Comprehensive Study Guide: Indices and Surds

Maths in Context: Indices and Piano Note Frequencies

  • An octave is a musical interval consisting of 12 consecutive semitones. When moving up an octave from a starting note C, the frequency doubles.

  • For a piano, multiplying the lowest C frequency by 21,22,23,242^1, 2^2, 2^3, 2^4, etc., calculates all its higher C frequencies. Multiplying the highest C frequency by 2−1,2−2,2−3,2−42^{-1}, 2^{-2}, 2^{-3}, 2^{-4}, etc., gives all lower C frequencies.

  • Within an octave, the frequency increases from one semitone to the next by a factor of 21122^{\frac{1}{12}} because:

(2112)12=2112×12=21=2(2^{\frac{1}{12}})^{12} = 2^{\frac{1}{12} \times 12} = 2^1 = 2

  • Consequently, the 11 notes above a starting C in an octave are found by multiplying the C frequency by:

2112,(2112)2,(2112)3,…,(2112)10,(2112)112^{\frac{1}{12}}, (2^{\frac{1}{12}})^2, (2^{\frac{1}{12}})^3, \dots, (2^{\frac{1}{12}})^{10}, (2^{\frac{1}{12}})^{11}

  • Frequencies starting from Middle C (261.6 Hz261.6\,\text{Hz}):

    • Middle C (1st note): 261.6 Hz261.6\,\text{Hz}

    • C sharp (2nd note): 261.6×2112=277.2 Hz261.6 \times 2^{\frac{1}{12}} = 277.2\,\text{Hz}

    • D (3rd note): 261.6×(2112)2=293.6 Hz261.6 \times (2^{\frac{1}{12}})^2 = 293.6\,\text{Hz}

    • B (12th note): 261.6×(2112)11=408.9 Hz261.6 \times (2^{\frac{1}{12}})^{11} = 408.9\,\text{Hz}

    • Next higher C: 261.6×(2112)12=261.6×2=523.2 Hz261.6 \times (2^{\frac{1}{12}})^{12} = 261.6 \times 2 = 523.2\,\text{Hz}

  • Tuning concert pitch: Standard concert pitch tunes A above middle C to 440 Hz440\,\text{Hz}. Each note above A is ×2112\times 2^{\frac{1}{12}} of the frequency of the note below it; each note below A is ×2−112\times 2^{-\frac{1}{12}} of the frequency of the note above it. Since Middle C is 9 semitones below A, its frequency is calculated as:

440×(2−112)9=261.6 Hz440 \times (2^{-\frac{1}{12}})^9 = 261.6\,\text{Hz}

Index Notation (Consolidating)

Group of diverse professionals
  • Indices (plural of index) provide a concise shorthand notation for repeated multiplication of the same factor.

  • Key Components of a Power:

    • Power: An expression written in index form, such as ana^n.

    • Base (aa): The factor being repeatedly multiplied.

    • Index / Exponent / Power (nn): The number of times the base factor is written.

    • Basic Numeral: The evaluated single number value of a power (e.g., in 25=322^5 = 32, 3232 is the basic numeral).

    • Fundamental Rule: a1=aa^1 = a (e.g., 51=55^1 = 5).

  • Representation Comparison:

    • Expanded Form: 2×2×2×2×22 \times 2 \times 2 \times 2 \times 2

    • Index Form: 252^5

    • Basic Numeral: 3232

    • Pronumeral Expanded Form: x×x×x×xx \times x \times x \times x

    • Pronumeral Index Form: x4x^4

  • Prime Factorisation:

    • Prime factorisation involves expressing a composite number as a product of its prime factors in index notation.

    • Example (Factor Tree for 108108):

108=2×54=2×2×27=2×2×3×9=2×2×3×3×3=22×33108 = 2 \times 54 = 2 \times 2 \times 27 = 2 \times 2 \times 3 \times 9 = 2 \times 2 \times 3 \times 3 \times 3 = 2^2 \times 3^3

  • Real-World Example (Mass Decay):

    • The mass of a 100 kg100\,\text{kg} limestone block decreasing by 2%2\% per year over 2020 years is calculated as:

Mass=100×(0.98)20 kg\text{Mass} = 100 \times (0.98)^{20}\,\text{kg}

  • Professional Applications:

    • Index laws are utilized across numerous fields including by scientists, chemists, radiographers, financial planners, economists, actuaries, astronomers, geologists, computer programmers, and medical, electrical, sound, and aerospace engineers.

