Class 7 Mathematics Expressions Using Letter Numbers Study Notes

Fundamentals of Letter Numbers and Algebraic Expressions

  • Letter numbers (also referred to as variables) are letters used in mathematics to represent numbers or quantities that can vary or take on different values.

  • An algebraic expression is a mathematical expression containing letter numbers (variables), constants (fixed numbers), and operational signs (++, -, ×\times, or×\text{or} \times).

  • Age Relationship Example (Shabnam and Aftab):

    • Shabnam is 33 years older than Aftab.

    • Let Shabnam's age be represented by the letter number ss (or SS).

    • Let Aftab's age be represented by the letter number aa (or AA).

    • The algebraic equation representing this relationship is:     s=a+3s = a + 3

    • Case 1: When Aftab is 1010 years old (a=10a = 10):     s=10+3=13s = 10 + 3 = 13     Shabnam's age is 1313 years.

    • Case 2: When Aftab is 1818 years old (a=18a = 18):     s=18+3=21s = 18 + 3 = 21     Shabnam's age is 2121 years.

    • In this expression, aa represents a number that varies (1010, 1818, etc.), and ss takes the corresponding evaluated value (1313, 2121, etc.).

Real-World Applications and General Expression Building

  • Ketki's Coconut and Jaggery Laddus:

    • Ketki prepares and supplies coconut-jaggery (nariyal and gud) laddus.

    • Price of 11 coconut = Rupees 35\text{Rupees } 35

    • Price of 1 kg1\text{ kg} jaggery = Rupees 60\text{Rupees } 60

    • Specific Purchase Calculation:

    • Cost for 1010 coconuts: 10×35=Rupees 35010 \times 35 = \text{Rupees } 350

    • Cost for 5 kg5\text{ kg} jaggery: 5×60=Rupees 3005 \times 60 = \text{Rupees } 300

    • Total amount paid: 350+300=Rupees 650350 + 300 = \text{Rupees } 650

    • General Algebraic Expression:

    • Let the number of coconuts bought be cc

    • Let the quantity of jaggery bought in kg be jj

    • Total cost of coconuts = 35×c=35c35 \times c = 35c

    • Total cost of jaggery = 60×j=60j60 \times j = 60j

    • Total amount to be paid = 35c+60j35c + 60j

    • Verification: Substituting c=10c = 10 and j=5j = 5 into 35c+60j35c + 60j yields 35(10)+60(5)=350+300=65035(10) + 60(5) = 350 + 300 = 650.

  • Munirata's Garden Watering Pipe:

    • Initial pipe length owned = 20 meters20\text{ meters}

    • Munirata joins an additional pipe of length k metersk\text{ meters} to extend the overall length.

    • Combined total length expression = (20+k) meters(20 + k)\text{ meters}

    • Addition is used because the total length requires adding the joined section to the original pipe length.

  • Kritika's Currency Notes:

    • Kritika holds currency notes of denominations Rupees 100\text{Rupees } 100, Rupees 20\text{Rupees } 20, and Rupees 5\text{Rupees } 5.

    • Combination 1: 33 notes of Rupees 100\text{Rupees } 100, 55 notes of Rupees 20\text{Rupees } 20, and 66 notes of Rupees 5\text{Rupees } 5:     Total Amount=3×100+5×20+6×5=300+100+30=Rupees 430\text{Total Amount} = 3 \times 100 + 5 \times 20 + 6 \times 5 = 300 + 100 + 30 = \text{Rupees } 430

    • Combination 2: 66 notes of Rupees 100\text{Rupees } 100, 44 notes of Rupees 20\text{Rupees } 20, and 33 notes of Rupees 5\text{Rupees } 5:     Total Amount=6×100+4×20+3×5=600+80+15=Rupees 695\text{Total Amount} = 6 \times 100 + 4 \times 20 + 3 \times 5 = 600 + 80 + 15 = \text{Rupees } 695

