of gaseous products and reactants.

Multiple Equilibria

  • If a reaction proceeds through a series of steps (reaction mechanism), each step has its own equilibrium constant.
  • The overall equilibrium constant for the reaction is the product of the equilibrium constants of the individual steps:
    • K=K1×K2×...K = K_1 \times K_2 \times ...

Solved Problems

  • Haber Process: For N2(g)+3H2(g)2NH3(g)N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) with equilibrium concentrations [N2]=0.30molL1[N_2] = 0.30\,mol\,L^{-1}, [H2]=0.10molL1[H_2] = 0.10\,mol\,L^{-1}, and [NH3]=0.20molL1[NH_3] = 0.20\,mol\,L^{-1}, the calculated K=1.3×102K = 1.3 \times 10^2.
  • Nitrogen Oxide Reaction: For 2NO(g)+O2(g)2NO2(g)2NO(g) + O_2(g) \rightleftharpoons 2NO_2(g) where K=5.0×105K = 5.0 \times 10^{-5}. If [NO2]=[NO][NO_2] = [NO], then [O2]=15.0×105=2×104moleL1[O_2] = \frac{1}{5.0 \times 10^{-5}} = 2 \times 10^4\,mole\,L^{-1}.
  • Esterification Calculations:
    • For ethanol and acetic acid reacting to form ethyl acetate and water, starting with 138g138\,g ethanol and 120g120\,g acetic acid, the mass of ethyl acetate at equilibrium is 138.2g138.2\,g.
    • When 2mol2\,mol ethanoic acid is mixed with 1mol1\,mol ethanol (K=4.0K = 4.0), the amount of ester produced is 0.845mol0.845\,mol.
  • Constant Conversion: For the reaction 2NOCl(g)2NO(g)+Cl2(g)2NOCl(g) \rightleftharpoons 2NO(g) + Cl_2(g), given Kc=4.4×104K_c = 4.4 \times 10^{-4} at 500K500\,K, the partial pressure constant is calculated as Kp=1.8×102K_p = 1.8 \times 10^{-2}.