  • Worked Examples:

    • Example 1 (Expanded Form):

    • a) a3=a×a×aa^3 = a \times a \times a

    • b) (xy)4=xy×xy×xy×xy(xy)^4 = xy \times xy \times xy \times xy

    • c) 2a3b2=2×a×a×a×b×b2a^3 b^2 = 2 \times a \times a \times a \times b \times b

    • Example 2 (Expanding and Evaluating):

    • a) 53=5×5×5=1255^3 = 5 \times 5 \times 5 = 125

    • b) (−2)5=(−2)×(−2)×(−2)×(−2)×(−2)=−32(-2)^5 = (-2) \times (-2) \times (-2) \times (-2) \times (-2) = -32

    • c) (25)3=25×25×25=8125(\frac{2}{5})^3 = \frac{2}{5} \times \frac{2}{5} \times \frac{2}{5} = \frac{8}{125}

    • Example 3 (Index Form):

    • a) 6×x×x×x×x=6x46 \times x \times x \times x \times x = 6x^4

    • b) 37×37×45×45×45=(37)2×(45)3\frac{3}{7} \times \frac{3}{7} \times \frac{4}{5} \times \frac{4}{5} \times \frac{4}{5} = (\frac{3}{7})^2 \times (\frac{4}{5})^3

    • c) 8×a×a×8×b×b×a×b=8×8×a×a×a×b×b×b=82a3b38 \times a \times a \times 8 \times b \times b \times a \times b = 8 \times 8 \times a \times a \times a \times b \times b \times b = 8^2 a^3 b^3

    • Example 4 (Prime Factor Form):

    • Express 4848 as a product of prime factors in index form:

48=8×6=(2×4)×(2×3)=2×(2×2)×2×3=2×2×2×2×3=24×348 = 8 \times 6 = (2 \times 4) \times (2 \times 3) = 2 \times (2 \times 2) \times 2 \times 3 = 2 \times 2 \times 2 \times 2 \times 3 = 2^4 \times 3

  • Key Principles for Powers of Negative Numbers:

    • Even powers of negative base numbers produce positive results:

(−3)2=9,(−4)2=16(-3)^2 = 9, \quad (-4)^2 = 16

  • Odd powers of negative base numbers produce negative results:

(−2)3=−8,(−2)5=−32(-2)^3 = -8, \quad (-2)^5 = -32

  • Distinguish carefully between brackets and leading negative signs:

(−3)2=9whereas−(3)2=−9(-3)^2 = 9 \quad \text{whereas} \quad -(3)^2 = -9

  • Decimal Powers as Fractions:

    • Converting decimals to fractions simplifies mental power calculations:

(0.5)4=(12)4=12×12×12×12=116(0.5)^4 = (\frac{1}{2})^4 = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{16}

  • Highest Common Factor (HCF) and Lowest Common Multiple (LCM) from Prime Factorisation:

    • HCF: Product of all common prime factors raised to their smallest power.

    • LCM: Product of all different prime factors raised to their highest power.

    • Example for 1212 and 3030:

12=22×3,30=2×3×512 = 2^2 \times 3, \quad 30 = 2 \times 3 \times 5

Common prime factors: 2 and 3  ⟹  HCF=21×31=6\text{Common prime factors: } 2 \text{ and } 3 \implies \text{HCF} = 2^1 \times 3^1 = 6

Highest powers: 22,31,51  ⟹  LCM=22×3×5=60\text{Highest powers: } 2^2, 3^1, 5^1 \implies \text{LCM} = 2^2 \times 3 \times 5 = 60

Index Laws for Multiplication and Division

  • An index law (or identity) is an algebraic equation that holds true for all possible values of the variables involved.

  • Index Law for Multiplication:

    • When multiplying terms with the same base, keep the base and add the powers:

am×an=am+na^m \times a^n = a^{m+n}

  • Derivation via expanded form:

am×an=(a×a×⋯×a)⏟m factors×(a×a×⋯×a)⏟n factors=a×a×⋯×a⏟m+n factors=am+na^m \times a^n = \underbrace{(a \times a \times \dots \times a)}_{m \text{ factors}} \times \underbrace{(a \times a \times \dots \times a)}_{n \text{ factors}} = \underbrace{a \times a \times \dots \times a}_{m+n \text{ factors}} = a^{m+n}

  • Index Law for Division:

