capacitators and ev
Introduction to Capacitors
Topic overview:
Discussion on capacitors
Introduction to a new unit for energy: electron volt (eV)
Electron Volt (eV)
Definition:
An electron volt (eV) is the kinetic energy gained by an electron when it is accelerated through a potential difference of one volt. It's a unit of energy.
Conversion:
1 eV = 1.6 \times 10^{-19} joules
Relevance of eV in Medical Fields
Connection to medical applications:
The principle of charged particles moving through a potential difference is how X-rays are generated.
In radiology, the energy gained by electrons transformed into X-rays is frequently expressed in eV.
Clinical settings often utilize eV to discuss the energy of various X-ray emissions.
Example Problem
Problem statement:
Calculate the work done by the electric field in moving a proton from +125 volts to -45 volts. Answer should be in both joules and eV.
Calculation:
Work done = (Final potential - Initial potential) × charge;
W = (125 - (-45)) \times e = (125 + 45) \times e = 170 \times e where e is the charge of an electron.
Results:
Work done: 170e eV; Convert 170e eV to joules using conversion factor.
Parallel Plate Capacitors
Definition:
A parallel plate capacitor consists of two parallel plates made of conducting material, one carrying positive charge and the other carrying negative charge.
Important characteristics:
Potential difference between plates is denoted as \Delta V_c (potential difference across the capacitor).
Generates a uniform electric field between the plates.
The electric field points from the positive plate to the negative plate (direction of decreasing potential).
Key Variables in Parallel Plate Capacitors
Charge on plates:
Positive charge is denoted as Q and negative charge as -Q.
Distance variables:
x: position in between the plates.
d: total separation distance between the plates.
Electric Field and Potential Calculations
Electric field ( E) in parallel plate capacitors:
E = \frac{\Delta V_c}{d} where:
\Delta V_c is the potential difference across the capacitor.
d is the distance between the plates.
Electricity field magnitude also given by:
E = \frac{Q}{\varepsilon_0 A}
Where A is the plate area and \varepsilon_0 = 8.85 \times 10^{-12} \text{ F/m} (constant).
Electric potential at position x:
V(x) = E \times x
Example Problem for Electric Potential and Electric Field
Given:
Electric field: E = 1600 \text{ V/m}
Distance between plates: 0.0075 m
Objective:
Find potential difference (\Delta V_c).
Approach:
Use the formula \Delta V_c = E \times d to find:
\Delta V_c = 1600 \times 0.0075 = 12 \text{ V}.
Relationships between Variables
Notation of different electric potentials:
V is the potential at a specific point between plates, and \Delta V_c is the overall potential difference across the capacitor.
Commonly assumed values in parallel plate capacitors:
V = 0 at the negative plate.
V = V_c at the positive plate
Capacitance
Definition:
Capacitance C measures an object’s ability to store electrical charge.
Formula relating charge, potential difference, and capacitance:
C = \frac{Q}{\Delta V_c}
C: Capacitance measured in farads (F)
Q: Charge in coulombs (C)
\Delta V_c: Potential difference in volts (V)
SI Unit of Capacitance:
Farad (
F) defined as 1 \text{ F} = 1 \text{ C/V}
Charging a Capacitor
Charging mechanism:
Capacitors are charged by connecting to a battery, which acts as a charge pump.
Electrons move from one plate to accumulate charge on the other plate until equilibrium is reached where potential difference = battery voltage.
Important note:
Direction of charge movement is conventionally described as the movement of positive charges, although it’s the electrons (negative charges) that actually move.
Summary of Key Formulas
Electric field in a parallel plate capacitor:
E = \frac{\Delta V_c}{d}
Relationship between charge, capacitance:
C = \frac{Q}{\Delta V_c}
Capacitance of a parallel plate capacitor:
C = \frac{\varepsilon_0 A}{d}