    • Combination 3: 88 notes of Rupees 100\text{Rupees } 100, 44 notes of Rupees 20\text{Rupees } 20, and zz notes of Rupees 5\text{Rupees } 5:     Total Amount=8×100+4×20+5×z=800+80+5z=880+5z\text{Total Amount} = 8 \times 100 + 4 \times 20 + 5 \times z = 800 + 80 + 5z = 880 + 5z

    • General Combination: xx notes of Rupees 100\text{Rupees } 100, yy notes of Rupees 20\text{Rupees } 20, and zz notes of Rupees 5\text{Rupees } 5:     Total Amount=100x+20y+5z\text{Total Amount} = 100x + 20y + 5z

Translating Verbal Statements to Algebraic Expressions

  • Algebraic expressions require converting word phrases into mathematical operations:

    • Phrases indicating addition:

    • "55 more than a number": x+5x + 5 or 5+x5 + x

    • Demonstrates the Commutative Property of Addition: a+b=b+aa + b = b + a

    • Phrases indicating subtraction:

    • "44 less than a number": x4x - 4

    • Multi-operation phrases:

    • "22 less than 1313 times a number": 13x213x - 2

    • "1313 less than 22 times a number": 2x132x - 13

  • Venkatesh's Flour Mill Application:

    • Roller mill startup time delay = 10 seconds10\text{ seconds}

    • Grinding rate per kilogram of grain = 8 seconds8\text{ seconds}

    • Time required to grind y kgy\text{ kg} of grain = 8×y=8y seconds8 \times y = 8y\text{ seconds}

    • Total time expression to complete grinding y kgy\text{ kg} of grain = 10+8y seconds10 + 8y\text{ seconds}

    • Operational misconception caution: Expression (10+8)y=18y(10 + 8)y = 18y is mathematically incorrect because the startup time of 10 seconds10\text{ seconds} is a constant initial delay, not a rate multiplied by the quantity of grain yy.

Calendar Grid Expressions and Common Evaluation Pitfalls

  • 2×32 \times 3 Calendar Grid Expression:

    • Selecting a 2×32 \times 3 grid of consecutive dates on a calendar:

    • If the bottom middle cell date is denoted by ww:

    • Cell directly to the left of ww = w1w - 1

    • Cell directly to the right of ww = w+1w + 1

    • Cell directly above ww (1 week prior) = w7w - 7

    • Cell top-left (directly above w1w - 1) = (w7)1=w8(w - 7) - 1 = w - 8

    • Cell top-right (directly above w+1w + 1) = (w7)+1=w6(w - 7) + 1 = w - 6

    • Summary of grid positions:

    • Top Row: w8w - 8, w7w - 7, w6w - 6

    • Bottom Row: w1w - 1, ww, w+1w + 1

  • Common Errors to Avoid during Algebraic Evaluation:

    • Incorrect Substitution with Negative Numbers:

    • Evaluating 10a10 - a when a=4a = -4:

    • Incorrect logic: Dropping the negative sign and calculating 104=610 - 4 = 6

    • Correct evaluation: 10(4)=10+4=1410 - (-4) = 10 + 4 = 14

    • Improper Concatenation vs Multiplication:

    • Evaluating 3d3d when d=6d = 6:

    • Incorrect logic: Placing digits side-by-side to write 3636

    • Correct evaluation: 3×d=3×6=183 \times d = 3 \times 6 = 18

    • Evaluating 3s23s - 2 when s=7s = 7:

    • Incorrect logic: Concatenating to get 372=3537 - 2 = 35

    • Correct evaluation: 3×72=212=193 \times 7 - 2 = 21 - 2 = 19

    • Evaluating Terms with Multiple Variables:

    • Evaluating 2fg2g2fg - 2g when f=3f = 3 and g=1g = 1:

    • Correct evaluation: 2×3×12×1=62=42 \times 3 \times 1 - 2 \times 1 = 6 - 2 = 4

    • Incorrect Expansion of Brackets with Negative Signs:

    • Evaluating h(3n)h - (3 - n) when h=5h = 5 and n=6n = 6:

    • Correct expansion: Distributing the negative sign changes the signs inside the bracket:       h3+n=53+6=8h - 3 + n = 5 - 3 + 6 = 8

    • Alternative correct evaluation order: 5(36)=5(3)=5+3=85 - (3 - 6) = 5 - (-3) = 5 + 3 = 8

Simplification of Algebraic Expressions, Like Terms, and Unlike Terms

  • Pencil and Eraser Store Sales Example:

    • Price per pencil = cc

    • Price per eraser = dd

    • Sales over three days:

    • Day 1: 55 pencils (5c5c), 44 erasers (4d4d)

    • Day 2: 33 pencils (3c3c), 66 erasers (6d6d)

    • Day 3: 1010 pencils (10c10c), 11 eraser (1d1d)

    • Total money earned from pencils = 5c+3c+10c=18c5c + 3c + 10c = 18c

    • Total money earned from erasers = 4d+6d+1d=11d4d + 6d + 1d = 11d

    • Total shopkeeper revenue = 18c+11d18c + 11d

  • Definitions and Classification of Terms:

    • Like Terms: Terms containing the exact same letter numbers (variables) raised to the exact same exponents (powers).

    • Examples: 5c5c and 6c6c are like terms; 7y7y and 19y19y are like terms.

    • Coefficients (numerical factors) are ignored when determining if terms are like terms.

    • Unlike Terms: Terms containing different letter numbers or the same letter numbers raised to different exponents.

    • Examples: 6c26c^2 and 4c4c are unlike terms because the exponents on cc differ (22 versus 11); 7y7y and 8x8x are unlike terms because the variables differ (yy versus xx).

    • Fundamental Rule of Algebraic Operations: Only like terms can be added or subtracted together by operating on their numerical coefficients.

Furniture Rental and Operation Properties

  • Furniture Rental Deposit and Refund Problem:

    • Chair deposit per piece = Rupees 40\text{Rupees } 40

    • Chair refund upon return = Rupees 6\text{Rupees } 6

    • Net rental price per chair = 406=Rupees 3440 - 6 = \text{Rupees } 34

    • Table deposit per piece = Rupees 75\text{Rupees } 75

    • Table refund upon return = Rupees 10\text{Rupees } 10

    • Net rental price per table = 7510=Rupees 6575 - 10 = \text{Rupees } 65

    • For renting xx chairs and yy tables:

    • Total deposit paid upfront = 40x+75y40x + 75y

    • Total payback refunded = 6x+10y6x + 10y

    • Net payment formula = (40x+75y)(6x+10y)=40x+75y6x10y=34x+65y(40x + 75y) - (6x + 10y) = 40x + 75y - 6x - 10y = 34x + 65y

    • Equivalent algebraic expression expansion: 40x+75y+(6x10y)40x + 75y + (-6x - 10y)

  • Application of the Distributive Property:

    • Simplifying 4(x+y)y4(x + y) - y:     4(x+y)y=4x+4yy=4x+3y4(x + y) - y = 4x + 4y - y = 4x + 3y

  • Non-Equivalence Demonstration (5u5u versus 5+u5 + u):

    • Multiplication (5u5u) and addition (5+u5 + u) yield entirely different values for identical variable inputs:

    • If u=11u = 11: 5u=5(11)=555u = 5(11) = 55, whereas 5+u=5+11=165 + u = 5 + 11 = 16

    • If u=8u = 8: 5u=5(8)=405u = 5(8) = 40, whereas 5+u=5+8=135 + u = 5 + 8 = 13

    • If u=2u = 2: 5u=5(2)=105u = 5(2) = 10, whereas 5+u=5+2=75 + u = 5 + 2 = 7

    • If u=5u = 5: 5u=5(5)=255u = 5(5) = 25, whereas 5+u=5+5=105 + u = 5 + 5 = 10

    • Conclusion: 5u5+u5u \neq 5 + u

Expressions with Operations and Pattern Recognition

  • Simplifying Sequences of Variables:

    • p+p+p+p+p+p+p+q=7p+qp + p + p + p + p + p + p + q = 7p + q

    • p+pqq=2p2q=2(pq)p + p - q - q = 2p - 2q = 2(p - q)

    • (p+q)(p+q)=p+qpq=0(p + q) - (p + q) = p + q - p - q = 0

    • 2ddcc=d2c2d - d - c - c = d - 2c

  • Rules of Signs for Integers in Terms:

    • Same Signs: Add absolute values and preserve the common sign (1c1c=2c-1c - 1c = -2c).

    • Opposite Signs: Subtract the smaller absolute value from the larger absolute value and retain the sign of the number with the larger absolute value (14c+16c=2c-14c + 16c = 2c).

  • Numeric Input-Output Pattern Expressions:

    • Pattern 1:

    • Data pairs: (5,2)8(5, 2) \rightarrow 8; (8,1)15(8, 1) \rightarrow 15; (9,11)7(9, 11) \rightarrow 7; (6,4)8(6, 4) \rightarrow 8

    • Mathematical rule: Multiply the 1st number by 22, then subtract the 2nd number.

    • Expression for inputs xx (1st number) and yy (2nd number): 2xy2x - y

    • Pattern 2:

    • Data pairs: (5,2)5(5, 2) \rightarrow 5; (8,1)7(8, 1) \rightarrow 7; (9,11)18(9, 11) \rightarrow 18; (10,10)18(10, 10) \rightarrow 18

    • Mathematical rule: Add the 1st number and 2nd number together, then subtract 22

    • Expression for inputs aa (1st number) and bb (2nd number): a+b2a + b - 2

Periodic Design Patterns and Calendar Mathematical Structures

  • Saree Border Periodic Designs:

    • A repeating cycle consists of three distinct designs: Design A, Design B, and Design C (Period k=3k = 3):

    • Position 1: A, Position 2: B, Position 3: C

    • Position 4: A, Position 5: B, Position 6: C

    • Position 7: A, Position 8: B, Position 9: C

    • Mathematical rules based on division remainders when position number nn is divided by 33:

    • Design C: Occurs at positions where nn is divisible by 33 (remainder = 00, form 3k3k).

      • Example: Position 2727 (27×13=927 \times \frac{1}{3} = 9, remainder 00) \rightarrow Design C.

      • Example: Position 9999 (99×13=3399 \times \frac{1}{3} = 33, remainder 00) \rightarrow Design C.

    • Design A: Occurs at positions where nn leaves remainder 11 when divided by 33 (form 3k+13k + 1).

      • Example: Position 148148 (148=3×49+1148 = 3 \times 49 + 1) \rightarrow Design A.

    • Design B: Occurs at positions where nn leaves remainder 22 when divided by 33 (form 3k+23k + 2).

      • Example: Position 88 (8=3×2+28 = 3 \times 2 + 2) \rightarrow Design B.

  • Calendar Diagonal Properties (2×22 \times 2 Blocks):

    • Any 2×22 \times 2 block selected from a calendar page takes the algebraic form:

    • Top-left cell = aa

    • Top-right cell = a+1a + 1

    • Bottom-left cell = a+7a + 7

    • Bottom-right cell = a+8a + 8

    • Diagonal Addition:

    • Diagonal 1 sum: a+(a+8)=2a+8a + (a + 8) = 2a + 8

    • Diagonal 2 sum: (a+1)+(a+7)=2a+8(a + 1) + (a + 7) = 2a + 8

    • Conclusion: Diagonal sums of any 2×22 \times 2 calendar section are identically equal regardless of the starting date aa

  • Calendar Cross/Plus Pattern Centered at Cell aa:

    • Selecting a 5-cell cross array centered at date aa:

    • Center cell = aa

    • Left cell = a1a - 1

    • Right cell = a+1a + 1

    • Top cell (1 week prior) = a7a - 7

    • Bottom cell (1 week later) = a+7a + 7

    • Total Sum of Cross Cells:     Sum=(a7)+(a1)+a+(a+1)+(a+7)=5a\text{Sum} = (a - 7) + (a - 1) + a + (a + 1) + (a + 7) = 5a

    • Conclusion: The sum of numbers in a calendar cross configuration is always exactly 55 times the center number aa.