    • When dividing terms with the same base, keep the base and subtract the powers:

am÷an=aman=am−na^m \div a^n = \frac{a^m}{a^n} = a^{m-n}

  • Derivation via cancelling factors:

am÷an=a×a×⋯×a⏞m factorsa×a×⋯×a⏟n factors=am−na^m \div a^n = \frac{\overbrace{a \times a \times \dots \times a}^{m \text{ factors}}}{\underbrace{a \times a \times \dots \times a}_{n \text{ factors}}} = a^{m-n}

  • Real-World Modeling Application:

    • Bacteria population after nn generations: P=2nP = 2^n

    • Projected Australian population in millions nn years from 2018: P=25×(1.04)nP = 25 \times (1.04)^n

  • Worked Examples:

    • Example 5 (Numerical Bases):

    • a) 36×34=36+4=3103^6 \times 3^4 = 3^{6+4} = 3^{10}

    • b) 79÷75=79−5=747^9 \div 7^5 = 7^{9-5} = 7^4

    • Example 6 (Algebraic Multiplication):

    • a) x4×x5=x4+5=x9x^4 \times x^5 = x^{4+5} = x^9

    • b) x3y4×x2y=x3+2y4+1=x5y5x^3 y^4 \times x^2 y = x^{3+2} y^{4+1} = x^5 y^5

    • c) 3m4×2m5=(3×2)×m4+5=6m93m^4 \times 2m^5 = (3 \times 2) \times m^{4+5} = 6m^9

    • Example 7 (Algebraic Division):

    • a) x10÷x2=x10−2=x8x^{10} \div x^2 = x^{10-2} = x^8

    • b) 8a6b312a2b2=812a6−2b3−2=23a4b=2a4b3\frac{8a^6 b^3}{12a^2 b^2} = \frac{8}{12} a^{6-2} b^{3-2} = \frac{2}{3} a^4 b = \frac{2a^4 b}{3}

    • Example 8 (Combining Multiplication and Division):

    • a) x2×x3÷x4=x2+3÷x4=x5÷x4=x5−4=x1=xx^2 \times x^3 \div x^4 = x^{2+3} \div x^4 = x^5 \div x^4 = x^{5-4} = x^1 = x

    • b) 2a3b×8a2b34a4b2=16a3+2b1+34a4b2=16a5b44a4b2=4a5−4b4−2=4ab2\frac{2a^3 b \times 8a^2 b^3}{4a^4 b^2} = \frac{16 a^{3+2} b^{1+3}}{4a^4 b^2} = \frac{16 a^5 b^4}{4a^4 b^2} = 4 a^{5-4} b^{4-2} = 4ab^2

Index Laws for Power of a Power and the Zero Index

  • Index Law for Power of a Power:

    • When raising a term in index form to another power, retain the base and multiply the indices:

(am)n=am×n=amn(a^m)^n = a^{m \times n} = a^{mn}

  • Derivation:

(am)n=am×am×⋯×am⏟n factors of am=am+m+⋯+m⏞n times=amn(a^m)^n = \underbrace{a^m \times a^m \times \dots \times a^m}_{n \text{ factors of } a^m} = a^{\overbrace{m + m + \dots + m}^{n \text{ times}}} = a^{mn}

  • The Zero Index Rule:

    • Any non-zero expression raised to the power of zero equals 1:

a0=1,where a≠0a^0 = 1, \quad \text{where } a \neq 0

  • Proof using division law:

amam=1\frac{a^m}{a^m} = 1

Using division law: amam=am−m=a0\text{Using division law: } \frac{a^m}{a^m} = a^{m-m} = a^0

  ⟹  a0=1\implies a^0 = 1

  • Crucial Bracketing Distinctions with Zero Powers:

    • (2a)0=1(2a)^0 = 1 (the power applies to the entire product 2a2a)

    • 2a0=2×1=22a^0 = 2 \times 1 = 2 (the power applies only to aa)

    • (−3)0=1(-3)^0 = 1

    • −(5x)0=−1-(5x)^0 = -1

    • 2y0−(3y)0=2(1)−1=2−1=12y^0 - (3y)^0 = 2(1) - 1 = 2 - 1 = 1

  • Worked Examples:

    • Example 9 (Power of a Power):

    • a) (x5)4=x5×4=x20(x^5)^4 = x^{5 \times 4} = x^{20}

    • b) 3(y5)2=3y5×2=3y103(y^5)^2 = 3y^{5 \times 2} = 3y^{10}

    • Example 10 (Zero Index):

    • a) (−3)0=1(-3)^0 = 1

    • b) −(5x)0=−1-(5x)^0 = -1

    • c) 2y0−(3y)0=2(1)−1=12y^0 - (3y)^0 = 2(1) - 1 = 1

    • Example 11 (Combining Laws):

    • a) (x2)3×(x3)5=x6×x15=x6+15=x21(x^2)^3 \times (x^3)^5 = x^6 \times x^{15} = x^{6+15} = x^{21}

    • b) (m3)4m7=m12m7=m12−7=m5\frac{(m^3)^4}{m^7} = \frac{m^{12}}{m^7} = m^{12-7} = m^5

    • c) 4x2×3x36x5=12x2+36x5=12x56x5=2x5−5=2x0=2×1=2\frac{4x^2 \times 3x^3}{6x^5} = \frac{12x^{2+3}}{6x^5} = \frac{12x^5}{6x^5} = 2x^{5-5} = 2x^0 = 2 \times 1 = 2

  • Exponential Population Growth Example (Mt Burrow Rabbits):

    • Starting population in 2010 (t=0t = 0): 100100

    • Growth model: N=100×2tN = 100 \times 2^t

    • At t=0t = 0 (20102010): N=100×20=100N = 100 \times 2^0 = 100

    • At t=2t = 2 (20122012): N=100×22=400N = 100 \times 2^2 = 400

    • At t=6t = 6 (20162016): N=100×26=6400N = 100 \times 2^6 = 6400

  • Base Transformation Techniques:

    • Base numbers can be converted to prime bases using power of a power:

82=(23)2=26,93=(32)3=36,323=(25)3=215,815=(34)5=3208^2 = (2^3)^2 = 2^6, \quad 9^3 = (3^2)^3 = 3^6, \quad 32^3 = (2^5)^3 = 2^{15}, \quad 81^5 = (3^4)^5 = 3^{20}

Index Laws for Brackets and Fractions

  • Index Law for Brackets (Power of a Product):

    • When multiplying two or more terms inside brackets raised to a power mm, raise each factor inside the brackets to the power mm:

(a×b)m=(ab)m=ambm(a \times b)^m = (ab)^m = a^m b^m

  • Derivation:

(ab)m=ab×ab×⋯×ab⏟m factors=(a×a×⋯×a)⏟m factors×(b×b×⋯×b)⏟m factors=ambm(ab)^m = \underbrace{ab \times ab \times \dots \times ab}_{m \text{ factors}} = \underbrace{(a \times a \times \dots \times a)}_{m \text{ factors}} \times \underbrace{(b \times b \times \dots \times b)}_{m \text{ factors}} = a^m b^m

  • Index Law for Fractions (Power of a Quotient):

    • When dividing two terms inside brackets raised to a power mm, raise both the numerator and denominator to the power mm (b≠0b \neq 0):

(ab)m=ambm\left(\frac{a}{b}\right)^m = \frac{a^m}{b^m}

  • Derivation:

(ab)m=ab×ab×⋯×ab⏟m factors=a×a×⋯×a⏞m factorsb×b×⋯×b⏟m factors=ambm\left(\frac{a}{b}\right)^m = \underbrace{\frac{a}{b} \times \frac{a}{b} \times \dots \times \frac{a}{b}}_{m \text{ factors}} = \frac{\overbrace{a \times a \times \dots \times a}^{m \text{ factors}}}{\underbrace{b \times b \times \dots \times b}_{m \text{ factors}}} = \frac{a^m}{b^m}

  • Real-World Finance Application (Compound Interest):

    • An amount $P\$P invested at r%r\% p.a. for nn years grows to:

A=P(1+r100)nA = P \left(1 + \frac{r}{100}\right)^n

  • Worked Examples:

    • Example 12 (Index Law for Brackets):

    • a) (5b)3=53b3=125b3(5b)^3 = 5^3 b^3 = 125b^3

    • b) (−2x3y)4=(−2)4(x3)4y4=16x12y4(-2x^3 y)^4 = (-2)^4 (x^3)^4 y^4 = 16x^{12} y^4

    • c) 4(c2d3)5=4(c2)5(d3)5=4c10d154(c^2 d^3)^5 = 4(c^2)^5 (d^3)^5 = 4c^{10} d^{15}