    • Example: Center date = 1515

    • Total cross sum = 5×15=755 \times 15 = 75

  • Matchstick Connected Patterns:

    • Building connected triangular/polygonal shapes using matchsticks:

    • Shape 1 (11 unit): 33 matchsticks

    • Shape 2 (22 connected units): 3+2=53 + 2 = 5 matchsticks

    • Shape 3 (33 connected units): 5+2=75 + 2 = 7 matchsticks

    • General expression for yy connected shapes: 3+2(y1)=2y+13 + 2(y - 1) = 2y + 1

Extended Word Problems, Addition, and Subtraction Rules

  • Jowar Roti and Pulao Ordering Problem:

    • Price per plate of Jowar Roti = Rupees 30\text{Rupees } 30

    • Price per plate of Pulao = Rupees 20\text{Rupees } 20

    • Total cost for ordering xx plates of Jowar Roti and yy plates of Pulao = 30x+20y30x + 20y

  • Snail Climbing a Deep Well:

    • Daytime climb distance = u cmu\text{ cm}

    • Nighttime slip distance = d cmd\text{ cm}

    • Net daily progress (1 day + 1 night) = (ud) cm(u - d)\text{ cm}

    • Total progress after 1010 days and 1010 nights = 10u10d10u - 10d or 10(ud) cm10(u - d)\text{ cm}

  • Local Train Travel Time (Yahanpur to Wahanpur):

    • The train line contains 33 intermediate stations spaced at equal distances.

    • Total journey segments between consecutive stations = 44

    • Time taken to travel between consecutive stations = t minutest\text{ minutes}

    • Total movement time = 4t minutes4t\text{ minutes}

    • Dwell/stop time at each intermediate station = 2 minutes2\text{ minutes}

    • Total dwell time at 33 intermediate stations = 3×2=6 minutes3 \times 2 = 6\text{ minutes}

    • Expression for total journey duration = 4t+6 minutes4t + 6\text{ minutes}

    • Evaluation for t=4 minutest = 4\text{ minutes}:     Total time=4(4)+6=16+6=22 minutes\text{Total time} = 4(4) + 6 = 16 + 6 = 22\text{ minutes}

  • Algebraic Polynomial Addition:

    • Problem: Add (8d14c+9)(8d - 14c + 9) and (16c119d)(16c - 11 - 9d)

    • Rearranging like terms:     (8d9d)+(14c+16c)+(911)(8d - 9d) + (-14c + 16c) + (9 - 11)

    • Simplifying each component:

    • 8d9d=1d=d8d - 9d = -1d = -d

    • 14c+16c=2c-14c + 16c = 2c

    • 911=29 - 11 = -2

    • Simplified result: d+2c2-d + 2c - 2

  • Algebraic Polynomial Subtraction Rule:

    • Critical Rule: Statements formatted as "Subtract AA from BB" MUST be written as BAB - A.

    • Problem: Subtract (9a6b+14)(9a - 6b + 14) from (6a9b18)(6a - 9b - 18)

    • Algebraic Setup: (6a9b18)(9a6b+14)(6a - 9b - 18) - (9a - 6b + 14)

    • Distributing the negative sign through the second expression:     6a9b189a+6b146a - 9b - 18 - 9a + 6b - 14

    • Grouping like terms:

    • aa terms: 6a9a=3a6a - 9a = -3a

    • bb terms: 9b+6b=3b-9b + 6b = -3b

    • Constant terms: 1814=32-18 - 14 = -32

    • Simplified result: 3a3b32-3a - 3b - 32