    • d) 3a2(2a3)4=3a2×24(a3)4=3a2×16a12=48a2+12=48a143a^2 (2a^3)^4 = 3a^2 \times 2^4 (a^3)^4 = 3a^2 \times 16 a^{12} = 48a^{2+12} = 48a^{14}

    • Example 13 (Index Law for Fractions):

    • a) (6b)3=63b3=216b3(\frac{6}{b})^3 = \frac{6^3}{b^3} = \frac{216}{b^3}

    • b) (−2a23bc3)4=(−2)4(a2)434b4(c3)4=16a881b4c12(\frac{-2a^2}{3bc^3})^4 = \frac{(-2)^4 (a^2)^4}{3^4 b^4 (c^3)^4} = \frac{16a^8}{81b^4 c^{12}}

    • c) (x2y3c)3×(xcy)4=x6y9c3×x4c4y4=x10y9c4c3y4=x10y5c(\frac{x^2 y^3}{c})^3 \times (\frac{xc}{y})^4 = \frac{x^6 y^9}{c^3} \times \frac{x^4 c^4}{y^4} = \frac{x^{10} y^9 c^4}{c^3 y^4} = x^{10} y^5 c

Negative Indices

  • Definition and Derivation:

    • A negative index indicates division or reciprocal relationship:

a−m=1ama^{-m} = \frac{1}{a^m}

  • Derivation via division:

a2a5=a2−5=a−3\frac{a^2}{a^5} = a^{2-5} = a^{-3}

Alternatively: a2a5=a×aa×a×a×a×a=1a3  ⟹  a−3=1a3\text{Alternatively: } \frac{a^2}{a^5} = \frac{a \times a}{a \times a \times a \times a \times a} = \frac{1}{a^3} \implies a^{-3} = \frac{1}{a^3}

  • Core Negative Index Rules:

    • Negative index in denominator:

1a−m=am\frac{1}{a^{-m}} = a^m

  • Reciprocal rule:

a−1=1aa^{-1} = \frac{1}{a}

  • Fraction raised to negative power:

(ab)−1=ba\left(\frac{a}{b}\right)^{-1} = \frac{b}{a}

(ab)−m=(ba)m=bmam\left(\frac{a}{b}\right)^{-m} = \left(\frac{b}{a}\right)^m = \frac{b^m}{a^m}

  • Real-World Audio Engineering Application:

    • Inverse square law for sound intensity II relative to distance dd:

I∝1d2  ⟹  I∝d−2I \propto \frac{1}{d^2} \implies I \propto d^{-2}

  • Worked Examples:

    • Example 14 (Expressing with Positive Indices):

    • a) x−2=1x2x^{-2} = \frac{1}{x^2}

    • b) 3a−2b4=31×1a2×b41=3b4a23a^{-2} b^4 = \frac{3}{1} \times \frac{1}{a^2} \times \frac{b^4}{1} = \frac{3b^4}{a^2}

    • Example 15 (Moving Negative Powers Across Fractions):

    • a) 1c−2=c2\frac{1}{c^{-2}} = c^2

    • b) 5x3y−4=5y4x3\frac{5}{x^3 y^{-4}} = \frac{5y^4}{x^3}

    • c) x−3y−5=1x3×y51=y5x3\frac{x^{-3}}{y^{-5}} = \frac{1}{x^3} \times \frac{y^5}{1} = \frac{y^5}{x^3}

    • Example 16 (Evaluating without Calculator):

    • a) 3−4=134=1813^{-4} = \frac{1}{3^4} = \frac{1}{81}

    • b) −53−2=−5×32=−5×9=−45\frac{-5}{3^{-2}} = -5 \times 3^2 = -5 \times 9 = -45

    • c) (23)−4=2−43−4=3424=8116(\frac{2}{3})^{-4} = \frac{2^{-4}}{3^{-4}} = \frac{3^4}{2^4} = \frac{81}{16}

Scientific Notation

Nanobots and red blood cells
  • General Form of Scientific Notation (Standard Form):

a×10m,where 1≤a<10 (or −10<a≤−1) and m∈Za \times 10^m, \quad \text{where } 1 \le a < 10 \text{ (or } -10 < a \le -1\text{) and } m \in \mathbb{Z}

  • Sign of the Power mm:

    • Large numbers (≥10\ge 10): Use positive powers of 1010.

    • Example: 38 million years=38000000=3.8×10738\,\text{million years} = 38000000 = 3.8 \times 10^7

    • Small numbers (<1< 1): Use negative powers of 1010.

    • Example: 417 nanoseconds=0.000000417=4.17×10−7417\,\text{nanoseconds} = 0.000000417 = 4.17 \times 10^{-7}

  • Metric Prefixes and Corresponding Powers of 10:

    • Tera (T\text{T}): 101210^{12} (e.g., 1 terabyte=1012 bytes1\,\text{terabyte} = 10^{12}\,\text{bytes})

    • Giga (G\text{G}): 10910^9 (e.g., 16 gigabytes=1.6×1010 bytes16\,\text{gigabytes} = 1.6 \times 10^{10}\,\text{bytes})

    • Mega (M\text{M}): 10610^6 (e.g., 1 megalitre=106 litres1\,\text{megalitre} = 10^6\,\text{litres})

    • Kilo (k\text{k}): 10310^3 (e.g., 2178 km=2.178×106 m2178\,\text{km} = 2.178 \times 10^6\,\text{m})

    • Milli (m\text{m}): 10−310^{-3} (e.g., 109 ms=0.109 s=1.09×10−1 s109\,\text{ms} = 0.109\,\text{s} = 1.09 \times 10^{-1}\,\text{s})

    • Micro (μ\mu): 10−610^{-6} (e.g., 27 microns=2.7×10−5 m27\,\text{microns} = 2.7 \times 10^{-5}\,\text{m})

    • Nano (n\text{n}): 10−910^{-9} (e.g., 54 nanoseconds=5.4×10−8 s54\,\text{nanoseconds} = 5.4 \times 10^{-8}\,\text{s})

    • Pico (p\text{p}): 10−1210^{-12} (e.g., 18 picograms=1.8×10−11 g18\,\text{picograms} = 1.8 \times 10^{-11}\,\text{g})

  • Real-World Context Examples:

    • Concrete in Hoover Dam: 3400000 m3=3.4×106 m33400000\,\text{m}^3 = 3.4 \times 10^6\,\text{m}^3

    • Mass of water molecule: 0.0000000000000000000000299 g=2.99×10−23 g0.0000000000000000000000299\,\text{g} = 2.99 \times 10^{-23}\,\text{g}

    • Targeted nanobots: 3×10−6 m3 \times 10^{-6}\,\text{m} long with 1×10−9 m1 \times 10^{-9}\,\text{m} components.

  • Worked Examples:

    • Example 17 (Converting to Scientific Notation):

    • a) 4500000=4.5×1064500000 = 4.5 \times 10^6 (decimal shifted 6 places left)

    • b) 0.0000004=4×10−70.0000004 = 4 \times 10^{-7} (decimal shifted 7 places right)

    • Example 18 (Converting to Decimal Form):

    • a) 9.34×105=9340009.34 \times 10^5 = 934000

    • b) 4.71×10−5=0.00004714.71 \times 10^{-5} = 0.0000471

Scientific Notation using Significant Figures

Palaeontologist examining T-Rex skull
  • Rules for Counting Significant Figures:

    • Count digits from left to right starting at the first non-zero digit.

    • Zeros to the left of the first non-zero digit are not significant.

    • Examples:

    • 3804138041 has 5 significant figures.

    • 0.00160.0016 has 2 significant figures.

    • 3.21×1043.21 \times 10^4 has 3 significant figures.

  • Scientific Notation and Significant Figures:

    • In scientific notation a×10ma \times 10^m, exactly one non-zero significant figure sits to the left of the decimal point, and all digits shown in aa are significant.

  • Palaeontology Application:

    • Estimated timeframe for Tyrannosaurus Rex on Earth: 7×1077 \times 10^7 to 6.5×1076.5 \times 10^7 years ago.

  • Calculator Notation:

    • Calculators represent 2.37×1052.37 \times 10^5 as 2.37E5 or 2.37EE5 or using EXP / x10^x keys.

  • Worked Examples:

    • Example 19 (Counting Significant Figures):

    • a) 451  ⟹  3 significant figures451 \implies 3\text{ significant figures}

    • b) 0.005012  ⟹  4 significant figures0.005012 \implies 4\text{ significant figures}

    • c) 3.2×107  ⟹  2 significant figures3.2 \times 10^7 \implies 2\text{ significant figures}

    • Example 20 (Rounding to Significant Figures):

    • a) 2183000=2.18×1062183000 = 2.18 \times 10^6 (correct to 3 significant figures)

    • b) 0.0019482=1.95×10−30.0019482 = 1.95 \times 10^{-3} (correct to 3 significant figures)

    • Example 21 (Calculator Operations):

    • a) (3.67×105)×(23.6×104)=8.6612×1010=8.661×1010(3.67 \times 10^5) \times (23.6 \times 10^4) = 8.6612 \times 10^{10} = 8.661 \times 10^{10} (to 4 sig. figs.)

    • b) 7.6×10−3+2.4×10−2=0.162518⋯=1.625×10−17.6 \times 10^{-3} + \sqrt{2.4 \times 10^{-2}} = 0.162518\dots = 1.625 \times 10^{-1} (to 4 sig. figs.)

Fractional Indices and Surds (Extending)

  • Relationship Between Radical Notation and Fractional Indices:

    • A fractional power represents a root:

a1m=ama^{\frac{1}{m}} = \sqrt[m]{a}

  • Specifically:

a12=a(square root),a13=a3(cube root)a^{\frac{1}{2}} = \sqrt{a} \quad (\text{square root}), \quad a^{\frac{1}{3}} = \sqrt[3]{a} \quad (\text{cube root})

  • General Fractional Exponent:

anm=(a1m)n=(am)n=anma^{\frac{n}{m}} = (a^{\frac{1}{m}})^n = (\sqrt[m]{a})^n = \sqrt[m]{a^n}

  • Rational Numbers vs. Surds (Irrational Numbers):

    • Rational Numbers: Can be expressed exactly as a fraction pq\frac{p}{q} (q≠0q \neq 0).

    • Example: 912=9=3=319^{\frac{1}{2}} = \sqrt{9} = 3 = \frac{3}{1}

    • Surds: Irrational numbers written with a root sign whose decimal expansion is infinite and non-recurring with no repeating pattern.

    • Example: 513=53=1.70997594668…5^{\frac{1}{3}} = \sqrt[3]{5} = 1.70997594668\dots

    • Example: 2=1.41421356237…\sqrt{2} = 1.41421356237\dots

    • Example: 3=1.73205080757…\sqrt{3} = 1.73205080757\dots

  • Classical Guitar Fret Spacing Application:

    • For a scale length L mmL\,\text{mm}, the distance x mmx\,\text{mm} of the nn-th fret from the bridge is modeled by:

x=L×2−n12x = L \times 2^{-\frac{n}{12}}

  • At the 12th fret: x=L×2−1212=L×2−1=L2x = L \times 2^{-\frac{12}{12}} = L \times 2^{-1} = \frac{L}{2} (halving distance, doubling pitch to one octave higher).

    • Worked Examples:

  • Example 22 (Writing with Root Signs):

    • a) 612=66^{\frac{1}{2}} = \sqrt{6}

    • b) 215=252^{\frac{1}{5}} = \sqrt[5]{2}

  • Example 23 (Evaluating Fractional Powers):

    • a) 14412=144=12144^{\frac{1}{2}} = \sqrt{144} = 12

    • b) 2713=273=327^{\frac{1}{3}} = \sqrt[3]{27} = 3

  • Example 24 (Index Laws with Fractional Indices):

    • a) a12×a32=a12+32=a42=a2a^{\frac{1}{2}} \times a^{\frac{3}{2}} = a^{\frac{1}{2} + \frac{3}{2}} = a^{\frac{4}{2}} = a^2

    • b) x12x13=x12−13=x36−26=x16\frac{x^{\frac{1}{2}}}{x^{\frac{1}{3}}} = x^{\frac{1}{2} - \frac{1}{3}} = x^{\frac{3}{6} - \frac{2}{6}} = x^{\frac{1}{6}}

    • c) (y2)14=y2×14=y24=y12(y^2)^{\frac{1}{4}} = y^{2 \times \frac{1}{4}} = y^{\frac{2}{4}} = y^{\frac{1}{2}}

Simple Operations with Surds (Extending)

  • Addition and Subtraction of Surds:

    • Surds can only be added or subtracted if they are 'like' surds (contain the exact same number under the radical sign).

    • Examples:

23+33=532\sqrt{3} + 3\sqrt{3} = 5\sqrt{3}

117−27=9711\sqrt{7} - 2\sqrt{7} = 9\sqrt{7}

3+5(cannot be simplified, as they are unlike surds)\sqrt{3} + \sqrt{5} \quad \text{(cannot be simplified, as they are unlike surds)}

  • Key Operations and Identities:

    • Square of a Radical:

(a)2=a(\sqrt{a})^2 = a

  • Multiplication Rule for Surds:

a×b=ab\sqrt{a} \times \sqrt{b} = \sqrt{ab}

  • Division Rule for Surds:

a÷b=ab=ab\sqrt{a} \div \sqrt{b} = \frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}

  • Spacecraft Escape Velocity Application:

    • Formula for a spacecraft's escape velocity from gravity:

v=2GMRv = \sqrt{2} \sqrt{\frac{GM}{R}}

  • Worked Examples:

    • Example 25 (Adding and Subtracting Surds):

    • a) 25+65=852\sqrt{5} + 6\sqrt{5} = 8\sqrt{5}

    • b) 3−53=−43\sqrt{3} - 5\sqrt{3} = -4\sqrt{3}

    • Example 26 (Multiplying and Dividing Surds):

    • a) 3×10=3×10=30\sqrt{3} \times \sqrt{10} = \sqrt{3 \times 10} = \sqrt{30}

    • b) 24÷8=248=3\sqrt{24} \div \sqrt{8} = \sqrt{\frac{24}{8}} = \sqrt{3}

  • Simplifying Surds using Perfect Square Factors:

    • If the number under the root sign has a factor that is a perfect square (4,9,16,25,36,49,64,81,1004, 9, 16, 25, 36, 49, 64, 81, 100, etc.), extract it:

18=9×2=9×2=32\sqrt{18} = \sqrt{9 \times 2} = \sqrt{9} \times \sqrt{2} = 3\sqrt{2}

8−2=4×2−2=22−2=2\sqrt{8} - \sqrt{2} = \sqrt{4 \times 2} - \sqrt{2} = 2\sqrt{2} - \sqrt{2} = \sqrt{2}

Applications, Technology, and Investigations

  • Geometric Construction of Surds on a Number Line:

Geometrical construction of surds on a number line
  • Surds can be located precisely on a number line using right-angled triangle diagonals and circles (Pythagoras' Theorem: c2=a2+b2  ⟹  c=a2+b2c^2 = a^2 + b^2 \implies c = \sqrt{a^2 + b^2}):

    • Unit square (1×11 \times 1): Diagonal length c=12+12=2≈1.4142c = \sqrt{1^2 + 1^2} = \sqrt{2} \approx 1.4142

    • Rectangle 1×21 \times 2: Diagonal length c=12+22=5≈2.2361c = \sqrt{1^2 + 2^2} = \sqrt{5} \approx 2.2361

    • Constructing 6\sqrt{6}: Use a rectangle with sides 22 and 2\sqrt{2}: Diagonal length c=22+(2)2=4+2=6c = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{4 + 2} = \sqrt{6}

    • Cell Division and Growth (Mitosis):

  • Single cell dividing into 2 every hour: N=2nN = 2^n

  • Single cell dividing into 3 every hour: N=3nN = 3^n

  • Splitting every 20 minutes (33 cycles per hour) for 4 hours (1212 cycles): N=212=4096 cellsN = 2^{12} = 4096\,\text{cells}

    • Physics Application (Universal Law of Gravitation):

  • Gravitational force formula:

F=Gm1m2d2,where G=6.67×10−11 Nm2kg−2F = \frac{G m_1 m_2}{d^2}, \quad \text{where } G = 6.67 \times 10^{-11}\,\text{N}\text{m}^2\text{kg}^{-2}

  • Gravitational acceleration formula a=Gmr2a = \frac{Gm}{r^2}.

    • Surface acceleration on Earth (m=5.98×1024 kg,r=6.375×106 mm = 5.98 \times 10^{24}\,\text{kg}, r = 6.375 \times 10^6\,\text{m}):

aEarth=(6.67×10−11)×(5.98×1024)(6.375×106)2≈9.81 m/s2a_{\text{Earth}} = \frac{(6.67 \times 10^{-11}) \times (5.98 \times 10^{24})}{(6.375 \times 10^6)^2} \approx 9.81\,\text{m/s}^2

- Surface acceleration on Mars (m=6.42×1023 kg,r=3.37×106 mm = 6.42 \times 10^{23}\,\text{kg}, r = 3.37 \times 10^6\,\text{m}):

aMars=(6.67×10−11)×(6.42×1023)(3.37×106)2≈3.77 m/s2a_{\text{Mars}} = \frac{(6.67 \times 10^{-11}) \times (6.42 \times 10^{23})}{(3.37 \times 10^6)^2} \approx 3.77\,\text{m/s}^2